The form of kinetic energy is that is larger is translational kinetic energy.
The translational kinetic energy is given by,
TK = 1/2mv²
m is the mass of the sphere,
v is the translational speed of sphere.
The rotational kinetic energy is given by,
RE = 1/2IW²
I is the moment of inertia,
W is the angular speed of the sphere.
The moment of inertia of the solid sphere is 2/5mr²
r is the radius of the sphere,
Angular speed W = v/r
Putting these values,
RE = 1/2 x 2/5mr² x v²/r²
RE = (1/2 x 2/5)mv²
RE = 1/5mv²
Comparing both the energy we can see,
The translational kinetic energy is more as compared to rotational kinetic energy.
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In order for work to be done on an object, the force must be in the same direction as the object moves. true or false?
Answer:
True
Explanation:
because in science work is only said to be done when the body moves through the distance of the force applied
Vector A is 3.2 m in length and points along the positive y-axis. Vector B is 4.6 m in length and points
along a direction 195° counterclockwise from the positive x-axis. What is the magnitude of the resultant
when vectors A and B are added?
A ball is thrown horizontally with a velocity of 12m / s . How long will it take for the ball to hit the ground if it is released 3.5 m from the ground ? Assume no air resistance
A.3.4s
B.1.1s
C.0.85s
D.0.30s
The time taken by the ball is 0.30s.
What is the time taken?We know that the horizontal velocity has to do with the speed of the object has it moves along a horizontal path. In this case, we can see that the ball is thrown horizontally with a velocity of 12m / s. We have also been told in this question as we have it here to assume that there was no air resistance that is involved.
Thus we have;
Horizontal speed of the ball = 12m / s
Distance covered by the ball = 3.5 m
Let us see that;
V = s/t
V = speed
s = distance
t = time
t = s/V
We should now have;
t = 3.5 m/12 m/s
t = 0.30s
We can now see that the time that t would take the ball to hit the ground is 0.30 seconds of time.
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Answer:
Explanation:
Given:
Vₓ = 12 m/s
H = 3.5 m
g = 9.8 m/s²
__________
t - ?
According to the principle of independence of motion, we find the fall time from the formula:
H = g·t²/ 2
t = √ (2·H / g)
t = √ (2·3.5 / 9.8 ) ≈ 0.85 s
Correct answer:
C. 0.85 s
a rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below. if the plane is traveling horizontally with a speed of 69.4 m/s how far in advance of the recipients (horizontal distance) must the goods be dropped?
4.80m is the far of the recipients must goods dropped.
What is speed?The speed of an object is the rate at which it moves through space. A slow-moving object travels a relatively short distance in a given amount of time, whereas a fast-moving object travels a long distance in a short amount of time.
A)Since we are aware that the plane's vertical speed is zero
In this instance, the mass is dropped with no beginning speed.
thus, we will
y=1/2gt²
235=1/2(9.81)t²
t=6.92s
Consequently, it is given as the horizontal distance it moved.
d=vt
d=(69.4)(6.92)
d=480.4m
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you toss a ball straight upward so it leaves your hand at a speed of 10.1 m/s. if the 3.3 kg ball started at rest and the tossing action lasted 0.33 s, what was the strength of the force exerted on the package by your hand?
The strength of the force exerted on the package by your hand: 101 N
We know v = u+at
v =10.1 m/s
u = 0
t =0.33 s
10.1 = 0+a*0.33
10.1 = a*0.33
a = 30.6 m/s^2
Force exerted F = ma
= 3.3*30.6
= 101
F = 101 N
What is Force ?A force is an effect that can change the motion of an object. Under the influence of a force, an object with mass can change its speed (e.g. move from standstill), i.e. to speed up A force can also be intuitively described as a push or a pull. A force has both magnitude and direction, so it is a vector quantity. It is measured in SI units Newton (N). Power is represented by the symbol F (formerly P).
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What do you think happens to a sound wave when the volume of sound increase
Answer:
sound wave's amplitude relates to the change in pressure caused by the wave measured at a specific location. The sound is perceived as louder if the amplitude increases, and softer if the amplitude decreases.
a constriction in a pipe reduces its diameter from 6.5cm to 2.7cm. where the pipe is wider, the fluid velocity is 8m/s. find the fluid velocity where the pipe is narrow. answer in units of m/s
The velocity of the fluid where the pipe is narrow s 46.36m/s.
