Which value is in the domain of f(x)?

The Answer is C

Answers

Answer 1

A value which is in the domain of f(x) include the following: C. 4.

What is a piecewise-defined function?

In Mathematics, a piecewise-defined function is a type of function that is defined by two (2) or more mathematical expressions over a specific domain.

Generally speaking, the domain of any piecewise-defined function simply refers to the union of all of its sub-domains. By critically observing the given piecewise-defined function, we can reasonably infer and logically deduce that it is defined over the interval -6 < x ≤ 0 and 0 < x ≤ 4.

In conclusion, a value of 4 is the only answer option that is in the domain of this piecewise-defined function.

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Complete Question:

Which value is in the domain of f(x)?

A.) –7

B.) –6

C.) 4

D.) 5

Which Value Is In The Domain Of F(x)?The Answer Is C

Related Questions

Maura spends $5.50 in materials to make a scarf. She sells each scarf for 600% of the cost of materials.
Complete the sentence by selecting the correct word from the drop down choices.
Maria sells each scarf for Choose... ✓ or

Answers

The price that Maura sell each scarf would be =$33. Maura sells each scarf for $33. That is option A.

How to calculate the selling price of each scarf?

To calculate the amount of money that Maura spends on each scarf the following is carried out.

The amount of money that she spends on the scarf material = $5.50

The percentage selling price of each scarf = 600% of $5.50

That is ;

= 600/100 × 5.50/1

= 3300/100

= $33.

Therefore, each price that is sold by Maura would probably cost a total of $33.

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2.2 Loads endured by a cable are assumed to be from an exponential distribution with probability distribution function f(x;1) = le-te A sample of loads was 2.39 3.11 2.91 2.51 3.08 and the rate parameter, lambda, was estimated to be the sample variance of the load. Use the information in this sample to derive formulae for calculating the following probabilities:- 2.2.1 the maximum load is at least 3, [4 2.2.2 the minimum load is no more than 4.11, [4] EFFE 2.2.3 the median load is between 1.2 and 6. [4] 2.2.4 the range of the load is at most 2.5. [4]

Answers

The estimated value of λ and x = 2.91, we get:

P(1.2 ≤ median load ≤ 6) = 1 - e^(-0.38*2.91) - (

2.2.1 To calculate the probability that the maximum load is at least 3, we first need to find the distribution of the maximum load. Let X be the random variable representing the loads. Then the probability that the maximum load is less than or equal to x is given by:

P(X ≤ x)^n = (1 - e^(-λx))^n

where n is the sample size. Taking the derivative of this expression with respect to x and setting it equal to zero, we get:

n(1 - e^(-λx))^(n-1)λe^(-λx) = 0

Solving for x, we get

x = -ln(1 - 1/n)/λ

Now, we can calculate the probability that the maximum load is at least 3 as follows:

P(X ≤ 3)^n = (1 - e^(-λ*3))^n

P(maximum load ≥ 3) = 1 - P(X ≤ 3)^n

Substituting the estimated value of λ (sample variance of the loads) and the sample size n = 5, we get:

P(maximum load ≥ 3) = 1 - (1 - e^(-0.38*3))^5 ≈ 0.578

Therefore, the probability that the maximum load is at least 3 is approximately 0.578.

2.2.2 To calculate the probability that the minimum load is no more than 4.11, we can use the same approach as in 2.2.1, but with the inequality flipped:

P(minimum load ≤ 4.11) = 1 - P(X ≥ 4.11)^n

where we need to find the distribution of the minimum load. The probability that the minimum load is greater than or equal to x is given by:

P(X ≥ x) = e^(-λx)

Substituting the estimated value of λ and x = 4.11, we get:

P(minimum load ≤ 4.11) = 1 - e^(-0.38*4.11) ≈ 0.448

Therefore, the probability that the minimum load is no more than 4.11 is approximately 0.448.

2.2.3 To calculate the probability that the median load is between 1.2 and 6, we first need to estimate the median load from the sample. The sample is already sorted as 2.39, 2.51, 2.91, 3.08, 3.11. The median load is the middle value, which is 2.91.

