why can two prime numbers only have one common factor?

Answer:

The answer is "[tex]y\approx 1.4[/tex]".

Step-by-step explanation:

In the given question the y-coordinates range between -1 to -2. Its distance between -1 and -2 is near, and less than halfway.

Answer:

b

Step-by-step explanation:

If these are number systems then it will turn out like this                                            [tex]\displaystyle\bf 523_7-65_7=\boxed{425_7}[/tex]

Answer:

Side IJ would be 15

Step-by-step explanation:

Since Triangle HIJ is dilated by a scale factor of 5, that means Triangle H'I'J' would have side measurements that are 5 times as much as Triangle HIJ.

They give you that side I'J' is 75

so you divide 75 by 5 and you'll end up with 15

Answer:

3 to the power of 4 equals 81 times 3 equals 243

Step-by-step explanation:

Hello,

A:

[tex]\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&1&-a&b&c\\x=-1&&-1&a+1&-a-b-1\\---&---&---&---&---\\&1&-a-1&a+b+1&-a-b+c-1\\\end{array}\\\\\\\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&1&-a&b&c\\x=2&&2&-2a+4&-4a+2b+8\\---&---&---&---&---\\&1&-a+2&-2a+b+4&-4a+2b+c+8\\\end{array}\\\\\\\\-a-b+c-1=-4a+2b+c+8\\\\\boxed{b=a-3}\\[/tex]

B:

[tex](2x-1)^3+6(3+4x^2)\\\\=8x^3-12x^2+6x-1+18+24x^2\\\\=8x^3+12x^2+6x+17\\\\\\\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&8&12&6&17\\x=-\dfrac{1}{2} &&-4&-4&-1\\---&---&---&---&---\\&8&8&2&16\\\end{array}\\\\\\(2x-1)^3+6(3+4x^2)=(2x+1)(4x^2+4x+1)+16[/tex]

Answer:

[tex]8x^2y-18y^3[/tex]

[tex]=8x^2y-18yy^2[/tex]

[tex]=4\cdot \:2x^2y+9\cdot \:2yy^2[/tex]

[tex]=2y\left(4x^2-9y^2\right)[/tex]

[tex]=2y\left(2x+3y\right)\left(2x-3y\right)[/tex]

----------------------

Hope it helps...

Have a great day!!

Answer: (-1, 2)

Step-by-step explanation:

Let's start by solving for x in

[tex]-5x+2y=9\\-5x+2y+-2y=9+-2y\\-5x=9+-2y\\\frac{-5x}{-5} =\frac{9+-2y}{-5} \\x=\frac{2}{5} y+\frac{-9}{5}[/tex]

We can now sub this value of x in 3x+5y=7 and solve

[tex]3x+5y=7\\3(\frac{2}{5} y+\frac{-9}{5})+5y=7\\(3)(\frac{2}{5} y)+(3)(\frac{-9}{5})+5y=7\\\frac{6}{5} y+\frac{-27}{5}+5y=7\\\frac{6}{5} y+\frac{25}{5}y +\frac{-27}{5}=7\\\frac{31}{5} y+\frac{-27}{5}=7\\\frac{31}{5} y+\frac{-27}{5}+\frac{27}{5}=7+\frac{27}{5}\\\frac{31}{5} y=\frac{62}{5} \\\frac{\frac{31}{5} y}{\frac{31}{5}} =\frac{\frac{62}{5} }{\frac{31}{5}} \\y=2[/tex]

Now we can sub in 2 for y in one of the equations

[tex]3x+5(2)=7\\3x+10=7\\3x+10-10=7-10\\3x=-3\\\frac{3x}{3} =\frac{-3}{3} \\x=-1[/tex]

x=-1 and y=2 giving us the point (-1, 2)

Answer:

Answer: The arc PS would be a minor arc · Step-by-step explanation: As a minor arc is one that is less that 180 degrees, it would be the only viable ...

Answer: Five and a quarter

Step-by-step explanation:

Answer:

[tex]7h - 5(3h - 8) - 28 = 100 \\ 7h - 15h + 40 - 28 = 100 \\ 7h - 15h + 12 = 100 \\ - 8h + 12 = 100 \\ - 8h = 100 - 12 \\ - 8h = 88 \\ \frac{ - 8h}{ - 8} = \frac{88}{ - 8} \\ h = - 11[/tex]

Answer:

19.

h=0, the result is 1000×2⁰ = 1000

this is the population of bacteria the excitement started with at the very beginning.

h=-3, the result is 1000×2-³ = 1000/(2³) = 1000/8 = 125

this is a calculation 3 hours backwards from the very start of the experiment, saying that if we started the experiment 3 hours earlier, this would have had to be the starting population of the bacteria so we would arrive at the same amount of population at any given time (value of h).

20.

