When you remove your finger from the coin, sliding friction between the coin and the paper causes it to slow down and stop because it changes the kinetic energy into other sorts of disordered energy, such as heat. Because of static friction and gravity, the coin began at rest.
What is friction?The force that stops solid surfaces, fluid layers, and material components from moving against one other is known as friction. There are several types of friction: Dry friction is the force that opposes the relative lateral motion of two solid surfaces that are in contact. Friction is the force created when one object rubs against another. Friction happens when two objects rub against one another. Friction works in the opposite direction of motion. The amount of friction is determined by the materials used to create the two surfaces.
Here,
When you stop touching the coin, there is sliding friction between the coin and the paper, which causes it to slow down and halt because it converts the kinetic energy into other types of disordered energy, such as heat. The coin began at rest due to static friction and gravity.
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Matt's book is motionless on a table.
Which force diagram would represent Matt's book? You may neglect the effects of air resistance.
1. Diagram A
2. Diagram B
3. Diagram C
4. Diagram D
identify the ways in which ocean sediments can be used as direct evidence in solving different type of issues. (select all that apply.)
To map offshore pollution patterns, to identify sites for underwater construction projects, and to find offshore mineral resources, are the ways in which ocean sediments can be used as direct evidence of issues.
To map offshore pollution patterns: Changes in the composition and distribution of pollutants and trace elements in ocean sediments can provide evidence of environmental changes, including pollution.
To identify sites for underwater construction projects: The composition and physical characteristics of sediments can provide information about the suitability of a site for underwater construction, such as the stability of the sea bed and the potential for sediment movement.
To find offshore mineral resources: The distribution of specific mineral deposits in ocean sediments can be used to identify areas with potential for offshore mineral extraction.
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--The given question is incomplete, the complete question is:
"Identify the ways in which ocean sediments can be used as direct evidence in solving different type of issues. (Select all that apply.)
To map offshore pollution patterns
To identify sites for underwater construction projects
To find offshore mineral resources
To determine how climate has changed over geologic time"--
Which of the following options correctly reflects the relationship between dispersion forces and particle size? Select all that apply.
a)larger particle are more polarizable and experience stronger dispersion forces
b) dispersion forces tend to decrease with size as larger particles are farther apart and therefore attract each other less
c) dispersion forces are strongest for small particles since they can get closer together in space
d) for molecules of similar shape, dispersion forces tend to increase with increasing molar mass
A) larger particles are more polarizable and experience stronger dispersion forces and c) dispersion forces are strongest for small particles since they can get closer together in space
What is polarizable?Polarizability is the ability of a molecule or atom to become polarized when subjected to an external electric field. It is the measure of the ease with which the electrons in a molecule or atom can be redistributed in response to an external electric field. Polarizability is a characteristic of all molecules, atoms, and ions, and governs their behavior in electric and magnetic fields. Polarizable molecules tend to be more reactive and more capable of forming strong bonds with other molecules or atoms. Polarizability is an important factor in determining a molecule's behavior in a variety of biological, chemical, and physical processes.
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Two pans of a balance are 39.3 cm apart.
The fulcrum of the balance has been shifted
1.46 cm away from the center by a dishonest
shopkeeper.
By what percentage is the true weight of the
goods being marked up by the shopkeeper?
Assume the balance has negligible mass.
Answer in units of %.
pls help I'm so lost
The true weight of the goods is being marked up 1,936.5% by the shopkeeper.
What is the error in percentage?To calculate the percentage of increase in weight, we need to calculate the actual increase in weight, then divide it by the true weight and multiply by 100.
The displacement of the fulcrum has caused a torque on the balance, and we can calculate this torque using the formula: torque = force x distance. The force causing the torque is the weight of the goods, and the distance is the displacement of the fulcrum from the center.
Torque = weight x displacement
= weight x (39.3 / 2 + 1.46)
= weight x (20.365)
The balance is in equilibrium, so the sum of torques on the two pans is zero. Therefore, the torque on the pan with the goods is equal in magnitude but opposite in direction to the torque on the other pan.
