you change the distance to a sound source from 1 m to 10 m. by how much does the intensity level change in decibel (db)?

The time period of vibrations varies inversely as the square root of the force constant of the spring.

When released, the restoring force returns the ruler to a stable equilibrium position with zero net force. The deflection of the spring is zero when the object is at equilibrium. This means that the force on the object due to the spring is also zero.

Therefore, when the object is in the equilibrium position it reaches zero acceleration and maximum velocity. At equilibrium, the velocity is maximum and the acceleration is zero. Simple harmonic motion is characterized by this varying acceleration. This changing acceleration is always directed toward equilibrium and proportional to the displacement from equilibrium.

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The two blocks used in a measuring device have negligible weight. The spring has constant k = 20 lb/in and is compressed 5 in. when in the position shown. The end of the screw is smooth and the coefficient of static friction at all other points of contact is µs = 0.3.

A.  Draw the free-body diagrams for blocks A and B. (See picture 1)

B.  Determine the minimum horizontal applied force P required to move block B to the right (and downward).

∑[tex]f_x =N_2 cos60^{0} +u_s N_2 cos30^0 -N_3=0[/tex] (See picture 2)

F = μN

The force that prevents motion when the surfaces of two objects come into contact is known as friction. Friction lessens a machine's mechanical advantage, or, to put it another way, friction decreases the output to input ratio. A car spends one-fourth of its energy-reducing friction. However, friction in the clutch and the tyres also contribute to the vehicle's ability to maintain its position on the road. One of the most important phenomena in the physical universe is friction, which affects everything from machines to molecular structures to matches. Let's talk about frictional force and its various forms in this article.The formula to calculate the static friction is given as Static Friction = Normal Force x Static Friction coefficient

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The power wasted in heating the cables of total resistance 9.0 Ω  is 74365290000 W.

Electric power is the rate at which work is done or energy is transformed into an electrical circuit.

To calculate the electric power wasted in heating the wire, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the power wasted is 74365290000 W.

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The ground speed and direction of the plane is 323 kph with a directional bearing of S 22° E.

What is speed?

The rate at which an object moves along a path is defined as its speed. The SI Unit of speed is metre per second or m/s or m.s-1.

What is vector?

A vector is a quantity that has magnitude as well as direction. It is often represented by an arrow whose length is proportional to the quantity and whose direction is the same as that of the quantity. Resultant vector is the sum of two or more vectors.

Since the airplane is headed due south with an airspeed of 300 kph, its vector is V = (-300 kph) j.

Also, the wind is blowing from the west at 120 kph. Its vector is v = (-120 kph) i.

So, the ground speed of the plane V' is the resultant vector of the airspeed and wind speed.

[tex]So, V' = v + V[/tex]

[tex]V' = (-120 kph)i + (-300 kph)j[/tex]

So, its magnitude V' = √[tex]x^{2} + y^{2}[/tex] where,

[tex]x = -120 kphy = -300 kph.[/tex]

[tex]So, V' =[/tex] √ [tex][(-120 kph)^{2} + (-300 kph)^{2}][/tex]

= √[tex](104400 kph^{2} )[/tex]

[tex]= 323.11 kph[/tex]

≅ 323 kph

The direction of plane,

Ф[tex]Its direction, Ф = tan^{-1} (y/x)\\Ф\\ = tan^{-1}(-300 kph/-120 kph)\\Ф\\ = tan^{-1}(2.5)\\Ф\\ = 68.2°[/tex]

From south line, α = [tex]90 - 68.2[/tex] ≅ 22°

So, the direction of the plane is S22°E.

The ground speed and direction of the plane is 323 kph with a directional bearing of S 22° E.

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The magnetic force operating on this electron has a maximum value of 79.02 x 10^-13 N; its minimum magnitude is zero when the electron goes in the magnetic field's direction.

The total of all forces exerted on an object is referred to as the magnitude of the force. A crucial physics measurement is calculating the magnitudes of forces. Regardless of the direction in which it works, a force's "magnitude" is its "size" or "strength."

The magnetic field, which is the region around a magnet that exerts a magnetic force and is caused by moving electric charges, surrounds an electric charge similarly to how an electric field does the same for an electric charge. A visual representation of magnetic fields is made using magnetic field lines.

Let v represent the velocity an electron gains in an electric field.

Charge is applied with a potential difference of V q = 1/2 m v2 V. q, m denotes charge mass, and v denotes acquired velocity.

2400 x 1.6 x 10^-19 =0.5 x 9.1 x 10^31 x v2, where v2 = 844 x 10^12 v and v = 29.05 x 10^6 m/s.