The probability that the median load is less than or equal to x is given by:

P(median load ≤ x) = P(X1 ≤ x, X2 ≤ x, X3 ≥ x, X4 ≥ x, X5 ≥ x) + P(X1 ≤ x, X2 ≤ x, X3 ≥ x, X4 ≥ x, X5 ≤ x) + P(X1 ≤ x, X2 ≤ x, X3 ≥ x, X4 ≤ x, X5 ≥ x)

where Xi represents the ith load in the sample. The probability that the median load is between 1.2 and 6 is then given by:

P(1.2 ≤ median load ≤ 6) = P(median load ≤ 6) - P(median load ≤ 1.2)

Substituting the estimated value of λ and x = 2.91, we get:

P(1.2 ≤ median load ≤ 6) = 1 - e^(-0.38*2.91) - (

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The scale on this drawing is 2 in: 5 ft. Based on this, how
many inches long and wide will the kitchen be?

Answers

The actual length and width of the kitchen in the scale drawing is: 22.5 ft x 17.5 ft

How to Interpret Scale Drawing?

A scale drawing is defined as an enlargement of an object. An enlargement changes the size of an object by multiplying each of the lengths by a scale factor to make it larger or smaller. The scale of a drawing is usually stated as a ratio.

Now, the scale factor of the given drawing is seen as 2 in : 5 ft

From the drawing the dimensions of the kitchen are:

9" x 7"

Thus:

True length = (9 * 5)/2 = 22.5 ft

True width = (7 * 5)/2 = 17.5 ft

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T/FThe area of descriptive statistics was developed to provide further detail to statisticians about population inferences.

Answers

Descriptive statistics is a branch of statistics that deals with the collection, analysis, interpretation, and presentation of data. It focuses on summarizing and describing the characteristics of a sample or population. The purpose of descriptive statistics is to provide a clear and concise summary of the data, including measures of central tendency, variability, and distribution.

True,This information can be used to make inferences about the population as a whole. Therefore, descriptive statistics helps statisticians to better understand and interpret the population data.

False, Descriptive statistics is a branch of statistics that focuses on summarizing and organizing data from a sample or population. It provides insights into the basic features of the data, such as the mean, median, and standard deviation, but does not make inferences about the population.

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What conclusion can you draw from the number line? -10 -0 A When you add opposite numbers, the sum is 0. B Adding a negative number to 0 and subtracting a negative number from 0 give the same result. When you multiply numbers with opposite signs, the product is 0. D Subtracting a number from its opposite gives a difference of 0.

Answers

When you add opposite numbers, the sum is 0. Then the correct option is A.

A number line refers to a straight line in mathematics that has numbers arranged at regular intervals or portions along its width. A number line is often shown horizontally and can be postponed in any direction.

Let if 'a' lie on the number axis. Then the opposite of the number 'a' will be '-a'. Then the addition of the numbers is calculated as,

⇒ a + (-a)

⇒ a - a

⇒ 0  

When you add opposite numbers, the sum is 0. Then the correct option is A.

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Concert tickets go on sale for $34. 00 each

Answers

The required amount will be earn is $3400.

This calculation only takes into account the revenue earned from ticket sales and does not include any additional revenue streams such as merchandise sales or sponsorships.

The total earnings will depend on various factors such as ticket pricing strategy, marketing efforts, and concert attendance.

Here given concert tickets are selling for $34.00 each and it is also given a total number of 100 tickets are sold.

the total earnings will be calculated by multiplying the ticket price by the number of tickets sold.

So,total amount earn = $34×100 = $3400.

This is a problem of Multiplication.

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Correct question is " Concert tickets go on sale for $34. 00 each . Now total number of sold tickets are 100 . Count how many money will earn ."

A population has standard deviation o=17.5. Part 1 of 2 (a) How large a sample must be drawn so that a 99.8% confidence interval for j. will have a margin of error equal to 4.7? Round the critical value to no less than three decimal places. Round the sample size up to the nearest Integer. A sample size of is needed to be drawn in order to obtain a 99.8% confidence interval with a margin of error equal to 4.7. Part 2 of 2 (b) If the required confidence level were 99.5%, would the necessary sample size be larger or smaller? (Choose one) , because the confidence level is (Choose one) V.

Answers

We would choose "smaller" for the necessary sample size and "smaller" for the confidence level.

(a) We know that the margin of error E is 4.7 and the population standard deviation is o = 17.5.

The formula for the margin of error is:

E = z* (o/ sqrt(n))

where z is the critical value for the desired level of confidence, o is the population standard deviation, and n is the sample size.

