which statement best explain the relationship between numbers divisable by 9 and 3

The integral using integration by parts with the indicated choices of u and dv is equal to,   [tex]\int\limits 5x^{2} lnx dx[/tex] = [tex]\frac{5x^{3} }{3} (ln(x)-\frac{1}{3} )[/tex] + c

Basic Power Rule:

f(x) = cxⁿ

f’(x) = c· n xⁿ⁻¹

Integration

Integrals

[Indefinite Integrals] Integration Constant C

Integration Property [Multiplied Constant]:              

[tex]\int\limits cf(x)dx[/tex] = c [tex]\int\limitsf(x) dx[/tex]

Integration Rule [Reverse Power Rule]:

[tex]\int\limits x^{n} dx[/tex] = [tex]\frac{x^{n+1} }{n+1}[/tex] + c

Integration by Parts:  

[tex]\int\limits u dv[/tex] = uv - [tex]\int\limits v du[/tex]

Given that,

= [tex]\int\limits 5x^{2} lnx dx[/tex]

Rewrite [Integration Property - Multiplied Constant]:

[tex]\int\limits 5x^{2} lnx dx[/tex] = 5 [tex]\int\limits x^{2} lnx dx[/tex]

Set u:  

u = [tex]lnx[/tex]

[u] Logarithmic Differentiation:          

du = [tex]\frac{1}{x}[/tex] dx

Set dv:  

dv = [tex]x^{2}[/tex]                                                                                                        

[dv] Integration Rule [Reverse Power Rule]:  

v = [tex]\frac{x^{3} }{3}[/tex]

Integration by Parts:  

[tex]\int\limits 5x^{2} lnx dx[/tex] = 5 [tex]( \frac{x^{3}ln(x) }{3} - \int\limits \frac{x^{2} }{3} dx )[/tex]

Rewrite [Integration Property - Multiplied Constant]:  

[tex]\int\limits 5x^{2} lnx dx[/tex] = 5 [tex](\frac{x^{3}ln(x) }{3} -\frac{1}{3} \int\limits x^{2} dx )[/tex]

Factor:  

[tex]\int\limits 5x^{2} lnx dx[/tex] = [tex]\frac{5}{3} (x^{3} ln(x) - \int\limits x^{2} dx )[/tex]

Integration Rule [Reverse Power Rule]:  

[tex]\int\limits 5x^{2} lnx dx[/tex] = [tex]\frac{5}{3} (x^{3} ln(x) - \frac{x^{3} }{3} )[/tex] + c

Factor:

[tex]\int\limits 5x^{2} lnx dx[/tex] = [tex]\frac{5x^{3} }{3} (ln(x)-\frac{1}{3} )[/tex] + c

Therefore,

The integral using integration by parts with the indicated choices of u and dv is equal to,   [tex]\int\limits 5x^{2} lnx dx[/tex] = [tex]\frac{5x^{3} }{3} (ln(x)-\frac{1}{3} )[/tex] + c

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Answer:

-5

Step-by-step explanation:

Δy =9-7=2

Δx = -12-(-2) =-10

-10/2= -5

The number of campers is y = 650(676/650)^x

Exponential equations are equations in which variables occur as exponents.

An exponential equation in the form y = a(b)^x can be used to model the number of campers, y, x years after the camp opened. Let's use x = 0 for the first year the camp opened (last year) and x = 1 for this year.

Then, we have:

y = a(b)^0 = 650 (when x = 0)

y = a(b)^1 = 676 (when x = 1)

We can use these two points to solve for the values of a and b.

First, we'll use the first equation to solve for a:

a = 650

Next, we'll use the second equation to solve for b:

676 = 650(b)^1

676/650 = (b)^1

b = 676/650

So, the exponential equation in the form y = a(b)^x that can model the number of campers is:

y = 650(676/650)^x

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Answer:

y = 8x+3

Step-by-step explanation:

hoping its correct for you

Answer:

see explanation

Step-by-step explanation:

for the given angles to form a triangle they must sum to 180°

given

31 [tex]\frac{3}{4}[/tex]°  , 53 [tex]\frac{1}{2}[/tex]° , 94 [tex]\frac{3}{4}[/tex] ° ( changing to decimal form and adding )

= 31.75° + 53.5° + 94.75°

= 180°

Thus the 3 given angle measures can form a triangle.