When an electron moves perpendicular to the magnetic field, the strongest force is applied to it.

Maximum force = Bqv, where B is the magnetic field, q is the charge on the electron, and v is the electron's velocity, resulting in a force of 1.7 x 1.6 x 10^-19 x 29.05 x 10^6 = 79.02 x 10^-13 N.

When an electron moves in the magnetic field's direction, the minimum force is zero.

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The drag force on the object is 73.5N.

What is drag force?

The drag force (D) is the force that opposes the movement of a body through a fluid. It is the fluid's resistive force. Drag force on air resistance on the object is proportional to its speed:

[tex]F_{d} = kV[/tex]

where,

k = constant

We know, [tex]F =mg[/tex]

From above equations,

[tex]mg = kV[/tex]

[tex]\frac{mg}{V} = k[/tex]

[tex]\frac{20 * 9.8}{80} = k[/tex]

[tex]k = 2.45[/tex]

For drag force,

[tex]F_{d} = kV[/tex]

[tex]F_{d} = 2.45 * 30\\\\F_{d} = 73.5 N[/tex]

The drag force on the object is 73.5N.

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The mass of the object will be 20 kg

First, create a free-body diagram for the item and label it. I've included a drawing I made that depicts all the relevant forces at work on the object.

The tension forces (T1 and T2), their x and y components, and the weight force are shown on the free-body diagram (w).

In order to apply this angle later in the issue to determine the object's mass using Newton's Second Law, we want to start by determining the angle theta ().

By utilizing the knowledge that there are no imbalanced horizontal forces acting on the item and that the net force is zero, we can determine the angle.

This implies that T1 sin(40) = T2 sin(). Create an equation with them equal to one another and find the angle. The tension forces are provided as T1 = 34 N and T2 = 24 N.

T1 sin(40) equals T2 sin().

220 * sin() = 135 * sin(40).

To determine sin(), multiply 135 by sin(40) and divide the result by 220.

0.3944378513 = sin(Θ)

Consider both sides of the equation's inverse sine.

Θ = sin⁻¹(0.3944378513) (0.3944378513)

Θ = 23.2309189°

Now that we have the angle, we can utilize it to construct a mass-related equation according to Newton's Second Law.

We are aware that the object is subject to a weight force that is applied downward and is equal to mg (mass divided by the gravitational acceleration).

The two tension forces' x-components are the two forces pushing upward on the item.

Since the item is not moving vertically, we may infer that the net force must be zero (F = ma, and since there is no acceleration, F = 0 N).

The forces acting in the y-direction added together will equal zero. We can construct the following equation by making the upward direction positive and the descending way negative:

F is equal to T1 cos(40) plus T2 cos(23.2309189) - mg = 0.

Weight force (mg) should be added to both sides of the equation.

T2 cos(23.2309189) + T1 cos(40) = mg

Change T1 to 135 and T2 to 220.

220 * cos(23.2309189) + 135 * cos(40) = mg

On Earth, the gravitational acceleration is 9.8 m/s2. To find the object's mass, m, solve the problem using this number as a substitute.

220 * cos(65.59058699) + 135 * cos(40) = m (9.8)

Analyze the equation's left side.

194.30766 = 9.8m

M = 19.829, multiply both sides of the equation by 9.8.

Since the problem provides us with the tension forces as two significant values, round this to two.

m ≈ 20 kg

The object in the image weighs about 20 kg.

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Kepler's theory revisions to the theory of planet formation have astronomers had to make as a result of the discovery of exoplanets

What is Kepler's theory?

They explain how planets orbit the Sun in elliptical fashion, how they cover the same amount of space in a given amount of time regardless of where they are in their orbits, and how their orbital periods are proportional to the size of their orbits.

What are exoplanets?

Any planet outside the solar system is considered an exoplanet. Rogue planets are free-floating exoplanets that orbit the galactic center without being bound to any star, unlike the majority of exoplanets that orbit other stars.

The planets may move in the protoplanetary disk due to drag or friction caused by gravity. In order to model or detect the presence of a planet using the radial velocity technique, an entire orbit is necessary.

Therefore, the closest planets have brief periods, according to Kepler's laws.

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If k is used as the proportionality coefficient, the relationship between volume v of a sphere and cube of its radius r is v = kr³.

If any two quantities are directly proportional to each other, a ∝ b, then the relation between a and b can be written as a = kb. This is because a and b are directly proportional to each other.

It is given that, volume of a sphere is directly proportional to the cube of its radius, v ∝ r³.