The diameter of the larger end of the constriction pipe is 6.5 cm and the diameter of the narrow end of the pipe is 2.7cm.
According to equation of continuity, the volume of the fluid incoming is equal to the volume of the fluid outgoing.
So, we can write,
A₁V₁ = A₂V₂
A₁ and V₁ are the area and speed at the larger end and A₂ and V₂ are area and speed at the narrow end.
Putting values,
π(6.5/2)².8 = π(2.7/2)².V
V = 46.36m/s
The velocity of the fluid where the pipe is narrow is 46.36m/s.
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a longitudinal wave is observed. Exactly 6 crests are observed to move past a given point in 9.1 s. Its wavelength is 2.4 m and its frequency is 0.66 HZ. What is the speed of the wave.
The speed of the longitudinal wave is 1.584 or approximately 1.6 meters per second.
What is a longitudinal wave?Longitudinal waves are waves in which the medium's vibration is parallel to the wave's travel direction and the medium's displacement is in the same direction as the wave's propagation.
Sound waves are one example of longitudinal waves. Waves of ultrasound P-waves from earthquakes
A longitudinal wave's key features include compression, rarefaction, wavelength, amplitude, period, and frequency.
To calculate the above answer multiply wavelength by frequency to get the speed of a wave.
That is:
2.4 x 0.66
= 1.584
Where the frequency is not given beforehand, you can divide 6 crests by 9.1 seconds to determine the frequency.
Hence, the speed of the longitudinal wave is 1.584 which is approximately 1.6.
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a 500 g mass is tied to a string and swung in a horizontal circle with a radius of 40 cm. the speed of the mass is held constant, and the period of rotation is 0.7 s.the direction of the velocity of the object is:
The direction of the velocity of the object is 3.6 m/s.
Velocity is the directional pace of an item in motion as an indication of its rate of exchange in the role as determined from a selected frame of reference and as measured by way of a selected standard of time.
Average velocity is defined as the trade in position or displacement (∆x) divided by the time durations (∆t) wherein the displacement takes place. The common velocity can be effective or negative depending upon the sign of the displacement. The SI unit of average velocity is meters per second (m/s or ms-1).
Given;
m = 500g = 0.5 kg
r = 40 cm = 0.4 m
T = 0.7 sec
The perimeter of circular rotation = 2πr
= 2 ×π (0.4)
= 2.51 m
Speed = distance traveled / total time taken
= 2πr/T
= 2.51/0.7
= 3.59 m/s
speed = 3.6 m/s
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A truck is traveling clockwise around a circular track at a constant speed of 10 m/s.
The track is flat and has a radius of 100 m. While driving around the track, the driver
is describing his experience to his driving coach:
"The whole time I'm traveling around the track, I feel like I'm being pushed to the left
even though I'm constantly turning right. I'm always leaning toward the outside of
the circle."
Which best explains the Physics concept of why the driver felt this?
The best suitable answer is Option 4 " The driver experienced centrifugal "force" which was actually just his inertia .
What is centrifugal force ?
A hypothetical force called centrifugal force, which is unique to particles travelling in a circle, is a force that has the same strength and dimensions as the centripetal force, but acts in the opposite direction.
A stone rotating in a horizontal plane while attached to a string that is fastened to a ground-based post experiences a constant change in velocity and acceleration in the direction of the post. The square of the speed divided by the length of the string gives us the acceleration.
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betelgeuse is a red giant. this means the star is nearing the end of its life, and becoming larger and redder in the process. what's happening to the surface of the star as it becomes redder?
For a solar mass star, the red-giant phase normally lasts just around a billion years overall, with practically all of that time being spent on the red-giant branch.
The phases of horizontal branch and asymptotic huge branch move ten times more quickly.After a star exhausts its hydrogen fuel for nuclear fusion and starts to die, a red giant develops. A star keeps itself stable by carefully balancing the forces of its own gravity, which holds it together, with the pressure exerted outward by continuing thermonuclear fusion reactions occurring at its core.The typical lifespan of red giant stars is between 0.1 and 2 billion years. Red giant stars are significantly less massive and smaller than red supergiant stars.To know more about red-giant
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A TV with the power rating of 200 Watt uses 0.8 kilowatt of electrical energy in one day. For how many hours was the TV on during this day?
