write a function update dict2(dict2, key1, key2, value), where dict2 is a two-level dictionary; key1 is the first-level key; key2 is the second-level key; and value is a value to be stored at dict2[key1][key2]. this function should modify dictionary dict2 so that the following holds: dict2[key1][key2]

This function can be used to modify a two-level dictionary by providing the first-level key (`key1`), the second-level key (`key2`), and the value (`value`) that should be stored at `dict2[key1][key2]`.

To write the function `update_dict2(dict2, key1, key2, value)`, we can follow these steps:
1.
```python
def update_dict2(dict2, key1, key2, value):
   if key1 in dict2:
       dict2[key1][key2] = value
   else:
       dict2[key1] = {key2: value}
```

2.

The function `update_dict2` takes four parameters: `dict2`, `key1`, `key2`, and `value`.

Inside the function, we first check if `key1` exists in `dict2` using the `in` operator. If `key1` is already a key in `dict2`, we update the value of `dict2[key1][key2]` to the provided `value`.

If `key1` is not a key in `dict2`, we create a new dictionary with `key2` as the key and `value` as the value, and assign it to `dict2[key1]`. This ensures that the structure of `dict2` is maintained, with `key1` as the first-level key and `key2` as the second-level key.

This function modifies `dict2` in-place, meaning the changes are made directly to the original dictionary.
```python
dict2 = {"a": {"x": 1, "y": 2}, "b": {"x": 3, "y": 4}}
key1 = "b"
key2 = "y"
value = 5

update_dict2(dict2, key1, key2, value)

print(dict2)
```

Output:
```python
{"a": {"x": 1, "y": 2}, "b": {"x": 3, "y": 5}}
```

In this example, we have an existing dictionary `dict2` with two first-level keys: "a" and "b". The second-level keys for both "a" and "b" are "x" and "y". We want to update the value of `dict2["b"]["y"]` to 5. After calling the `update_dict2` function, we can see that the value has been successfully updated in the dictionary.

This function can be used to modify a two-level dictionary by providing the first-level key (`key1`), the second-level key (`key2`), and the value (`value`) that should be stored at `dict2[key1][key2]`.

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The complete question is,

CSc 120: Update a 2-level dictionary Definitions A two-level dictionary is analogous to a list-of-lists (aka "2D-list), except that it involves dictionaries rather than lists: . Alist-of-lists L is a list where each element L[ someidx) is itself a list; and LIaomeidx) anotheridx] gives us a value stored in L . Analogously, a two-level dictionary D is a dictionary-of-dictionaries: D[ somekey] is itself a dictionary, and DI somekey]Ianotherkey] gives us a value stored in the two-level dictionary D. In this example, somekey is called the first-leve key and anotherkey is called the second-level key. In the examples below, DD is assumed to be the following two-level dictionary: bbb' Cstring4, ddd string5 ece 'string6, 'Estring'. ccc· { .aaa . ; .string 8., .bbb. ; .string9. } Thus, we have: DD bbb' cec' is the value string4', while DD ccbbb' is string9 Expected Behavior Write a function update dict2(dict2, keyl, key2, value), where diet2 is a two-level dictionary: key1 is the first-level key: key2 is the second-level key: and value is a value to be stored at dict2[key1key21. This function should return a dictionary obtained by updating dict2 such that in the resulting dictionary, which we refer to as newdictz, the following holds newdict2[ key1keyz- value. Examples DD is the two-level dictionary shown above (under Definitions) 1. update dict2 (DD, 'aaa,'cce,12) return value: 2. update_dict2 (DD, 'aaa', 9g,string17) return value: 3. update dict2(DD, 'ggg', 'aaa, 'string17") return value:

5. Given that \( n=32, w=2,1 \) word \( =1 \) byte, and cache size \( =512 \) Bytes. Determine: a) Memory capacity b) Total number of blocks in memory c) Number of cache lines