Torque_goods = -Torque_counterweights
= - (weight_counterweights x 20.365)
= - (weight_goods x 20.365)
Dividing both sides by weight_goods, we get:
20.365 = - weight_goods / weight_counterweights x 20.365
Solving for weight_goods, we find:
weight_goods = weight_counterweights x 20.365 / 20.365
Therefore, the actual weight of the goods is 20.365 times the true weight. The percentage increase in weight is:
percentage increase = (actual weight - true weight) / true weight x 100
= (20.365 - 1) / 1 x 100
= 1,936.5%
So, the true weight of the goods is being marked up by 1,936.5%.
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a clue to the process of planetary formation comes from meteorites, which are pieces of debris that have fallen from space to earth. most meteorites are made of materials that have remained unchanged since the time that the solar system was first forming, which make them excellent indicators of what conditions were like during that time.
Individual particles in the nebula stick together to form larger pieces which later collide with and stick to other pieces to gradually form larger objects, which eventually grow to the size of a planet.
A meteorite is a rock that falls to Earth from space. Some meteorites even contain tiny particles that formed around other stars that existed before our Sun.
All meteorites come from inside our solar system. Most of them are fragments of asteroids that broke apart long ago in the asteroid belt, located between Mars and Jupiter. Such fragments orbit the Sun for some time–often millions of years–before colliding with Earth.
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A square plate is produced by welding together four smaller square plates, each of side
a. The weight of each of the four plates is
shown in the figure.
Find the x-coordinate of the center of gravity (as a multiple of a).
Answer in units of a.
Find the y-coordinate of the center of gravity
(as a multiple of a).
Answer in units of a.
A square flange plate is a metal plate with four projections or “flanges” extending outward from the plate’s edges.
What are square plates?
The four projections create a square shape when viewed from the top. Depending on your needs and budget, these plates can be made from steel or aluminium.
Square flange plates are extremely adaptable and have a wide range of uses. By distributing weight uniformly throughout the structure, they support the beams and columns.
They can also be utilized in welding operations to join two pieces together without gaps or irregularities. Finally, they can offer structural support for surfaces like walls in building projects.
Therefore, A square flange plate is a metal plate with four projections or “flanges” extending outward from the plate’s edges.
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A truck with 28-In.-diameter wheels is traveling at 45 mph.
How many revolutions per minute do the wheels make?rpm
What is the angular speed of the wheels In radians/min?rad/min
Round answers to 2 decimal places
Answer:
To find the number of revolutions per minute (RPM) the wheels make, we first need to find the circumference of the wheel. We can use the equation:
Circumference = 2 * pi * radius
The diameter of the wheel is 28 inches, so we can find the radius by dividing the diameter by 2:
Radius = 28 inches / 2 = 14 inches
Now we can find the circumference of the wheel:
Circumference = 2 * pi * 14 inches = 87.96 inches
To find the number of revolutions per minute, we need to know how many inches the wheel travels in one minute, we can convert 45 mph to inches per minute by multiplying 45 mph by 1.46667 (1 mph = 1.46667 inches/s)
inches per minute = 45 * 1.46667 = 66.00015 inches
So we can find the number of revolutions per minute by dividing the distance traveled per minute by the circumference of the wheel:
RPM = inches per minute / circumference
RPM = 66.00015 inches / 87.96 inches = 0.75 rev/min
To find the angular speed of the wheels in radians per minute, we can use the equation:
Angular speed = 2 * pi * RPM
Angular speed = 2 * pi * 0.75 rev/min = 4.71 rad/min
So the angular speed of the wheels in radians per minute is 4.71 rad/min (rounded to 2 decimal places)
A thin, square, conducting plate 42.0 cm on a side lies in the xy plane. A total charge of 4.20 10-8 C is placed on the plate. You may assume the charge density is uniform. (a) Find the charge density on each face of the plate. C/m2 (b) Find the electric field just above the plate. magnitude N/C direction (c) Find the electric field just below the plate. magnitude N/C direction
(a) The charge density on each face of a thin, square, conducting plate 42.0 cm on a side lies in the xy plane. A total charge of 4.20 x 10⁻⁸ C is placed on the plate = 8.4 nC/m²
(b) The electric field just above the plate = 95 kN/C k
(c) The electric field just below the plate = -95 kN/C k
