Which sequence is modeled by the graph below?

The total surface area of the shape is 10053 cm²

From the question, we are to determine the surface area of the shape

The surface area of the shape = Surface area of hemispherical part + Surface are of the cylindrical part

∴ Surface area of the shape = 2πr² + 2πrh + πr²

Where r is the radius

and h is the height of the cylindrical part

From the given information.

r = 20

h = 50

Putting the parameters into the equation, we get

Surface area of the shape = 2π(20)² + 2π(20)(50) + π(20)²

Surface area of the shape = 2π×400+ 2π×1000 + π×400

Surface area of the shape = 800π+ 2000π + 400π

Surface area of the shape = 3200π cm²

Surface area of the shape = 10053.096 cm²

Surface area of the shape ≈ 10053 cm²

Hence, the total surface area of the shape is 10053 cm²

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Answer:

$1.40

Step-by-step explanation:

5.00-0.80=4.20

4.20 ÷ 3= 1.40

The price of the product before promotional sales was 500,000.

To find what the previous price of the product was, we must take into account that we know that 87% of the value is equal to 435,000. So to find out how much the 13% (discount) that the product had is equivalent to, we do the following operation:

435,000 × 100 ÷ 87 = 500,000

So we know that the 13% discount was 65,000

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Answer:

14cm.

Step-by-step explanation:

X is the hypotenus, 7√3 is the opposite and the other side is the adjacent. Choose sin from (soh, cah, toa) because you have to find 'H' (hyp) and opposite is given. Hence, sin 60= 7√3 over x. Cross multiply and you'll get x * sin 60= 7√3. Make x the subject of formula and 14 will be the answer.

Answer:

12

Step-by-step explanation:

Factoring out a 1/4 from 1/4a - 3, you get 1/4 (a - 12) as 12 * 1/4 = 3. Thus, ? = 12.

Answer:

either 885 more or 450 more

Step-by-step explanation:

Monday: 1000

Tuesday: 1000*1.3 = 1300

Wednesday:

I'm assuming 45% more from tuesday?

          1300*1.45 = 1885

or if not:

          1000*1.45 = 1450

either 885 more or 450 more

you can also just do 1000*1.3*1.45 = 1000*1.885 = 1885 if thats what the question means

The mold the candlemaker can use to make the larger-sized candle is 480 cubic centimeters.

A cylinder is a surface created by projecting a closed two-dimensional curve along an axis intersecting the plane of the curve.

larger-sized candle = 2(smaller-sized candle)

= 2(240 cubic centimeters)

= 480 cubic centimeters

Therefore, the mold the candlemaker can use to make the larger-sized candle is 480 cubic centimeters.

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Answer:

A cylinder with a height that is double the height of the original mold, and a radius that is the same as the radius of the original mold.

Hope this helps!

Step-by-step explanation:

An example of the real world example of a rational function would be when a person would decide to share a cookie with their friend. Each of them would get half of the cookie each.

This is the term that is used to refer to the fraction that is represented by the use of a rational fraction. That is there is denominator and a numerator.

The denominator must have a variable and this variable has to be of degree 1. Hence the real world example of a rational function would be when a person would decide to share a cookie with their friend. Each of them would get half of the cookie each.

First you have to know if it is an inequality or not. Then you have to assign x and y variables to numbers. From here you form an equation. This equation is plotted on a graph.

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The most appropriate model for a given situation is exponential.

The most appropriate model for a given situation is exponential.

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The length of the side of the square is [tex]44 cm[/tex].

Determine the length of the side of the square:

Radius of circle[tex]=28.[/tex]

Circumference[tex]=2\pi r[/tex]

                        [tex]2\pi (28)=176[/tex]

Side of the square[tex]=\frac{176}{4} =44cm.[/tex]

The length of the side of the square is [tex]44 cm[/tex].

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The Laplace of the given equation is [tex]y=-\frac{15e^2}{8}e^{2t}+\left(-3e^2+\frac{15e^2}{4}\right)e^{2t}t+\frac{e^2t^4}{4}+e^2t^3+\frac{9e^2t^2}{4}+3e^2t+\frac{15e^2}{8}[/tex].