We want to find n, so we can rearrange the formula to solve for n:

n = (z*o/E)^2

For a 99.8% confidence level, the critical value is z = 2.967.

Substituting the values into the formula, we get:

n = (2.967*17.5/4.7)^2

n = 157.82

Rounding up to the nearest integer, we get a sample size of 158.

Therefore, a sample size of 158 must be drawn in order to obtain a 99.8% confidence interval with a margin of error equal to 4.7.

(b) If the required confidence level were 99.5%, the necessary sample size would be smaller.

This is because the critical value for a 99.5% confidence level is smaller than the critical value for a 99.8% confidence level. As the critical value gets smaller, the margin of error also gets smaller, which means we need a smaller sample size to achieve the same margin of error.

So, we would choose "smaller" for the necessary sample size and "smaller" for the confidence level.

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Write an equation for a line parallel to f(x) = -3x - 5 and passing through the point (2.-6). Show all steps

Answers

please see attached...

ignore 8/52 in the top right hand corner

The equation for a line parallel to f(x) = -3x - 5 and passing through the point (2, -6) is y = -3x.

An equation for a line parallel to f(x) = -3x - 5 and passing through the point (2, -6). Here are the steps:

Step 1: Identify the slope of the given line, f(x) = -3x - 5. Since it's in the form y = mx + b, where m is the slope, we see that the slope of the given line is -3.

Step 2: Since we want a line parallel to the given line, the slope of our new line will be the same, which is -3.

Step 3: Use the point-slope form of a linear equation, which is y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point the line passes through. In this case, m = -3 and the point is (2, -6), so x1 = 2 and y1 = -6.

Step 4: Plug the values into the point-slope form equation: y - (-6) = -3(x - 2)

Step 5: Simplify the equation. First, change y - (-6) to y + 6, then distribute -3: y + 6 = -3x + 6

Step 6: Write the equation in slope-intercept form (y = mx + b) by subtracting 6 from both sides: y = -3x

So, the equation for a line parallel to f(x) = -3x - 5 and passing through the point (2, -6) is y = -3x.

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What is the slope intercept equation of the line shown below

Answers

The slope of the given line is -1.

Given is a line passing through the points (-2, 3) and (4, -3) we need to find the slope of the line,

Slope = y₂ - y₁ / x₂ - x₁

Here, (x₁, y₁) and (x₂, y₂) are (-2, 3) and (4, -3),

So, the slope of the line =

Slope = -3-3 / 4+2

= -6 / 6

= -1

Hence, the slope of the given line is -1.

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In order to solve a system by substitution, you want to...
*
get opposite coefficients for each variable in each equation.

get opposite coefficients for one set of variables in each equation.

isolate a variable in an equation and then substitute into the other equation.

put the corresponding augmented matrix into RREF (row reduced echelon form).

Answers

In order to solve a system by substitution, you want to isolate a variable in one equation and then substitute it into the other equation.

Given that;

To complete the sentence for solving the system of equation.

Now, We know that;

Once you have substituted the variable, you can solve for the remaining variable(s) and find the solution to the system.

Hence, In order to solve a system by substitution, you want to isolate a variable in one equation and then substitute it into the other equation.

Therefore, Option C is true.

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Use the diagram to answer the question.



The measure of ∠1

1
is 62°
62
°
. What is the approximate value of n
n
?

Answers

Applying the definition of a linear pair, the value of n is calculated as: n =  41.33.

What is a Linear pair?

A linear pair consist of two angles that are on a straight line and also have a sum of 180 degrees.

The missing diagram is in the attachment provided below which shows the angles in question.

Angle 1 and (3n - 6) are two angles on a straight line, therefore, they are a linear pair. This also implies that they will have a sum of 180 degrees.

Therefore, we have:

62 + 3n - 6 = 180

Solve for the value of n:

56 + 3n = 180

3n = 180 - 56

3n = 124

n = 124/3

n = 41.33

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Find the zeros of the quadratic function f(x) = –3x2 + 12x – 9 from the graph.
A −9
B−3 and −9
C1 and 3
D 2

Answers

Check the picture below.

he sum of two numbers is 3 . the larger number minus twice the smaller number is zero. find the numbers.

Answers

The smaller number is 1 and the larger number is 2. To find these numbers, we used algebraic equations and solved for one variable in terms of the other.

To solve this problem, we need to use algebraic equations. Let's call the smaller number "x" and the larger number "y".