How to determine the charge density of the plate?We disregard "edge" effects and assume that the total charge is distributed uniformly across the plate, with one-half of the total charge on each side. The charge density on the plate's upper and lower surfaces is:
σ = [tex]\frac{1}{2}[/tex] (q / A)
Where:
σ = charge density
q = total charge
A = the area of the plate
Hence,
(a)
σ = [tex]\frac{1}{2}[/tex] (4.20 x 10⁻⁸ C) / (0.500m²)
= 8.4 x 10⁻⁸
= 8.4 nC/m²
The direction ⇒ positive
(b)
The electric field just above the plate:
Ё = (σ / ε₀) k
= (8.4 x 10⁻⁸ / 8.85 x 10⁻¹²)
= (95 kN/C) k
The direction ⇒ positive
(c)
The electric field just below the plate:
(-95 kN/C) k
The direction ⇒ negative
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An astronaut with mass MA within satellite that orbits Earth at = height H above its surface Earth has mass ME ad radius RE. Which of the following correct expression for the gravitational force exerted on the astronaut by Earth? A. Fg = GMgMa/H^2B. Fg = GMeMa/R^2 eC. Fg = GMgMa/(Re + H)^2 D. Fg = 0
According to the problem the correct expression is C: Fg = GMgMa/(Re + H)^2.
What is expression?Expression is the communicative use of language to convey a thought, idea, emotion, or feeling. It is the process of making meaning out of language through the use of tone, pitch, volume, and other non-verbal communication tools. Expression can be used to express a wide range of feelings and emotions, and can be used to communicate a variety of ideas. It is a powerful way to communicate to others and is an important part of effective communication.
This is because the gravitational force exerted by Earth on the astronaut is a function of the masses of both Earth and the astronaut, as well as the distance between them. This distance is the distance from the center of Earth to the astronaut, which is equal to the radius of Earth (RE) plus the height of the satellite above Earth's surface (H). Therefore, the expression for the gravitational force is Fg = GMgMa/(Re + H)^2.
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Describe an experiment to determine the frequency, amplitude and period of a flywheel in motion.
To determine the frequency, amplitude, and period of a flywheel in motion, one can conduct the following experiment:
Obtain a flywheel that is capable of rotating and vibrating.Attach a tachometer or a high-speed camera to the flywheel to measure its speed of rotation.Use a strobe light to freeze the motion of the flywheel at regular intervals.Observe and measure the displacement of the flywheel from its center of rotation at each interval.Plot the displacement of the flywheel against time to obtain a waveform.Determine the frequency of the waveform by counting the number of complete cycles of vibration that occur in one second.Calculate the amplitude of the waveform by measuring the maximum displacement of the flywheel from its center of rotation.Determine the period of the waveform by measuring the time it takes for one complete cycle of vibration.Repeat the experiment multiple times to confirm the results and calculate an average.The resulting data can be used to calculate the frequency, amplitude, and period of the flywheel's motion and can provide insight into the mechanical properties of the system.What is the flywheel about?A flywheel in motion refers to a rotating wheel that is used to store energy. It helps to maintain the velocity of an engine and to reduce fluctuations in the energy supplied to it.
In an experiment to determine the frequency, amplitude and period of a flywheel in motion, researchers will measure various characteristics of the wheel as it rotates, such as the speed of rotation, the amount of energy being stored, and the amount of time it takes for the wheel to complete one full rotation.
Therefore, This information will allow them to calculate the frequency, amplitude, and period of the flywheel, providing valuable insights into its behavior and performance.
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a spring is hanging from the ceiling. attaching a 560 gg physics book to the spring causes it to stretch 25 cmcm in order to come to equilibrium.part awhat is the spring constant?express your answer with the appropriate units.view available hint(s)for part aactivate to select the appropriates template from the following choices. operate up and down arrow for selection and press enter to choose the input value typeactivate to select the appropriates symbol from the following choices. operate up and down arrow for selection and press enter to choose the input value typekk
The value of the spring constant is 8704 N/m.
The spring constant (k) can be found using Hooke's law, which states that the force required to stretch or compress a spring is proportional to the distance it is stretched or compressed.
