(x+ 3/8 ​ ) 2 + y 2 =1
what is the radius & units?

Answers

Answer 1

The radius of the circle of the circle equation (x + 3/8)^2 + y^2 = 1 is 1 unit

How to determine the radius of the circle?

The circle equation of the graph is given as:

(x + 3/8)^2 + y^2 = 1

The general equation of a circle is represented using the following formula

(x - a)^2 + (y - b)^2 = r^2

Where the center of the circle is represented by the vertex (a, b) and the radius of the circle is represented by r

By comparing the equations (x - a)^2 + (y - b)^2 = r^2 and (x + 3/8)^2 + y^2 = 1, we have the following comparison

(x - a)^2 = (x + 3/8)^2

(y - b)^2 = y^2

1 = r^2

Rewrite the last equation as follows:

r^2= 1

Take the square root of both sides of the equation

√r^2 = √1

Evaluate the square root of 1

√r^2 = 1

Evaluate the square root of r^2

r = 1

Hence, the radius of the circle of the circle equation (x + 3/8)^2 + y^2 = 1 is 1 unit

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Related Questions

Which is a true statement about the function f(x)= 8x^3

Answers

Answer:

The function is odd because f(-x) = -f(x)

Step-by-step explanation:

[tex]f(x)=8x^3[/tex]
[tex]f(-x)=8(-x)^3[/tex]
[tex]f(-x)=-8x^3[/tex]
[tex]-f(x)=-(8x^3)[/tex]
[tex]-f(x)=-8x^3=f(-x)[/tex]
[tex]f(-x)=-f(x)[/tex], therefore the function is odd

The function is odd because f(-x)=-f(x).

What is a function?

A relation is a function if it has only One y-value for each x-value.

The given function is f(x)=8x³.

We need to find which statement would be true in the given options.

Let us find this by taking x as -x.

f(-x)=8(-x)³

We know that when a negative sign is multiplied three times we get negative sign.

f(-x)=-8x³

-f(x)=-(8x³)

-f(x)=-8x³=f(-x)

f(-x)=-f(x)

By the definition of odd function f(-x)=-f(x).

Hence, the function is odd because f(-x)=-f(x).

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1. You have learned several techniques for solving quadratic equations. Create an equation that would be best for each technique listed below. Then explain why that technique would be best for each equation that you created.
2.What is the discriminant and what happens if you are solving and the discriminant turns out to be negative?

Answers

The  techniques that can be used to best explain for each equation that I have created are:

What are the techniques?

A)  For  graphing -  This is often used in checking if your answer is correct, if the math is known to be a little tedious, graphing is recommended

(b) For factoring:  x^2 -3x +4 '

Where: (x-4)(x+1)=0

Then x=-1, 4

(c) For  square root method:   x^2 = 64

Therefore x = + or - [tex]-\sqrt{64}[/tex] = + or - 8

(d) For  completing the square:  x^2 + 4x = 11 and x^2 +4x + 4

Note that:  x^2 +4x + 4

= x^2 + 4x = -4

= x^2 +4x + 4 = -4 + 4

= (x+2)^2 = 0

So, x = -2

(e) For quadratic formula: 6x² + 7x -19 =0  

x= [-b + or - sqr(b² - 4ac)]/2a

Note that b=7

a=6

c=-19

Therefore

x= [-7+ or - sqr(49+4(6)(9)]/2

2.  if the discriminant is said to be negative,   then the equation is one that is made up of two imaginary or complex solutions.

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See full question below

You have learned several techniques for solving quadratic equations. Create an equation that would be best for each technique listed below. Then explain why that technique would be best for each equation that you created.

a. graphing

b. factoring

c. square root method

d. completing the square

e. quadratic formula

2. What is the discriminant and what happens if you are solving and the discriminant turns out to be negative?

Una química tiene 3 soluciones acidas de varias concentraciones. La primera es 10% acida; la segunda 20% y la tercera 40%. ¿Cuántos mililitros de cada una debe ella usar para hacer 100ml de una solución al 18%, si tiene que usar cuatro veces mas de la solución al 10% que de la solución al 40%?

