Cal made the graph at right. Use the graph to write a problem involving fractions.

Cal Made The Graph At Right. Use The Graph To Write A Problem Involving Fractions.

Answers

Answer 1

We need to come up with a question involving the graph.

Very simple!

We can ask how much time in a day Cal spends for different activities.

We can say:

According to the graph, how much time of the day does Cal spend studying and sleeping?

answering this question:

[tex]\begin{gathered} \frac{1}{8}+\frac{1}{3} \\ =\frac{3(1)+8(1)}{3\times8} \\ =\frac{3+8}{24} \\ =\frac{11}{24} \end{gathered}[/tex]


Related Questions

A pipe is at least 21 feet long and you want to cut it into three pieces

Answers

The length of the each piece of pipe is 7 feet

What is Length?

Distance is measured in length. Length has the dimension of distance in the International System of Quantities. The majority of measurement systems choose a base unit for length from which all other units are derived. The meter serves as the foundational unit of length in the International System of Units.

Given,

Total length of the pipe = 21feet

The pipe after 3 pieces = ?

We have to find the length of pipe after it is cut down into three piece

To find that we have to divide the length of the pipe with 3

The length of 3 pieces = 21/3

                                      = 7 feet

Hence, The length of each piece will be 7 feet  

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Solve: 4,557 ÷ 22 A 27332 B 222073 C 207422 D 207322
plssss i really need a answer fast!!

Answers

C or D pretty sure it's d

4,557 divided by 22is about 207.1364

Tracy opened a savings account and deposited $600.00. The account earns 4% interest,compounded annually. If she wants to use the money to buy a new bicycle in 3 years, howmuch will she be able to spend on the bike?Round your answer to the nearest cent.

Answers

The compound interest formula is:

[tex]C(n)=P\lbrack(1+i)^n-1\rbrack[/tex]

Where:

C(n) is the interest generated after n periods

P is the principal value, the values deposited initially.

i is the annual interest rate in percentage terms.

n is the number of compounding periods.

In this case:

P = $600.00

i = 0.04 (converted from percentage to decimal by dividing by 100

n = 3 years

Then:

[tex]C(3)=600.00\lbrack(1+0.04)^3-1\rbrack[/tex]

Then solve:

[tex]C(3)=600\lbrack1.04^3-1\rbrack=600\lbrack1.124864-1\rbrack=600\cdot0.124864=74.9184[/tex]

This is the amount of interest generated over 3 years. The total amount then will be the initial amount plus the interest generated:

[tex]600+74.9184=674.9184[/tex]

Rounded up to the nearest cent, the amount she will be able to spend after 3 years is $674.91

DIRECTIONS: Use this information to answer Parts A and B.
Marisol deposits $5,000 in a savings account earning 5.75% simple interest per year.
Part A
How much interest will Marisol earn for a period of 5 years?
Part B
Marisol receives 8,450 when she close her savings account if she made no changes to the account, for how many years did Marisol keep the account open?

Answers

Answer: 287.&. Multiply 365 x 10 Great, you get 3650 . . . Multiply 287 by 3650 which then equals 1049375 . . . Wow! The interest will then be a total of 60929$ with the 8450 that she recieved that should equal 3 years total keeping it open . . .

Step-by-step explanation: Hope This Helps! Pls mark Branliest!

1....
1) 3х = 27
2) 5х-2 = 25
3) (1/7)х = 49
4) 2х+8 = 1/32
5) 6х-4 = 36
6) 3х+2+3х = 90

2...
1) 2х = 32
2) 6х-3 = 36
3) (2/3)х = 1,5
4) 52х-1 = 0,2
5) 9х-1 = 81
6) 2х+1+2х = 96

Answers

Answer:

Step-by-step explanation:

3x=27

please help me solve this please and thank you m8

Answers

We will hve the following:

[tex](5x+8)(x^3-x-4)=(5x^4-5x^2-20x)+(8x^3-8x-32)[/tex][tex]=5x^4+8x^3-5x^2-28x-32[/tex]

To indirectly measure the distance across a lake, Jeremiah makes use of a couplelandmarks at points O and P. He measures NR, RP, and Q R as marked. Find thedistance across the lake (OP), rounding your answer to the nearest hundredth of ameter.