Mathematically, it can be expressed as:
F = -kx
where F is the force applied to the spring,
k is the spring constant, and
x is the distance the spring is stretched or compressed.
Since the force applied to the spring is equal to the weight of the book, we can write:
F = mg = -kx
where m is the mass of the book and
g is the acceleration due to gravity.
Substituting the given values, we get:
560 g * 9.8 m/s^2 = -k * 0.25 m
Dividing both sides by -0.25 m and solving for k,
we will get it as:
k = (560 g * 9.8 m/s^2) / 0.25 m
k= 8704 N/m
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It takes 1.20 X 104 J of work to pull a loaded sled weighing 8.00 X 10² N a distance of
2.00 X 102 m. To do this, a force of 1.20 X 10 2N is exerted on a rope, which makes an
angle with the horizontal.
At what angle is the rope held? Express your answer as a number, space, then the word
degrees.
The angle with which the rope is held is 85.7⁰.
What is the angle made by the rope with horizontal?
The angle with which the rope is held is calculated by applying the following work formula.
W = Fd cosθ
where;
W is the work done by the applied forced is the displacement of the loadθ is the angle made by the applied force with the horizontalcosθ = ( W / Fd )
θ = arc cos ( W / Fd )
The angle with which the rope is held is calculated as;
θ = arc cos ( W / Fd )
θ = arc cos ( 12,000 ) / ( 800 x 200 )
θ = arc cos ( 0.075 )
θ = 85.7⁰
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which of the following melodic features is used in the treble clef in measures 45 and 46 ?
There are two forms of the melodic minor scale: ascending and descending.
What is melodic features?
A melodic line has several key characteristics, including contour, range, and scale. The contour of melody is the overall line that rises, falls, arches, undulates, or moves in any other characteristic way.Definitions of melodic. adjective. containing or constituting or characterized by pleasing melody. synonyms: melodious, musical ariose, songlike. having a melody (as distinguished from recitative).For example: Solo vocalists use melody when they sing the main theme of a song. Choral vocalists sing melodies as a group. Some choruses sing the same notes in unison, like in the traditions of ancient Greece.There are two types of melodic motion: conjunct motion, which proceeds by step from one scale degree to the next (i.e., by the interval of a 2nd) and disjunct motion, which proceeds by leap.To learn more about features refers to:
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Observe the example of foe on the box. The give a complete answer to each question below. Force in Same Direction Force in opposite Direction 1. How would you calculate the net force for example A? Explain. 2. How would you calculate the net force for example 87 Explain.
Answer:
To calculate the net force for example A, you would add the two forces together. Since they are in the same direction, the net force would be equal to the sum of the two forces. 2. To calculate the net force for example 87, you would subtract the force in the opposite direction from the force in the same direction. The net force would then be equal to the difference between the two forces.
A car is traveling at a steady 71 km/h in a 50 km/h zone. A police motorcycle takes off at the instant the car passes it, accelerating at a steady 7.5 m/s2.
a. How much time elapses before the motorcycle is moving as fast as the car?
b. How far is the motorcycle from the car when it reaches this speed?
(a) The time elapses before the motorcycle is moving as fast as the car is 2.6296 second.
(b) The motorcycle is 25.93 meter far from the car when it reaches this speed.
What is acceleration?Acceleration is rate of change of velocity with time. Si unit of acceleration is meter/second² (m/s²).
Speed of the car = 71 km/h = 71 ×5/18 m/s = 19.722 m/s.
Acceleration of the police motorcycle = 7.5 m/s²
Hence, Time taken by the motorcycle to be as fast as the car = 19.722 ÷ 7.5 s
= 2.6296 second.
The distance between the motorcycle and the car
= (19.722×2.6296 - 1/2×7.5 × 2.6296²) meter
= 25.93 meter.
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You have a remote-controlled car that has been programmed to have velocity v⃗ =(−3ti^+2t2j^)m/s, where t is in s. At t = 0 s, the car is at r⃗ 0=(3.0i^+2.0j^)m.
What is the y component of the car's position vector at 8.0 s ?
What is the x component of the car's acceleration vector at 8.0 s ?
What is the y component of the car's acceleration vector at 8.0 s ?