Answer:

In the given triangle △ABC, AB is equal to 4 and m∠F is equal to 30°. In the triangle △DEF, AB is equal to 6 and m∠F is equal to 50°.

There about 24 hockey tickets were bought by Bryant. Out of which 14 tickets were child tickets.

A mathematical claim containing two equal algebraic expressions is known as an algebraic equation.

Given that the cost of an adult ticket is $5.50, and a child ticket is $2.00. The total spent is $83, and the total number of tickets bought is 24.

Let us consider the number of adult tickets bought is x and the number of children tickets bought is y.

Then x+y=24. From this, x=24-y.

Also, the given situation is written in an expression as,

[tex]\begin{aligned}5.50x+2.00y&=83\\5.50(24-y)+2.00y&=83\\132-5.50y+2.00y&=83\\-3.5y&=-49\\y&=14\end{aligned}[/tex]

The required answer is 14.

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If [tex]\overline{x}$[/tex] represents the mean of n observations x₁, x₂, ……xₙ, then the value of [tex]$\sum_{i=0}^{n} (x_{i} - \overline{x})$[/tex] is 0.

Mean is the average value of the group of values. It shows the equal distribution of values for a given data set.

To calculate the arithmetic mean of a group of data, first, add up (sum) all of the data values (x) and then divide the result by the number of values (n). Since ∑ is the symbol used to indicate that values are to be summed, we obtain the following formula for the mean ([tex]\overline{x}[/tex]):

[tex]\overline{x}= $\sum {\frac{x}{n} $[/tex]

The formula of the mean ([tex]\overline{x}$[/tex]) is:

[tex]\overline{x} = $\sum_{i=0}^{n} {x_{i}$/n[/tex]

[tex]$\sum_{i=0}^{n} {x_{i} = \overline{x}n[/tex]           Eqn(1)

Here, n is total number of observations.

The value of [tex]$\sum_{i=0}^{n} (x_{i} - \overline{x})$[/tex] is calculated as follows:

[tex]$\sum_{i=0}^{n} (x_{i} - \overline{x}) = \sum_{i=0}^{n} x_{i} - \sum_{i=0}^{n}\overline{x}[/tex]

Now, from equation (1), we get

[tex]$\sum_{i=0}^{n} (x_{i} - \overline{x}) = n\overline{x} - \sum_{i=0}^{n}\overline{x}[/tex]

[tex]$\sum_{i=0}^{n} (x_{i} - \overline{x}) = n\overline{x} - \overline{x}\sum_{i=0}^{n}1[/tex]

[tex]$\sum_{i=0}^{n} (x_{i} - \overline{x}) = n\overline{x} - \overline{x}n[/tex]

[tex]$\sum_{i=0}^{n} (x_{i} - \overline{x}) = 0[/tex]

Hence, the correct answer is B.

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The principal that would need to be invested to have an accrued amount of 1 million dollars after 30 years is $90,717.95.

The formula compound interest where interest is compounded continuously is expressed as;

A = P × e^(rt)

Where A is accrued amount, P is principal, r is interest rate and t is time.

Given the data in the question;

Plug the given values into the above formula and solve for P.

A = P × e^(rt)

P = A / e^(rt)

P = $1,000,000 / e^( 0.08 × 30 )

P = $1,000,000 / e^( 2.4 )

P = $90,717.95

Therefore, the amount of principal is $90,717.95.

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The system of equation has no solution

From the question, we have the following parameters that can be used in our computation:

2y = 6

y = -15

Since these are two different equations with the same variable, y, we can use substitution to find a solution.

Starting with the second equation, y = -15, we can substitute this value into the first equation:

2y = 6

2(-15) = 6

-30 = 6

This equation is false, meaning there is no solution for y that satisfies both equations.