According to the statement

we have given that the equation and we have to solve this problem with the help of the Laplace transform.

So, According to the statement

the given equation is

y'' − 4y' + 4y = t^3e^2t, y(0) = 0, y'(0) = 0

And the Laplace transform is an integral transform method which is particularly useful in solving linear ordinary differential equations.

Firstly fill the value of the Laplace of the second order derivative and put x = 0 in the equation

And same it with the first order of the derivative.

And then the Laplace of the equation become

[tex]y=-\frac{15e^2}{8}e^{2t}+\left(-3e^2+\frac{15e^2}{4}\right)e^{2t}t+\frac{e^2t^4}{4}+e^2t^3+\frac{9e^2t^2}{4}+3e^2t+\frac{15e^2}{8}[/tex]

So, The Laplace of the given equation is [tex]y=-\frac{15e^2}{8}e^{2t}+\left(-3e^2+\frac{15e^2}{4}\right)e^{2t}t+\frac{e^2t^4}{4}+e^2t^3+\frac{9e^2t^2}{4}+3e^2t+\frac{15e^2}{8}[/tex]

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Hey there!

⇒ Use the vertex as the middle letter, and the point from each side (<ABC or <CBA)

⇒ Use the vertex only (<B)

⇒ Use a number (<1)

⇒ Acute angle: less than 90°

⇒ Right angle: exactly 90°

⇒ Obtuse angle: between 90° and 180°

⇒ Straight angle: exactly 180°

Thank you,

Eddie

See the attachment for a visual!

Part (a)

We'll use the distance formula.

[tex](x_1,y_1) = (-4,-7) \text{ and } (x_2, y_2) = (5,-2)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-4-5)^2 + (-7-(-2))^2}\\\\d = \sqrt{(-4-5)^2 + (-7+2)^2}\\\\d = \sqrt{(-9)^2 + (-5)^2}\\\\d = \sqrt{81 + 25}\\\\d = \sqrt{106}\\\\d \approx 10.2956\\\\[/tex]

The diameter is exactly [tex]\sqrt{106}[/tex] units long which approximates to roughly 10.2956 units. Round that decimal value however your teacher instructs.

========================================================

Part (b)

We divide the diameter in half to get the radius.

Therefore, the radius is exactly [tex]\frac{\sqrt{106}}{2}[/tex] units long which is approximately 5.1478 units.

By trigonometric functions and formulae, we find that the exact value of the cosine function is -√3 / 2.

In this question we have hints from two trigonometric functions necessary to find the exact value of the cosine function. In accordance with trigonometry, cosecant function is positive and tangent function is negative in the third quadrant of Cartesian plane and therefore the cosine function must be a negative number. Therefore, we can derive the value of the latter function by trigonometric formulas:

cos θ = - √[1 - (1 / csc θ)²]

If we know that csc θ = 2, then the exact of the cosine function is:

cos θ = -√[1 - (1 / 2)²]

cos θ = -√(3 / 4)

cos θ = -√3 / 2

By trigonometric functions and formulae, we find that the exact value of the cosine function is -√3 / 2.

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The area of the square A2 is 20 squared units

The complete question requires that we calculate the area of square A2

The side length of each square is 6 units.

So, the side length (L) of A2 is

L^2 = (2)^2 + (6 - 2)^2

This gives

L^2 = 20

The above represents the area of the square A2

Hence, the area of the square A2 is 20 squared units

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Answer:

Step-by-step explanation:

assuming you are looking for the area of ​​the triangles, there is no specific question, they are right-angled triangles congruent with the catheti of 2 and 4 units.

Triangle area = 1/2 base x height.

so 1/2 2 * 4 = 4 units^2

From the graph, the equation of f(x) + g(x) is f(x) + g(x) = 2x + 3

The functions are given as:

f(x) = x + 3

g(x) = x

From the above functions, we can see that the function g(x) is the parent function of a linear function.