A student does 65.0 J of work to move a stack of books 3.5 m up to a shelf at a
constant velocity. What amount of vertical force does she lift it with?
The vertical force applied by the student to lift the book is 18.57 N.
What amount of vertical force does she lift it with?
The vertical force applied by the student to lift the book is calculated by applying the following formula.
W = Fd
where;
F is the applied forced is the displacement of the objectW is the wok done by the studentF = W / d
The vertical force applied by the student to lift the book is calculated as;
F = ( 65 J ) / ( 3.5 m )
F = 18.57 N
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Which of the following statements are true concerning particles and antiparticles?Check all that apply.a) All particles have antiparticles.b) The antiproton can be described as the antiparticle to the proton.c) Antiparticles have a very long lifetime.d) Some particles serve as their own antiparticles.e) The proton can be described as the antiparticle to the electron.f) Antiparticles are produced in nuclear reactions.
The true statements concerning particles and antiparticles are:
b) The antiproton can be described as the antiparticle to the proton.
d) Some particles serve as their own antiparticles.
f) Antiparticles are produced in nuclear reactions.
Every charged particle has an antiparticle, which has the same mass and spin as it has but the opposite charge, according to the quantum field theory. All of the available experimental data supports this broad quantum field theory conclusion. The positron is the electron's antiparticle.
Antiparticles are subatomic particles with opposing electric charge and magnetic moment but the same mass as a particle of regular matter. Consequently, the positron (a positively charged electron) is the negatively charged electron's antiparticle.
An antiparticle is a subatomic particle that, by definition, has the same mass as its counterpart in a normal particle but the opposite magnetic moment and electric charge. For instance, the antiparticle of an electron is a positron.
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In Vander Waal's equation (P+ a/v^2) (V - b) = RT, what are the dimensions of constants 'a' and 'b'?
Answer:
Explanation:
(P+ a/v^2) (V - b) are two factors in parentheses. These factors which represent physical quantities and are determined by subtraction. You can’t subtract unless both terms have the same dimensions.
[tex]a/v^{2}[/tex] has the same units as p
a=p[tex]v^{2}[/tex] =
[tex][ML^{-1}T^{-2}] [L^{6}] = [ML^{5}T^{-2}][/tex]
v has the same units as b
B = [tex][L^{3}][/tex]
which of the following defines a formula for computing the time, t , as a function of the volume, v ?
The t(v) = v/2, defines a formula for computing the time, t as a constant , as a function of the volume, v
What is constant?A constant is a value that does not change. It can be a number, a string of characters, a boolean (true/false) or a constant expression. Examples of constants include pi (3.14159), a string of characters such as “Hello World” and a boolean value of true or false. Constants are used in programming to represent values that are not liable to change, such as the value of pi, or a string of characters that will remain the same throughout the program's execution. They are also used to represent values that are not known until the program is run, such as a user inputted value.
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Complete question:
Can someone please help answer these 5 questions the picture is attached
Based on the diagram of the figure:
1. The acceleration of the train between 0 and 20 s = 0.5 m/s²
2. The acceleration of the train between 20 and 40 s = 0.5 m/s²
3. The train's speed at 80 second = 15 m/s
4. The acceleration of the train between 100 and 120 s = 0.75 m/s² (deceleration)
5. The train travel (when the train's speed 10 m/s) = 200 m
The equation of the acceleration:
a = Δv/t
Where,
a = acceleration (m/s²)
Δv = velocity (m/s)
t = time (s)
Hence,
1. The acceleration between 0 and 20:
a = 10/20
= 0.5 m/s²
2. The acceleration between 20 and 40:
a = 10 / (40 - 20)
= 0.5 m/s²
3. The train's speed at 80 = 15 m/s
4. The acceleration between 100 and 120:
a = 15/20
= 0.75 m/s² (deceleration)
5. The distance:
d = speed x time
= 10 x 20
= 200 m
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The angular speed of Earth is 1.99 x 10-7 radians /seconds.
Yes, that is correct. The angular speed of Earth is 1.99 x 10-7 radians per second. This is equal to 2π radians per year, or 1 revolution per 365.25 days.