It can be written as v = kr³.

Hence, if k is used as the proportionality coefficient, the relationship between volume v of a sphere and cube of its radius r is v = kr³.

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The angular velocity, in rad/s, of the rod of length 2.00 m is suspended from a horizontal bar so it is free to swing about that end immediately after the collision is 0.29 rad /s

p = m v

Initially,

p = 0.25 * 13

p = 3.25 kg m / s

Finally,

p = 0.25 * 9.5

p = 2.375 kg m / s

The point where the ball hits the rod,

r = 4 / 5 * 2

r = 1.6 m

Moment of inertia of a rod at a point,

I = Icm + M r²

I = M L² / 12 + M r²

I = ( ( 3.4 * 2² ) / 12 ) + ( 3.4 * 1.6² )

I = 1.13 + 3.7

I = 4.83 kg m²

According to law of conservation of angular momentum,

Initial momentum of ball + Initial momentum of rod = Final momentum of ball + Final momentum of rod

( 3.25 * 1.6 ) + 0 = ( 2.375 * 1.6 ) +  4.83 ω

4.83 ω = 5.2 - 3.8

ω = 1.4 / 4.83

ω = 0.29 rad / s

Therefore, the angular velocity, in rad/s, of the rod immediately after the collision is 0.29 rad /s

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19.7 km distance far south of its starting point does the Robin land .

What distance?

The amount of space between two places or things is called distance.

It is a numerical qualitative measurement of how far apart objects or points are.

Sol-

Angle B = angle EAB =39°

BC= AB.COS B =21 COS 39°=16.3 km

CD = 36-16.32 =19.7 km

So south of stating point 19.7 km.

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Size of 12 AWG would be required for a copper conductor with an overcurrent protection device rated at 70 amperes

A substance or material that allows electricity to flow through it is referred to as an electrical conductor. When voltage is applied to a conductor, electrical charge carriers, typically electrons or ions, move easily from atom to atom.

The components or elements that permit electricity to flow through them are known as conductors. Conductors also permit the passage of heat through them. Animals, the Earth, copper, and the human body are all examples of conductors. A powerful conductor, the human body.

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The work that must be done by the frictional force in slowing a 1000 kg car from 26.1 m/s to a stop is 3.41 x 10⁵ J

Work in physics is the amount of energy given to move an object.

The magnitude of the work of an object is equal to the kinetic energy experienced by the object.

So,

W = KE

W = ½ mv²

We have,

Mass of the car (m) = 1000 kg

Deceleration (v) = 26.1 m/s

Now, calculate the work that must be done:

W = KE

=  ½ mv²

= ½ (1000) (26.1)²

= 340,605 = 3.4 x 10⁵ J

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True, twice each lunar month, all year long, these tides occur. whenever the moon, earth and sun are aligned, the gravitational pull of the sun to that of the moon causing tides.

When the Earth, Sun, and Moon align twice a month, their gravitational power combines to produce extremely high tides where the bulges occur, known as spring tides, Spring tides occur just after the full and new moons, when the sun, moon, and earth align. That is when the lunar and solar tides align and reinforce each other, resulting in a larger total tide. Neap tides occur when the moon is in its first or third quarter, forming a right angle with the sun, earth, and moon.

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The derived formulas for the final velocity of the carts in elastic collisions are as follows:

Suppose you have a cart of mass m1 and velocity v1i colliding with a cart of mass m2 and velocity v2i, with motion confined to one dimension. If the collision is perfectly elastic, then both momentum and energy are conserved. in this case, the final velocities are:

Calculations;

v1f = (2m1/m1 + m2) × v1i - ( m1 - m2/m1+m2) × v2i                             ....     (1)

v2f = (m1 - m2/m1 + m2) ×v1i + ( 2(m2)/ m1 + m2) × v2i                        ....    (2)

If the collision is totally inelastic, then only momentum is conserved; energy is lost. in this case, the carts end up moving together with one common final velocity:

vf= (m1/ m1 + m2) × v1i + (m2/ m1 + m2) v2i                                         ....    (3)

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The magnitude of the force of gravity that is acting on the objects is  1.33 × 10^−10 N.

We know that the gravitational force is an attractive force that acts on all the objects that do exist in the universe. Thus, once  body lies within the gravitational field of the earth this force of gravity can be said to act on the object. We have in the question two objects that are positioned on the cartesian coordinates as shown. The distance between the objects is 2 m.