When the parent function of a linear function is added to another function to form a composite function, the new function would pass through the following points

(x, y)= (0, b) and (-b, -b)

Where b is the y-intercept of the other function

i.e b = 3 from f(x) = x + 3

So, we have the following points

(0, 3) and (-3, -3)

Next, we draw the points and we connect the points

When the equation of f(x) + g(x) is calculated, we have

f(x) + g(x) = 2x + 3

See attachment for the graph of the functions

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[tex](\stackrel{x_1}{10}~,~\stackrel{y_1}{7})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{2}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7}=\stackrel{m}{-\cfrac{2}{5}}(x-\stackrel{x_1}{10})[/tex]

Answer:

  21.0 m²

Step-by-step explanation:

The formula for the area of a triangle from two sides and the included angle is ...

  A = 1/2ab·sin(C)

Using this formula, we find the area to be ...

  A = 1/2(14 m)(8 m)sin(22°) = 21.0 m²

The area of triangle ABC is about 21.0 square meters.

Using a linear function, it is found that they will have 405 MB of free space when they first have the same amount of space left.

A linear function is modeled by:

y = mx + b

In which:

The free space for each of Nereo and Azeneth can be modeled by a linear function, in which the slope is negative with the amount that each second of video takes and the y-intercept is the initial free space. Her the functions for the amount of free space after x seconds are given by:

They will have the same amount of free space when:

N(x) = A(x)

1000 - 7x = 1255 - 10x

3x = 255

x = 255/3

x = 85.

The space will be of:

N(85) = 1000 - 7 x 85 = 405 MB.

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Concluding, there are (2 + 12) boxes of pencils left.

We know that Ms. Bloom had (4 + 7/12) boxes of pencils, and we also know that (2 + 1/12) of the boxes were broken.

The number of boxes of pencils left is given by the difference between the two above numbers, then we get:

N = (4 + 7/12) - (2 + 1/12) = (4 - 2) + (7/12 - 1/12) = 2 + 6/12

Now we can simplify the fraction:

N = 2 + 1/2

Concluding, there are (2 + 12) boxes of pencils left.

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The area of the trapezoidal tarp in the hotel is 47.3 square inches.

How do determine the area of the trapezoid?

From the complete question, the parallel sides are 10ft and 12ft.

Evaluate,

The height (h) is computed using the cosine function shown below:

This gives

Make h the subject:

Evaluate:

So, we get:

Evaluate:

Therefore, the area of the trapezoidal tarp in the hotel is 47.3 square inches.

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The complete question is given below:
A hotel builds an isosceles trapezoidal pool for children. it orders a tarp to cover the pool when not in use. what is the area of the tarp?

to find the height. first find that d is 60,45, or 120. this means the height of the trapezoid is approximately 2.5,4.3, or 3.5 feet. so the area of the tarp is approximately 47.3,30.0 or 38.5 square feet.

The equivalent expression to [tex](k o h)(x)[/tex]is [tex]\frac{1}{5 + x}[/tex]

Therefore  [tex](k o h)(x) = \frac{1}{5 + x}[/tex]

Given that the functions h is defined by h(x)=5+x

and k is defined by k (x) = [tex]\frac{1}{x}[/tex]

To find the composition of k and h that is: (k o h) (x)

Therefore

k (h(x)) = k (5+x)

k (h(x)) = [tex]\frac{1}{5+ x}[/tex]

The equivalent expression to is [tex]\frac{1}{5+ x}[/tex]

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The given height of this trapezoid is given to be 4.5m

We have to solve for this by making use of the height of a trapezoid. The height is given as

A = (1/2) h (b1 + b2)

The variables here are

h = height

b1 = lenght at base 1

b2 = length at base 2

If the trapezoid that we have is a isosceles triangle, then base 1 is going to be the same length as that of the first base

b1 = 4 ft is the area. Given that the height has to be at least 4.5feet, then this would ensure that the trapezoid would be able to hold the shed.