Answers

Based on the percentage of the first, second, and third acids, the milliliters of each acid that should be used to make 100 ml of 18% are:

10% acid  = 40 ml20% acid = 50 ml40% acid = 10 ml

What concentrations are needed to make the solution?

Assuming the concentration of the 40% acid is denoted as x, the other acid concentrations would be:

10% acid = 4x

20% = 100 - 5x

The target solution is 100ml of 18%.

Solving gives:

(10% × 4x) + (20% × (100 - 5x)) + (40% × x) = 18% x 100

(80% × x) + 20 - x = 18

(80x - 100x) / 100 = 18 - 20

-20x / 100 = -2

20x = 200

x = 200 / 20

x = 10 ml

The 10% solution:

= 10 x 4

= 40 ml

20% acid:

= 100 - (5 x 10)

= 50 ml

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Find the future value and interest earned if $8704.56 is invested for 8 years at 4% compounded (a) semiannually and (b) continuously.
intorntic compounded semiannually is approximately

Answers

a) The future value, principal plus interest, with compound interest on a principal of $8,704.56 at a rate of 4% per year compounded 2 times per year over 8 years is $11,949.50.

b) The future value, principal plus interest, with compound interest on a principal of $8,704.56 at a rate of 4% per year compounded continuously over 8 years is $11,987.29.

How is the future value determined?

The future value can be determined using an online finance calculator.

Data and Calculations:

a) Compounded Semiannually:

Principal (P): $8,704.56

Annual Rate (R): 4%

Compound (n): Compounding Semi-Annually

Time (t in years): 8 years

Result:

A = $11,949.50

A = P + I where

P (principal) = $8,704.56

I (interest) = $3,244.94

Calculation Steps:

First, convert R as a percent to r as a decimal

r = R/100

r = 4/100

r = 0.04 rate per year,

Then solve the equation for A

A = P(1 + r/n)nt

A = 8,704.56(1 + 0.04/2)(2)(8)

A = 8,704.56(1 + 0.02)(16)

A = $11,949.50

b) Compounded Continuously:

Using the formula A = Pert

Principal (P):  $8,704.56

Annual Rate (R): 4%

Compound (n): Compounding Continuously

Time (t in years):   8 years

Result:

A = $11,987.29

A = P + I where

P (principal) = $8,704.56

I (interest) = $3,282.73

Calculation Steps:

First, convert R as a percent to r as a decimal

r = R/100

r = 4/100

r = 0.04 rate per year,

Then solve the equation for A, using the mathematical constant, e = 2.71828

A = Pert

A = 8,704.56(2.71828)(0.04)(8)

A = $11,987.29

Thus, while the future value of $8,704.56 at a rate of 4% per year compounded semiannually over 8 years is $11,949.50,  the future value of $8,704.56 at a rate of 4% per year compounded continuously over 8 years is $11,987.29.

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Use the normalcdf function on a calculator to find the probability that battery life is 20 ± 2 hours (between 18 and 22 hours) for each phone.


Prior values (If needed)
.159
.50

Answers

The probability that the battery life is  20 ± 2 hours (between 18 and 22 hours) for each of the phones is:

Phone C = 15.9%Phone T = 50%

What is the probability of the battery life?

Using the normalcdf function on a calculator, the probability that Phone C's battery would last between 18 and 22 hours can be found by inputing the function:

normalcdf (20, IE99, 18, 2)

The result is 0.158655 or 15.9%.

For Phone T, the function is:

normalcdf (20, IE99, 20, 3)

The result is 0.5 or 50%.