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Answer:

It's already in order

[tex]\frac{3}{4}[/tex] × [tex]\frac{4}{9}[/tex], [tex]\frac{7}{7}[/tex] × [tex]\frac{4}{9}[/tex]  , [tex]1\frac{2}{3}[/tex] × [tex]\frac{4}{9}[/tex], [tex]2[/tex] × [tex]\frac{4}{9}[/tex]

Step-by-step explanation:

[tex]\frac{3}{4}[/tex] × [tex]\frac{4}{9}[/tex]

[tex]=\frac{1}{3}[/tex]

[tex]\frac{7}{7}[/tex] × [tex]\frac{4}{9}[/tex]

[tex]=\frac{4}{9}[/tex]

[tex]1\frac{2}{3}[/tex] × [tex]\frac{4}{9}[/tex]

[tex]=\frac{20}{27}[/tex]

[tex]2[/tex] × [tex]\frac{4}{9}[/tex]

[tex]=\frac{8}{9}[/tex]

Change them all to the same common denominator of 27

[tex]\frac{9}{27}, \frac{12}{27}, \frac{20}{27}, \frac{24}{27}[/tex]

Answer:

the number of revolutions that are required to level the playground is 194 revolutions

Step-by-step explanation:

We know that LSA, that is lateral surface area of a cylinder is the area of a rectangular sheet, which when spread onto the ground, covers the area equal to the LSA of the cylinder.

Hence, area covered by the roller in one revolution = area of LSA of cylinder  = 32 cm².

Now, to cover the are of 6200 cm²,

the number of revolutions required  = Total area of the playground/ LSA of the cylinder = 6200/32 = 193.75 = 194

Hence the number of revolutions that are required to level the playground is 194.

The coordinate of the point P that lies on the line segment AB will be (6.6, 3.8).

Let A (x₁, y₁) and B (x₂, y₂) be a line segment. Then the point P (x, y) divides the line segment in the ratio of m:n. Then we have

x = (mx₂ + nx₁) / (m + n)

y = (my₂ + ny₁) / (m + n)

AP to PB is in the ratio of 4 to 1. Then the coordinate of the point P is given as,

x = (4 × 8 + 1 × 1) / (4 + 1)

x = (32 + 1) / 5

x = 33 / 5

x = 6.6

y = (4 × 4 + 1 × 3) / (4 + 1)

y = (16 + 3) / 5

y = 19 / 5

y = 3.8

The coordinate of the point P that lies on the line segment AB will be (6.6, 3.8).

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The volume of the sawdust pile is 3754.667 cubic feet

A cone is a three-dimensional shape that has a circular base with tapers from the flat base into the vertex.

The formula for searching the volume of the cone can be described below :

V = [tex]\frac{1}{3}[/tex] π [tex]r^{2}[/tex] h

which

V = volume of the cone

r = radius of cone circular base

h = height of cone ( tall of the cone )

From the question, we have following information :\

1. Base diameter = 32 feet

  Base radius = Base diameter / 2 = 32 feet / 2 = 16 feet

2. Tall / Height of the cone = 14 feet

Since the known parameter is enough to be put into the formula, we can simply subtitute the formula with known parameter

V = [tex]\frac{1}{3}[/tex] π [tex]r^{2}[/tex] h

  = [tex]\frac{1}{3}[/tex] x π x [tex]16^{2}[/tex] x 14

  = 3754.667 cubic feet

Hence the volume of the cone is 3754.667 cubic feet

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The rate at which the area of the circle is increasing when the radius is 7 m is 527.52 m^2.

We already know that the area of a circle can easily be calculated using the formula -

= A = π(r^2)

So, in order to find out the rate at which it increases, we have to -

= dA/dt = dπ(r^2)/dt

= dA/dt = dπ(r^2)/dr × dr/dt

= dA/dt = 2πr × dr/dt

It has been mentioned that the value of dr/dt is 12 m/s.

