Answer:
Option i
Step-by-step explanation:
The given expression is , 5x² - 3xy .
We can clearly see that there are two terms in the expression , 5x² and 3xy .
Therefore option (i) is correct .
It took Sarah 4 days to write a paper, she wrote 12 pages on day 1, 15 pages on day 2 and 9 pages on day 3. If she wrote 12 pages per day , how many pages did she write on the fourth day ?
Answer:
Option A
Step-by-step explanation:
Sarah took 4 days to write a paper.
She wrote 12 pages per day, so total number of pages she wrote in 4 days = 12 × 4
= 48 pages
On day 1, she wrote number of pages = 12
On day 2, she wrote number of pages = 15
On day 3, she wrote number of pages = 9
On day 4, she wrote number of pages = P
She wrote total number pages in 4 days = 12 + 15 + 9 + P
= 36 + P
Therefore, P + 36 = 48
P = 48 - 36
P = 12
She wrote 12 pages on day 4.
Option A is the answer.
SI SE EXTRAE UNA BOLITA DE UNA CAJA CERRADA CON UNA ABERTURA EN LA PARTE SUPERIOR DE LA MISMA.¿CUAL ES LA PROBABILIDAD DE EXTRAER UNA BOLITA DE COLOR SECUNDARIO? LA CAJA CONTIENE : TRES BOLAS DE COLOR PRIMARIO (1 BOLA ROJA,1 BOLA AMARILLA, 1 AZUL) DOS DE COLOR SECUNDARIO(1 NARANJA,1VERDE)
Answer:
La probabilidad es P = 0.4
Step-by-step explanation:
Sabemos que la caja tiene:
3 bolas de color primario (1 roja, 1 amarilla, 1 azul)
2 de color secundario (1 verde, 1 naranja)
Como la bola la sacaremos al azar, todas las bolas tienen exactamente la misma probabilidad de salir.
Queremos obtener la probabilidad de sacar una bolita de color secundario.
Esta probabilidad se calculará como el cociente entre el número de bolitas que cumplen este requisito (es decir, ser de color secundario, sabemos que hay dos de esas) y el número total de bolitas en la caja ( son 5)
La probabilidad es:
P = 2/5 = 0.4
Escribiendo esto en porcentaje (solo se lo multiplica por 100%) tenemos:
40%
Es decir, hay un 40% de posibilidades de sacar una bolita de un color secundario.
Pleaseeeeeee help its late and i have to get up for camp tmr but I HAVE to finish this :(
Answer:
a. ALL
Step-by-step explanation:
for a relation to be a function it must have exact one output for an input. since all tables have one output for a given input all are functions.
Find the value of x. Round to
the nearest tenth.
17°
47
Х
X =[?]
Answer:
13.7 units
Step-by-step explanation:
Hi there!
The dotted lines and the hypotenuse of the green triangle create a new right triangle, with one of its acute angles measuring 17 degrees and its hypotenuse measuring 47 units.
Given this information and that we must solve for the side opposite the given angle, we can use the sine ratio:
[tex]sin\theta=\frac{opposite}{hypotenuse}[/tex]
Plug in known information
[tex]sin17=\frac{x}{47}\\47*sin17=x\\13.7=x[/tex]
Therefore, the value of x when rounded to the nearest tenth is 13.7 units.
I hope this helps!
What number could replace the box so that the system of equations has
infinitely many solutions?
A. -9
B. 3
C. 9
D. -3
Answer:
d || if its wrong cancel me lol <3
Step-by-step explanation:
If the measure of < A is 99 ° and the measure of < B is 81 ° , then < A and < B are _____.
Select one:
a. complementary angles
b. adjacent angles
c. vertical angles
d. supplementary angles
Answer:
D.supplementary angles
Step-by-step explanation:
81+99=180
sharon is planning a holiday for 4 people for 7 days
just multiply the numbers together, and it gives you 28, which is what she did thought everything
Please help!!
y= 1/2 x + 2
One equation in a system of two linear equations is
shown above. If the system has one solution (x, y),
where x = 2, which of the following could be the
other equation in the system?
A) y = -2x + 4
B) y = -x+ 5
C) y = 2x
D) y = 2x + 1
Answer: B) y = -x+ 5
Step-by-step explanation:
If the x-value in the solution (x, y) is 2, then the y-value is:
[tex]y=\frac{1}{2} (2)+2 = \frac{2}{2} +2=1+2=3[/tex]
So the solution coordinate is (2, 3).
