wo rectangular sheets of glass have equal perimeters. One has a length of 36 inches and a width w. The equation 2 (26+3) = 2(36+w) models the
elationship between the perimeters. What is the width in inches of the first sheet, w?

The correct option is:

c. y¹ = 3 + √(x - 7)

To find the inverse function of y = (x - 3)^2 + 7 for x > 3, we can follow these steps:

Step 1: Replace y with x and x with y in the given equation:

x = (y - 3)^2 + 7

Step 2: Solve the equation for y:

x - 7 = (y - 3)^2

√(x - 7) = y - 3

y - 3 = √(x - 7)

Step 3: Solve for y by adding 3 to both sides:

y = √(x - 7) + 3

So, the inverse function of y = (x - 3)^2 + 7 for x > 3 is y¹ = √(x - 7) + 3.

Therefore, the correct option is:

c. y¹ = 3 + √(x - 7)

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The correct answer is 32.

In an integer optimization problem with binary variables, each variable can take one of two possible values: 0 or 1. Therefore, for 5 binary variables, each variable can be assigned either 0 or 1, resulting in 2 possible choices for each variable. The maximum number of potential solutions in an integer optimization problem with 5 binary variables is 32 because each binary variable can take on 2 possible values (0 or 1)

In this case, we have 5 binary variables, so the maximum number of potential solutions is given by 2 * 2 * 2 * 2 * 2, which simplifies to 2^5. Calculating 2^5, we find that the maximum number of potential solutions is 32.

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        In this question, we need to calculate the proportion of sizes in 100   rolls, repeated 100 times.

        Then we can use the formula to calculate the interval containing the middle 95% of the data based on the data from the simulation.

         Finally, we can compare the observed proportion with the margin of error of the simulation results.

         P  =  20/100  =  0.2

       Mean  P and Standard Deviation:  √P(1 - P)/n  Where n is the sample size.

      √0.2(1 - 0.2)/100 = 0.04

        m  =  1.96 *  0.04/√100 = 0.008

        (0.2  -  m, 0.2 + m)  =  (0.192,  0.208)

       The interval containing the middle 95% of the data based on the data from the simulation is:  (0.192,  0.208 ), and the observed proportion is within the margin of error of the simulation results.

Hope it helps!

(a) f(x) = 2 for all x in R is a function from R to R.

(b) f(x) = √x is not a function from R to R because it is undefined for negative values of x.

(c) The set {(x, y) | x = y², x = 0} is not a function from R to R because it violates the vertical line test.

(d) The set {(x, y) | x = y³} is a function from R to R.

(a) The function f(x) = 2 for all x in R is a constant function. It assigns the value 2 to every real number x. Since there is a well-defined output for every input, it is a function from R to R.

(b) The function f(x) = √x represents the square root function. However, it is not defined for negative values of x because the square root of a negative number is not a real number. Therefore, it is not a function from R to R.

(c) The set {(x, y) | x = y², x = 0} represents a parabola opening upwards. For every y-coordinate, there are two corresponding x-coordinates, one positive and one negative, except at x = 0. This violates the vertical line test, which states that a function must have a unique output for each input. Therefore, this set is not a function from R to R.

(d) The set {(x, y) | x = y³} represents a cubic function. For every real number y, there is a unique corresponding x-coordinate, given by y³. This satisfies the definition of a function, as there is a well-defined output for each input. Thus, this set is a function from R to R.

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The population of a city was 101 thousand in 1992. The exponential growth rate was 1.8% per year. We need to find the exponential growth function in terms of t, where t is the number of years since 1992.So, the formula for exponential growth is given by;[tex]P(t)=P_0e^{rt}[/tex]

Where;P0 is the population at time t = 0r is the annual rate of growth/expansiont is the time passed since the start of the measurement period101 thousand can be represented in scientific notation as 101000.Using the above formula, we can write the population function as;[tex]P(t)=101000e^{0.018t}[/tex]