So, after using this value, we find that the rate of increase is -

= dA/dt = 2π × 7 × 12

= dA/dt = 527. 52 m^2

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A statement could be used to describe the functions include the following: D. the domain of f(x) is (−∞, 0] while the domain of g(x) is [0, ∞).

In Mathematics, a domain can be defined as the set of all real numbers for which a particular function is defined.

Additionally, the horizontal extent of any graph of a function represents all domain values and they are read and written from smaller to larger numerical values, and from the left of a graph to the right.

By using interval notation, the domain of this function shown in the graph above can be written as follows;

Domain of f(x) = {-∞, 0}

Domain of g(x) = {0, ∞}

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The number of students actually enrolled is 6000.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that a large university accepts 50​% of the students who apply. Of the students the university​ accepts, 40​% actually enroll. If 30,000.

The number of students will be calculated as:-

Number = ( 30000 x 0.5 x 0. 4 )

Number = 6000

Therefore, the number of students will be 6000.

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Salut/Hello!

Answer: w = 20 cm and l = 28 cm

Step-by-step explanation:
l - length
w - width
P - perimeter
/ - fraction line
=> - results

we know that P = 2 x (l + w)
we also know that our ratio is l/w = 7/5

l/w = 7/5 => l = 7/5 x w
so now we can go back to the perimeter and replace l

96 = 2 x (7/5 x w + w)
96 = 2 x (7/5 x w/1 + w)   Why w/1? - We can't multiply unless w is also in a fraction, so we put it as w/1
96 = 2 x (7w/5 + w)
96 = 2 x (7w/5 + w/1)  and we amplify w/1 with 5
96 = 2 x (7w/5 + 5w/5)
96 = 2 x 12w/5
48 = 12w/5
48/1 = 12w/5
48 x 5 = 12w
240 = 12w
w = 20 cm

with that we can find l
96 = 2 x (l + 20)
48 = l + 20
l = 48 - 20
l = 28 cm

I hope it was helpful! :]

The probability that X is between 0.5 and 1 is (C) 19/24.

The probability that X is between 0.5 and 1 can be found by calculating the definite integral of the PDF f(x) over the interval [0.5, 1]:

P(0.5 <= X <= 1) = ∫f(x)dx from 0.5 to 1

Given the PDF f(x) = ax + X^2 for 0<=x<=1, we can evaluate this definite integral as:

P(0.5 <= X <= 1) = ∫(ax + X^2)dx from 0.5 to 1

= [ax^2/2 + x^3/3] from 0.5 to 1

= (1.5a + 1/3) - (0.5a + 0.125)

= (1 + 1/6) - (0.5 + 1/8)

= (2/3 - 3/8)

= 5/24

Since 5/24 is equal to 0.2083, the closest answer choice to this value is 19/24.

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(a) the root of the equation is =4.4.(b) x=31pi for x=100 approx.

the root of an equation is said to be that value where the equation gets zero. And the intersection point of two equations is the same value of equations.

The roots of x =tan(x), graph y = x and y = tan(x), and look at the intersection points of the two curves.

a) Find the smallest nonzero positive root of x = tan(x),

after seeing the graph the root of the equation is =4.4.

(The desired root is greater than pi/2).

b) Solve x =tan(x) for the root that is closest to x = 100.

after examining the graph of the function we can see that 31pi for x=100 approximately.

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The mean of the sample size of 25 would fall between 68 and 72 68% of the time.

Using the 68-95-99.7 rule, if a variable is normally distributed with mean μ and standard deviation σ, then:

Since the interval we are interested in (68 to 72) falls within the 68% of the data that falls within 1 standard deviation of the mean, it means that 100% - 32% = 68% of the data falls within this interval.

Thus, the mean of this sample size of 25 would fall between 68 and 72 68% of the time.

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If Brenda plans to reduce her spending by $70 a month, the future value of this reduced spending over the next 12 years is $14710.5.

We are given that Brenda will be saving $70 every month for a period of 12 years.

So, the future value of the annuity formula will be used for the calculation of future value.