Answers

Notice that triangles NPQ and NRQ are similar, then:

[tex]\frac{OP}{QR}=\frac{NP}{NR}.[/tex]

Now, notice that:

[tex]PN=NR+RP.[/tex]

Therefore:

[tex]\frac{OP}{QR}=\frac{NR+RP}{NR}.[/tex]

Multiplying the above result by QR we get:

[tex]\begin{gathered} \frac{OP}{QR}\times QR=\frac{NR+RP}{NR}\times QR, \\ OP=\frac{NR+RP}{NR}\times QR. \end{gathered}[/tex]

Substituting NR=125m, RP=65m, and QR=106.75m we get:

[tex]OP=\frac{125m+65m}{125m}\times106.75m.[/tex]

Simplifying the above result we get:

[tex]\begin{gathered} OP=\frac{190m}{125m}\times106.75m \\ =162.26m. \end{gathered}[/tex]

Answer:

[tex]OP=162.26m.[/tex]

For y = 10*0.5^x , doesthis model exponential growth or decay? Explain how you know.

Answers

Answer:

Exponential decay

Explanation:

The exponential functions have the following form:

[tex]y=a\cdot b^x[/tex]

If b is a number greater than 1, the equation models exponential growth, and if b is lower than 1, the equation models an exponential decay.

Since the equation is:

[tex]y=10\cdot0.5^x[/tex]

We can say that the value of b is 0.5. 0.5 is lower than 1, so this equation models exponential decay.

Find the radius of the given circle with the given central angle and arc length. Round your answer to the nearest tenth.

Answers

The arc length, when the central angle is measure in degrees, is given by:

[tex]s=2\pi r(\frac{\theta}{360})[/tex]

In this case the arc length is 19.6 cm and the angle is 130°, plugging these values we have that:

[tex]\begin{gathered} 19.6=2\pi r(\frac{130}{360}) \\ r=(\frac{19.6}{2\pi})(\frac{360}{130}) \\ r=8.6 \end{gathered}[/tex]

Therefore, the radius is 8.6 cm

multiply the following decimals-0. 8 • (-0.3) • (-0.4) = -0. 096

Answers

Remember when we multiply negative numbers we need to be careful in the sign

[tex]-0.8\cdot-0.3\cdot-0.4=-0.096​[/tex]

Remember when we multiply decimals, first multiply as if there is no decimal. Next, count the number of digits after the decimal in each factor. Finally, put the same number of digits behind the decimal in the product.

Use the given information to find the unknown value:y varies inversely with a. When x = 4, then y= 4. Find y when I = 2.Iyy =help (numbers)

Answers

Inverse variation:

[tex]y=\frac{k}{x}[/tex]

k is a constant

Use the given information (when x=4 y=4) to find the value of the constant:

[tex]\begin{gathered} 4=\frac{k}{4} \\ \\ \text{Multiply both sides of the equation by 4:} \\ 4\times4=4\times\frac{k}{4} \\ \\ 16=k \\ \\ \\ k=16 \end{gathered}[/tex]

Then, the given relationship has the next equation:

[tex]y=\frac{16}{x}[/tex]

Use the equation above to find y when x=2:

[tex]\begin{gathered} y=\frac{16}{2} \\ \\ y=8 \end{gathered}[/tex]Then, when x=2, y=8

Erin receives a 20% employee discount at the camera store where she works. She alsoreceives a $10 off the price on Wednesdays.a. Write a function e(p) that calculates Erin's new price after the employee discount(hint: what percent of the original price does she have to pay?)ep) =B. Write a function a(p) that calculates Erin's new price using her Wednesday discountonlya (p) =C. Write the function e(a(p))e a(p)) =D. What would Erin's final price be for a $400 camera she purchases on a Wednesday?

Answers

ANSWERS

A. e(p) = 0.8p

B. a(p) = p - 10

C. e(a(p)) = 0.8p - 8

D. $312

EXPLANATION

A. The employee discount is 20%. To the total price, which is 100%, we have to subtract the 20% to find the final price of the product. If the price is p, then the price after the employee discount would be,

[tex]e(p)=(1-0.2)p=0.8p[/tex]

Hence, the function is e(p) = 0.8p

B. On Wednesdays, Erin gets a $10 discount on the price p of a product in the store, so if she buys on a Wednesday, she would pay a(p) = p - 10.