Using the formula;

F = Gm1m2/r^2

F = gravitational force

G = gravitational constant

m1  and m2 = masses of the objects

r = distance of separation

Then we have;

F = 6.6726 × 10^−11 * 4 * 2/(2)^2

F = 1.33 × 10^−10 N

Thus the attractive force has a magnitude of  1.33 × 10^−10 N.

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The things that digital society can offer compared to the previous type of society are mentioned below.

The things that digital society can offer compared to the previous type of society are increased rate of productivity and easier means to gain more knowledge. Also gaining information on what is happening on the other side of the world is received at a rapid speed.

A society in which everything runs on digital technology and electronic means and paperless is called as digital society. In the previous type of society paper is the norm and digital technology and electronic means are rare.

Therefore, the things that digital society can offer compared to the previous type of society are mentioned above.

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A machine part has the shape of a solid uniform sphere of mass 230 g and diameter 2.7 cm. The angular acceleration is 16.10 rad / s².

Given that, mass of the sphere is 230 g

diameter is 2.7 cm

Frictional force = 0.02N

Now, we need to calculate angular acceleration. We know the formula of torque as τ = f × r

I × α = f × r

Here, I is the moment of inertia of the sphere

2/5 m r² × α = f × r

α = 5 f /( 2 m r) = (5* 0.02) / (2 * 230 * 10⁻³ * 1.35 * 10⁻²)

α = 16.10 rad / s²

Thus, the angular acceleration is 16.10 rad / s².

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An item has potential energy when it's miles in a state of affairs wherein, if its actions, the potential energy can drop because it profits kinetic electricity.

Potential energy due to the electric dipole is "Udipole = -P∈cosФ"; where P is dipole moment, ∈ electric, Ф is the angle made by the dipole. Therefore potential energies from largest to smallest are as follows; Ua > Uc > Uf = Ue > Ub >Ud

Potential energies may be defined as the potential for doing work that arises from function or configuration. inside the electrical case, a  charge will exert a force on another rate, and the ability of electricity arises from any series of fees. the electrical ability, or voltage, is the distinction in capacity power according to unit rate among locations in an electric-powered area.

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The force on the clove will have the same magnitude but a negative sign with it that is F = - 14 N

The definition of force is: The pushing or pulling on a massed object changes its velocity. Force is an external agent that has the power to alter a body's resting or moving condition.

It has a size and a movement.

Newton's second law of motion defines the force formula as follows:

A force is equal to an object's mass times its acceleration, or F = m a. You must use SI units when applying this formula: kilograms for mass, meters per second squared for acceleration, and newtons for force.

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The objective of this lab is to find the resonance in air column.

The apparatus of this experiment are a long cylindrical plastic tube attached to a water reservoir. The length of the water column can be changed by raising or lowering the water level while the tuning fork is held over the open end of the tube.

Resonance is indicated by a sudden increase in the intensity of the sound when the column is adjusted to a proper length.

The resonance is nothing but a standing wave phenomenon in the air column and occurs when the column length is λ/4, 3λ/4, 5λ/4.

Second resonance is occurred at third harmonic and third resonance is occurred at fifth harmonic.

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Mass of w load is 876.71 kg. According to which the weight of the liquid that is being propelled away from a body equals the force applied to that body.

The air density at T = 25oC is = 1.18 kg / m3, thus we can calculate w load = 1.18 9.8 4/3 7.153 - 930 9.8 w load = 17705,77 - 9114 w_ load = 8591.77 N, which translates to a mass of w load = m g m = w load / g m = 8591.77 / 9.8 m = 876.71 kg.    

The complete question is,

Helium is used to fill spherical balloons, which have a radius of 7.15 meters. Given that the balloon's structure and skin weigh 930 kg, how much weight can it lift? Don't think about the bulk of the cargo itself being buoyant.

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Surface waves, longitudinal waves, and transverse waves. Any wave in which the motion of the medium's particles is perpendicular to the wave's direction is referred to as a transverse wave.

Wave motion refers to the movement of energy and momentum between two locations in a medium without the physical movement of any substance.

Wave Waves move when there is motion. A wave is characterized as a disruption brought on by the transmission of energy across space or a medium. Wave motion is exemplified by the motion of water ripples, sound waves, and light rays.

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The focal length of the lens is  21.26 cm.

The radius of curvature, R, is the reciprocal of the curvature. For a curve, it equals the radius of the round arc which fine approximates the curve at that point. For surfaces, the radius of curvature is the radius of a circle that best suits an ordinary phase or combos thereof.