From the problem, we know that:

x + y = 3 (the sum of two numbers is 3)

y - 2x = 0 (the larger number minus twice the smaller number is zero)

Now, we can solve for one variable in terms of the other:

y = 2x (by rearranging the second equation)

Substituting this into the first equation, we get:

x + 2x = 3

3x = 3

x = 1

Now that we know x is 1, we can use the equation y = 2x to find y:

y = 2(1) = 2

Therefore, the two numbers are 1 and 2.

In summary, the smaller number is 1 and the larger number is 2. To find these numbers, we used algebraic equations and solved for one variable in terms of the other. It's important to carefully read and understand the problem and to keep track of the information given.

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4. The proportion of the defective paper cups from Supplier A is 0.08. A random sample of 200 cups from each supplier is taken. What is the probability that the sample proportion of defective from Supplier A is a) less 10%.
b) at least 5%?
c) from 5% to 10%?
d) exactly 8%?

Answers

a) To calculate the probability that the sample proportion of defective cups from Supplier A is less than 10%, we need to find the probability that the sample proportion is less than 0.10. Thus, we need to find P(p < 0.10).

We can use the central limit theorem to approximate the distribution of the sample proportion as a normal distribution, with mean μ = 0.08 and standard deviation [tex]σ = \sqrt{0.08 (\frac{1-0.08)}{200} )}= 0.024[/tex]. Then, we can standardize the distribution and use a standard normal table or calculator to find the probability:

[tex]P (p < 0.10)=P(\frac{p-u}{σ} < \frac{0.10-0.08}{0.024} = P(z < 0.83)=0.7977[/tex]

Therefore, the probability that the sample proportion of defective cups from Supplier A is less than 10% is approximately 0.7977.

b) To calculate the probability that the sample proportion of defective cups from Supplier A is at least 5%, we need to find the probability that the sample proportion is greater than or equal to 0.05. Thus, we need to find P(p≥ 0.05).

Using the same approach as in part (a), we can find that                                                             P(p < 0.05)=-0.0207. Therefore, P(p ≥ 0.05) = 1 - P(p< 0.05) =0.9793.

Therefore, the probability that the sample proportion of defective cups from Supplier A is at least 5% is approximately 0.9793.

c) To calculate the probability that the sample proportion of defective cups from Supplier A is between 5% and 10%, we need to find the probability that 0.05 ≤ p < 0.10. We can use the same approach as in part (a) to find that P(p < 0.05) = 0.0207 and P(p < 0.10) = 0.7977. Therefore, P(0.05 ≤ p < 0.10) = P(p < 0.10) - P(p < 0.05) = 0.7770.

Therefore, the probability that the sample proportion of defective cups from Supplier A is between 5% and 10% is approximately 0.7770.

d) To calculate the probability that the sample proportion of defective cups from Supplier A is exactly 8%, we need to find P(p = 0.08). Since the sample proportion is a discrete random variable, we can use the binomial distribution to find the probability:

[tex]P(p=0.08)=(200 choose 16) (0.080)^{16} (1-0.08)^{184} = 0.1567[/tex]

Therefore, the probability that the sample proportion of defective cups from Supplier A is exactly 8% is approximately 0.1567.

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Match each multiplication problem with the
answer.

Answers

Answer:

1. D

2.C

3. A

4. B

Step-by-step explanation:

times each of the numbers by however many r in the brackets

3×2=6

3×-1=-3

so the answer to 1 will be (6)

(-3)

In a binary communication channel, the receiver detects binary pulses with an error probability Pe. What is the probability that out of 100 received digits, no more than four digits are in error?

Answers

The probability of having no more than four errors out of 100 digits received is about 99.3%.

To solve this problem, we can use the binomial distribution.

Let p be the probability of a single digit being received in error, which is equal to Pe. The probability of a single digit being received correctly is therefore 1-Pe.

Let X be the number of digits received in error out of 100. Then X follows a binomial distribution with parameters n=100 and p=Pe.

To find the probability that no more than four digits are in error, we need to calculate [tex]P(X\leq4)[/tex].