So, P(t) is the population of the city t years since 1992, where t > 0.P(t) will give the city population for a given year if t is equal to that year minus 1992. Example, To find the population of the city in 2012, t would be 2012 - 1992 = 20.P(20) = 101,000e^(0.018 * 20)P(20) = 145,868.63 Rounded to the nearest whole number, the population in 2012 was 145869. Therefore, the exponential growth function in terms of t, where t is the number of years since 1992 is given as:[tex]P(t)=101000e^{0.018t}[/tex]

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The percent decrease in Val's fund from last quarter to this quarter is 14.4%

To calculate the percent decrease in Val's mutual fund from last quarter to this quarter, we can use the following formula:

Percent Decrease = (Change in Value / Initial Value) * 100

Given that last quarter her fund was worth $37,500 and this quarter it is worth $32,100, we can calculate the change in value:

Change in Value = Initial Value - Final Value

= $37,500 - $32,100

= $5,400

Now we can plug these values into the formula for percent decrease:

Percent Decrease = (5,400 / 37,500) * 100

= 0.144 * 100

= 14.4%

Therefore, the percent decrease in Val's fund from last quarter to this quarter is 14.4%.

This means that the value of Val's mutual fund decreased by 14.4% over the given time period. It is important to note that this calculation assumes a simple percentage decrease based on the initial and final values and does not take into account any additional factors such as fees or dividends.

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The sum of 5500 mm, 720 cm, 90 dm, and 20 dam can be expressed in meters as 58.2 meters. To convert the given measurements to a common unit, we need to convert each unit to meters and then add them together.

1 meter is equal to 1000 millimeters (mm), 100 centimeters (cm), 10 decimeters (dm), and 0.1 decameters (dam).

Converting the given measurements to meters:

5500 mm = 5500/1000 = 5.5 meters

720 cm = 720/100 = 7.2 meters

90 dm = 90/10 = 9 meters

20 dam = 20 * 0.1 = 2 meters

Now, we can add these converted measurements together:

5.5 meters + 7.2 meters + 9 meters + 2 meters = 23.7 meters

Therefore, the sum of 5500 mm, 720 cm, 90 dm, and 20 dam in meters is 23.7 meters.

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(a) The 99% confidence interval for the selling price-list price difference is approximately -$16,636 to $9,889.

(b) This suggests that housing prices can vary significantly, with potential discounts or premiums compared to the listed price.

(a) Based on the provided data, the 99% confidence interval for the difference between the selling price and list price (selling price - list price) is approximately (-$16,636 to $9,889) rounded to the nearest dollar. This interval notation represents the range within which we can estimate the true difference to fall with 99% confidence.

(b) Interpreting the confidence interval in terms of the housing market, it means that we can be 99% confident that the actual difference between the selling price and list price of homes lies within the range of approximately -$16,636 to $9,889. This interval reflects the inherent variability in housing prices and the uncertainty associated with estimating the exact difference.

In the housing market, the confidence interval suggests that while the selling price can be lower than the list price by as much as $16,636, it can also exceed the list price by up to $9,889. This indicates that negotiations and market factors can influence the final selling price of a property. The wide range of the confidence interval highlights the potential variability and fluctuation in housing prices.

It is important for buyers and sellers to be aware of this uncertainty when pricing properties and engaging in real estate transactions. The confidence interval provides a statistical measure of the range within which the true difference between selling price and list price is likely to fall, helping stakeholders make informed decisions and consider the potential variation in housing market prices.

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Proved: a)sinxsin2x + cosxcos2x = cosx is true for all values of x.   b) cotx = sinxsin(π/2−x) + cos2xcotx is true for all values of x.    c)  2csc^2x = secx cscx is true for all values of x.

To prove a trigonometric identity, we need to manipulate the expressions using known identities until we obtain an equation that is true for all values of the variable.

1. To prove sinxsin2x + cosxcos2x = cosx:

We will use the identity sin(A + B) = sinAcosB + cosAsinB.