Calculation:-

1/f = (μ - 1)(1/R₁ - 1/R₂)

   = (1.45 - 1)(1/2.04 - 1/2.6)

   = 0.45 × 0.10

1/f    = 0.047 cm

f = 1/0.047 cm

f = 21.26 cm.

The focal length of an optical system is a degree of the way strongly the system converges or diverges light; it is the inverse of the gadget's optical electricity. An effective focal period indicates that a device converges light, even as a negative focal duration indicates that the device diverges light.

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We can easily experience black body in practical.

What is black body?

A black body or blackbody is the  an idealized physical of the  body that absorbs all to the  incident of a  electromagnetic radiation, regardless of frequency or angle of incidence. The probability is a name "black body" is given because it is  absorbs all colors of light. A black body also emits the  black-body radiation.

A body which completely absorbs all heat radiation incident on it is called perfectly black body. A perfectly black body can not be realised in practice but materials like Platinum black or Lamp black come close to being ideal black bodies. Such materials absorbs 96% to 85% of the incident radiations.

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A leaf and a solar panel both use the energy of the sun to function. The leaf uses the sun’s energy to produce food through photosynthesis, while the solar panel uses the sun’s energy to generate electricity.

Both processes require sunlight and the energy it produces to work. Additionally, both a leaf and a solar panel are reliant on the environment around them. A leaf needs sunlight, water, and other nutrients from the soil to survive, while a solar panel needs to be situated in an area with lots of direct sunlight and not a lot of shade to effectively produce energy. This means both are very dependent on their environment for their success.

Finally, both a leaf and a solar panel play an important role in the environment. Leaves are an essential part of the food chain, providing food for animals and oxygen for us to breathe. Solar panels are also important as they provide a clean, renewable source of energy that can help reduce our reliance on fossil fuels and the negative environmental impacts they have.

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The percentage difference between these particles is 7.14%.

Calculation:-

Given mass = 0.100 kg

length of rod = 6 cm

I total =  md² + m(2d)² + m(3d)²

if the Innermost one is removed then would only m92d)² = 13 md²

The percentage difference between these is

(13-14)/4 = 0.714% = 7.14%

For any planar body, the moment of inertia about any axis perpendicular to the plane is equal to the sum of the moments of inertia about any two perpendicular axes in the plane of the body that intersect the first axis in the plane. The axis of rotation is always perpendicular to the plane of motion. The sagittal plane divides the body into left and right sections, with axes on the left and right sides.

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The parts of rock cycle are -melting, cooling, eroding, compacting, or deforming. These are the physical changes by which rock undergoes during formation.

There are mainly three main types of rocks: sedimentary, igneous, and metamorphic. Each of these rocks are formed by undergoing physical changes.

Sedimentary Rocks

Sedimentary rocks are formed from pieces of already existing rock or organic material.  Sedimentary rocks are further classified into three types of rocks listed as: clastic, organic (biological), and chemical.

Metamorphic Rocks

Metamorphic rocks are defined as those rocks that have been changed from their original form by immense heat or pressure.

When a rock with flat or elongated minerals is put under the immense pressure, the minerals line up in layers, creating the foliation.

Igneous Rocks

Igneous rocks  are formed when the molten hot material cools and solidifies. There are different ways by which igneous rocks can be formed. When they formed inside of the earth, they are called intrusive, or plutonic, igneous rocks.

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The acceleration due to gravity of the exoplanet is 1.49 times the acceleration due to gravity of the earth.

What is exoplanet?

Exoplanets are the heavenly bodies which exist in deep space having the sizes of the planets and the constituents depends on the formation of their solar systems. Some of the major elements of the exoplanets are iron, minerals.

The acceleration due to gravity of the exoplanet can be calculated as,

gp = G mp / r^2

gp = G 7.9 me / (2.3 re)^2

gp = 1.49 ge

Therefore the acceleration due to gravity of the exoplanet is 1.49 times the acceleration due to gravity of the earth.

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Two identical speakers in the same orientation produce waves of the same wavelength that are in phase. At a point midway between the speakers, you would expect to hear louder due constructive interference took place.

While destructive interference can result in the complete cancellation of the contributing waves, constructive interference causes an increase in the amplitude of the sum wave. The "speaker and baffle" experiment, which uses a small loudspeaker and a large, square wooden sheet with a circular hole the same size as the speaker, is an intriguing demonstration of both sound interference and diffraction. When music is played through the loudspeaker, out-of-phase sound waves from the speaker's front and back diffract into the surrounding area. Particularly at very low frequencies, where the wavelength is longest and the diffraction is therefore greatest, the two waves interfere destructively and cancel one another.

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