A low partial pressure of oxygen promotes hemoglobin binding to carbon dioxide. This is an example of the?

What mechanisms function to localize sound in the horizontal and vertical planes?

Horizontal sound localization results from two mechanisms: interaural time delay and interaural intensity difference.

The capacity to pinpoint the position or source of a detected sound in terms of distance and direction is known as sound localization.

Numerous studies have been conducted on the mammalian auditory system's sound localization mechanisms. The auditory system uses a variety of indicators, such as spectral information, timing difference, level difference (or intensity difference) between the ears, and others, to locate the source of sound. Other animals, including birds and reptiles, employ these cues as well, however there may be variances in how they are used. In addition, there are localization cues that are not present in the human auditory system, such as the results of ear movements. It is obvious that animals that can localize sound have an evolutionary advantage.

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Hi, your answer is below.

Time dilation is usually defined as the slowing of the passage of time experienced by objects in motion relative to an observer; measurable only a relativistic speeds.  Because time moves at various rates for the two of them depending on their relative velocities and/or proximity to things of considerable mass, if two persons (or objects) are moving relative to one another, they will age at separate rates. They will age differently from one another over time since their two timepieces will really tick at separate speeds. If they cross paths again later, they will both have aged differently, which may be determined by using their own timepieces, presuming they each had one. Einstein's Special and General Relativity equations, which have undergone extensive testing over the past 115 years and have never been shown to falter, regulate this "time dilation." The general relativity theory of Einstein, which states that a huge body's gravity warps space-time around it, causes time to move more quickly or more slowly depending on how far away the mass is from the observer, is what causes this so-called "time-dilation" phenomenon.

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The cannonball will travel 311.8 m  horizontally. Among the given options, 310 m is the correct answer.

What is a Projectile ?

A projectile is any object like stone, ball or javelin that take a trajectory path when thrown into the air.

The following parameters are given from the question

Resolve the initial velocity into horizontal and vertical components. That is,

To calculate the range that is, the horizontal distance, will can first calculate the total time take by the ball to reach the ground.

Total time T = 2usinФ / g

Substitute all the parameters

T = (2 x 60sin30) / 10

T = (2 x 30) / 10

T = 60 / 10

T = 6 s

The horizontal distance R = ucosФ x T

R = 60 x cos 30 x 6

R = 311.77 m

Therefore, the cannonball will travel 312 m approximately horizontally.

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Vmax = 1.258 m/s

Maximum velocity of any point on the string is 1.258 m/s.

Maximum velocity is given by,

Vmax = Aω

where,

V = velocity

A = amplitude

ω = angular displacement

ω is given by,

ω = 2[tex]\pi[/tex]f

where f = frequency

ω = 2[tex]\pi[/tex]f

   = 2*3.147*100

   = 629.4 rad

A = amplitude = 2mm

Vmax = Aω

         = 2 ×[tex]10^{-3}[/tex] × 629.4

         = 1.258 m/s

Maximum velocity = Vmax =  1.258 m/s

Maximum velocity of any point on the string is 1.258 m/s.

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At r = 0.766 R the magnetic field intensity will be half of its value at the center of the current carrying loop.

We have a circular loop of radius ' r ' carrying current ' i '.

We have to find at what distance along the axis of the loop is the magnetic field one-half its value at the center of the loop.

The formula to calculate the magnetic field intensity due to a current carrying ( i ) circular loop of radius ' R ' at a distance ' x ' on its axis is given by -

[tex]B(x) = \frac{\mu_{o} iR^{2} }{2(x^{2} +R^{2})^{\frac{3}{2} } }[/tex]

Now, for magnetic field intensity at the center of the loop can calculated by putting x = 0 in the above equation. On solving, we get -

[tex]B(0) = \frac{\mu_{o} i}{2R}[/tex]

Let us assume that the distance at which the magnetic field intensity is one-half its value at the center of the loop be ' r '. Then -

[tex]\frac{\mu_{o} iR^{2} }{2(r^{2} +R^{2})^{\frac{3}{2} } } = \frac{1}{2} \frac{\mu_{o}i }{2R}[/tex]

[tex]2R^{3} = (r^{2} +R^{2} )^{\frac{3}{2} }[/tex]

[tex]4R^{6} = (r^{2} +R^{2} )^{3}[/tex]

[tex]r^{2} =0.587R^{2}[/tex]

r = 0.766R

Hence, at r = 0.766 R - the magnetic field intensity will be half of its value at the center of the current carrying loop.