The number of hours that the TV was on is four hours.
What is the number of hours that the TV was on?We know that is possible to calculate the cost of electricity and this is done when we convert the electricity to the billing unit that we call the kilowatt hour.
Now we know that;
Power rating of the TV = 200 watt or 0.2 KW
The amount of electricity that was used by the TV in a day = 0.8 KWh
We can now find the number of hours from the relation;
Power rating * time = Energy used
0.2 * t = 0.8
t = 0.8/0.2
t = 4 hours
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a car of mass 1689 kg collides head-on with a parked truck of mass 2000 kg. spring mounted bumpers ensure that the collision is essentially elastic. if the velocity of the truck is (in the same direction as the car's initial velocity) after the collision, what was the initial speed of the car?
If the velocity of the truck is (in the same direction as the car's initial velocity) after the collision, The initial speed of the car is 18.565 km/h.
Let the initial velocity of the car be uc
the truck is parked it implies ut = 0
for a head on elastic collision the final velocities are given by
[tex]vc = - (mt - mc/mt + mc) uc[/tex]
[tex]vt = (2mc/mt + mc)uc[/tex]
Velocity (vt) = 17 Km/hr
uc = 18.565 Km/hr
In physics, a collision, which is also known as an impact, is the abrupt, violent coming together in close proximity of two bodies, such as two pool cues, The force and the amount of time the objects are in touch, in addition to the materials the two objects are made of, have an impact on the outcome of the impact. It is generally knowledge that a hard steel ball dropped on a steel plate would rebound almost to the original position from where it was dropped, while a ball made of putty or lead will not.
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a hot air balloon is rising vertically with a velocity of 10.0 feet per second. a very small ball is released from the hot air balloon at the instant when it is 1280 feet above the ground. use a(t)
the final velocity of the hot air balloon before touching the ground is 286.16 ft/s.
the final velocity can be calculated as follows:
initial velocity of the sphere, u = 10 ft/s
Acceleration due to gravity, g = 32 ft/s²
Ground clearance, h = 1280 feet
The time it takes for the ball to hit the ground is calculated as:
[tex]h= ut +\frac{1}{2}gt^2\\ 1280= 10t + (0.5X 32 )t^2\\1280 = 10t +16t^2\\16t^2+ 10t-960 = 0[/tex]
then we can solve the quadratic equation using formula method
[tex]t=\frac{ -b+/- \sqrt{b^2-4ac} }{2a} \\t = \frac{ -10+/- \sqrt{10^2-4(16X1280)} }{2(16)}\\t= 8.63[/tex]
The final velocity of a hot air balloon is calculated as:
v = u + gt
v = 10 + (8.63 × 32)
v = 286.16 ft/sec
therefore, the final velocity of the hot air balloon before touching the ground is 286.16 ft/s.
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what is an example of a supplementary light source that you might bring to a photo shoot as a photographer?
An example of supplementary light source that you might bring to a photo shoot as a photographer is a : separate flashlight.
Why do you need a flashlight?The flash is very important in photography because it acts as a second light source. It fills in areas where the image is underexposed due to the metering mode of camera prioritizing a different part of the frame, such as the sun in the photo below.
Professional photographers use a flash light frequently, although not the pop up flash on the camera. Photographers generally use an off camera strobe. Common reason to use flash unit is low-light indoor environments.
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why do neutrinos generated in the core of the sun travel to the surface so quickly, compared to gamma ray photons?
Neutrinos generated in the core of the sun travel to the surface so quickly, compared to gamma ray photons because they don't interact with electromagnetic forces.
Neutrinos are neutral, massless particles. Because of their lack of mass, neutrinos can travel through space faster than photons. They have no electric charge, so they don't interact with electromagnetic forces. They also have no strong interactions and only weak ones, which means they can pass through matter without interacting with it at all.
Gamma rays are another type of radiation that originates from nuclear reactions in stars like our sun. however, photons are affected by gravity and other forces just like any other particle would be when moving at these speeds. They're also absorbed by matter much more readily than neutrinos are because they do interact electromagnetically with other particles around them.
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How large a net force is required to accelerate a 2000-kg suv from rest with an acceleration of 0. 14 m/s2?.