Let's apply this identity to the left-hand side of the equation:
sinxsin2x + cosxcos2x
= sinx(cosx + cos3x) + cosx(1 - 2sin^2x)
= sinxcosx + sinxcos3x + cosx - 2cosxsin^2x
= cosx(sinxcosx + sin3xcosx) + cosx - 2cosxsin^2x
= cosx(sinxcosx + sin3xcosx) - 2cosxsin^2x + cosx
= cosx(sinxcosx + sin3xcosx - 2sin^2x + 1)
= cosx[2sinxcosx + (1 - 2sin^2x)]
= cosx[2sinxcosx + cos^2x - sin^2x]
= cosx[cos^2x + 2sinxcosx - sin^2x]
= cosx[cos(2x) + 2sinxsin(2x)]
= cosx[cos(2x) + sin(2x)]
= cosxcos(2x) + cosxsin(2x)
= cosx.

Therefore, sinxsin2x + cosxcos2x = cosx is true for all values of x.

2. To prove cotx = sinxsin(π/2−x) + cos2xcotx:

We will use the identity cotx = cosx/sinx and the Pythagorean identity sin^2x + cos^2x = 1.

Let's manipulate the right-hand side of the equation:
sinxsin(π/2−x) + cos2xcotx
= sinxcosx/sinx + cos^2x(cosx/sinx)
= cosx + cos^3x/sinx
= cosx(1 + cos^2x/sinx)
= cosx(1 + cos^2x/(√(1 - sin^2x)))
= cosx(1 + cos^2x/√(1 - cos^2x))
= cosx(1 + cos^2x/√(sin^2x))
= cosx(1 + cos^2x/sinx)
= cosx(1 + cot^2x)
= cosx + cosx(cot^2x)
= cosx(1 + cot^2x)
= cotx.

Therefore, cotx = sinxsin(π/2−x) + cos2xcotx is true for all values of x.

3. To prove 2csc^2x = secx cscx:

We will use the identity cscx = 1/sinx and secx = 1/cosx.

Let's manipulate the left-hand side of the equation:
2csc^2x
= 2(1/sinx)^2
= 2/sin^2x
= 2/(1 - cos^2x)
= 2/(1 - cos^2x)/(1/cosx)
= 2cosx/(cos^2x - cos^4x)
= 2cosx/(cos^2x(1 - cos^2x))
= 2cosx/(cos^2xsin^2x)
= 2cosx/sin^2x
= 2cot^2x.

Therefore, 2csc^2x = secx cscx is true for all values of x.

In conclusion, we have proven the given trigonometric identities using known trigonometric identities and algebraic manipulation.

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The equation that represents the relationship between the number of hours worked (x) and the total amount earned (y) based on the given table is y = 5x + 17.50.

To write an equation relating the number of hours worked (x) and the total amount earned (y) based on the given table, we can use the method of linear regression. This involves finding the equation of a straight line that best fits the data points.

Let's assign x as the number of hours worked and y as the total amount earned. From the table, we have the following data points:

(x, y) = (5, 42.50), (10, 50), (15, 85), (20, 127.50), (25, 170)

We can calculate the equation using the least squares method to minimize the sum of the squared differences between the actual y-values and the predicted y-values on the line.

The equation of a straight line can be written as y = mx + b, where m represents the slope of the line and b represents the y-intercept.

By performing the linear regression calculations, we find that the equation relating the hours worked (x) and the total amount earned (y) is:

y = 5x + 17.50

Therefore, the equation that represents the relationship between the number of hours worked (x) and the total amount earned (y) based on the given table is y = 5x + 17.50.

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Differentiating w with respect to t using the chain rule we get -12xcost - 14ysint. When we evaluate dw/dt at t=π4 we get -13.

i. Differentiate w with respect to t using the chain rule.

Substitute x and y in the given function by their values and differentiate with respect to t.

We getdw/dt =dw/dx × dx/dt + dw/dy × dy/dt    (1)

The differentials are:

dx/dt = -sint ,

dy/dt = cost,

dw/dx = -12x, and

dw/dy = -14y

Substituting these values in equation (1), we get

dw/dt = -12xcost - 14ysint    (2)

ii. Differentiate w directly with respect to t

Express x and y in terms of t.