We can do this using the cumulative distribution function of the binomial distribution:
[tex]P(X\leq4)[/tex] = ΣP(X=k) for k=0 to 4

= P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4)

= [tex]C(100,0)(1-Pe)^{100} + C(100,1)(1-Pe)^{99}Pe + C(100,2)(1-Pe)^{98}Pe^{2} + C(100,3)(1-Pe)^{97}Pe^{3} + C(100,4)(1-Pe)^{96}Pe^{4}[/tex]

where C(n,k) is the binomial coefficient (n choose k), which represents the number of ways to choose k elements out of a set of n.

[tex]P(X\leq4)[/tex] = 0.9930

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Determine over what interval(s) (if any) the Mean Value Theorem applies. (Enter your answer using interval notation. If an answer does not exist, enter DNE.)
y=√x2−25

Answers

The Mean Value Theorem applies over the interval (-5, 5) and (5, ∞).

To determine the interval(s) where the Mean Value Theorem (MVT) applies for the function y=√(x^2-25), we need to ensure that the function is continuous and differentiable on the given interval.

1. The function is continuous when the expression under the square root is non-negative, which means x^2-25≥0. Solving for x, we get x≥5 or x≤-5. In interval notation, the domain for continuity is (-∞,-5] U [5,∞).

2. To check for differentiability, we need to find the derivative of the function. The derivative of y=√(x^2-25) is:

y' = (1/2)(x^2-25)^(-1/2) * 2x
y' = x/√(x^2-25)

Now, we need to ensure that the derivative is defined on the given interval. Since x=5 or x=-5 makes the denominator zero, we should exclude these points. Hence, the interval for differentiability is (-∞,-5) U (5,∞).

Since the MVT requires both continuity and differentiability, the applicable interval(s) for the Mean Value Theorem are (-∞,-5) U (5,∞).

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A gym subscription runs several promotions. Customers can choose from the following deals.

Option A: 25% off an annual subscription of $308.00

Option B: pay $29.00 per month

What is the difference between the two price options customers will pay annually?

Answers

The difference between the two price options is $117.

What is the price difference?

After a 25% off, the annual subscription in option A would be lower.

Price after the 25% off = initial annual subscription x (1 - discount/100)

$308 x (1 - 25/100)

$308 x (1 - 0.25)

$308 x 0.75 = $231

Annual fee with option B = cost per month x 12

$29 x 12 = $348

Price difference = $348 - $231 = $117

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number of employees 1 2 3 4 10
number of customers 8 4 13 17 39
Would a linear or exponential model for the relationship between the number of employees and number of customers be more appropriate? Explain how you know.​

Answers

A linear or exponential model would not model the relationship between the number of employees and number of customers

Would a linear or exponential model the relationship

From the question, we have the following parameters that can be used in our computation:

number of employees 1 2 3 4 10

number of customers 8 4 13 17 39

Testing a linear model

To do this, we calculate the difference between the y values

So, we have

13 - 4 = 4 - 8

9 = -4 ---- this is false

So, the function is not a linear function

Testing an exponential model

To do this, we calculate the ratio of the y values

So, we have

13/4 = 4/8

3.25 = 1/2 ---- this is false

So, the function is not an exponential function

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If g(6) = 3 - 5(6), what is g(x)?

Answers

Step-by-step explanation:

g(6) = 3 - 5(6) = 3 - 30 = -27

We know the value of function g at 1 single point, g(6) = -27.

That is not enough to know what function g is.

Since the problem states that g(6) = 3 - 5(6), the problem is trying to guide you into answering that g(x) = 3 - 5x, but this is simply an assumption.

1. Prove that each function is uniformly continuous on the given set by directly verifying the E - 8 property in Definition 5.4.1. (a) f(x) = x^3 on (0,2] (b) f(x)= 1/2 on (2,[infinity] ) (c) f(x) = x-1 /x+1 on (0,[infinity] ) 4.1 DEFINITION Let f:D R. We say that f is uniformly continuous on Dif for every e > 0 there exists a 8 >0 such that Sx)-f()

Answers

a. At (0,2] f is uniformly continuous.

b. At (2,∞) f is uniformly continuous.

c. At (0,∞) f is uniformly continuous.

What is function?

A function connects an input with an output. It is analogous to a machine with an input and an output. And the output is somehow related to the input. The standard manner of writing a function is f(x) "f(x) =... "

(a) Let f(x) = x³ on (0,2]. Let ε > 0 be given. We need to find a δ > 0 such that |x - y| < δ implies |f(x) - f(y)| < ε for all x,y in (0,2]. Note that |f(x) - f(y)| = |x³ - y³| = |x - y||x² + xy + y²|. Since x,y ∈ (0,2], we have x² + xy + y² ≤ 12. Thus, if we choose δ = ε/12, then for any x,y ∈ (0,2] such that |x - y| < δ, we have |f(x) - f(y)| < ε. Hence, f is uniformly continuous on (0,2].