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The area of a second piston that exerts a force of 24,000 N is 0.04 [tex]m^{2}[/tex].

Gravitational force is measured in newtons. Utilizing the physics formula pressure = force/area, you can compute pressure if you know the value of a force. Both pounds per square inch (psi) and newtons per square meter (N/m2) are acceptable units of measurement for this pressure.

Given force 1 =  12,000 N

The pressure which has produced a force of 12,000 N at the piston 1 = Force/ area

= 12,000N / 0.020 [tex]m^{2}[/tex]

= 6,00,000 N/[tex]m^{2}[/tex]

Now force at piston 1 must be equal to force at piston 2. thus, force at piston 2 is given by:

Force at piston 2 = pressure × area

24,000 N = 6,00,000 × area

area = 0.04 [tex]m^{2}[/tex]

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Answer:

ΔV=Vi + Vf

           2

ΔV= 11m/s + 19m/s

                 2

ΔV= 15m/s

Explanation:

The cost of operating the iron is $2186.49.

To find the answer, we have to know about the power.

              [tex]cost=power(kW)*t(hours)*(price/ kWh)[/tex]

                        [tex]P=IV=5.2*240=1248W[/tex]

                     [tex]t=2*365*24hours=17520hours.[/tex]

                  [tex]cost=1248*10^{-3}*17520*0.10} =\$2186.49[/tex]

Thus, we can conclude that the cost of operating the iron is $2186.49.

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The unit of the quotient of inductance and resistance will be Henry and ohm

Inductance is the tendency of an electrical conductor to oppose a change in the electric current flowing through it. The flow of electric current creates a magnetic field around the conductor. The field strength depends on the magnitude of the current, and follows any changes in current.

Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω). Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who studied the relationship between voltage, current and resistance.

unit of quotient of inductance = henry (H)

unit of resistance = ohm

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Answer:

-79.6

-80

-81.2

Explanation:

Fart

What is the change in temperature for the aluminum wire?

-79.6

What is the change in temperature for the steel wire?

-80

What is the change in temperature for the lead pellets?

-81.2

The speed of one rocket relative to the other is 8.5 cc.

Let s be the frame at rest relative to the earth. Let the spaceship moving to the left with respect to the earth at speed [tex]v[/tex] be the particle in the terminology. Then the velocity of the spaceship relative to each other is simply the velocity of the second spaceship.

That for speeds small compared with the speed of light the relativistic velocity addition law gives the usual Newtonian result, whereas for speed near c the result is not what has been expected classically.

[tex]v' = 0.96cc\\\\v= 0.84cc\\\\\\v' = \frac{v+V}{1+ \frac{vV}{c^2} } \\\\v' = \frac{v+V}{ \frac{c^2+ vV}{c^2} }\\\\v' = \frac{(v+V) c^2} {c^2+ vV}\\\\\\v'c^2 + c^2v = V (c^2 - v'v)\\\\V = \frac{v'c^2+c^2v}{c^2 - v'v} \\ \\ = \frac{0.96 * 9* 10 ^1^6 + 0.84*9*10^1^6}{9*10^1^6 - 0.96 * 0.84} \\\\ =\frac{16.2}{1.9}\\ \\= 8.5 cc[/tex]

Therefore, the speed of one rocket relative to the other is 8.5 cc.

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The maximum weight of a luminaire (lighting fixture) permitted to be hung directly from an outlet box in a ceiling 50 pound.

A luminaire that weighs more than 23 kg (50 lb) shall be supported independently of the outlet box, unless the outlet box is listed for not less than the weight to be supported.

Luminaire, or light fixture, complete lighting unit, consisting of one or more lamps (bulbs or tubes that emit light), along with the socket and other parts that hold the lamp in place and protect it, wiring that connects the lamp to a power source, and a reflector that helps direct and distribute the light.