We get,

x = cost,

y = sint

Substituting these values in the given function we get:

w = -6cos^2t - 7sin^2t

Now, differentiating w with respect to t, we get

dw/dt = d/dt[-6cos^2t - 7sin^2t]dw/dt

= 12cos(t)sin(t) - 14cos(t)sin(t)dw/dt

= -2cos(t)sin(t).....(3)

iii. Evaluate dw/dt at t=π/4

Substituting π/4 in equation (2) we get:

dw/dt = -12×cos(π/4)×sin(π/4) - 14×sin(π/4)×cos(π/4)dw/dt

= -12(1/2)(1/2) - 14(1/2)(1/2)dw/dt

= -6-7dw/dt

= -13

Therefore, dw/dt at t=π/4 is -13.

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Answer:

[tex]54c^3+68c^2-72c[/tex]

Step-by-step explanation:

[tex]6c(9c^2+11c-12)+2c^2\\=(6c)(9c^2)+(6c)(11c)+(6c)(-12)+2c^2\\=54c^3+66c^2-72c+2c^2\\=54c^3+68c^2-72c[/tex]

The differential equations are:

1. `y(t) = (e^(0.5t)sin((sqrt(4r - 3)t)/2))/(sqrt(4r - 3))`

2. `x(t) = 1 - cos(t)`

3. `y(t) = 3te^(3t) - e^(3t) + (1/2)e^(15t)`

Here are the properly spaced solutions:

The Laplace transform of Y' is sY(s) - y(0). The Laplace transform of yr et is Y(s-r). Therefore, sY(s) - y(0) - Y(s-r) = 0. Solving this equation for Y(s), we get: Y(s) = (y(0))/(s-1) + (1)/(s-1+r). Substituting y(0) = 1 and rearranging the terms, we get: Y(s) = (s-1+r)/(s^2 - s - r) = (s - 0.5 + r - 0.5)/(s^2 - s - r). Using the inverse Laplace transform formula, we get: y(t) = (e^(0.5t)sin((sqrt(4r - 3)t)/2))/(sqrt(4r - 3)).

The Laplace transform of X'' is s^2 X(s) - sx(0) - x'(0). The Laplace transform of x(t) is X(s). Therefore, s^2 X(s) - x'(0) - X(s) = 4/(s^2 + 1). Substituting x'(0) = 1 and rearranging the terms, we get: X(s) = (s^2 + 1)/(s^3 + s). Using partial fraction decomposition, we can rewrite this as: X(s) = 1/s - 1/(s^2 + 1) + 1/s. Using the inverse Laplace transform formula, we get: x(t) = 1 - cos(t).

The Laplace transform of Y' is sY(s) - y(0). The Laplace transform of 6y' is 6sY(s) - 6y(0). The Laplace transform of 9y is 9Y(s). The Laplace transform of 6t e^(3t) is 6/(s-3)^2. Therefore, sY(s) - y(0) - (6sY(s) - 6y(0)) - 9Y(s) = 6/(s-3)^2. Simplifying this equation, we get: Y(s) = 6/(s-3)^2(s-15). Using partial fraction decomposition, we can rewrite this as: Y(s) = (1)/(s-3)^2 - (1)/(s-3) + (1)/(s-15). Using the inverse Laplace transform formula, we get: y(t) = 3te^(3t) - e^(3t) + (1/2)e^(15t).

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Answer:

The correct answer is:

||u|| = 18.439; θ = 130.601°

The magnitude of the vector u is 18.439 and its direction is 130.601°. These values come from the formulae for the magnitude and direction of a vector, given its initial and terminal points.

The initial and terminal points of vector u decide its magnitude and direction. The magnitude of the vector ||u|| can be calculated using the distance formula which is √[(x2-x1)²+(y2-y1)²]. The direction of the vector can be found using the inverse tangent or arctan(y/x), but there are adjustments required depending on the quadrant.