(b) Let f(x) = 1/2 on (2,∞). Let ε > 0 be given. We can choose any δ > 0 since for any x,y ∈ (2,∞), we have |f(x) - f(y)| = 0 < ε. Thus, f is uniformly continuous on (2,∞).

(c) Let f(x) = (x-1)/(x+1) on (0,∞). Let ε > 0 be given. We need to find a δ > 0 such that |x - y| < δ implies |f(x) - f(y)| < ε for all x,y in (0,∞). Note that |f(x) - f(y)| = |(x-1)/(x+1) - (y-1)/(y+1)| = |(x-y)(2/(x+1)(y+1))|. Thus, if we choose δ = ε/2, then for any x,y in (0,∞) such that |x - y| < δ, we have |f(x) - f(y)| = |(x-y)(2/(x+1)(y+1))| < ε. Hence, f is uniformly continuous on (0,∞).

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Examine the ratios to find the one that is not equivalent to the others. Which ratio is different from the other three?

Answers

The ratio StartFraction 14 Over 35 EndFraction is equivalent to the other three ratios, and the ratio that is different from the others is StartFraction 8 Over 20 EndFraction.

To determine which ratio is not equivalent to the others, we need to simplify each ratio to its lowest terms.

Give the following ratios :

[tex]2 / 5 = 6 /10 = 8 / 20 = 12 / 30.[/tex]

- StartFraction 2 Over 5 EndFraction: This ratio is already in its simplest form.

- StartFraction 6 Over 10 EndFraction: We can simplify this ratio by dividing both the numerator and denominator by their greatest common factor (GCF), which is 2.

-StartFraction 6 Over 10 EndFraction = StartFraction 3 Over 5 EndFraction

- StartFraction 8 Over 20 EndFraction: We can simplify this ratio by dividing both the numerator and denominator by their GCF, which is 4.

StartFraction 8 Over 20 EndFraction = StartFraction 2 Over 5 EndFraction

- StartFraction 12 Over 30 EndFraction: We can simplify this ratio by dividing both the numerator and denominator by their GCF, which is 6.

StartFraction 12 Over 30 EndFraction = StartFraction 2 Over 5 EndFraction

Therefore, the ratios StartFraction 6 Over 10 EndFraction, StartFraction 8 Over 20 EndFraction, and StartFraction 12 Over 30 EndFraction are all equivalent to StartFraction 2 Over 5 EndFraction. The ratio that is different from the others is StartFraction 14 Over 35 EndFraction, which can be simplified by dividing both the numerator and denominator by their GCF, which is 7.

[tex]StartFraction 14 Over 35 EndFraction = StartFraction 2 Over 5 EndFraction.[/tex]

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The students in homeroom 232 are exploring equivalencies when saddened or minuend is missing.
How might we solve for this problem? Can you explain what would make this equation true?

Answers

To solve a problem involving missing addends or minuends in homeroom 232, students can use the concept of equivalencies to create an equation.

Let's say we have the equation A + B = C, where A is the missing addend or minuend, B is a known value, and C is the given sum or difference. To make this equation true, students can use algebraic manipulation to find the missing value (A). For example, if the equation is A + B = C, then A = C - B. By substituting the known values for B and C, students can determine the missing addend or minuend (A) and establish equivalencies between both sides of the equation. This will help them understand the relationships among the numbers and effectively solve the problem.

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A pole 12 feet tall is used to support a guy wire for a tower, which runs from the tower to a metal stake in the ground. After placing the pole, Jamal measures the distance from the pole to the stake and from the pole to the tower, as shown in the diagram below. Find the length of the guy wire, to the nearest foot.

Answers

Answer:

The given question is on trigonometry which requires the application of required function so as to determine the value known. So that the length of the guy wire is 67.0 feet.

Trigonometry is an aspect of mathematics that requires the application of some functions to determine the value of an unknown quantity.