Test each of the answer choices to see if whether the y-value is 3 when the x-value is 2. If it's true, then it could be the other equation in the system.
A) y = -2x + 4
[tex]y = -2x + 4\\\y = -2(2) + 4 = -4 + 4 = 0[/tex]
B) y = -x+ 5
[tex]y = -x+ 5\\y = -(2) + 5 = 5 - 2 =3[/tex]
C) y = 2x
[tex]y=2x\\y=2(2)=4[/tex]
D) y = 2x + 1
[tex]y = 2x + 1\\y=2(2)+1=4+1=5[/tex]
A condition statement is logically equivalent to a biconditional statement. true or false
Answer:
true
Step-by-step explanation:
Because a logically equivalent is the same as biconditional statement
Step-by-step explanation:
hello the answer is true, you can check but it's obviously true
What expression represents the product of b and 34
Answer:
b + 24
Step-by-step explanation:
b and 24 would be b + 24
Solve for x. Round your answer to the nearest tenth if necessary.
Answer:
12.6
Step-by-step explanation:
[tex]\frac{84}{87}[/tex] = [tex]\frac{x}{13}[/tex]
cross multiply
87x = 1092
x = 12.6 rounded
Solve the equation and enter the value of x below. 4(x + 1) = 64
Answer:
15
Step-by-step explanation:
Use the distributive property
4x+4=64, then subtract
4x=60, then divide
x=15
[tex] \huge\boxed{\mathfrak{Answer}}[/tex]
[tex]4(x + 1) = 64 \\ 4x + 4 = 64 \\ 4x = 64 - 4 \\ 4x = 60 \\ x = \frac{60}{4} \\ x = 15[/tex]
=> The answer is 15.
help me pls I dont get this
Answer:
D
Step-by-step explanation:
The answer is D because if you flip those circles down and wrap the rectangle around it will create a cylinder
Find the quotient: 63/-9
Answer:
-7
Step-by-step explanation:
63/9 but there is an odd number of negative numbers so negative answer
Someone pls help me ill give out brainliest pls don’t answer if you don’t know
Answer:
i dont know
Step-by-step explanation:
figure it out yourself
if <ABC measures 100 and is inscribed in a circle O. find <BAO and <BCO
Answer:
<BCO = <BAO = 20degrees
Step-by-step explanation:
If <ABC measures 100 and is inscribed in a circle O. find <BAO and <BCO
To get <BAO and <BCO, we need to get <AOC first.
From the figure, it can be seen that triangle ABC is an isosceles trinagle. Hence;
<BAC + <BCA + 100 = 180
Since <BAC = <BCA
<BAC + <BAC = 180 - 100
2<BAC = 80
<BAC = 80/2
<BAC = 40
Also;
<BAO = <BCO and <BAO = <BAC/2
<BAO = 40/2 = <BCO
Hence <BCO = <BAO = 20degrees
Write an expression for each statement: A truck has a total of a pounds of fruit which were packed in n boxes. How many pounds of fruit are in each box?
Answer:
The answer is "[tex]\text{Total number of boxes} =\frac{a}{n \ boxes}[/tex]"
Step-by-step explanation:
Total pounds carried by the vehicle are "a" pounds.
This will be spread into many boxes, each containing "n" pounds.
It implies that:
[tex]\text{Total pounds = box number} \times \text{amount of pounds from every box} \\\\a = \text{box number} \times n\\\\\text{Box number} = \frac{a}{n \ boxes}[/tex]
Solve for x. Round to the nearest tenth of a degree, if necessary.
Sin (angle) = opposite leg / hypotenuse
Sin(x) = 2.1/4
x = arcsin(21./4)
x = 31.7 degrees
Find the distance between A (2,0,-1) and B (3,1,4) and find the mid-point of line segment AB."
Step-by-step explanation:
To Find :-
Distance between the two points .Solution :-
Using Distance Formula ,
> d = √{ ( 2-3)² + (0-1)² + (-1-4)² }
> d = √{ (-1)² + (-1)² + (-5)² }
> d = √{ 1 + 1 + 25 }
> d = √26 .