Given the initial point (4, 8) and terminal point (–12, 14), we derive the magnitude as √[(-12-4)²+(14-8)²] = 18.439, and the direction θ as atan ((14-8)/(-12-4)) = -49.399°. However, since the vector is in the second quadrant, we add 180° to the angle to get the actual direction, which becomes 130.601°. Therefore, ||u|| = 18.439; θ = 130.601°.

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Answer:

x = 6

Step-by-step explanation:

the 3 angles in a triangle sum to 180°

sum the 3 angles and equate to 180

7x + 8 + 102 + 28 = 180

7x + 138 = 180 ( subtract 138 from both sides )

7x = 42 ( divide both sides by 7 )

x = 6

The vector field F(x, y, z) is conservative. The potential function for the given vector field is Φ(x, y, z) = 2/3 x³ + 2/3 y³ - (x² + y²)z + C.

To show that a vector field is conservative, we need to check if its curl is zero. If the curl of the vector field is zero, it implies that the vector field can be expressed as the gradient of a scalar function, which is the potential.

Given the vector field:

F(x, y, z) = 2x²i + 2y²j - (x² + y²)k

To find the curl of this vector field, we can use the curl operator:

∇ x F = (∂F₃/∂y - ∂F₂/∂z)i + (∂F₁/∂z - ∂F₃/∂x)j + (∂F₂/∂x - ∂F₁/∂y)k

Computing the partial derivatives:

∂F₁/∂x = 4x

∂F₁/∂y = 0

∂F₁/∂z = 0

∂F₂/∂x = 0

∂F₂/∂y = 4y

∂F₂/∂z = 0

∂F₃/∂x = -2x

∂F₃/∂y = -2y

∂F₃/∂z = 0

Substituting these values into the curl expression, we have:

∇ x F = (0 - 0)i + (0 - 0)j + (0 - 0)k

= 0i + 0j + 0k

= 0

Since the curl of the vector field is zero, we can conclude that the vector field F(x, y, z) is conservative.

To find the potential function, we need to integrate the components of the vector field. Since the curl is zero, the potential function can be found by integrating any component of the vector field. Let's integrate the x-component:

∫ F₁ dx = ∫ 2x² dx = 2/3 x³ + C₁(y, z)

Where C₁(y, z) is the constant of integration with respect to y and z.

Similarly, integrating the y-component:

∫ F₂ dy = ∫ 2y² dy = 2/3 y³ + C₂(x, z)

Where C₂(x, z) is the constant of integration with respect to x and z.

Finally, integrating the z-component:

∫ F₃ dz = ∫ -(x² + y²) dz = -(x² + y²)z + C₃(x, y)

Where C₃(x, y) is the constant of integration with respect to x and y.

The potential function, Φ(x, y, z), can be obtained by combining these integrated components:

Φ(x, y, z) = 2/3 x³ + 2/3 y³ - (x² + y²)z + C

Where C is a constant of integration.

Therefore, the potential function for the given vector field is Φ(x, y, z) = 2/3 x³ + 2/3 y³ - (x² + y²)z + C.

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To calculate the mass of the load, we can use the equation W = m × g, where W is the weight, m is the mass, and g is the acceleration due to gravity. When we simplify this, we see that the burden weighs about 500 kg.

Given that the weight of the fully loaded lorry is 14700 N and the mass of the lorry is 500 kg, we can use these values to find the value of g.

Using the equation W = m × g, we can rearrange it to solve for g:

g = W / m

Substituting the given values, we have:

g = 14700 N / 500 kg

Calculating this, we find that g ≈ 29.4 m/s².

Now, to calculate the mass of the load, we can rearrange the equation W = m × g to solve for m:

m = W / g

Substituting the known values, we have:

m = 14700 N / 29.4 m/s²

Simplifying this, we find that the mass of the load is approximately 500 kg.