The angular speed of the Earth is the rate at which it rotates around its own axis. It is measured in radians per second, and is typically expressed as 2π radians per day, or 7.27 x 10-5 rad/s. The angular speed of the Earth is constant, meaning that it does not change over time. This is important, as it allows us to measure the length of a day and use this to calculate the rate of other processes such as the seasons and the passage of time.
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consult multiple-concept example 10 to review an approach to problems such as this. a cd has a mass of 17 g and a radius of 6.0 cm. when inserted into a player, the cd starts from rest and accelerates to an angular velocity of 21 rad/s in 0.80 s. assuming the cd is a uniform solid disk, determine the net torque acting on it.
A mass of 17 g and a radius of 6.0 cm. when inserted into a player, the cd starts from rest and accelerates to an angular velocity of 21 rad/s in 0.80 s. assuming the cd is a uniform solid disk, the net torque acting on the CD is 16063.5 g cm²/s².
To determine the net torque acting on a uniform solid disk, we need to find the moment of inertia and the net force acting on it.
The moment of inertia (I) of a uniform solid disk can be found using the formula: I = (1/2)mr², where m is the mass and r is the radius. In this case, I = (1/2)(17 g)(6.0 cm)² = 612 g cm².
The net torque (τ) can be found using the formula: τ = Iα, where α is the angular acceleration. To find α, we need to use the formula: α = Δω/Δt, where Δω is the change in angular velocity and Δt is the change in time. In this case, Δω = 21 rad/s and Δt = 0.80 s, so α = Δω/Δt = 21/0.80 = 26.25 rad/s².
Finally, the net torque can be found using the formula: τ = Iα = (612 g cm²)(26.25 rad/s²) = 16063.5 g cm²/s².
Therefore, the net torque acting on the CD is 16063.5 g cm²/s².
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A body moves 5m in 3rd second and it moves 9m in the 7th second. Find the distance moved by the body between t = 5s and t = 8s.
tysm! :)
Answer:
34 m
Explanation:
I will assume the body is accelerating uniformly
accel = change in velocity/change in time
4 m/s / 4 s =1 m/s^2
So in second 4 it moves 6 Then for second 5 it moves 7 m then 8 m Then 9 m in second 7 Then 10 m in second 8
Total(5 thru 8) = 34m
Calculate the static thrust of the rocket and turbojet engines. The thrust T is the force necessary to prevent horizontal movement o the engine. Both engines exhaust a massflow of 40 kg/s. The ratio of air and fuel mass flowing into the turbojet is 50:1, and in its exhaust plane the velocity is 500 m/s and the pressure is the same as the ambient pressure. The rocket propellant exhausts at a velocity of 3000 m/s through an area of 0.2 m2. The pressure in the exhaust plane of the rocket is 0.15 MPa and the ambient pressure is 0.101 MPa.
The static thrust of the turbojet engine is 20,000 N, and the static thrust of the rocket engine is 36,000 N.
The calculation of the static thrust of a rocket and turbojet engine is determined by the following equation:
T = m × (Ve - V0)
where T is the thrust, m is the mass flow rate, Ve is the exhaust velocity, and V0 is the ambient velocity.
For the turbojet engine, the thrust can be calculated as follows:
T = 40 kg/s × (500 m/s - 0) = 20,000 N
For the rocket engine, the thrust can be calculated as follows:
P0 = 0.15 MPa, Pa = 0.101 MPa, Ve = 3000 m/s
A = 0.2 m2
m = 40 kg/s
P0 - Pa = (m × Ve²) / 2A
0.15 - 0.101 = (40 × 3000²) / (2 × 0.2)
T = (40 × 3000) / 0.2 = 36,000 N
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A piston absorbs 42 J of heat from its surroundings while being compressed
from 0.0007 m³ to 0.0002 m³ at a constant pressure of 1.0 × 105 Pa. What
are the correct values for heat and work for the piston?
OA. Q=-42 J, W = +50 J
OB. Q = +42 J, W = +50 J
OC. Q = +42 J, W = -50 J
OD. Q = -42 J. W = -50 J
The correct values for heat and work for the piston are;
Q = +42 J, W = -50 J
Option C
What is the work done?
