A softball pitcher has a 0. 431 probability of throwing a strike for each pitch. if the softball pitcher throws 22 pitches, what is the probability that exactly 12 of them are strikes?

The probability that the base-9 representation and the base-11 representation of are both three-digit numerals is 0.6753

To calculate the probability that the base-9 representation and the base-11 representation of are both three-digit numerals, we need the following parameters:

The smallest 3-digit base-11 number is 100

When converted to base 10, the equivalent number is 121

The largest 3-digit base-9 number is 888

When converted to base 10, the equivalent number is 728

So, the total number of possibilities is:

Possibilities = 728 - 121 + 1

Possibilities = 608

The count of base 10 3-digit numbers is

Count = 999 - 100 + 1

Count = 900

The required probability is:

P = 608/900

Evaluate

P = 0.6753

Hence, the probability that the base-9 representation and the base-11 representation of are both three-digit numerals is 0.6753

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Complete question

A base-10 three-digit number is selected at random. What is the probability that the base-9 representation and the base-11 representation of are both three-digit numerals

Answer: 4

Step-by-step explanation:

f(g(x)) = f(x+2) = 3(x+2) = 18

x + 2 = 6

x = 4

The height of the second square base prism is 50 cm.

The volume of the first square base prism is represented as follows:

v = ha²

where

Therefore, the height of the prism is 10 cm.

v = 10a²

Hence, the volume of the initial prism is 5 times the volume. Therefore,

v = 5(10a²)

v = 50a²

Therefore,

50a² = ha²

divide both sides by a²

50a² / a² = ha² / a²

50 = h

h = 50  cm

Therefore, the height of the second square base prism is 50 cm.

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Answer:

$2,450

Step-by-step explanation:

21:150 is the ratio of people who will donate $5.

21:150 / 3 = 7:50

7:50 x 2 = 14:100

14:100 = 21:50

14:100 x 35 = 490:3500

490 out of 3500 people will contribute $5.

490 x 5 = $2,450

The change in Tina's account after the three days; Monday, Tuesday and Wednesday is $-25

Deposit is a sum of money or other asset given as an initial payment, to show good faith, or to reserve something for purchase.

Withdrawal on the other hand, is to extract money from an account.

Change in Tina's account after the three days = - 35 - 60 + 75

= -95 + 75

= $-20

Therefore, the change in Tina's account after the three days; Monday, Tuesday and Wednesday is $-25.

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Anderson could provide 0.5x2 + 4x + 8 = 0 has exactly one real root if the discriminant is 0,

Any equation that can be rewritten in standard form as where x represents an unknown, a, b, and c represent known numbers, and where a 0 is true is a quadratic equation. As there is no ax2 term when a = 0, the equation is linear rather than quadratic.

A polynomial's discriminant is a quantity that depends on the coefficients and enables for some root attributes to be inferred without actually computing them. It is actually a polynomial function of the original polynomial's coefficients.

0.5x^2 + 4x + 8 = 0

The discriminant is computed utilizing:

d = b^2 - 4ac

Thus, we have:

d = 4^2 - 4 * 0.5 * 8

Evaluate

d = 0

The equation has only one real root since the discriminant is 0,

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6.4 cm is the needed circumference of the gasket following dilatation with a scale factor of 2.

The boundary length of any circular shape is known as the circumference.

A scale factor is a quantity multiplier (also known as a scale). The scaling factor for x, for instance, is represented by the letter "C" in the equation y = Cx. The factor would be 5 if y = 5x were the equation.

After scale factor 2 is applied, 6.4 cm must be the gasket's needed circumference.

It includes a rubber gasket with a 3.2 cm circumference. The circumference of the gasket has must be calculated after scaling up by factor 2.

Here,

3.2 cm is the gasket's circumference.

The circumference changed upon scale factor 2 dilatation.

Dilated gasket circumference: 2 * 3.2 = 6.4 cm

As a result, 6.4 cm is the needed circumference of the gasket following dilatation with a scale factor of 2.

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Answer:

6.4cm

Step-by-step explanation:

I Just Took the Test.