C. Now we have to find the function e(a(p)). This is a composition, where we have to replace p with a(p) in function e(p),

[tex]e(a(p))=0.8a(p)=0.8(p-10)=0.8p-0.8\cdot10=0.8p-8[/tex]

Hence, the function is e(a(p)) = 0.8p - 8

D. If Erin buys a $400 camera on a Wednesday she will get both discounts: the employee discount and the Wednesdays discount. To find the final price for a selling price of p = 400, we have to use the function found in part C,

[tex]e(a(400))=0.8\cdot400-8=320-8=312[/tex]

Hence, the final price for the $400 camera is $312, after both discounts.

3) Write 3 different ratios that are equivalent to 7 : 3

Answers

From the given problem, we have a ratio of 7 : 3.

Just any number to the ratio to get as many ratios as you want.

Sinec we only need 3 ratios,

multiply, 2, 3 and 4

The ratios will be :

14 : 6

21 : 9

28 : 12

find the value of given​

Answers

The value of (p² + 1/p²) and (p + 1/p)²is 18 and 20 respectively.

The above question is from algebra section and is from the topic surds and indices.

One of the standard formula is

(a - b)² = a² - 2ab +b²

(i) Here the expression is

p - 1/p = 4 and we need to find the value of p² + 1/p²

(p - 1/p)² = p² + 1/p² -2p(1/p)

4² = p² + 1/p² - 2

16 + 2 =  p² + 1/p²

p² + 1/p² = 18

(ii) we need to find the value of (p + 1/p)²

(a + b)² - (a - b)² = 4ab

(p + 1/p)² - (p - 1/p)² = 4p(1/p)

(p + 1/p)² - 4² = 4

(p + 1/p)² = 4 + 16

(p + 1/p)² = 20

Therefore, the value of (p² + 1/p²) and (p + 1/p)² is 18 and 20 respectively.

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How do I Simplify (6 — 4i) — (і +5)?

Answers

To simplify (6 - 4i) - (і +5), you have to apply associative property.

First step is to remove the parenthesis, then you have:

[tex]6\text{ - 4i - i + 5}[/tex]

Now collect like terms:

[tex]\begin{gathered} 6\text{ + 5 - 4i - i} \\ =\text{ 11 - 5i} \end{gathered}[/tex]

ANSWER:

[tex]11\text{ - 5i}[/tex]

x-y=3, 2x-y=5 what’s the solution

Answers

Answer:

x = 2, y = -1

Solve the following system:

{-y + x = 3 | (equation 1)

-y + 2 x = 5 | (equation 2)

Swap equation 1 with equation 2:

{2 x - y = 5 | (equation 1)

x - y = 3 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{2 x - y = 5 | (equation 1)

0 x - y/2 = 1/2 | (equation 2)

Multiply equation 2 by 2:

{2 x - y = 5 | (equation 1)

0 x - y = 1 | (equation 2)

Multiply equation 2 by -1:

{2 x - y = 5 | (equation 1)

0 x + y = -1 | (equation 2)

Add equation 2 to equation 1:

{2 x + 0 y = 4 | (equation 1)

0 x + y = -1 | (equation 2)

Divide equation 1 by 2:

{x + 0 y = 2 | (equation 1)

0 x + y = -1 | (equation 2)

Collect results:

Answer: |

| {x = 2

y = -1

I believe that this is truly the answer.

(Find the sum of the infinite geometric series 3 + 12 + 48 + 192 + ...

Answers

Given the Infinite Geometric Series:

[tex]3+12+48+192+...[/tex]

You can find its sum by using this formula:

[tex]S=\frac{a_1}{1-r}[/tex]

Where "r" is the common ratio and the first term is:

[tex]a_1[/tex]

In this case, you can identify that each term is obtained by multiplying the previous term by 4. Therefore:

[tex]r=4[/tex]

You can identify that:

[tex]a_1=3[/tex]

Therefore, you can substitute values into the formula and evaluate:

[tex]S=\frac{3}{1-4}[/tex][tex]\begin{gathered} S=\frac{3}{-3} \\ \\ S=-1 \end{gathered}[/tex]

Hence, the answer is: Option B.

6pq³ x 2p⁹q²
solve this equation please and thanks

Answers

The resulting equation is 12[p^10][q^5].

