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A table of values of an increasing function f is shown.
x 10 14 18 22 26 30
f(x)
−14
−8
−1
1
4
7
Answers
The upper estimate and lower estimate become R5 = 16 and L5 = −64
According to the statement
we have given that the some values of the increasing function f and we have to find the lower estimate and upper estimate values.
So, For this purpose, we know that the
the values of x is 10 14 18 22 26 30
And the values of f(x) is −14 −8 −1 1 4 7
So,
Δx = 4 because
L5 = 4(−12 − 6 − 2 + 1 + 3) = −64,
And
R5 = 4(−6 − 2 + 1 + 3 + 8) = 16.
And from these functions we see that the
The function being increasing, the Riemann sum with left endpoint L5 = −64 is a lower estimate,
And while the sum with right endpoints R5 = 16 is an upper estimate.
So, The upper estimate and lower estimate become R5 = 16 and L5 = −64
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Related Questions
A farmer determines that, on average, his chickens lay a total of 16 eggs each day. A random sample of 10 days was taken, and the mean number of eggs was 15.1 eggs. Let μ = the true mean number of eggs the chickens lay each day. Under the assumption that the true mean number of eggs is 16, 100 simulated means for samples of size 10 are shown in the dotplot. A dotplot titled mean number of eggs. A number line labeled simulated means of samples, n = 10, goes from 15.0 to 17.2. A sample mean of eggs of 15.1 or less only occurred twice. Using the dotplot, is there evidence that the chickens are laying fewer than 16 eggs? Yes, since a sample mean number of eggs of 15.1 eggs or less only occurred twice in simulated values, there is evidence that the true mean number of eggs is less than 16. Yes, since a sample mean number of eggs of 15.1 is less than the mean number of eggs of 16, there is evidence to prove that the true mean number of eggs is less than 16. No, since a sample mean number of eggs of 15.1 is only 0.9 eggs less than a mean number of eggs of 16, there is insufficient evidence that the true mean number of eggs is less than 16. No, since a sample mean number of eggs of 15.1 never occurred in the dotplot, it is not possible that a random sample of 10 eggs will have a mean number of eggs of 15.1. Therefore, there is insufficient evidence that the true mean number of eggs is less than 16.
Answers
Given the above information, it is correct to say Yes, since a sample mean number of eggs of 15.1 eggs or less only occurred twice in simulated values, there is evidence that the true mean number of eggs is less than 16. (Option A)
What is the explanation for the above?
Recall that the mean (statistically speaking) is a measure of central tendency of a probability distribution along median and mode.
You could also state that it is an expected value. Given that samples of actual value taken from the
Hence, since from 100 samples taken, the number of eggs of 15.1 or less occurred, then the true mean or actual mean is less than 16.
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Which statement is true about the voting results?
Answers
Answer:
11% more people voted for Candidate B than Candidate A
Step-by-step explanation:
15+6=21
9+23=32
32-21=11
For a class project student in health class ask every tenth student entering school if they eat breakfast in the morning
Please answer all 4 I really need help
Answers
The types of study that we have hereare the
surveyexperimentobservational survey1. The statistical question that has to be answered would beHow many students in this school ate breakfast?The type of study is the survey2. The question here would be
Does music help in the recalling of knowledge?The type of study that is going to be conducted would be the experiment.3. The answer that would be answered here would be
Does regular exercise affect the rate of heart beat of an individual?The observation of the study participants and their behavior would be used to determine this.4. The question would be
Is there a relationship between the physical activity of children and their energy levelThe type of study is the surveyRead more on research study here:
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BUYING A TOWNHOUSE SELLING FOR $175,000. THE BANK IS
OFFERING A 30-YEAR FIXED RATE MORTGAGE AT 5.5% WITH A MINIMUM 20% DOWN
PAYMENT. DETERMINE THE AMOUNT OF THE DOWN PAYMENT AND THE MONTHLY PAYMENT
Answers
Using the monthly payment formula, we have that:
The down payment is $35,000.The monthly payment is of $795.87.What is the monthly payment formula?It is given by:
[tex]A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}[/tex]
In which:
P is the initial amount.r is the interest rate.n is the number of payments.The down payment is 20% of $175,000, hence:
D = 0.2 x 175,000 = $35,000.