Answer:

x < -19/7

Step-by-step explanation:

Solve for x

2x+5  < (x+1)/4

Multiply each side by 4

4( 2x+5) <  (x+1)/4 *4

8x + 20  < x+1

Subtract x from each side

8x+20-x < x+1-x

7x + 20 < 1

Subtract 20 from each side

7x+20-20 < 1-20

7x< -19

Divide by 7

7x/7 < -19/7

x < -19/7

Answer:

[tex] \red{x < \frac{ - 19}{7} }[/tex]

Step-by-step explanation:

[tex]2x + 5 < \frac{x + 1}{4} \\ \text{use \: cross \: muliplication} \\ 4(2x + 5) < x + 1 \\ 8x + 20 < x + 1 \\ 8x - x < - 20 + 1 \\ 7x < - 19 \\ \frac{7x}{7} < \frac{ - 19}{7} \\ x < \frac{ - 19}{7} [/tex]

Answer:

Step-by-step explanation:

7/3=7:

what will seven over three equals seven divide be

7/3 is a division (7:3)

so

your answer is :

3

(7/3=7:3)

The correct option is B.

Natalie charges $1490 in rent for each home Per month.

Natalie charges $1490 in rent for each home.

Given that Natalie owns three homes, her monthly rent will be:

= $4470 (3 * 1490) dollars.

The annual income Natalie receives from her three homes is

=($12 * $4470)

= $53680.

Natalie spends $5850 a year on maintenance for each home.

The total amount Natalie spends annually to maintain her three homes is therefore:

=(3 * 5850) dollars, which comes to 17550 dollars.

Then Natalie's annual income would be

= [(53640 - 17550) dollars]

= 36090 dollars.

The total amount Natalie made over the course of seven years was

= ($7 * 36090)

=$252630

The correct option is B.

Natalie charges $1490 in rent for each home Per month.

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Answer:B) $252630

Step-by-step explanation:edge

Step-by-step explanation:

x = 7

y = 5

[tex] = {x}^{2} + {y}^{2} [/tex]

[tex] = (7 {)}^{2} + (5 {)}^{2} [/tex]

= 7 × 7 + 5 × 5

[tex] = 49 + 25 [/tex]

[tex] = 74[/tex]

Hey there!

x^2 + y^2

= 7^2 + 5^2

= 7 * 7 + 5 * 5

= 49 + 25

= 74

Therefore, your answer should be: 74

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

In this situation, the cases are the bags or each piece of baggage.

In statistics, the word case is used to refer to the individual from which data is collected. For example, in a study about students' performance, the cases are each of the students.

Considering the administrators will need to weight and record each bag, the cases are each piece of baggage.

Note: This question is incomplete; here are the missing options:

A. Number of bags weighing more than 75 pounds.

B. Average weight of the bags.

C. Each piece of baggage.

D. The airport administrators.

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The height of the flag pole which is described as in the task content is; 8.2m.

The horizontal distance between the 6m house and the flagpole in discuss can be evaluated by means of the angle of depression and trigonometric identity, tan as follows;

tan 22° = 6/x

x = 6/tan 22 = 14.9m.

Consequently, the horizontal distance from the top of the house to the top of the flagpole is therefore;

tan 9° = y/14.9

y = 14.9 tan 9° = 2.2m

Ultimately, the height of the flagpole is; 6+2.2 = 8.2m.

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The answer is True.

On differentiating using product rule,

[tex]\mathsf {\frac{d}{dx}[xe^{x}] = x(e^{x})+e^{x}(1)}[/tex]

[tex]\mathsf {\frac{d}{dx}[xe^{x}] = e^{x}(x + 1)}[/tex]

The general form of product rule :

[tex]\boxed {\frac{d}{dx}(ab) = a(b')+b(a')}[/tex]

A graph which shows the image of ABCD is: A. on a coordinate plane, parallelogram A'B'C'D' has points (-2, 5), (0, 3), (0, -1.2), (-2, 1).

A transformation refers to the movement of a point on a cartesian coordinate from its original (initial) position to a new location.

In Geometry, there are different types of transformation and these include the following:

Based on transformation of parallelogram ABCD, we can infer and logically deduce that a graph which shows the image of ABCD is that on a coordinate plane, with parallelogram A'B'C'D' having points (-2, 5), (0, 3), (0, -1.2), (-2, 1) as shown in the image attached below.

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Since this is the result of the second function, hence equations I and II are inverse of each other.

Inverse of a function

Inverse of a function is s a function that serves to undo another function. That is, if f(x) produces y, then putting y into the inverse of f produces the output x.