Let the length of the guy wire be represented by l, and the angle that the guy wire makes with the stake be θ. So that applying the appropriate trigonometric function to determine the value of θ, we have:

Tan θ =

adjacent

opposite

=

11

4

4

11

Tan θ = 2.75

θ =

1

Tan

−1

2.75

= 70.0169

θ =

7

0

70

o

Considering triangle formed by the tower and the stake to determine the value of l, we have;

Cos θ =

hypotenuse

adjacent

Cos

7

0

70

o

=

23

l

23

l =

23

7

0

Cos70

o

23

=

23

0.3420

0.3420

23

l = 67.2515

l = 67 feet

The length of the guy wire is 67 feet.

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find a polynomial function of lowest degree with rational coefficients that has the given numbers as some of its zeros. -3i,5

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To find a polynomial function of the lowest degree with rational coefficients and given zeros -3i and 5, we first need to remember that complex zeros always come in conjugate pairs. Since -3i is one of the zeros, its conjugate 3i is also a zero.

Now, let's find the polynomial using these zeros: (x - (-3i))(x - 3i)(x - 5). We can rewrite this as:

(x + 3i)(x - 3i)(x - 5)

Now, let's multiply the first two factors:

(x^2 - 3ix + 3ix + 9) (x - 5)

Simplifying this gives us:

(x^2 + 9)(x - 5)

Now, let's multiply this with the remaining factor:

x^3 - 5x^2 + 9x - 45

So, the polynomial function of the lowest degree with rational coefficients that has the given zeros -3i and 5 is:

f(x) = x^3 - 5x^2 + 9x - 45

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A resistor-inductor-capacitor (RLC-)circuit is modeled by Kirchhoff's Second Law: L di/dt + Ri(t) + 1/c ∫ i(r) dr= V(t) Here, V(t) = 1(1-1, (t)) is the voltage coming from a source, and L, I, C correspond to physical

quantities which we treat as constants. Assuming (0) = 0, describe the corresponding current

function i(t)

Answers

In either case, we can solve for A and B using the initial condition i(0) = 0. This gives us the final form of the current function i(t) for the given RLC circuit.

The current function i(t) in the RLC circuit, we need to solve the differential equation given by Kirchhoff's Second Law: L di/dt + Ri(t) + 1/c ∫ i(r) dr= V(t), subject to the initial condition i(0) = 0.

To begin, we can simplify the equation by substituting V(t) = 1/(1+t) and integrating the integral term by parts. This gives us:

L di/dt + Ri(t) + 1/c [i(t) * t - ∫t0 i(t)dt] = 1/(1+t)

Next, we can differentiate both sides with respect to t, which gives:

[tex]L d^2i/dt^2 + R di/dt + i(t)/c = -1/(1+t)^2[/tex]

This is a second-order linear ordinary differential equation with constant coefficients, and we can solve it by assuming a solution of the form i(t) = [tex]e^{(rt)[/tex]. Substituting this into the differential equation and solving for r.

We have two cases, depending on whether the discriminant R^2 - 4L(1/c) is positive, negative, or zero.

Case 1: [tex]R^2 - 4L(1/c) > 0[/tex]

In this case, we have two distinct real roots:

[tex]r_1 = (-R + \sqrt{(R^2 - 4L(1/c)))/(2L} )\\r_2 = (-R - \sqrt{(R^2 - 4L(1/c)))/(2L} )[/tex]

The general solution to the differential equation is then given by:

i(t) = A [tex]e^{(r1t)} + B e^{({(r2t)} - 1/(1+t)^2c[/tex]

Case 2: [tex]R^2 - 4L(1/c) = 0[/tex]

In this case, we have a repeated real root:

r = -R/(2L)

The general solution to the differential equation is then given by:

i(t) = [tex](A + Bt) e^{(rt)} - 1/(1+t)^2c[/tex]

Here A and B are constants determined by the initial conditions.

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How many different 10-letter words (real or imaginary) can be formed from the following letters? T, S, O, Y, M, H, S, F, C, B. (Show what you put into the calculator, not just the result.)

Answers

1,814,400 different 10-letter words can be formed from the given letters.

To determine how many different 10-letter words (real or imaginary) can be formed from the letters T, S, O, Y, M, H, S, F, C, and B, we need to calculate the number of unique permutations.

Since there are 10 letters, with the letter "S" appearing twice, we can use the following formula:

Number of permutations = 10! / (2!)