We must note that the work that has been done by the piston can be obtained by the formula that we know and that formula states that;
w = PdV
w = work that have been done
P = pressure
dV = change in the volume
As such we would have that the work done is;
w = 1.0 × 10^5 Pa (0.0002 - 0.0007)
w = -50 J
This is the work that has been done but the heat was absorbed hence it is positive.
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A spaceship is traveling at a velocity of v⃗0=(28.9m/s)î v → 0 = ( 28.9 m / s ) i ^ when its rockets fire, giving it an acceleration of a⃗=(2.12m/s2)î+(4.95m/s2)ĵ a → = ( 2.12 m / s 2 ) i ^ + ( 4.95 m / s 2 ) j ^
The final speed of the plane after 6.29 s is 62.866 m/s.
So the magnitude of the initial velocity is, V(0) = (28.9 m/s)
And the acceleration component is,
a = (2.12 m/s2)i + (4.95m/s2)j
So the magnitude of the acceleration is
a = √2.122 + √4.952
a = √4.50 + √24.5
a = √29
a = 5.4 m/s2
And the time is, t = 6.29 seconds
By the first law of motion,
V(f) = V(i)+at
V(f) = 28.9 + 5.4(6.29)
V(f) = 62.866 m/s
Where v(f) is the final speed of the spacecraft after 6.29 seconds. So, the final speed of the plane after 6.29 s is 62.866 m/s.
Your question is incomplete but most probably your full question was:
A spaceship is traveling at a velocity of v⃗0=(28.9m/s)î v → 0 = ( 28.9 m/s)i when its rockets fire, giving it an acceleration of a⃗=(2.12m/s²)î+(4.95m/s2)ĵ a → = ( 2.12 m/s²)i + ( 4.95 m/s²)j. How fast, in meters per second, is the rocket moving 6.29s6.29s after the rockets fire?
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: Which of the following are evidence of past liquid water on the Martian surface? Sort as true or false Items (5 iterns) (Drag and drop into the appropriate area below) fossils minerals that form underwater rounded pebbles present day oceans dry river beds Categories True False
True: - Fossils - Minerals that form underwater - Rounded pebbles - Dry river beds and False: - Present day oceans.
What is Fossils?Fossils are the remains or traces of organisms that lived in past geological ages. They can be found in rocks, sediment, or soil and are usually the preserved remains of animals and plants that lived millions of years ago. Fossils can be bones, teeth, shells, or other body parts. They can also include footprints, nests, burrows, or other evidence of animal behavior. Fossils provide scientists with important information about ancient life and the Earth’s history. By studying fossils, scientists can learn how animals and plants lived, how they evolved, how they interacted with each other, and how their environment changed over time.
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You slide across a icy sidewalk. According to Newtons first law, why are you in motion?
A. Inertia caused you to accelerate.
B. There is no air resistance.
C. A force overcame your inertia.
D. You are subject to balanced forces.
When you slide across a icy sidewalk, you are in motion because you are subject to balanced forces according to Newton's first law.
What is Newton's first law?A body remains in a condition of rest or uniform motion in a straight line until and until an external force acts on it, according to Newton's first law of motion.
According to Newton's first law of motion, a body won't begin to move unless and until an outside force acts on it. When anything starts moving, it won't stop or vary its speed unless another force acts on it. Hence, you slide across a icy sidewalk.
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In the temperature experiment, you used a thermometer to measure the temperature inside a closed hand and in four beakers of water. Please match the question with the correct answer choice.
1. Temperature inside the beaker of room temperature water.
2. Temperature inside the closed hand.
3. Temperature inside the beaker of cold tap water.
4. Temperature inside the beaker of ice water.
5. Temperature inside the beaker of hot tap water.
In the temperature experiment, a thermometer was used to measure the temperature with a closed hand and four beakers of water. Then the correct answer is the temperature of a cup of water at room temperature, the temperature of a closed hand.
Averaged across all activities, the mean temperature of the closed side of the ring finger and palm was 17.7 °C (63.9 °F), significantly (p <0.01) a low temperature. °F). F). The water temperature in the cup is 25°C. Endothermic reactions absorb energy, so when the beaker is closed all the energy is absorbed by the reaction, and the temperature inside the beaker drops.
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