Given the function f(x) = 3x

Find its inverse

Replace with y with x

y = 3x

x =3y

Make y the subject of the formula

3y = x

y = x/3

Since this is the result of the second function, hence equations I and II are inverse of each other.

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4|a| + 8 - a, if a = -2

What we're doing here is plugging in the given value of a for every instance of a in the expression.

4|-2| + 8 - (-2)

---The absolute value of a number is its distance from 0. -2 is 2 units away from 0, so the absolute value of -2 is 2. And, remember two negatives make a positive!

4(2) + 8 + 2

8 + 8 + 2

16 + 2

18

Hope this helps!

The inequality sign < means "less than." If there is a line underneath the inequality sign that means "less than or equal to."

To graph x < 5, we first need to understand what the inequality is saying. In this case, x must be less than 5. So, a number that will make this inequality true will be less than, but not equal to, 5.

Start by putting an open circle on the number 5. An open circle indicates that 5 is not a value that works in this inequality. Then, we know that our values that make this inequality true are less than 5, so we'll draw an arrow from the circle to the left as numbers to the left of 5 are less than it.

Hope this helps!

Answer:

300 points

Step-by-step explanation:

Since we have a constant rate (12.5 points/game), we can find the number of points by setting up a proportion:

[tex]\frac{12.5}{1}=\frac{x}{24}\\\\x=(12.5*24)=300[/tex]

The sum of the given series is 49 and it converges to infinity.

According to the statement

we have given that a series which is 7, -8, 64/7, 512/49

And we have to find that the series is converges or diverges.

So, For this purpose,

The nth term in the series is 6 multiplied by the (n-1)th power of -8/7:

So,

[tex]a_{1} = 7(\frac{-8}{7} )^{1-1}[/tex]

[tex]a_{2} = -8(\frac{-8}{7} )^{2-1}[/tex]

[tex]a_{3} = \frac{64}{7} (\frac{-8}{7} )^{3-1}[/tex]

And so on then

Sum of the series become to the nth partial sum

[tex]S_{N} = 7(1 +\frac{-8}{7} + ......+ (\frac{-8^(n-2)}{7^(n-2)}) + (\frac{-8^(n-1)}{7^(n-1)}))[/tex]

Multiplying both sides by -8/7 gives

[tex]\frac{-8}{7} S_{N} = 7(\frac{-8}{7} +\frac{-8^{2} }{7^{2}} + ......+ (\frac{-8^(n-1)}{7^(n-1)}) + (\frac{-8^n}{7^n}))[/tex]

and subtracting this from [tex]S_{N}[/tex] gives

[tex]\frac{-1}{7} S_{N} = 7(1-\frac{-8^n}{7^n} )[/tex]

[tex]S_{N} = 49 (-1 + (8/7)^n)[/tex]

Now the sum of the series is 49 and the it converges to infinity.

So, The sum of the given series is 49 and it converges to infinity.

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Answer:

Step-by-step explanation:

let the ratio of men women and children be 13x 5x and 7x

now

13x + 5x + 7x = 4152

25x = 4152

x = 4152/25

x = 166.08

Answer:

4230.44

Step-by-step explanation:

The square root of the quantity x plus 7 end quantity minus 1 equals x=2.

To find the square root:

Check for extraneous solutions:

Therefore, the square root of the quantity x plus 7 end quantity minus 1 equals x = 2.

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The correct question is given below:
The square root of the quantity x plus 7 end quantity minus 1 equals x

The Laplace transform of the given function is [tex]f(s)=\frac{1-e^{-5s}(1-5s) }{s^{2} }[/tex]

Given,

[tex]f(t)=\left \{ {{t, 0\leq t < 5} \atop {0,t\geq 5}} \right.[/tex]

Write the function in unit step function.

[tex]f(t)=t(u_{0}(t)-u_{5} (t))[/tex]

      = [tex]t(1-u_{5}(t))[/tex]                       ∵[tex]u_{0} (t)=1[/tex]

      = [tex]t-tu_{5} (t)[/tex]

[tex]f(t)=t-tu_{5} (t)[/tex]

In order to make it easier to take the Laplace transform of the function, we can follow the steps:

[tex]f(t)=t-tu_{5} (t)[/tex]

      = [tex]t-(t-5+5)u_{5} (t)[/tex]

      = [tex]t-(t-5)u_{5} (t)+5u_{5} (t)[/tex]

[tex]f(t)=t-(t-5)u_{5} (t)+5u_{5} (t)[/tex]

We need to find the Laplace transform of f(t).