Using midpoint formula ,
> m = ( 2+3/2 , 0+1/2 , -1+4/3 )
> m = ( 5/2 , 1/2 , -3/3 )
> m = ( 2.5 , 0.5 , -1 )
Record the length of these
segments
PC =
PC' =
units
units
There's all the lengths so you don't have to search them all up
I NEED HELP ASAP HEELP
Answer:
S > 2kg
Step-by-step explanation:
Can someone help me with this math homework please!
Answer:
(B) h is the function name; t is the input, or independent variable; and h(t) is the output, or dependent variable.
Step-by-step explanation:
You've probably seen this function notation format before, most likely f(x). Other common ones are g(x) and p(x). The f, g, and p are just function names, like the h in this question.
The t in the parentheses is the input, because it's the same as the t in 210 - 15t.
Together, h(t) is the output, which is the exact same as y if you used the formula y = mx + b.
Hope it helps (●'◡'●)
(a) Determine a cubic polynomial with integer coefficients which has $\sqrt[3]{2} + \sqrt[3]{4}$ as a root.
(b) Prove that $\sqrt[3]{2} + \sqrt[3]{4}$ is irrational.
Answer:
(a) [tex]x\³ - 6x - 6[/tex]
(b) Proved
Step-by-step explanation:
Given
[tex]r = $\sqrt[3]{2} + \sqrt[3]{4}$[/tex] --- the root
Solving (a): The polynomial
A cubic function is represented as:
[tex]f = (a + b)^3[/tex]
Expand
[tex]f = a^3 + 3a^2b + 3ab^2 + b^3[/tex]
Rewrite as:
[tex]f = a^3 + 3ab(a + b) + b^3[/tex]
The root is represented as:
[tex]r=a+b[/tex]
By comparison:
[tex]a = $\sqrt[3]{2}[/tex]
[tex]b = \sqrt[3]{4}$[/tex]
So, we have:
[tex]f = ($\sqrt[3]{2})^3 + 3*$\sqrt[3]{2}*\sqrt[3]{4}$*($\sqrt[3]{2} + \sqrt[3]{4}$) + (\sqrt[3]{4}$)^3[/tex]
Expand
[tex]f = 2 + 3*$\sqrt[3]{2*4}*($\sqrt[3]{2} + \sqrt[3]{4}$) + 4[/tex]
[tex]f = 2 + 3*$\sqrt[3]{8}*($\sqrt[3]{2} + \sqrt[3]{4}$) + 4[/tex]
[tex]f = 2 + 3*2*($\sqrt[3]{2} + \sqrt[3]{4}$) + 4[/tex]
[tex]f = 2 + 6($\sqrt[3]{2} + \sqrt[3]{4}$) + 4[/tex]
Evaluate like terms
[tex]f = 6 + 6($\sqrt[3]{2} + \sqrt[3]{4}$)[/tex]
Recall that: [tex]r = $\sqrt[3]{2} + \sqrt[3]{4}$[/tex]
So, we have:
[tex]f = 6 + 6r[/tex]
Equate to 0
[tex]f - 6 - 6r = 0[/tex]
Rewrite as:
[tex]f - 6r - 6 = 0[/tex]
Express as a cubic function
[tex]x^3 - 6x - 6 = 0[/tex]
Hence, the cubic polynomial is:
[tex]f(x) = x^3 - 6x - 6[/tex]
Solving (b): Prove that r is irrational
The constant term of [tex]x^3 - 6x - 6 = 0[/tex] is -6
The divisors of -6 are: -6,-3,-2,-1,1,2,3,6
Calculate f(x) for each of the above values to calculate the remainder when f(x) is divided by any of the above values
[tex]f(-6) = (-6)^3 - 6*-6 - 6 = -186[/tex]
[tex]f(-3) = (-3)^3 - 6*-3 - 6 = -15[/tex]
[tex]f(-2) = (-2)^3 - 6*-2 - 6 = -2[/tex]
[tex]f(-1) = (-1)^3 - 6*-1 - 6 = -1[/tex]
[tex]f(1) = (1)^3 - 6*1 - 6 = -11[/tex]
[tex]f(2) = (2)^3 - 6*2 - 6 = -10[/tex]
[tex]f(3) = (3)^3 - 6*3 - 6 = 3[/tex]
[tex]f(6) = (6)^3 - 6*6 - 6 = 174[/tex]
For r to be rational;
The divisors of -6 must divide f(x) without remainder
i.e. Any of the above values must equal 0
Since none equals 0, then r is irrational
if u={1,2,3,4,5},A={2,4} and Beta {2,5,5}find n(AUB)
u={1,2,3,4,5},A={2,4} and Beta {2,5,5}
now, (AUB)={1,3,3,4,5}
[AUB is the set of all elements of set A and set B without any repetition ]
n(AUB)=5
n(AUB)is the total no of elements in set (AUB)
Three different non-zero digits can be arranged in six different ways to
form six three-digit numbers. If the smallest three of these numbers add
to 540, what is the sum of the largest three numbers?