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Answer:

(g ￮ f)(x) = x² + 8x + 15

Step-by-step explanation:

to find (g ￮ f)(x) substitute x = f(x) into g(x)

(g ￮ f)(x)

= g(f(x))

= g(x + 4)

= (x + 4)² - 1 ← expand factor using FOIL

= x² + 8x + 16 - 1 ← collect like terms

= x² + 8x + 15

Answer:

(please be aware that the answers are not ordered in abc!)

a. a = 120

c. a = 210

e. a = 105

g. a = 225

b. a = 72

d. a = 49

f. a = 160

h. a = 288

Step-by-step explanation:

Since we are given a base and height on all of these triangles, the formula you can use to solve for the area (a) is [tex]a = \frac{1}{2} * h * b[/tex], where h = height and b = base.

Simply plug your height and base values into the formula and solve.

The given binary integer program represents a decision problem for selecting potential locations for new warehouses. The objective is to maximize the net present value, subject to several constraints. Let's analyze the program:

Objective:

Maximize 20x1 + 30x2 + 10x3 + 15x4

Decision Variables:

x1, x2, x3, x4 (binary variables representing the selection of each location)

Constraints:

Constraint 1: 5x1 + 7x2 + 12x3 + 11x4 ≤ 21

This constraint represents the limitation on the total budget/capital available for the new warehouses.

Constraint 2: x1 + x2 + x3 + x4 ≥ 2

This constraint ensures that at least two locations are selected for the new warehouses.

Constraint 3: x1 + x2 ≤ 1

This constraint limits the selection to a maximum of one location from the first two potential locations.

Constraint 4: x1 + x3 ≥ 1

This constraint ensures that at least one location is selected from the first and third potential locations.

Constraint 5: x2 = x4

This constraint imposes the condition that the selection of the second and fourth potential locations must be the same.

The binary variables x1, x2, x3, and x4 can take values of 0 or 1, indicating whether a particular location is selected or not.

The objective is to maximize the net present value of the decision while satisfying the budget constraint and the conditions for the number and specific locations of the warehouses. The values of x1, x2, x3, and x4 will determine the optimal selection of locations that maximize the objective function while meeting all the given constraints.

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They rode 15 miles before replacing each horse.

Let's assume that each rider rode a different number of horses, denoted as x, y, and z respectively. Since they used a total of 16 horses, we have the equation x + y + z = 16.

Since they rode the same number of miles on each horse, let's denote the distance traveled by each horse as d. Therefore, the total distance covered by all the horses can be calculated as 16d.

We are given that the three riders rode a total of 240 miles. Therefore, we have the equation xd + yd + z*d = 240.

From the given information, we have two equations:

x + y + z = 16 (Equation 1)

xd + yd + z*d = 240 (Equation 2)

Since we need to find the number of miles they rode before replacing each horse, we need to find the value of d. To solve this system of equations, we can substitute one variable in terms of the others.

Let's assume x = 16 - y - z. Substituting this into Equation 2, we get:

(16 - y - z)d + yd + z*d = 240

Simplifying, we have:

16d - yd - zd + yd + zd = 240

16d = 240

d = 240/16

d = 15

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The given system of equations is inconsistent and has no solution.

To solve the system of equations using augmented matrix methods, we can represent the system in matrix form as:

[tex]\left[\begin{array}{cc}1&2\\2&4\end{array}\right][/tex]  [tex]\left[\begin{array}{ccc}x_1\\x_2\end{array}\right][/tex]  = [tex]\left[\begin{array}{ccc}-4\\8\end{array}\right][/tex]

Augmented Matrix

We can write the augmented matrix as:

[tex]\left[\begin{array}{cc|c}1&2&4\\2&4&-8\end{array}\right][/tex]

Row Operations

We'll perform row operations to transform the augmented matrix into row-echelon form or reduced row-echelon form.

R2 = R2 - 2R1 (Multiply the first row by -2 and add it to the second row)

[tex]\left[\begin{array}{cc|c}1&2&4\\0&0&-16\end{array}\right][/tex]

Interpret the Result

From the row-echelon form of the augmented matrix, we can see that the second equation simplifies to 0 = -16, which is not a valid equation.

This implies that the system of equations is inconsistent and has no solution.