Hence the height would begiven as 4.5 ft

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Answer: 4.5

Step-by-step explanation:

Step-by-step explanation:

the general slope-intercept form is

y = ax + b

a is the slope, b is the y-intercept.

we need to transform x + 2y = 6, so that we end up with y being all alone on one side, and the rest on the other side.

x + 2y = 6

2y = -x + 6

y = -x/2 + 6

Answer:

5/6

Step-by-step explanation:

slope = 4-(-1)/8-2 = 5/6

The limit of [tex]\lim_{x \to \infty} \frac{lnx}{x}[/tex]  using L'Hospital rule is 0.

According to the given question.

We have to find the limit of ln(x)/x when x approaches to infinity.

If we let x = ∞, we get an indeterminate form [tex]\frac{\infty}{\infty}[/tex] ie. [tex]\frac{ln(x)}{x} = \frac{\infty}{\infty}[/tex].

And, we know that whenever we get indeterminate form ∞/∞ we apply L'Hospital rule.

Therefore, defferentiating numerator ln(x) and x with respect to x.

[tex]\implies \frac{d(ln(x))}{dx} = \frac{1}{x}[/tex] and [tex]\frac{d(x)}{dx} =1[/tex]

So,

[tex]\lim_{x\to \infty}\frac{\frac{1}{x} }{1}[/tex]

[tex]= \lim_{x \to \infty} \frac{1}{x}[/tex]

As, x tends to ∞, 1/x tends to 0. Because ∞ is very large number and 1 divided by a very large number always approaches to 0 and it is very close to zero.

Therefore,

[tex]\lim_{x \to \infty} \frac{1}{x} = 0[/tex]

Hence, the limit of [tex]\lim_{x \to \infty} \frac{lnx}{x}[/tex] is 0.

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Answer:

23.  216

24.  56

25.  52

26.  -7

27.  5

Step-by-step explanation:

Work out the differences between the terms until the differences are the same:

[tex]1 \underset{+7}{\longrightarrow} 8 \underset{+19}{\longrightarrow} 27 \underset{+37}{\longrightarrow} 64 \underset{+61}{\longrightarrow} 125[/tex]

    [tex]7 \underset{+12}{\longrightarrow} 19 \underset{+18}{\longrightarrow} 37 \underset{+24}{\longrightarrow} 61[/tex]

        [tex]12 \underset{+6}{\longrightarrow} 18 \underset{+6}{\longrightarrow} 24[/tex]

As the third differences are the same, the sequence is cubic and will contain an n³ term.  The coefficient of n³ is always a sixth of the third difference.  Therefore, the coefficient of n³ = 1.

To work out the nth term of the sequence, write out the numbers in the sequence n³ and compare this sequence with the sequence in the question.

[tex]\begin{array}{| c | c | c | c | c | c |}\cline{1-6} n&1 & 2 & 3&4&5 \\\cline{1-6} n^3 & 1 & 8 & 27 & 64 & 125 \\\cline{1-6} \sf sequence & 1 & 8 & 27 & 64 & 125 \\\cline{1-6}\end{array}[/tex]

Therefore, the nth term is:

[tex]a_n=n^3[/tex]

So the next term in the sequence is:

[tex]\implies a_6=6^3=216[/tex]

Work out the differences between the terms until the differences are the same:

[tex]2 \underset{+4}{\longrightarrow} 6 \underset{+6}{\longrightarrow} 12 \underset{+8}{\longrightarrow} 20 \underset{+10}{\longrightarrow} 30 \underset{+12}{\longrightarrow} 42[/tex]

     [tex]4 \underset{+2}{\longrightarrow} 6 \underset{+2}{\longrightarrow} 8 \underset{+2}{\longrightarrow} 10 \underset{+2}{\longrightarrow} 12[/tex]

As the second differences are the same, the sequence is quadratic and will contain an n² term.  The coefficient of n² is always half of the second difference.  Therefore, the coefficient of n² = 1.

To work out the nth term of the sequence, write out the numbers in the sequence n² and compare this sequence with the sequence in the question.