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Identify what a, b, and c would equal in standard form.
Do not simplify the equation.
-14y= 28-10x

a=
b=
C=

Answers

Answer:

below

Step-by-step explanation:

-14y = 28 - 10x

10x - 14y - 28 = 0.

a = 10

b = -14

c = -28

Answer:

a = 10

b = -14

c = 28

Step-by-step explanation:

Goal form: Standard form

ax + by = c

Given form: linear form (not fully simplified)

-14y = 28 - 10x

Add 10x on both sides (to move the x-value to the left-hand side of the equation)

-14y + 10x = 28 - 10x + 10x

-14y + 10x = 28

10x - 14y = 28

Determine [ a ], [ b ], [ c ]

ax + by = c

10x - 14y = 28

[tex]\Large\boxed{a=10}[/tex]

[tex]\Large\boxed{b=-14}[/tex]

[tex]\Large\boxed{c=28}[/tex]

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Working together a small pipe and large pipe can fill a big pool in 6 hour. It takes the smaller pipe 5 hours longer than the large pipe to fill the big pool working alone. How long does it take the smaller pipe to fill the pool by itself ?

Answers

The time taken for the smaller pipe to fill the pool by itself is 15.71 hours

Rate of work

Time taken for both pipes = 6 hoursTime taken for long pipe = xTime taken for small pipe = x + 6

Rate of work of both pipes = 1/6Rate of work of long pipe = 1/xRate of work of small pipe = 1/x + 6

1/6 = 1/x + 1/(x+6)

1/6 = (x+6)+(x) / (x)(x+6)

1/6 = (x+6+x) / x²+6x

1/6 = (2x+6)(x² + 6x)

cross product

1(x² + 6x) = 6(2x+6)

x² + 6x = 12x + 36

x² + 6x - 12x - 36 = 0

x² - 6x - 36 = 0

Using quadratic formula

x = 9.71 or -3.71

The value of x cannot be negative

Therefore, the

Time taken for long pipe = x

= 9.71 hours

Time taken for small pipe = x + 6

= 9.71 + 6

= 15.71 hours

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elsa sold 24 drawings for $12 each at the art fair. She is going to use 1/3 of the money to buy books. The rest of the money is going into her savings account. How much money will she put into her savings account?

Answers

$192

If we multiply the 24 drawing by $12 for each drawing we get $288, the total she made at the art fair. By multiplying this total by 1/3, we get $96 which is the amount she spent on books. If we subtract the $96 spent from the $288 she made, we get $192, the amount she put into her savings account.

24 * $12 = $288
$288 * 1/3 = $96
$288 - $96 = $192

If 1/2x = a= 2/3y and x + y= na, what is the value of n?

Answers

Answer:

Step-by-step explanation:

[tex]\frac{1}{2} x=a=\frac{2}{3} y\\\frac{1}{2}x=a\\x=2a \\\frac{2}{3} y=a\\y=\frac{3}{2} a\\x+y=2a+\frac{3}{2} a=\frac{4a+3a}{2} =\frac{7}{2} a=na\\n=\frac{7}{2}[/tex]

"Solve the following first order differential equation for x(t):


x'=-9tx"


How do I do this?

Answers

I'm not sure if the last two apostrophes are part of the quote - "Solve ... " - or if you mean the second derivative [tex]x''[/tex]. I think you mean the first interpretation, but I'll include both cases since they are both solvable.

If the former is correct, separate variables to solve.

[tex]x' = -9tx \implies \dfrac{dx}{dt} = -9tx \implies \dfrac{dx}x = -9t\,dt[/tex]

Integrate both sides to get

[tex]\ln|x| = -\dfrac92 t^2 + C[/tex]

Solve for [tex]x[/tex].

[tex]e^{\ln|x|} = e^{-9/2\,t^2 + C} \implies \boxed{x = Ce^{-9/2\,t^2}}[/tex]

If you meant the latter, then the ODE can be rewritten as

[tex]9t x'' + x' = 0[/tex]

Reduce the order of the equation by substituting [tex]y(t) = x'(t)[/tex] and [tex]y'(t) = x''(t)[/tex].