Hence the parameters are:
P = 175,000 - 35,000 = 140,000, r/12 = 0.055/12 = 0.004583, n = 30 x 12 = 360.
Then the monthly payment is found as follows:
[tex]A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}[/tex]
[tex]A = 140,000\frac{0.004583(1.004583)^{360}}{(1.004583)^{360} - 1}[/tex]
A = $795.87.
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5. Compound Interest - Single Payment: $5000 was invested at 5.2%, compounded semi-annually, for 3 years. What was the investment worth at its maturity? (3)
Answers
Answer:
78000
Step-by-step explanation:
5000/1 times 52/10 times 3)1
You and Jake are studying together and after correctly solving a system of equations using
the substitution method the result is 3 3. Jake does not know how to interpret this
result.
In at least one complete sentence, explain to Jake the number of solutions, solution type,
and how the graph of the system of equations would look
Answers
Answer: its the 3rd one if im wrong im sorry
:3
Find the measure of c.
Answers
Answer:
100°
Step-by-step explanation:
basically, in this situation, whatever number or angle you're given, and the number diagonally across from it are supposed to add up to 180°.
(i think its called a cyclic quadrilateral, so do with that what you will.)
Find a polynomial $f(x)$ of degree $5$ such that both of these properties hold:
$\bullet$ $f(x)$ is divisible by $x^3$.
$\bullet$ $f(x)+2$ is divisible by $(x+1)^3$.
Write your answer in expanded form (that is, do not factor $f(x)$).
Answers
Answer:
Step-by-step explanation:
f(x)=ax³
ax³+2=b(x+1)³
ax³+2=b(x³+3x²+3x+1)
(a-b)x³-3bx²-3bx-b=0
question is in the image
Answers
From the information given, F(x) = 9.3319419 or approximately 9. This is problem relating to math functions
What is the calculation supporting the above answer?Recall that we are given x to be = 16.1
Hence,
[tex]f\left(x\right)=\ 2x^{\frac{1}{4}}\ +\ 3x^{\frac{1}{2}}[/tex] =
2 (16.1) ⁰°²⁵ + 3 (16.1)⁰°⁵
= 32.2⁰°²⁵ + 48.3⁰°⁵
= 2.3821218 +6.9498201
f(x) = 9.3319419
f(x) approximately 9
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9/16+7/8=
A.)1-3/16inches
B.)1-7/16inches
C.)1-11/16inches
D.)1/-13/16inches
Answers
Answer:
hey can you show me the pic because the question doesn't make any sense
A Ferris wheel with a diameter of 10 m and makes one complete revolution every 80
seconds. Assume that at time t = 0, the Ferris Wheel is at its lowest height above
the ground of 2 m. You will develop the equation of a cosine graph that models your
height, in metres, above the ground as you travel on the Ferris Wheel over time, t in
seconds. To do this, answer the following questions.
1. State the amplitude of the graph.
2. State the value of k in the general form y = a cos [k(x - d)] + c.
3. State the value of d.
4. State the value of c.
5. State the cosine equation of the graph.
Answers
The cosine equation of the attached graph is; y = 5 cos [( π/40)(x - (π/2))] + 3
How to plot a trigonometric graph?
The given parameters are:
Diameter = 10 m
Thus;
Radius; r = 5 m
Time; t = 80 s
Height above the ground, h = 2 m
The above means that:
Amplitude; A = 5 m
Period, T = 80 s
Minimum = 2 m
The cosine function is represented as:
y = a cos [k(x - d)] + c.
where;
A is amplitude
B is cycles from 0 to 2π
period = 2π/k
d is horizontal shift
c is vertical shift (displacement)
Thus;
2π/k = 80
k = 2π/80 = π/40
Where
c = Amplitude - Minimum
c = 5 - 2
c = 3
Shift to the left by π/2 gives;
d = π/2
Thus, the equation of the cosine graph is;
y = 5 cos [( π/40)(x - (π/2))] + 3
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A normal population has a mean u = 31 and standard deviation = 10. What proportion of the population is less than 30?
Answers
The proportion of the population exists less than 30 then
(x< 30) = 0.986.
How to estimate the proportion of the population that exists less than 30?To estimate the z-score using the formula, z = (x - µ)/σ
Where, x be the randomly chosen values = 30
µ be the mean = 31
σ be the standard deviation = 10
Proportion of the population that exists less than 18 = P(x < 30)
Plug in the values into z = (x - µ)/σ, to get z-score.