The expression given to us is "6pq³ * 2(p^9)q²".The first term of the expression contains a constant that is 6.The first term of the expression contains a variable "p" raised to the power of 1.The first term of the expression contains a variable "q" raised to the power of 3.The second term of the expression contains a constant that is 2.The second term of the expression contains a variable "p" raised to the power of 9.The second term of the expression contains a variable "q" raised to the power of 2.We need to multiply the terms in the expression.In order to get the correct result, multiply the constants together and add the powers of the same variables.The final expression is "(6*2)[p^(1+9)][q^(3+2)]".The final expression is "12[p^10][q^5]".Hence, the resulting equation is 12[p^10][q^5].

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use the product to sum formula to help me solve this problem in trig

Answers

Explanation

The product-to-sum formula can be seen below.

[tex]cosAsinB=\frac{1}{2}(sin(A+B)-sin(A-B))[/tex]

Therefore, we can insert the values of the angles into the formula

[tex]\begin{gathered} Cos37.5sin7.5=\frac{1}{2}(sin(37.5+7.5)-sin(37.5-7.5)) \\ =\frac{1}{2}(sin45-sin30) \\ =\frac{1}{2}(\frac{\sqrt{2}}{2}-\frac{1}{2}) \\ =(\frac{\sqrt{2}}{4}-\frac{1}{4}) \\ =\frac{\sqrt{2}-1}{4} \end{gathered}[/tex]

Answer:

[tex]\begin{gathered} A=2 \\ B=1 \end{gathered}[/tex]

Hello! Can you help with part A & B? Thank you!

Answers

we have the functions

[tex]\begin{gathered} g(x)=-2x^2+13x+7 \\ h(x)=-x^2+4x+21 \end{gathered}[/tex]

Part A

Equate both equations

[tex]-2x^2+13x+7=-x^2+4x+21[/tex]

Solve for x

[tex]\begin{gathered} -2x^2+13x+7+x^2-4x-21=0 \\ -x^2+9x-14=0 \end{gathered}[/tex]

Solve the quadratic equation

using the formula

a=-1

b=9

c=-14

substitute

[tex]x=\frac{-9\pm\sqrt{9^2-4(-1)(-14)}}{2(-1)}[/tex][tex]x=\frac{-9\pm5}{-2}[/tex]

The values of are

x=2 and x=7

The answer Part A

The distances are x=2 units and x=7 units

Part B

f(x)=g(x)/h(x)

so

[tex]f(x)=\frac{-2x^2+13x+7}{-x^2+4x+21}[/tex]

Rewrite in factored form

[tex]\begin{gathered} f(x)=\frac{-2(x+\frac{1}{2})(x-7)}{-(x+3)(x-7)} \\ \\ f(x)=\frac{(2x+1)}{(x+3)} \end{gathered}[/tex]

The given function has a discontinuity at x=7 (hole), a vertical asymptote at x=-3

and horizontal asymptote at y=2

If the following function is continuous then what is the value of b?

Answers

Answer:

Explanations:

For a function g(t) to be continuous at t = a:

1) The limit of g(t) must exist at t = a

2) g(a) must exist

3) The limit of g(t) at t = a must be equal to g(a)

[tex]undefined[/tex]

Let f be a differentiable function with f(2)=-3 and f'(2)=-4.

Answers

The value of differentiable function g(x)=x³ × f(x) if f(2)=-3 and f'(2)=-4 is -68.

If the derivative of a function exists at every point inside its domain, the function is said to be differentiable. In particular, f′(a) exists in the domain if a function f(x) is differentiable at x = a.

Given function

g(x)=x³ × f(x)

FInd out -

Value of g′(2) = ?

If f(2) = -3 and f'(2) = -4.

Let us apply the product rule of differentiation of a product of two functions. The product rule states that

d/dx (fg) = d/dx (f) × g + f × d/dx(g)

or

(fg)'(x) = f'(x) × g(x) + f(x) × g'(x).

Observe that if g(x) = x³ × f(x) then

g'(x) = 3x² × f(x) + x³ × f'(x).

Thus, g'(2) = 3 × 2² × f(2) + 2³ × f'(2)

Put the value of f(2) and f'(2)

= 3 × 4 × (-3) + 8 × (-4)

= -36 - 32

= - 68.

Therefore , If f(2)=-3 and f'(2)=-4, the value of the differentiable function g(x)=x³ × f(x) is -68.

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Find the equation of the line in slope intercept form that passes through the point with the given slope. Simplify your answer.

Point (0, 8); Slope = 8

Answers

y=8x+8 because m=8 and the y intercept is 8

5.(A.3A) The table represents some points on the graphof a linear function. What is the slope of thisfunction?х у-6-70-106-1312-16

Answers

The slope of a linear function can be obtained as:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Where (x1,y1) and (x2,y2) are points of the line.