D 25x⁶

Step-by-step explanation:

for 19 there is not more explanation. it is all ashtray in the answer.

for 20 we see that we are dealing with a square, so ask 4 sides have the same length.

one side is 5x³.

the area of a square is simply side².

so, here (5x³)² = 25x⁶

[tex]11. \: we \: know \: that \\ \frac{sum \: of \: all \: quantities}{number \: of \: quantities} = mean \\ => \frac{7 + 11 + 13 + 6 + 8 + x}{6} = 8 \\ = > \frac{45 + x}{6} = 8 \\ = > 45 + x = 8 \: \times 6 \\ = > 45 + x = 48 \\ = > x = 48 - 45 \\ = > x = 2 \\ \\ 12. we \: know \: that \\ \frac{sum \: of \: all \: quantities}{number \: of \: quantities} = mean \\ => \frac{2 + 5 + 1.3 + 2.2 + x}{5} = 1.8 \\ = > \frac{10.5 + x}{5} = 1.8 \\ = > 10.5 + x = 5 \times 1.8 \\ = > 10.5 + x = 9 \\ = > x = 9 - 10.5 \\ = > x = - 1.5 \\ [/tex][/tex]

This is the answer.

Hope it helps!!

Answer:

the answer is 3x2-10x+6=0

Answer:

It's d or the 4th graph

Step-by-step explanation:

A graph which represents the overall equation (inequality) represented by this scenario.

A graph can be defined as a type of chart that is commonly used for the graphical representation of data points on both the horizontal and vertical lines of a cartesian coordinate, which are the x-coordinate (x-axis) and y-coordinate (y-axis).

Let the variable x represent the total number of guests.

Let the variable y represent the amount of meat

Next, we would write an inequality that represents an amount of meat that must be 2 pounds fewer than one-third (1/3) the total number of guests. Since the customer decides they want at least that amount of meat, the inequality symbol that must be used is greater than (>).

y > 1/3(x) + 2

y > x/3 + 2

In conclusion, the y-value for this inequality graph (see attachment) intersects the x-axis at 0 and 6 with the boundary line shaded upward and dashed to indicate that it is not part of the solution, which must be represented with a greater than (>) inequality symbol.

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Answer:

y= -1/15x + 16/15

Step-by-step explanation:

When two lines are perpendicular to each other that means their slopes are the negative reciprocals of each other.

So that means if a line has has a slope of 6, a line perpendicular to that line will have a slope of -1/6.

(a reciprocal is when the fraction is flipped over)

In this case, the negative reciprocal of 15 would be -1/15. So the slope of the line that is perpendicular would be -1/15.

The equation we would have so far for that line would be: y=-1/15x+b

Now we have to find the 'b' or the y intercept, which we can get by plugging in the point that was given (1,1), which is on that line.

Which gives us 1=-1/15(1)+b.

1=-1/15+b

1+1/15=b

Then you solve for b and get b= 16/15.

The equation of the line that is perpendicular to the given line is y= -1/15x + 16/15.

The equation of the line that passes through the point (1, 1) and is perpendicular to y = 15x + 45 is

y = 15x - 14.

The equation of a line is given by:

y = mx + c

where m is the slope of the line and c is the y-intercept.

Example:

The slope of the line y = 2x + 3 is 2.

The slope of a line that passes through (1, 2) and (2, 3) is 1.

We have,

Let the equation of a line is y = mx + c.

The line is perpendicular to y = 15x + 45.

y = 15x + 45 is in the form of y = mx + c

This means,

Slope = 15

m = 15

The line passes through the point (1, 1) = (x, y).

This means,

y = mx + c

1 = 15 x 1 + c

1 = 15 + c

c = 1 - 15

c = -14

The equation of the line is y = 15x - 14.

Thus,

The equation of the line that passes through the point (1, 1) and is perpendicular to y = 15x + 45 is

y = 15x - 14.

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Answer:

Get all the values of the histogram and put them in order:

For example 2,5,7,1,7,3  becomes 1,2,3,5,7,7 and then you get the middle number, which is in this case (3+5)/2=3.5

Then see which of the readings lie on 3.5.

Step-by-step explanation:

9514 1404 393

Explanation:

The histogram will have a count associated with each class. You may have to read the count from the vertical scale of the graph. If it is a histogram of relative frequencies, each class will have a fraction or percentage instead of a count.

Find the total of all counts. Determine what half that number is. If the total is odd, then round up to the nearest integer. This is the index number of the median value.

Add up the counts in the classes starting at one side of the graph, working toward the other side. (Left-to-right is the usual direction for doing this.) When you find the class that increases the total to a value equal or greater than the index number, this is the class that contains the median.

__

If the histogram is a relative frequency histogram, the class that brings the total to 50% is the one containing the median.