Substitute the values in the above equation, we get
z = (30 - 31)/10
z = -1/10 = -0.1
Therefore, the value of z = - 0.1.
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In the parallelogram below,
y = [? ]°
2
Z
1240
33%
Answers
Answer:
y = 33
Step-by-step explanation:
Angle y and 33 are alternate interior angles since the figure is a parallelogram and alternate interior angles are equal
y = 33
Answer:
y = 33°
Step-by-step explanation:
The diagonal of the parallelogram (a transversal) intersects two opposite and parallel sides of the parallelogram
Then
The angles of measures y° and 33° are Alternate interior angles
Then
they are congruent.
In other words , y = 33°
Please help fast please
Answers
Answer:
See image
Step-by-step explanation:
It cant be wrong
Find a formula for the nth term
of the arithmetic sequence.
First term 9
Common difference -2
Answers
Answer:
arithmetic sequence formula: first term + (n - 1)common difference
9 + (n - 1)-2
9 + -2n + 2
= -2n + 11
given,a= 9 and d= -2
nth term=a+(n-1)d
=9+(n-1)-2
=9-2n+2
=11-2n
Therefore nth term = 11-2n
. A school band sold 432 tickets for their upcoming spring concert. This represents about 85.5% of the number of tickets sold last year. How many tickets were sold last year? (Round to the nearest whole number)
Answers
original value multiplied by .855 will equate
to 432:
ticketstastyear * 0.855 = 132
Dividing each side by 0.855 results in the
amount of tickets sold last year:
ticketslastyear ~ 505.263
We round to the nearest whole number of
505.
The answer is 505
What is the simplest form of the expression below?
-2x²(3x²-2x-6)
Answers
Answer:
Solution Given:
To find the simplest form we need to open bracket
-2x²(3x²-2x-6)
-2x²*3x²-2x²*(-2x) -2x²*(-6)\
[tex]-6x^{4}+4x^{3}+12x^2[/tex] is a required answer.
Name the intersection of plane K and plane L.
Answers
Answer:
line NM
Step-by-step explanation:
Since planes extend infinitely in all directions, planes intersect at a line, not at a line segment.
Select the correct answer. The graph of function f is shown. An exponential function passes through (minus 4, 9), (0, 1), (1, 0), and (5, minus 2). Function g is represented by the table. x -1 0 1 2 3 4 g(x) 24 6 0 -2 Which statement correctly compares the two functions? A. They have different end behavior as x approaches -∞ and different end behavior as x approaches ∞. B. They have different end behavior as x approaches -∞ but the same end behavior as x approaches ∞. C. They have the same end behavior as x approaches -∞ and the same end behavior as x approaches ∞. D. They have the same end behavior as x approaches -∞ but different end behavior as x approaches ∞.
Answers
The answer choice which correctly draws a comparison between the end behaviours of the functions is; Choice C; They have the same end behavior as x approaches -∞ and same end behavior as x approaches ∞.
Which answer choice correctly compares the end behaviour of the functions?As given in the task content; the graph of the exponential function passes through (-4, 9), (0, 1), (1, 0), and (5, -2).
It therefore follows that as; x reduces (approaches -∞), the y value increases.
And, as x -increases (approaches +∞), the y-value decreases.
For the table, the values can be written as coordinates as follows; (-1,2), (0,4), (1,6), (2, 0), (3,-2).
Consequently, as x reduces (approaches -∞), the y- values decrease.
And, as x increases (approaches +∞), the y-values decrease.
Ultimately, the two functions in discuss can be concluded to have; Choice C.
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Find the standard form of the equation whose graph is the line through (1, -2) and (-5, 6).
Answers
The standard form of the equation whose graph is the line through (1, -2) and (-5, 6) is 3y = -4x -2.
According to the question,
The standard form of the equation whose graph is the line through (1, -2) and (-5, 6). Now first to find slope of the equation using below formula,
Slope of the equation (m)= (change in y axis) / (change in x axis)
= (6- (-2))/(-5 - 1)
= 8/-6
=-(4/3)
Slope of the equation (m) = -4/3. whose graph is the line through (1, -2) and (-5, 6).Formula to find Standard form of the equation is y = mx + c.