Fluorescent fixtures usually have lenses or louvers to shield the lamp (thus reducing glare) and redirect the light emitted. Luminaires include both portable and ceiling- or wall-mounted fixtures.

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~400 nm to ~700 nm are the wavelengths of electromagnetic wave in free space.

What are the wavelengths of electromagnetic wave in free space?

Electromagnetic waves are categorized on the basis of their frequency f, which is equivalent to wavelength λ = c/f. Visible light has a wavelength that ranges from ~400 nm to ~700 nm. Violet light has a wavelength of ~400 nm, and having a frequency of ~7.5*1014 Hz.

So we can conclude that: ~400 nm to ~700 nm are the wavelengths of electromagnetic wave in free space.

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The wavelengths of the light are 4.3 * 10^-12 m and 0.2 m respectively.

The term wavelength has to do with the horizontal distance that is covered by a wave. We know that a long wavelength implies that the wave is able to travel a long distance from one point to another.

Given that;

c = λf

c = speed of light

λ = wavelength of ight

f = frequency of light

Thus;

λ = 3 * 10^8/ 7.00 x 10^19

λ = 4.3 * 10^-12 m

λ = 3 * 10^8/1.50 x 10^9

λ = 2 * 10^-1 or 0.2 m

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Missing parts:

What are the wavelengths of electromagnetic wave in free space that have the following frequencies? (a) 7.00 x 10^19 Hz______ pm (b) 1.50 x 10^9 Hz__________ cm

Convex lens  had the largest overall magnification .

In optics, It is a quantification of comparing the size of the image with respect to the size of the object. It gives us information about the image in terms of how large or small is the image formed. Magnification is defined as the ratio of the height of image to the height of object.

The convex lens has the largest overall magnification. To get maximum magnification by convex lens object must be placed between center of curvature and pole of the lens .

Magnifying glasses make objects appear larger because their convex lenses (convex means curved outward) refract or bend light rays, so that they converge or come together.

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The probability that she makes 6 of them is 0.242

Simply put, the probability is the likelihood that something will occur. When we don't know how an event will turn out, we can discuss the likelihood or likelihood of several outcomes. Statistics is the study of events that follow a probability distribution.

A basketball player has a probability = 0. 603

The player shoots 10 free throws.

Let x be a random variable that represents the number of free throws made by a basketball player.

x ≈ Binomial (n,p)

p = 0.603

n= 10

P(x=k) = [tex]_nC_k p^k (1-p)^{n-k}[/tex]

P(6)    [tex]= _1_0C_6 (0.603)^6 (1-0.603)^{10-6}[/tex]

           [tex]=210 (0.048) (0.397)^4[/tex]

           [tex]=210 (0.048)(0.024)[/tex]

           [tex]= 0.242[/tex]

Therefore, the probability that she makes 6 of them is 0.242

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When a proton slows from 0. 8c up to 0. 6c, it’s kinetic energy decreases by what factor of 1/4.

Kinetic energy of a proton having a charge Q and Voltage V is given by:

Kinetic energy = Q×V

Where, Q is the charge

            V is the Voltage

Kinetic energy is directly proportional to the charge on a proton.

Let the kinetic energy of proton having charge 0.8C be KE₁ and kinetic energy of proton having charge 0.6C be KE₂

Hence KE₁ = 0.8 × V

KE₂ = 0.6 × V

Now, KE₁ / KE₂ = 0.8 V / 0.6 V

⇒          KE₁ / KE₂ = 4 / 3

⇒         KE₂ / KE₁ = 3/4

⇒         KE₂ = 3/4 times KE₁

Hence, the final kinetic energy becomes 3/4 times the initial kinetic energy.

The kinetic energy decreases by a factor of:

Change = KE₁ - KE₂

Change = KE₁ - 3/4KE₁

Change = 1/4 KE₁

Hence, the kinetic energy decreases by a factor of 1/4

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Electric utility power blackouts will result in short electric power outages for the organization.

When the electrical power network, often known as the electrical grid, is down, there are power outages. Power outages can have a variety of causes, but they always tend to affect entire regions or cities rather than simply a single residence. For example, the Northeast blackout of 2003 left 50 million people without power from New York to Canada’s capital Ottawa.  