[tex]9t y' + y = 0[/tex]

Solve for [tex]y'[/tex] and separate variables.

[tex]y' = -\dfrac y{9t} \implies \dfrac{dy}{dt} = -\dfrac y{9t} \implies \dfrac{dy}y = -\dfrac{dt}{9t}[/tex]

Integrate.

[tex]\ln|y| = -\dfrac19 \ln|t| + C[/tex]

Solve for [tex]y[/tex].

[tex]e^{\ln|y|} = e^{-1/9 \,\ln|t| + C} \implies y = Ct^{-1/9}[/tex]

Solve for [tex]x[/tex] by integrating.

[tex]x' = Ct^{-1/9} \implies x = C_1 t^{8/9} + C_2[/tex]

if 6m of a uniform iron rod weighs 21 kg what will be the weight of 16 m of the same rod?​

Answers

Answer:

56kg

Step-by-step explanation:

If 6m of a rod is 21 kg, then 21/6 will give us the weight of 1m of the rod. 21/6 = 3.5 kg

16*3.5 = 56 kg

what is 4,928 will rounded to the nearest hundred​

Answers

Answer:

4900

Step-by-step explanation:

When rounding a number such as 4928 to the nearest hundred, we use the following rules:

A) We round the number up to the nearest hundred if the last two digits in the number are 50 or above.

B) We round the number down to the nearest hundred if the last two digits in the number are 49 or below.

C) If the last two digits are 00, then we do not have to do any rounding, because it is already to the hundred.

In this case, Rule B applies and 4928 rounded to the nearest hundred is:

4900

Answer:

Step-by-step explanation:

4,928, look at the last two numbers 28 if they are above 50 you round up, if below 50 round down,

The answer is 4,900

Instructions: Identify the vertices of the feasible region for the given linear programming constraints.

Optimization Equation:
z=−3x+5y

Constraints:
x+y≥−2
3x−y≤2
x−y≥−4

Fill in the vertices of the feasible region:

(0, )
(−3, )
(3, )

Answers

The vertices of the feasible region are (0, -2), (-3, 1) and (3, 7)

How to identify the vertices of the feasible region for the given linear programming constraints?

The optimization equation is given as

z=−3x+5y

The constraints are given as:

x+y≥−2

3x−y≤2

x−y≥−4

Next, we plot the constraints on a graph and determine the points of intersections

See attachment for the graph


From the attached graph, the points of intersections are

(-3, 1), (3, 7) and (0, -2)

So, we have:

(0, -2)

(-3, 1)

(3, 7)

Hence, the vertices of the feasible region are (0, -2), (-3, 1) and (3, 7)

So, the complete parameters are:

Optimization Equation:

z=−3x+5y

Constraints:

x+y≥−2

3x−y≤2

x−y≥−4

Vertices of the feasible region

(0, -2)

(-3, 1)

(3, 7)

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Find the value of x.

Answers

Answer:

x = 52

Step-by-step explanation:

Since the inscribed angle measures 64 degrees, the minor arc is 64*2 = 128 degrees. Therefore the major arc is 180-128 = 232 degrees. Angle X is the difference of major and minor arc divided by 2, so X = (232-128)/2 = 52 degrees.

What number is six and four hundredths larger than two and five tenths?

Answers

Answer:

eight and thirty-seven fiftyths

Step-by-step explanation:

6 and 4/100 + 2 and 5/10

6 and 1/25 + 2 and 1/2

156 / 25 + 5 / 2

312 / 50 + 125 / 50

437 / 50

400 / 50 = 8

8 and 37 / 50

if a rectangular piece of metal has 27.75 square inches what is the length and width?

Answers

We cannot get further information about the dimensions of the piece since the number of variables is greater than the number of equations.

What are the dimensions of a rectangular piece of metal?