-2 = -(4/3) 1 + c
c = -2 +(4/3)
c = -2/3
The standard form of the equation whose graph is the line through (1, -2) and (-5, 6) is 3y = -4x -2. y = -(4/3)x -(2/3).
⇒ 3y = -4x -2.
Hence, the standard form of the equation whose graph is the line through (1, -2) and (-5, 6) is 3y = -4x -2.
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A large university has 24,000 students. A
randomly selected sample of 750 students
were surveyed and asked how far away
they live from the university. Of those
surveyed, 120 students live more than
500 miles away from the university.
Based on the survey results, estimate the
number of students who live within 500
miles of the university?
Answers
Answer:
23370 students live with in 500 miles of the university.
Step-by-step explanation:
large university students =24000
selected students = 750
surveyed students =120 lives far away from university.
students live with in 500mile=?
750-120=630
24000-630=23370
Why my foot keep makin cheese?!?!?!?
Answers
Answer:i am not sure
Step-by-step explanation:
This question is very hard to answer
Answer: I think your brain needs cheese but..............................................
Step-by-step explanation:
Don't know
Select the correct answer. which expression is equivalent to 2x√44-2√11x³, if x > 0? OA 2x√11x OB. 6x√22x OC. 21 O D. 8x²√11 Reset Nex
Answers
The equivalent expression of 2x√44x - 2√11x is 2x√11x
How to find equivalent expression?An equivalent expression can be find when simplified or factorised.
An expression is a combination of numbers, variables, functions (such as addition, subtraction, multiplication or division etc.)
In other words, an expression or algebraic expression is any mathematical statement which consists of numbers, variables and an arithmetic operation between them.
The expression equivalent to 2x√44x - 2√11x is as follows:
2x√44x - 2√11x
factorise
2x√44x - 2√11x = 2(x√44x - √11x³)
Hence,
2(x√44x - √11x) = 2(x√4 × 11x - √11x³)
2(x√4 × 11x - √11x) = 2(2x√11x - x√11x)
Therefore,
2(2x√11x - x√11x) = 4x√11x - 2x√11x
4x√11x - 2x√11x = 2x√11x
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Assume that adults have IQ scores that are normally distributed with a mean of 105 and a standard deviation 15. Find the probability that a randomly selected adult has an IQ less than 123.
The probability that a randomly selected adult has an IQ less than 123 is ____.
Answers
Answer:
.8849 or 88.49% have score ess than 123
Step-by-step explanation:
Answer:
88.49 % have less than 123 (or .8849)
Step-by-step explanation:
123 is 18/15 = 1.2 S.D. ABOVE the mean z-score +1.2
from z- score table +1.2 this is .8849 or 88.49 %
Find the difference between 0.84 and 17.1. (a) Give your answer as a mixed number in its simplest form. (b) Divide your answer by 9 and give your answer correct to 2 decimal places.
Answers
Answer:
in case you don't understand feel free to ask bye.
What are the rational roots for the polynomial shown below?
x³ + 5x²-8r-20=0
Answers
[tex]x ^{3} + 5x {}^{2} - 8 r - 20 = 0 \\ x { }^{3} + 5x {}^{2} - 8r - 20(x {}^{3} + 5x {}^{2} ) = 0 - (x {}^{3} + 5x {}^{2} ) \\ - 8r - 20 = - (x {}^{3} + 5x {}^{2} ) \\ \\ - 8r - 20 + 20 = - (x {}^{3 } + 5x {}^{2} ) + 20 \\ \\ - 8r = x {}^{3} - 5x {}^{2} + 20 \\ \\ [/tex]
hope it is helpful
A radar unit is used to measure speeds of cars on a miter way the speed are normally distributed with a mean of 90 km/hr and a standard deviation of 10 km/hr what is the probability that’s a car picked at random is traveling at more than 100 km/hr
Answers
Using the normal distribution, there is a 0.1587 = 15.87% probability that’s a car picked at random is traveling at more than 100 km/hr.
Normal Probability DistributionThe z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.The mean and the standard deviation are given, respectively, by:
[tex]\mu = 90, \sigma = 10[/tex]
The probability that’s a car picked at random is traveling at more than 100 km/hr is one subtracted by the p-value of Z when X = 100, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{100 - 90}{10}[/tex]
Z = 1
Z = 1 has a p-value of 0.8413.