Therefore, the given system of equations:

x₁ + 2x₂ = 4

2x₁ + 4x₂ = -8

has no solution.

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The compositions between f(x) and g(x) are:

a. (f∘g)(x) = 6x - 9

b. (g∘g)(x) = 9x - 20

c. (f∘f)(x) = 4x + 3

d. (g∘f)(x) = 6x - 2

To get a composition of the form:

(g∘f)(x)

We just need to evaluate function g(x) in f(x), so we have:

(g∘f)(x) = g(f(x))

Here we have the functions:

f(x) = 2x + 1

g(x) = 3x - 5

a. (f∘g)(x)

To find (f∘g)(x), we first evaluate g(x) and then substitute it into f(x).

g(x) = 3x - 5

Substituting g(x) into f(x):

(f∘g)(x) = f(g(x))

= f(3x - 5)

= 2(3x - 5) + 1

= 6x - 10 + 1

= 6x - 9

Therefore, (f∘g)(x) = 6x - 9.

b. (g∘g)(x)

To find (g∘g)(x), we evaluate g(x) and substitute it into g(x) itself.

g(x) = 3x - 5

Substituting g(x) into g(x):

(g∘g)(x) = g(g(x))

= g(3x - 5)

= 3(3x - 5) - 5

= 9x - 15 - 5

= 9x - 20

Therefore, (g∘g)(x) = 9x - 20.

c. (f∘f)(x)

To find (f∘f)(x), we evaluate f(x) and substitute it into f(x) itself.

f(x) = 2x + 1

Substituting f(x) into f(x):

(f∘f)(x) = f(f(x))

= f(2x + 1)

= 2(2x + 1) + 1

= 4x + 2 + 1

= 4x + 3

Therefore, (f∘f)(x) = 4x + 3.

d. (g∘f)(x)

To find (g∘f)(x), we evaluate f(x) and substitute it into g(x).

f(x) = 2x + 1

Substituting f(x) into g(x):

(g∘f)(x) = g(f(x))

= g(2x + 1)

= 3(2x + 1) - 5

= 6x + 3 - 5

= 6x - 2

Therefore, (g∘f)(x) = 6x - 2.

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Answer: 0.86 or 86%

Step-by-step explanation:

To calculate the probability that a new insured with an unknown accident history will be accident-free in the second year of coverage, we can use conditional probability.

Let's define the following events:

A: Insured had no accidents last year

B: Insured is accident-free this year

Given information:

i) P(A) = 0.70 (probability that a new insured had no accidents last year)

ii) P(B | A) = 0.80 (probability that an insured who was accident-free last year will be accident-free this year)

iii) P(B | A') = 0.60 (probability that an insured who was not accident-free last year will be accident-free this year)

We want to find P(B), which is the probability that an insured is accident-free this year, regardless of their accident history last year.

We can use the law of total probability to calculate P(B):

P(B) = P(A) * P(B | A) + P(A') * P(B | A')

P(B) = 0.70 * 0.80 + (1 - 0.70) * 0.60

P(B) = 0.56 + 0.30

P(B) = 0.86

Therefore, the probability that a new insured with an unknown accident history will be accident-free in the second year of coverage is 0.86.

Based on the linear equation, y = 40 + 4x. the cost for 60 minutes is $260 since the fixed cost for the first 5 minutes or less is $40.

A linear equation represents an algebraic equation written in the form of y = mx + b.

A linear equation involves a constant and a first-order (linear) term, where m is the slope and b is the y-intercept.

The fixed cost for the first 5 minutes or less = 40

The cost for 30 minutes = 140

Slope = (140 - 40)/(30 - 5)

= 100/25

= 4

Let the total cost = y

Let the number of minutes after the first 5 minutes = x

y = 40 + 4x

The cost for 60 minutes:

The additional minutes of usage after the first 5 minutes = 55 (60 - 5)

y = 40 + 4(55)

y = 260

= $260

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Answer:

$408.73

Step-by-step explanation:

To determine how much more the SUV will be worth than the car five years after their model years, we first need to calculate how much the car is worth five years after its model year.