A place experiences a blackout when all power is lost. Power outages of this kind generally affect a sizable population over perhaps extraordinarily broad areas. Blackouts are particularly difficult to quickly fix because they typically result from significant damage to electrical generation facilities (such as structural damage from violent wind storms or lightning strikes). As a result, these types of outages can, in the worst-case scenarios, last for several weeks.

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We can see that the range from the calculation is 310 m.

When we throw something from a height and it lands at the same eight, we call it a projectile motion. A projectile must always be shot at an angle. The range of the projectile is obtained by the relation; R = u^2sin2θ/g

Thus;

g = acceleration due to gravity

θ = acute angle

u = velocity

R = (60)^2 sin2(30)/10

R = 310 m

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The hydroxide ion concentration in a solution is 3.31*10^-8M.

To find the answer, we have to know more concentration of solution.

                     [tex]pH=-log[H_3O^+][/tex]

                   [tex][H_3O^+]=-10^{pH}=10^{-6.25}=5.6*10^{-7}M[/tex]

                        [tex]K_w=[H_3O^+][OH^-]\\Where,\\K_w=10^{-14}[/tex]

                         [tex][OH^-]=\frac{K_w}{[H_3O^+]} =\frac{10^{-14}}{10^{-6.52}}\\\\[/tex]

                           [tex][OH^-]=3.31*10^{-8}M[/tex]

Thus, we can conclude that, the hydroxide ion concentration in a solution is 3.31*10^-8M.

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565.2 lbs pressure can apply to a plunger.

It is given that,

The air supplied to a diaphragm is 20 psig.

Diameter is 6

Then r=3

We know that,

Area=

πr²

=(3.14×3²)

= 28.26

The formula is (3.14 ×radius of diaphragm squared) ×psig.

=( 28.26 ×20)

= 565.2 lbs of pressure.

Hence, the pressure is  565.2 lbs.

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The resistance depends upon the length, area and material of the material.Option (a), (b) and (c) is correct.

Quantities that determine the resistance:

The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area. Resistance also depends on the material of the conductor.

A conductor's or circuit element's resistance typically rises as temperature rises. Some conductors exhibit negligible resistance at very low cooling rates. Even after the electromotive force is removed from these substances, known as superconductors, currents still flow through them.The conductance, 1/R, is the reciprocal of resistance and is measured in reciprocal ohm units, or mho.

The complete question is:

What quantities determine the resistance of a piece of material? Choose all that apply.

a)The length of the piece of material

b)The cross-sectional area of the piece of material

c)The type of material

d)The voltage across the material

e)The current flowing through the piece of material

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A lorenz curve represents the cumulative percentage of total income received along the horizontal axis and the cumulative share of population along the vertical axis.

The distribution of the cumulative percent of occurrences by the cumulative percent of population is shown graphically by the Lorenz Curve. By expanding the neighbourhood income quintile group, the horizontal axis (x-axis) of the curve shows the cumulative percent of persons in the population, and the vertical axis (y-axis) shows the cumulative percent of events in the population.

The Lorenz curve can be described as the proportion of the population that the neighbourhood income quintile represents holding the proportion of population events.

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The main purpose of any wave, including sound waves and ocean waves, is to carry energy from one place to another.

A sound wave is the pattern of disruption brought on by the movement of energy moving through a medium as it propagates away from the source of the sound (such as air, water, or any other liquid or solid matter). Pressure waves are produced when an object vibrates, such as a ringing phone, and these waves are known as sound waves.

A wave crest is produced when wind continuously disturbs the water's surface in an ocean or lake. Ocean waves, which often go by the name wind waves, are mostly gravity waves. The height, duration, and shape of succeeding waves vary with a certain level of randomness of ocean waves.

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The volume of a unit cell is 4.3 × 10⁻¹⁰ pm³.

We need to start with the features of a face-centered cubic system in order to be able to determine the edge length of the unit cell.

As we know, a face-centered cubic system is characterized by a unit cell that has a total of 14 lattice points.