Future value = R [( (1 + i)^n - 1 ) / i], where R is the regular payment, i is the interest rate and n is the number of payments

Here R = monthly amount to be saved = $70

i = interest rate = 6/12 = 0.5%

n = Number of payments = 12 x 12 = 144 months

Future value=70 [( (1+0.5%)^144 - 1) / 0.5%] = $14710.5

Hence, the future value of this reduced spending over the next 12 years is $14710.5.

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The midpoints of the segment is (4, -3.5).

The coordinates of the point A(x, y) which divides the line segment joining the points P(a , b) and Q(c , d) internally in the ratio m : n are given by the formula: P ( x , y ) = ( a x n + c x m / (m+n)  , bn + dn / (m+n))

Given:

Points (-4, -7) and (12, -6).

So, the ratio is line is m:n = 1:1

let (x, y) be the midpoint.

Now, using section formula

x = (-4 x 1 + 12 x 1)/ (1+1)

x= (-4 +12) /2

x= 8/2

x= 4

and, y = (-7 x 1 -6 x 1)/ 2

y = -7-6/2

y = -13/2

y = -3.5

Hence, the midpoints are (4, -3.5).

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Answer: the answer is A), normal is 28 + 4fee, but if she buys LOTS its 22 +8

contact me through discord Acathia#0103, its easier to help, I can help with multiple questions aswell

Step-by-step explanation:

Answer:

a) 144π cm²

b) 248π cm²

Step-by-step explanation:

Using the formula, curved surface area of a cone = πrl where r = radius and l = slant height,

Curved surface area of large cone = π (10) (12 + 3) = π (10)(15) = 150π

Curved surface area of small cone = π(2)(3) = 6π

a) Curved surface area of frustum = 150π - 6π = 144π cm²

b)
The frustum has a top surface which is a circle of radius 2 and a bottom surface which is also a circle of radius 10

The area of a circle is πr²

So Total area of both circles = π(2)² + π(10)² = 4π + 100π = 104π

Total surface area of frustrum = 144π + 104π = 248π cm²

Answer:

Hi, I'm Za'Riah! I will gladly assist you with your problem. (see explanation)

Step-by-step explanation:

Cylinder volume: Considering that;

14 feet is the cylindrical tank's diameter.

The cylindrical tank is 40 feet long.

Find:

how much gas is in the tank.

Computation:

14 feet is the cylindrical tank's diameter.

Tank's cylinder's radius is 14/2, or 7 feet.

Volume of the tank: x amount of gas inside it

Volume of gas in the tank equals πr²h.

Portion of gas in the tank = (3.14)(7)²(40)

Fuel level in tank equals (3.14)(49) (40)

6154.4 feet³ of gas have been filled into the tank.

(Hope this helped!)

Answer: 9

Step-by-step explanation:

g + 9 = 18

g = 18-9

  =9

The equation is in slope-intercept form is y = 240t + 0

The equation of a line in slope-intercept form is given by:

y = mx + b

where m is the slope and b is y-intercept

Let's say the number of times the insect beats its wing in t seconds is represented by y. Then the relationship can be expressed as:

y = 240t

The slope (240) shows that for every 1 second increase in time, the number of wing beats increases by 240. The y-intercept (0) indicates that when t = 0, y=0, i.e. when the insect has not started flying, it has not beaten its wing yet.

Therefore, the equation is in slope-intercept form: y = 240t + 0

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The number of orders placed in one quarter of the year and shipped in the next quarter will vary depending on the segment. To determine the exact number, you would need to analyze the data from each segment separately.

To determine the number of orders placed in one quarter of the year but shipped in the next quarter, you will need to analyze the data from each segment separately. Begin by extracting the data from the segment you are interested in and sorting it by order date and ship date. For example, if you are interested in orders placed in Q1 2009 and shipped in Q2 2009, you will need to identify all orders with an order date in Q1 2009 and a ship date in Q2 2009. Once you have identified these orders, you can count them up to determine the total number of orders in the segment that fit this criteria. You can then repeat this process for the other segments to determine the total number of orders placed in one quarter of the year but shipped in the next quarter across all segments.

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