By geometry we know that the area of the piece of metal is equal to the product of its length and width, then we must find two real numbers such that:

l · w = 27.75, where l, w > 0.

Unfortunately, we cannot get further information about the dimensions of the piece since the number of variables is greater than the number of equations. We need at least one equation to find an unique solution.

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Evaluate The quantity of x cubed plus 3x squared minus 2x plus 7 divided by the quantity of x minus 2 end quantity period.

1. x squared minus 5x plus 2 plus 23 divided by the quantity of x minus 2
2.x cubed plus 5x plus 8 plus 11 divided by the quantity of x minus 2 end quantity
3.x squared minus 5x plus 6 plus 3 divided by the quantity of x minus 2 end quantity 4. x squared plus 5x plus 8 plus 23 divided by the quantity of x minus 2 end quantity

Answers

The value of x^3 + 3x^2 - 2x + 7 divided by x- 2 is (x^2 + 5x + 8) + 23/(x - 2)

What is a quotient?

Quotients involve the result of dividing a dividend by a divisor.

In other words, quotient means division or the result of a division operation

How to solve the quotient?

The quotient expression is given as:

(x^3 + 3x^2 - 2x + 7)/x- 2

Expand the numerator in the above expression

(x^3 + 5x^2 - 2x^2 + 8x - 10x - 16 + 23)/(x - 2)

Rearrange the terms of the numerator in the above expression

(x^3 + 5x^2 + 8x - 2x^2 - 10x - 16 + 23)/(x- 2)

Factorize the numerator in the above expression

[x(x^2 + 5x + 8) - 2(x^2 + 5x + 8) + 23]/(x - 2)


Factor out x^2 + 5x + 8

[(x -2)(x^2 + 5x + 8) + 23]/(x - 2)

Split the fractions

(x -2)(x^2 + 5x + 8)/(x - 2) + 23/(x - 2)

Divide the common factors

(x^2 + 5x + 8) + 23/(x - 2)

Hence, the value of x^3 + 3x^2 - 2x + 7 divided by x- 2 is (x^2 + 5x + 8) + 23/(x - 2)

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Complete question

Evaluate (x^3 + 3x^2 - 2x + 7)/x- 2

Answer:

4 / D | x^2 + 5x + 8 + 23/x - 2

Step-by-step explanation:

The correct answer is D because when you divide & simplify the original question's equation, you get the results that are equivalent to answer D.


Select the correct answer.
What is the equation of the line that has a slope of 3 and goes through the point (-3,-5)?
OA.
y=3x+4
OB. y=3x-14
OC. y=3x-4
OD. y=3x + 12

Answers

Answer: [tex]\Large\boxed{A.~y=3x+4}[/tex]

Step-by-step explanation:

Given information

Slope = 3

Point = (-3, -5)

Given the format of the equation

Slope-intercept form: y = mx + b

m = Slopeb = y-intercept

Substitute values into the equation

y = (3)x + b

y = 3x + b

Substitute the given point into the equation to get the value of [ b ]

(-5) = 3(-3) + b

-5 = -9 + b

b = -5 + 9

b = 4

Therefore, the equation of the line is [tex]\Large\boxed{y=3x+4}[/tex]

Hope this helps!! :)

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Answers

[tex]x^3[/tex] is strictly increasing on [0, 5], so

[tex]\max\{x^3 \mid 0\le x\le5\} = 5^3 = 125[/tex]

and

[tex]\min\{x^3 \mid 0 \le x\le5\} = 0^3 = 0[/tex]

so the integral is bounded between

[tex]\displaystyle \boxed{0} \le \int_0^5x^3\,dx \le \boxed{125}[/tex]

Ellen read a book a day for 10 weeks. How many books did
she read in all?

Answers

1 week = 7 days

10 weeks = 10×7 days

= 70 days

if Ellen reads 1 book in a day

Therefore,

1 day = 1 book

70 days = 70×1

= 70 books.