For this problem we just have to pick 2 points from the table (they don't have to be consecutive). I'll pick:

• x1 = 0

,

• y1 = 4

,

• x2 = 2

,

• y2 = 14

And now we compute the slope:

[tex]m=\frac{14-4}{2-0}=\frac{10}{2}=5[/tex]

The slope is 5 (third option)

Determine whether the value is from a discrete or continuous data set.Number of members present at a meeting is 6Is the value from A) discrete B) continuous

Answers

To answer this question we need to understand the difference between discrete and continous data:

• Discrete data can only take certain values along some interval.

,

• Continuous data can take any value along some interval.

In this case we know that there will always be a integer number of people in the meeting, that is, we can only have certain values (we can't have 6.5 people in a meeting).

Therefore, this is a discrete data set.

compare the y-intercepts and the rates of change of the following items. y = -5x + 5 and a line which passes through the points (5, 0) and (-5, 5)

Answers

y-intercepts of line y = -5x + 5 is greater then a line which passes through the points (5, 0) and (-5, 5)

What is Algebraic expression ?

Algebraic expressions are the idea of expressing numbers using letters or alphabets without specifying their actual values. The basics of algebra taught us how to express an unknown value using letters such as x, y, z, etc. These letters are called here as variables. An algebraic expression can be a combination of both variables and constants. Any value that is placed before and multiplied by a variable is a coefficient.

Here the points are (5, 0) and (-5, 5) and it is to find the equation of line passing through these points :

Now using slope formula to find the slope of line m :

m = (y₂-y₁)/ (x₂-x₁)

m = (5-0)/(-5-5)

m = 5/-10

m = -1/2

Let us first find the equation of the line using point-slope equation of line :

(y-y₁) = m(x-x₁)

Substituting all the values in above equation to get the equation of line :

(y-0) = -1/2(x-5)

2y = -x+5

2y = -x + 5

2y = -x +5

y = -x/2 + 5/2

Therefore, the equation of line passing through the points (5, 0) and (-5, 5) is y = -x/2 + 5/2 and its y-intercepts is 5/2

Now, the y-intercepts of line y = -5x + 5 is 5

That is, y-intercepts of line y = -5x + 5 is greater then a line which passes through the points (5, 0) and (-5, 5)

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What is the estimated probability that at least two of the puppies will befemale?A. 6/10 = 60 %B. 5/10 = 50 % C. 7/10 = 70 % D. 4/10 = 40 %

Answers

Answer:

C. 7/10 = 70 %

Explanation:

We are asked to find the total number of outcomes that give us at least 2 female puppies.

Now outcomes 1,2,4,5,7,9, and 10, which are 7 outcomes in total, give us at least two female puppies. Therefore, we can say 7 out of 10 times we get at least 2 female supplies and hence the probability is

[tex]\frac{7}{10}=70\%[/tex]

Cathan and Jakove went out to eat, and the bill for their food was $24.50. If theyleft their server a 20% tip, what was the total cost of their dining experience? *

Answers

[tex]\begin{gathered} \text{The total cost of the experience is } \\ Bill+(Bill\cdot\frac{20}{100}) \end{gathered}[/tex][tex]\begin{gathered} \text{Then, the cost of the experience is } \\ 24.50+(24.50\cdot\frac{20}{100})=24.50+(24.50\cdot0.2) \\ =24.50+4.9 \\ =29.4 \end{gathered}[/tex]

And the cost is $29,40

what’s the correct answer answer asap for brainlist

Answers

Answer:

A. 12

Step-by-step explanation:

The next model of a sports car will cost 3.1% less than the current model. The current model cost $54,000. How much will the price decrease in dollars? What will be the price of the next model?

Answers

Answer:

The price decrease will be $1,674

The price of the next model will be $52,326

Explanation:

Given the cost of the current model as $54,000.

We're told that the next model of the car will cost 3.1% less than the current model, let's go ahead determine the price decrease as seen below;

[tex]54000\times\frac{3.1}{100}=54000\times0.031=\text{ \$1,674}[/tex]

We can see from the above that the price decrease is $1,674.

Let's go ahead and determine the price of the next model as seen below;

[tex]54000-1674=\text{ \$52,326}[/tex]

Therefore, the price of the next model will be $52,326

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