[tex]\begin{array}{| c | c | c | c | c | c | c |}\cline{1-7} n&1 & 2 & 3&4&5&6 \\\cline{1-7} n^2 & 1 & 4 & 9 & 16 & 25 &36\\\cline{1-7} \sf operation & +1 & +2 & +3 & +4 & +5 & +6 \\\cline{1-7} \sf sequence & 2 & 6 & 12 & 20 & 30 & 42 \\\cline{1-7}\end{array}[/tex]

Therefore, the nth term is:

[tex]a_n=n^2+n[/tex]

So the next term in the sequence is:

[tex]\implies a_7=7^2+7=56[/tex]

Work out the differences between the terms until the differences are the same:

[tex]4 \underset{+3}{\longrightarrow} 7 \underset{+5}{\longrightarrow} 12 \underset{+7}{\longrightarrow} 19 \underset{+9}{\longrightarrow} 28 \underset{+11}{\longrightarrow} 39[/tex]

     [tex]3 \underset{+2}{\longrightarrow} 5 \underset{+2}{\longrightarrow} 7 \underset{+2}{\longrightarrow} 9 \underset{+2}{\longrightarrow} 11[/tex]

As the second differences are the same, the sequence is quadratic and will contain an n² term.  The coefficient of n² is always half of the second difference.  Therefore, the coefficient of n² = 1.

To work out the nth term of the sequence, write out the numbers in the sequence n² and compare this sequence with the sequence in the question.

[tex]\begin{array}{| c | c | c | c | c | c | c |}\cline{1-7} n&1 & 2 & 3&4&5&6 \\\cline{1-7} n^2 & 1 & 4 & 9 & 16 & 25 &36\\\cline{1-7} \sf operation & +3 & +3 & +3 & +3 & +3 & +3 \\\cline{1-7} \sf sequence & 4&7&12&19&28&39 \\\cline{1-7}\end{array}[/tex]

Therefore, the nth term is:

[tex]a_n=n^2+3[/tex]

So the next term in the sequence is:

[tex]\implies a_7=7^2+3=52[/tex]

Given numbers:

-1, 2, -3, 4, -5, 6

As the list of numbers does not increase or decrease, we cannot apply the same method as the previous questions.

[tex]\begin{array}{| c | c | c | c | c | c | c |}\cline{1-7} n&1 & 2 & 3&4&5&6 \\\cline{1-7} \sf list & -1 & 2 & -3 & 4 & -5 & 6 \\\cline{1-7}\end{array}[/tex]

From comparing the position of the term to its number in the list, we can see that the nth term is the same as n, but the odd numbers are negative and the even numbers are positive.

Therefore, the rule is:

[tex]\implies a_n=n \quad \textsf{where }n \textsf{ is an even natural number}[/tex]

[tex]\implies a_n=-n \quad \textsf{where }n \textsf{ is an odd natural number}[/tex]

So the next term in the sequence is:

[tex]\implies a_7=-7[/tex]

(since 7 is an odd natural number)

Given numbers:

5, 3, 5, 5, 3, 5, 5, 5, 3, 5, 5, 5, 5, 3, 5, 5, 5, 5

The pattern of these numbers appears to be an ascending number of 5s with a 3 in between:

Therefore, the next number of 5s will be five.  This means the next number in the list will be 5, since there are only four 5s after the last 3.

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Answer:

Step-by-step explanation:

To find the x intercepts, substitute in 0 for y and solve for x

So,

2x^2+2x-4 = 0

2(x^2+x-4) = 0

2/2(x^2+x-4) = 0/2

x^2+x-4 = 0

(x-1) (x+2) = 0

now,

x-1 = 0

x = 1

or

x+2 = 0

x = -2

The x intercepts for the parabola (1,0), (-2,0)

Answer:

20

Step-by-step explanation:

x^2+18x-160

If you put this into your calculator or desmos, you will get a parabola. You want to know the value of x when y=600. You can look at the table for the graph or scan to where y = 600. The value of x is 20 at that point.

To check you can plug 20 in for x. When you do that, y = 600.