Thus Ellen reads 70 books in 10 weeks.

Hope helps

Answer:

70 books

Step-by-step explanation:

Ellen reads one book per day for 10 weeks.

All we need to do to know the number of books Ellen read overall is to multiply 1 (number of books he read each day) and 10 weeks (total number of days).

Each week is 7 days, so 10 weeks is equal to 70 days.

The equation will be: 1 x 70

We can conclude that Ellen read 70 books overall within 10 weeks.

NO LINKS!! Please help me with this problem​

Answers

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

The given figure shows a vertical hyperbola with its centre at origin, and as we observe the figure, we can conclude that :

Length of transverse axis is :

[tex]\qquad \sf  \dashrightarrow \: 2b = 12[/tex]

[tex]\qquad \sf  \dashrightarrow \: b = 6[/tex]

length of conjugate axis is :

[tex]\qquad \sf  \dashrightarrow \: 2a = 8[/tex]

[tex]\qquad \sf  \dashrightarrow \: a = 4[/tex]

Equation of hyperbola ~

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {y}^{2} }{ {b}^{2} } - \cfrac{ {x}^{2} }{ {a}^{2} } = 1[/tex]

plug in the values ~

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {y}^{2} }{ {6}^{2} } - \cfrac{ {x}^{2} }{ {4}^{2} } = 1[/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {y}^{2} }{ {36}^{} } - \cfrac{ {x}^{2} }{ {16}^{} } = 1[/tex]

Answer:

[tex]\dfrac{y^2}{36}-\dfrac{x^2}{16}=1[/tex]

Step-by-step explanation:

Standard form equation of a vertical hyperbola

[tex]\dfrac{(y-k)^2}{a^2}-\dfrac{(x-h)^2}{b^2}=1[/tex]

where:

center = (h, k)vertices = (h, k±a)co-vertices = (h±b, k)foci = (h, k±c) where c² = a² + b²[tex]\textsf{asymptotes}: \quad y =k \pm \left(\dfrac{a}{b}\right)(x-h)[/tex]Transverse axis: x = hConjugate axis: y = k

From inspection of the graph:

center = (0, 0)  ⇒ h = 0, k = 0vertices = (0, 6) and (0, -6)  ⇒  a = 6co-vertices = (4, 0) and (-4, 0)  ⇒  b = 4

Substitute the found values into the formula:

[tex]\implies \dfrac{(y-0)^2}{6^2}-\dfrac{(x-0)^2}{4^2}=1[/tex]

[tex]\implies \dfrac{y^2}{36}-\dfrac{x^2}{16}=1[/tex]

CAN SOMEONE HELP PLEASE!

Answers

Answer:

None of these

Step-by-step explanation:

[tex]\frac{360}{n}=24 \implies n=15[/tex]

This is called a pentadecagon.

Zoe is shopping for a new car and has to make some decisions. The model she’s chosen comes in two versions, hybrid and electric. For the exterior, she can choose red, blue, or green. For the interior, she can choose fabric, leather, or vinyl.

If Zoe randomly chooses from the options, the probability that Zoe picks a blue hybrid car with an interior that is not leather is
.

If Zoe randomly chooses from the options, the probability of Zoe picking an electric car in a color other than blue is

Answers

a) The probability is P = 1/9

b) The probability is P = 1/3.

How to get the probability?

First, we need to count the total number of outcomes (different cars that can be made with the given options):

There are 2 versions (electric and hybrid).There are 3 exterior colors (red, blue, green).There are 3 interiors (fabric, leather, vinyl)

Then there are 2*3*3 = 18 different cars.

a) Picking a blue hybrid car with an interior that is not leather.

There are 2 cars that meet that condition:

blue hybrid with fabric.blue hybrid with vinyl.