Apply Laplace transform on both sides,

£[tex][f(t)=[/tex]£[tex](t)-[/tex]£[tex](t-5)u_{5} (t))+5[/tex]£[tex](u_{5} (t))[/tex]

         = [tex]\frac{1}{s^{2} } -e^{-s}[/tex]£[tex](t)+5(\frac{e^{-5s} }{s} )[/tex]

         = [tex]\frac{1}{s^{2} } -e^{-5s} (\frac{1}{s^{2} } )+\frac{5se^{-5s} }{s^{2} }[/tex]

        = [tex]\frac{1-e^{-5s}+5se^{-5s} }{s^{2} }[/tex]

       = [tex]\frac{1-e^{-5s}(1-5s) }{s^{2} }[/tex]

[tex]f(s) =\frac{1-e^{-5s}(1-5s) }{s^{2} }[/tex]

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The correlation coefficient of r = 0.51 shows that it's an accurate value for this data.

A scenario that would be a causal relationship can be the quantity of fertilizer used vs kg of pumpkins picked on the farm

There is a correlation between the number of hours of sunlight that a plant receives and the height to which it grows.

The function that best fits the data is y = 3x + 4.

The y-intercept indicates that the plant started at 4cm and the slope shows that with each hour of sunlight, the plant grows 3 inches.

The association between two variables that are correlated can be shown by a scatter plot which has a trendline along which the data points are located.

A correlation coefficient of r = 0.51 is accurate based on the scatter plot given. If the trendline slopes upwards from the left to the right, it shows a positive correlation and vice versa.

A scenario that would be a causal relationship can be the quantity of fertilizer used vs kg of pumpkins picked on the farm.

There is a direct correlation between the number of hours of sunlight that a plant receives and the height to which it grows. This can be seen through the growth in the plant.

The function is y = 3x + 4

When x = 0, y = 3(0) + 4 = 4.

In conclusion, y-intercept indicates that the plant started at 4cm and the slope shows that with each hour of sunlight, the plant grows 3 inches.

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The first five terms of the recursively defined sequence are 6, 12, 48, 768, 196608

For given question,

We have been given the recursive formula of a sequence.

[tex]a_{k+1}=\frac{1}{3}{a_k}^2[/tex]

Also, the first term of the sequence is,

a1 = 6

Substitute k = 1 in given recursive formula.

⇒ [tex]a_{1+1}=\frac{1}{3}{a_1}^2[/tex]

⇒ a2 = 1/3 (6)²

⇒ a2 = (1/3) × 36

⇒ a2 = 12

Substitute k = 2 in given recursive formula.

⇒ [tex]a_{2+1}=\frac{1}{3}{a_2}^2[/tex]

⇒ a3 = (1/3) × (12)²

⇒ a3 = (1/3) × 144

⇒ a3 = 48

Substitute k = 3 in given recursive formula.

⇒ [tex]a_{3+1}=\frac{1}{3}{a_3}^2[/tex]

⇒ a4 = (1/3) × (48)²

⇒ a4 = (1/3) × 2304

⇒ a4 = 768

Substitute k = 4 in given recursive formula.

⇒ [tex]a_{4+1}=\frac{1}{3}{a_4}^2[/tex]

⇒ a5 = (1/3) × (768)²

⇒ a5 = (1/3) × 589824

⇒ a5 = 196608

Therefore, the first five terms of the recursively defined sequence are 6, 12, 48, 768, 196608

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[tex]c^2 = a^2 + b^2 - 2ab \cos C \\ \\ 55^2 = 24^2 + 40^2 - 2(24)(40)\cos C \\ \\ \cos C=\frac{55^2 - 24^2 - 40^2}{-2(24)(40)} \\ \\ C=\cos^{-1} \left(\frac{55^2 - 24^2 - 40^2}{-2(24)(40)} \right) \\ \\ \cos C=-\frac{283}{640} \\ \\ C=\boxed{\arccos \left(\-frac{283}{640} \right)}[/tex]

[tex]C=\boxed{\arccos \left( - \frac{283}{640} \right)}[/tex]