Answer:
1134
Step-by-step explanation:
We have 3 digits:
a, b, c
a 3 digit number can be written as:
a*100 + b*10 + c*1
Such that these numbers can be:
{1, 2, 3, 4, 5, 6, 7, 8, 9}
Let's assume that:
a < b < c
Then the 3 smaller numbers are:
a*100 + b*10 + c
a*100 + c*10 + b
b*100 + a*10 + c
The 3 larger numbers are:
b*100 + c*10 + a
c*100 + a*10 + b
c*100 + b*10 + a
We know that the sum of the 3 smaller numbers is equal to 540, then:
(a*100 + b*10 + c) + (a*100 + c*10 + b) + (b*100 + a*10 + c) = 540
Let's simplify this:
(a + a + b)*100 + (b + c + a)*10 + (c + b + c) = 540
(2a + b)*100 + (b + c + a)*10 + (2c + b) = 540
The sum of the 3 larger numbers is equal to X, we want to find the value of X:
(b*100 + c*10 + a) + (c*100 + a*10 + b) + (c*100 + b*10 + a) = X
Now let's simplify the left side:
(b + c + c)*100 + (c + a + b)*10 + (a + b + a)*1 = X
(b + 2*c)*100 + (c + a + b)*10 + (2a + b) = X
Then we have two equations:
(2a + b)*100 + (b + c + a)*10 + (2c + b) = 540
(b + 2*c)*100 + (c + a + b)*10 + (2a + b) = X
Notice that the terms are inverted.
By looking at the first equation, we can see that:
(2c + b) = 10 (because the units digit of 540 is 0)
Then, we can see that:
(b + c + a + 1 ) = 14 (the one comes from the previous 10)
finally:
(2a + b + 1) = 5 (the one comes from the previous 14)
Then we can rewrite:
(2*c + b) = 10
(b + c + a) = 14 -1 = 13
(2a + b) = 5 - 1 = 4
Now we can replace these 3 in the equation:
(b + 2*c)*100 + (c + a + b)*10 + (2a + b) = X
(10)*100 + (13)*10 + 4 = X
1000 + 130 + 4 = X
1134 = X
The sum of the 3 largest numbers is 1134.
I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.
Hello,
[tex]m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\[/tex]
[tex]cos(30^o)=\dfrac{\sqrt{3} }{2} \\[/tex]
In the triangle ABC,
[tex]cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\[/tex]
[tex]sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}[/tex]
In the triangle ACB,
[tex]cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\[/tex]
what is 9.7 as a fraction ?
Answer:
Step-by-step explanation:
9.7 = [tex]\frac{97}{10}[/tex]
Count the number of places in the decimal number after the decimal point.
Here , there is only one place.
So, multiply and divide by 10. 9.7 *10/1*10 = 97/10
help leee plzzzzzzzbbbnbbbb
Which of the following equations correctly represents the law of cosines?
A. 2 = 22 + b2 - 2ab.cos(B)
B. 2 = 22 + c2 - 2ac.cos(C)
C. a2 = b2 + c2 - 2bc.cos(A)
D. b2 = 22 +62 - 2bc.cos(B)
Answer:
D. b2 = 22 + 62-2bc.cos(B)
does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?
Given equation of the Circle is ,
[tex]\sf\implies x^2 + y^2 = 25 [/tex]
And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,
[tex]\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2[/tex]
Here we can say that ,
• Radius = 5 units
• Centre = (0,0)
Finding distance between the two points :-
[tex]\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }[/tex]
Here we can see that the distance of point from centre is less than the radius.
Hence the point lies within the circle .
Answer:
these points lie INSIDE THE CIRCLE
Hope it helps
have a nice day