2 out of the 18 cars meet the condition, then the probability is:

P = 2/18 = 1/9

b) picking an electric car in a color other than blue is

The cars that meet the condition are:

Green electric with any interior (3 options here)Red electric with any interior (3 options here)

So 6 out of the 18 cars meet the condition, then the probability is:

P = 6/18 = 1/3

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Find the gradient of the line passing through the points (– 2,– 4) and (3,5).

Answers

Answer is 9/5
You can count the rise/run on the graph or use slope formula (y2-y1) over (x2 -x1)

5-(-4) over 3-(-2) = 9/5

Answer:

Gradient of the line is choice D.9/5

Step-by-step explanation:

Hello!

Slope between two points:slope=(y-y)/(x-x)

(x.y)=(-2,-4)(x.y)=(3,5)

slope(m)=

[tex] \frac{5 - ( - 4)}{3 - ( - 2)} \\ refine \: (m )= \frac{9}{5} [/tex]

Anthony travels from Newcastle to Manchester at an average speed of 65 miles per hour.
The journey takes him 2 hours and 15 minutes.
Declan makes the same journey in 2 hours and 35 minutes.
(a) Work out Declan's average speed for the journey.

Answers

Answer:

See below

Step-by-step explanation:

Distance = rate * time

              = 65 m/hr * 2 1/4 hr = 146.25 miles

rate = distance / time

for Declan :   rate =  146.25 miles / (2 hrs + 35/60 min) = 56.61 mph

can someone please help me

Answers

The formula that shows the relationship between the distance, rate and time is t = d/r and t = 5.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depend on any other variable for its value while a dependent variable is a variable that depends on other variable.

Given that:

d = rt

Hence:

t = d/r

For d = 40, r = 8:

t = 40 / 8

t = 5

The formula that shows the relationship between the distance, rate and time is t = d/r and t = 5.

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What value of b will cause the system to have an infinite number of solutions y=6x+b
-3x+1/2y=-3
A-(-6)
B(-3)
C(3)
D(6)

Answers

Answer: -6

Step-by-step explanation:

[tex]-3x+\frac{1}{2}y=-3\\\\\frac{1}{2}y=3x-3\\\\y=6x-6[/tex]

For there to be infinite solutions, b = -6.

the cost of living is 230% of what it was 10 years ago. what mixed number is this?

Answers

Answer:

Step-by-step explanation:

23

Questions are in the pictures

Answers

The revenue function in terms of q will be 200q - 3q².

How to calculate the revenue?

The following can be deduced based on the information given:

P(q) = 200 - 3q

C(q) = 75 + 80q - q²

The revenue function in terms of q will be:

= Price × Quantity

= (200 - 3q) × q

= 200q - 3q²

The profit will be:

= Total revenue - Total cost

= (200q - 3q²) - (75 + 80q - q²)

= 200q - 3q² - 75 + 80q + q²

= -2q² + 280q - 75

= 2q² - 280q + 75

The average cost function will be:

= Total cost / Quantity

= (75 + 80q - q²) / q

= 75/q + 80 - q

The marginal cost will be 80 - 2q.

The marginal revenue will be 200 - 6q.

The marginal cost when q = 20 will be:

= 80 - 2q

= 80 - 2(20)

= 80 - 40

= 40

The marginal revenue when q = 20 will be:

= 200 - 6q

= 200 - 6(20)

= 200 - 120

= 80

The company should decrease production from 20 units in order to gain more profit.

The production level that gives the largest profit for the company will be gotten by finding the second derivative for the profit function as illustrated in the question. The profit function is 2q² - 280q. Then the production level will be 4.

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If f(x) = -5^x - 4 and g(x) = -3x - 2, find (f - g) (x).

Answers

Answer:

-5^x + 3x - 2.

Step-by-step explanation:

(f - g) (x) = f(x) - g(x)

=  -5^x - 4 - (-3x - 2)

= -5^x - 4 + 3x + 2

= -5^x + 3x - 2.

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