The value of the car (in dollars, x years from its model year) can be predicted by the function f(x):

[tex]f(x)= 12000(0.89)^x[/tex]

Therefore, to calculate how much the car will be worth five years after its model year, substitute x = 5 into the given function f(x):

[tex]\begin{aligned}x=5 \implies f(5)&=12000(0.89)^5\\&=12000(0.5584059449)\\&=6700.8713388\\&=6700.87\; \sf (nearest\;hundredth) \end{aligned}[/tex]

Therefore, the car will be worth $6,700.87 five years from its model year.

From observation of the given table, the SUV will be worth $7,109.60 five years from its model year.

To calculate how much more the SUV will be worth than the car five years from their model years, subtract the amount the car will be worth from the amount the SUV will be worth:

[tex]7109.60-6700.87=408.73[/tex]

Therefore, the SUV will be worth $408.73 more than the car five years after their model years.

Answer:

$408.73

Step-by-step explanation:

To determine how much more the SUV will be worth than the car five years after their model years, we first need to calculate how much the car is worth five years after its model year.

The value of the car (in dollars, x years from its model year) can be predicted by the function f(x):

Therefore, to calculate how much the car will be worth five years after its model year, substitute x = 5 into the given function f(x):

Therefore, the car will be worth $6,700.87 five years from its model year.

From observation of the given table, the SUV will be worth $7,109.60 five years from its model year.

To calculate how much more the SUV will be worth than the car five years from their model years, subtract the amount the car will be worth from the amount the SUV will be worth:

Therefore, the SUV will be worth $408.73 more than the car five years after their model years.

The expression is evaluated to -36

Algebraic expression are defined as mathematical expressions that are made up of terms, variables, constants, factors and coefficients.

These algebraic expressions are also composed of arithmetic operations. These operations are listed as;

From the information given, we have that;

3²2w+6 for when w = -5

substitute the values, we have;

3²(2(-5) + 6)

find the square and expand the bracket, we have;

9(-10 + 6)

add the values, we have;

9(-4)

expand the bracket, we get;

-36

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When w = -5, the value of the expression 3²2w+6 is -84.

To evaluate the expression 3²2w+6 when w = -5, we substitute -5 for w in the expression:

3²2(-5) + 6

First, we calculate the exponent:

3² = 3 * 3 = 9

Next, we multiply 9 by 2 and -5:

9 * 2(-5) + 6

Multiplying 2 by -5 gives us -10:

9 * (-10) + 6

Now we can perform the multiplication:

-90 + 6

Finally, we add -90 and 6:

-84

Therefore, when w = -5, the value of the expression 3²2w+6 is -84.

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Answer: 0.45, 45/100, 9/20, Any factors of the fractions.

Step-by-step explanation:

Answer:

c = 13.8

Step-by-step explanation:

[tex]c^2=a^2+b^2-2ab\cos C\\c^2=19^2+26^2-2(19)(26)\cos 31^\circ\\c^2=190.1187069\\c\approx13.8[/tex]

Therefore, the length of c is about 13.8 units

The parabola opens upward because the coefficient of the quadratic term is positive.

This part of the question concerns the quadratic function y = x² + 18x + 42.

To write the quadratic expression x² + 18x + 42 in completed-square form, we need to complete the square for the quadratic term.

We can do this by adding and subtracting the square of half the coefficient of the linear term.

Using the completed-square form from part (c)(i), we can solve the equation (x + 9)² - 39 = 0.

Therefore, the solutions to the equation x² + 18x + 42 = 0 are x = -9 + √39 and x = -9 - √39.

The vertex of the parabola y = x² + 18x + 42 is located at the value of x that corresponds to the minimum or maximum of the quadratic function.

In completed-square form, the vertex coordinates can be determined by taking the opposite of the constant term inside the parentheses.

To sketch the graph of the parabola y = x² + 18x + 42, we can plot the vertex (-9, -39) and draw a smooth curve passing through the vertex.

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