1 - 0.8413 = 0.1587.
0.1587 = 15.87% probability that’s a car picked at random is traveling at more than 100 km/hr.
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Absolute value of sqrt(5) - 2.2
Answers
0.03607
Step-by-step explanation:Absolute value is the distance of a number from zero. Since distance is always positive, the absolute value is the same number but positive.
Please note, for this problem I have rounded to 5 decimal points because the answer is irrational.
Subtracting
There are 2 different ways to approach this problem. You can either estimate the square root of 5 or plug this question straight into a calculator.
First, we can estimate [tex]\sqrt{5}[/tex] and round to 5 decimal places.
[tex]\sqrt{5}[/tex] ≈ 2.23607Then, take this value and subtract.
2.23607 - 2.2 = 0.03607Absolute Value
Now that we have solved the subtraction problem we have to find the absolute value. As stated above, the easiest way to find absolute value is to simply make the number positive. Since the answer is already positive, this is the final answer.
|0.03607| = 0.03607What else would need to be congruent to show that ABC DEF by SAS? E AA. А B OA. BC = EF B. CF OC. ZA ZD D. AC = OF F Given: AC = DF CE F
Answers
The two triangles exist congruent if they contain two congruent corresponding sides and their contained angles exist congruent.
Let [tex]$&\overline{A B} \cong \overline{D E} \\[/tex] and [tex]$&\overline{A C} \cong \overline{D F}[/tex]
Angle between [tex]$\overline{A B}$[/tex] and [tex]$\overline{A C}$[/tex] exists [tex]$\angle A$[/tex].
Angle between [tex]$\overline{D E}$[/tex] and [tex]$\overline{D F}$[/tex] exists [tex]$\angle D$[/tex].
Therefore, [tex]$\triangle A B C \cong \triangle D E F$[/tex] by SAS, if [tex]$\angle A \cong \angle D$$[/tex].
What is SAS congruence property?Given:
[tex]$&\overline{A B} \cong \overline{D E} \\[/tex] and
[tex]$&\overline{A C} \cong \overline{D F}[/tex]
According to the SAS congruence property, two triangles exist congruent if they contain two congruent corresponding sides and their contained angles exist congruent.
Let [tex]$&\overline{A B} \cong \overline{D E} \\[/tex] and [tex]$&\overline{A C} \cong \overline{D F}[/tex]
Angle between [tex]$\overline{A B}$[/tex] and [tex]$\overline{A C}$[/tex] exists [tex]$\angle A$[/tex].
Angle between [tex]$\overline{D E}$[/tex] and [tex]$\overline{D F}$[/tex] exists [tex]$\angle D$[/tex].
Therefore, [tex]$\triangle A B C \cong \triangle D E F$[/tex] by SAS, if [tex]$\angle A \cong \angle D$$[/tex].
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On November 1, the company rented space to another tenant. A check in the amount of $9,000, representing three months rent in advance, was received from tenant on that date. The payment was recorded with a credit to the
Answers
The adjusting entry to registering the Rent revenue shall be as pursues:
Unearned Rent Revenue Debit $6,000
Rent Revenue Credit $6,000
(being the adjustment made for Rent Revenue earned)
How to complete the necessary adjusting entry for December 31 by selecting the account names and dollar amounts?Adjusting entry to record the Rent Revenue are as follows:
It exists shown that on November 1, the company rented space to another tenant. A check in the amount of $9,000, symbolizing three months' rent in advance, stood obtained from the tenant on that date. The payment stood registered with a credit to the unearned rent revenue account.
Now on December 31, we must organize the adjusting access to record the Rent Revenue for the period (Nov. 1 to Dec. 31) which exists for two months. The Rent Revenue for two months shall be
9000 [tex]*[/tex] 2/3 = $6,000
Therefore the adjusting entry to registering the Rent revenue shall be as pursues:
Unearned Rent Revenue Debit $6,000
Rent Revenue Credit $6,000
(being the adjustment made for Rent Revenue earned)
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The complete question is:
On November 1, the company rented space to another tenant. A check for $9,000, representing three months' rent in advance, was received from the tenant on that date. The payment was recorded with a credit to the unearned rent revenue account. Complete the necessary adjusting entry for December 31 by selecting the account names and dollar amounts from the drop-down menus.