__

There may be cases where the total count is even, and the total of all of the classes up to a point is exactly equal to the index number you're looking for. In that case, the median is between that class and the next. Here's an example:

  class 1: count 3

  class 2: count 5

  class 3: count 4

  class 4: count 4

Total count: 3+5+4+4 = 16. Median index = 16/2 = 8

Total of classes 1 and 2 = 3+5 = 8. This means exactly half of the represented values are in class 2 or below, and half are in class 3 or above. If you had access to the actual data values, you would find the median as the average of the 8th and 9th data values (when they are sorted into increasing order). Here, the median might be estimated as the value halfway between the upper bound of class 2 and the lower bound of class 3.

__

2nd example

Consider the same histogram as above, but with a count of 3 in class 4. This brings the total count to 15, and the index of the median is 15/2 = 7.5, rounds to 8. Again, the 8th data value (median) is in class 2. There is no ambiguity in this case.

Answer:

Amount of orange juice = 75 ml

Amount of Pineapple juice = 125 ml

Amount of mix juice = 175 ml

Step-by-step explanation:

Given:

Type of juice

Orange juice, Pineapple juice, mix juice

Ratio: 3 : 5 : 7

Amount of juice mixture = 375 ml

Find:

Amount of each juice

Computation:

Let common ratio = a

So,

3a + 5a + 7a = 375

15a = 375

a = 375 / 15

a = 25

Amount of orange juice = 3a

Amount of orange juice = 3(25)

Amount of orange juice = 75 ml

Amount of Pineapple juice = 5a

Amount of Pineapple juice = 5(25)

Amount of Pineapple juice = 125 ml

Amount of mix juice = 7a

Amount of mix juice = 7(25)

Amount of mix juice = 175 ml

Answer: 8

Step-by-step explanation:

Given

Mean of the numbers is 8

If the ratio is 1:1:2:2:3:3

Suppose the numbers are [tex]x, x, 2x, 2x, 3x, 3x[/tex]

Write the mean of the numbers

[tex]\Rightarrow \dfrac{x+x+2x+2x+3x+3x}{6}=8\\\\\Rightarrow \dfrac{12x}{6}=8\\\\\Rightarrow x=4[/tex]

So, the numbers are [tex]4, 4, 8,8 ,12,12[/tex]

As the total numbers are even, median is the sum of the middle values

[tex]\Rightarrow \text{Median=}\dfrac{8+8}{2}\\\\\Rightarrow \text{Median=}8[/tex]

Answer: (1, 8)

Step-by-step explanation:

Substitute y = 3x + 5 into the equation 2x + 3y = 26:

2x + 3(3x + 5) = 26

2x + 9x + 15 = 26

11x = 26 - 15

11x = 11

x = 1

Substitute the value of x into the equation y = 3x + 5:

y = 3(1) + 5 = 3 + 5 = 8

Answer:

Domain is [-5, 5]

Range is [-3, 17]

Step-by-step explanation:

R1 = {(x, y)| y = 2x + 7, where x∈ R and -5 ≤ x ≤ 5}

The domain is given by the all possible input values of x . Here the function is defined for -5 ≤ x ≤ 5, so the domain is [ - 5, 5].

The range is given by the output values  of he function.

When x = - 5

f (- 5) = 2 (-5 ) + 7 = - 3

When x = 5

f (5) = 2 (5) + 7 = 17

So, the range is [ -3 , 17].

Answer:

Step-by-step explanation:

MM oute le iloa

The arc length is 10 Pi

(I don't know for sure, but its what I got)

Answer:

2a+15 = 125(being alternate angle)

or,2a = 125-15

or,2a = 110

or,a = 110÷2

,a = 55

again,2a+15+b+30=180(Being co-interior angle)

or,2×55+15+b+30=180

or,110+15+30+b=180

or,155+b=180

or,b=180-155

Therfore,b=25

Answer:

a) 12 'o' clock, b) 30 minutes c) you can do it your answer may differ

Step-by-step explanation:

a) look closely you will see it is 24 hours format, so it is proved she starts going to town at that that time

b) look you there is a downward movement of graph means it shows she is not travelling she is resting done let after 1500 or 3:00pm and before 1600 or 4:00pm point be 3:30 so till 3:30 to 4:00 rested in town

c) answer may differ

pls thank me and mark brainliest if you can

Answer:

a.

Step-by-step explanation:

Answer: A.Spreads: The weights of the tigers are more spread out.

B.Centers:The leopards have a lower median weight than the tigers

Step-by-step explanation:

On analyzing the dot plots, we find that the weight of Leopards are more spread out and the weight of Leopards has a lower median than Tiger.

Median is a statistical measure that determines the middle value of a dataset listed in ascending order. The measure divides the lower half from the higher half of the dataset.

Median of Weight of Leopard = 50 kg

Median of Weight of Tiger = 125 kg

This implies that the Leopards have a lower median weight than Tigers.

What is spread of data?

Spread describes the variation of the data. One of the measures of spread is range.

Range of weight of Leopards= 40 kg

Range of weight of Tigers = 90 kg

This implies that the weight of Tigers are more spread out.

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