Now, these lattice points will contain

Assume that r is the edge length of the unit cell and that r is the radius of an iron atom. You'll see that we can represent x in terms of the cell's diagonal, d, using Pythagoras' Theorem.

        [tex]d^2 = x^2+ x^2[/tex]

        [tex]d^2=2x^2[/tex]

The cell's diagonal will be equal to one radius from the atom in the top corner, two from the atom in the face, and one from the atom in the lower corner.

[tex]d= r+2r+r = 4r[/tex]

This means that we have,

[tex](4r)^2=2x^2[/tex]

[tex]16.r^2 = 2x^2 \\x=\sqrt{8r^2}[/tex]

This is equivalent to

[tex]x=2\sqrt{2} r = 2\sqrt{2} .124= 350.7 pm[/tex]

So, the edge length of the unit cell is equal to 350.7 pm.

The volume of a unit cell. As we know, the volume of a cube is given by the formula

V = [tex]l[/tex] × [tex]l[/tex] × [tex]l[/tex]

[tex]l[/tex] = the edge length of the cube

Volume = (350.7)³ pm³

            = 4.3 × 10⁻¹⁰ pm³

            = 4.3e-30 cm³

Therefore, the volume of the unit cell is 4.3 × 10⁻¹⁰ pm³.

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When the current in the micro-robot’s circuit increases and the resistance of the circuit remains constant, the voltage of the circuit: increases

With manual control, microrobots have demonstrated tremendous potential for carrying out microscale activities as drug delivery, cell manipulation, micro construction, and biosensing. Magnetotactic bacteria were used to illustrate the use of targeted delivery in the presence of DC magnetic field gradients. Microrobots for magnetic field-based delivery of target objects like cells and chemicals have also been investigated by other research teams. Micro-electro-mechanical systems have been used to create microgrippers for microrobots, a technique that can be used to increase the capability of microrobots in addition to targeted distribution. The kinematic models of produced microrobots have been researched in order to obtain motion control. Microrobots that are both biological and non-biological have been guided using autonomous motion planning. These devices utilize visual systems for feedback control.

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Building a telescope that detects radio waves must be built with a very large dish since radio waves have very large wavelengths is regarded as a true statement and is denoted as option A.

This is defined as the distance between two successive crests or troughs of a wave.

Radio waves have the longest wavelength in the electromagnetic spectrum which is therefore the reason why a very large dish is built to detect it.

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The amount of heat required to raise the temperature is 706.05J.

To find the answer, we need to know more about the specific heat capacity.

                                 Q=msΔT

                 [tex]m=2.50g=2.50*10^{-3}kg\\s=0.523 J/gK=\frac{0.523}{10^{-3}} J/kgK=523J/kgK\\T_1=65^0C=338K\\T_2=600^0C=873K\\[/tex]

            [tex]Q=2.5*10^{-3}*523*(873-333)=706.05 J[/tex]

Thus, we can conclude that, the amount of heat required to raise the temperature is 706.05J.

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When testing for friction loss coefficients, departments that use a pitot tube should use Smooth bore nozzle

The pitot tube is a simple and convenient instrument to measure the difference between static, total and dynamic pressure (or head) .

It is a device used to measure velocity in pipe, wide tunnel, aero planes , etc. Pitot tube is completely based on its principle that if the velocity of flow at any point becomes Zero. A pressure measuring instrument used to measure fluid flow speed, especially used to determine the airspeed of an aircraft

Smooth bore nozzles also use the lowest engine pump pressures, allowing for maximum reach. Smooth bore nozzles are often referred to as solid bore nozzles because they produce a solid stream to provide maximum reach and penetration to the seat of the fire.

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The work done by the unstretched spring is 5 J.

Hooke's law states that the extension of a given material is directly proportional to the force applied as log as the elastic limit is not exceeded. Thus we have to know that; F = Ke

F = force applied

K = force constant

e = extension

Using the graph;

K = F/e

F = 200N

e = 5 cm or 5 * 10^-2 m

K = 200N/ 5 * 10^-2 m

K = 4000 N/m

Now;

Work = 1/2Ke^2

Work = 0.5 *  4000 N/m * (5 * 10^-2 m)^2

Work = 5 J

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