1. Calculate the factorial of 10 (10!): 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 3,628,800
2. Calculate the factorial of 2 (2!): 2 × 1 = 2
3. Divide the factorial of 10 by the factorial of 2: 3,628,800 / 2 = 1,814,400

So, 1,814,400 different 10-letter words can be formed from the given letters.

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Determine how many terms of the following convergent series must be summed to be sure that the remainder is less than 10−2
[infinity]∑k=1(−1)k+1k4

Answers

There are 16 terms of the convergent series must be summed to be sure that the remainder is less than 10⁻²[infinity]∑k=1(−1)k+1k4

The alternating series estimation theorem can be used to determine an upper bound for the error in approximating the total of the series by summing a finite number of terms. As an example of an alternating sequence of the form:

∑(-1)^(n-1) b_n

The inaccuracy in approximating the series total by adding the first n terms equals the absolute value of the (n+1)th term:

|(-1)^n b_n+1|

In this case, we have:

∑k=1^∞ (-1)^(k+1) k^4

So the (n+1)th term is:

(-1)^n+1 (n+1)^4

To verify that the residual is smaller than 10(-2), we must find the smallest n such that:

|(-1)^n+1 (n+1)^4| < 10^(-2)

So let us try n = 1:

|(-1)^2 (2)^4| = 16 > 10^(-2)

So let us try n = 2:

|(-1)^3 (3)^4| = 81 > 10^(-2)

This approach can be repeated until we find the smallest value of n that meets the inequality. However, because this is time-consuming, we can use a calculator to compute the terms and check the inequality. As a result, we discover that n = 6 is the least value that works:

|(-1)^7 (7)^4| = 2401 > 10^(-2)

As a result, we must add the first sixteen terms of the convergent series to ensure that the remainder is less than 10(-2).

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A cruise ship leaves key west to go to cuba, which is 90 miles away. The cruise ship travels about 130 miles per hour. About how long will it take the ship to get to cuba

Answers

It will take 41.5 mins for the ship to get to Cuba which is 90 miles away

How to determine this

The cruise ships travels about 130 hours per hour

i.e 130 miles = 1 hours

How long can the ship for 90 miles

Let x represent the number of time it will take

When 130 miles = 1 hour

90 miles = x

To calculate this

x = 90 miles * 1 hour/ 130 miles

x =90/130 hour

x = 9/13 hour

To calculate in minutes

x = 9/13 * 60 minutes

x = 41.5 minutes

Therefore, it will take 41.5 minutes to go 90 miles away.

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Answer the following questions for the function

f(x) = x sqrt(x^2 + 36) defined on the interval - 5 ≤ r ≤ 6. F(x) is concave down on the interval x = to x =

f(x) is concave up on the interval x = to x = The inflection point for this function is at x = The minimum for this function occurs at x = The maximum for this function occurs at x =

Answers

f(x) is concave down on the interval -5 ≤ x ≤ -6 and 0 ≤ x ≤ 6.

f(x) is concave up on the interval -6 ≤ x ≤ 0.

To determine where f(x) is concave up or concave down, we need to calculate the second derivative of f(x):

f(x) = x √([tex]x^2[/tex] + 36)

f'(x) = √[tex]x^2[/tex] + 36) + [tex]x^2[/tex] √([tex]x^2[/tex] + 36)

f''(x) = (x ([tex]x^2[/tex] +72) )/(([tex]x^2[/tex]+36)[tex]^(3[/tex]/2))

To find where f(x) is concave up or concave down, we need to find where f''(x) > 0 (concave up) or f''(x) < 0 (concave down).

f''(x) = 0 when x = 0 or x = +/-6.

Thus, f(x) is concave down on the interval -5 ≤ x ≤ -6 and 0 ≤ x ≤ 6, and concave up on the interval -6 ≤ x ≤ 0.

The inflection point for this function is at x = 0.

To find the minimum and maximum for this function, we need to look at the endpoints and critical points of the interval -5 ≤ x ≤ 6.

f(-5) = -5√61 and f(6) = 6√72, so the minimum occurs at x = -5 and the maximum occurs at x = 6.

Therefore:

f(x) is concave down on the interval -5 ≤ x ≤ -6 and 0 ≤ x ≤ 6.

f(x) is concave up on the interval -6 ≤ x ≤ 0.

The inflection point for this function is at x = 0.

The minimum for this function occurs at x = -5.

The maximum for this function occurs at x = 6.

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