Answer:
280 N
Explanation:
Remember F = ma
F = 2000 * .14 = 280 N
An object has an acceleration of 8.0 m/s/s. If the net force experienced by the object is decreased by a factor of 3.7 and if the mass of the object is decreased by a factor of 2.6, then the new acceleration would be ____ m/s/s.
The new acceleration would be 5.62162m/s²
Given - acceleration a=8m/s²
As per question force = F/3.7
and mass = m/2.6
To find :- new acceleration α°
Formula: F=ma
Calculation : F/3.7= [mα°]/2.6
Divide these 2 equations
2.6= 3.7(α°/a)
α°= 2.6 x 8 / 3.7
α°=5.62162m/s²
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A 263 kg crate slides 3.2 m until coming to a stop after being pushed by a large man. The effective coefficient of kinetic friction between the crate and the surface is 0.13. Calculate the work done by friction .
WORK OUT AND USE UNITS
The work done by friction when a crate of 263 kg slides 3.2 m is 1072.2 J.
What is friction?Friction is the force that opposes the motion of two bodies in contact.
To calculate the work done by friction, we use the formula below.
Formula:
W = mgdμ............ Equation 1Where:
W = Work done by frictionm = Mass of the crateg = Acceleration due to gravityd = Distance traveled by the crateμ = Coefficient of kinetic frictionFrom the question,
Given:
m = 263 kgh = 3.2 mg = 9.8 m/s²μ = 0.13Substitute these values into equation 1
W = (263×3.2×9.8×0.13)W = 1072.2 JHence, the work done by friction is 1072.2 J.
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an engineer cuts a 1.0-m-long, 0.33-mm-diameter piece of wire, connects it across a 1.5 v battery, and finds that the current in the wire is 8.0 a. of what material is the wire made?
The resistivity rho of the piece of the wire will be 1.60 × 10⁻⁸ Ωm. So, the material is copper wire.
Copper is the electrical conductor in many categories of electrical wiring. Copper wire is used in power generation, power transmission, power distribution for telecommunications, electronics circuitry, and countless types of electrical equipment.
The resistivity of a material is the resistance of a wire of that material of unit length and unit area of cross-section. Its S.I. unit is ohm-metre.
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a car weighing 13,000 n starts from rest and accelerates to 84.0 km/h in 5.00 s. the friction force is 1,500 n. find the applied force (in n) produced by the engine.
The applied force is 7.68 × 10³N.
What does applied force mean?A force that is applied is one that one object applies to one or more other objects. Applied forces have the power to alter an object's shape, size, state of motion, direction of motion, and other properties.
W = 1.3 × 10⁴
v₁ = 0
v (friction) = 84km/h = 23.3 m/s
t = 5s
f = 1500N
Mass of body = W / g
Mass of body = 1.3 × 10⁴ / 9.8
Mass of body = 1327 kg
v(friction) = v + at
23.3 = 5a
a = 4.66 m/s
Force Net = F₁ + F₂ + F₃ = ma
F (engine) = ma + F
F = 1327 (4.66) + 1500
F = 768.382
F = 7.68 × 10³N.
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8. a car tire has a radius of 0.26 m. a) how far (path length) does a point on the circumference travel if the wheel is rotated through angles of 30 rad? b) if the car travels 80000 km before wearing out the tires, how many revolutions do the tires make, neglecting backing up and any change in radius due to wear?
a point on the circumference travel if the wheel is rotated through angles of 30 rad is 7.8m
4.9 x [tex]10^{7}[/tex] revolutions if the car travels 80000 km.
What is called radian?The Standard International (SI) unit of plane angular measurement is the radian.A full circle has a radius of 2 pi, or approximately 6.28318 radians.One radian therefore equals around 57.296 angular degrees.The Radius of the tyre = 0.26 m.
Perimeter = 2[tex]\pi r[/tex] =0.52[tex]\pi[/tex]m
When the circle is rotated through an 30rad angle, a point of its circumference travels a distance equal to an 30rad arc of this circle.
a full revolution is 2π rad, then an 30rad angle represents
30/2[tex]\pi[/tex] =15/[tex]\pi[/tex]
15/[tex]\pi[/tex] * .52 [tex]\pi[/tex] = 7.8 m
d = 7.8 m.
the car travels 80000 km
revolutions do the tires = 80000 * [tex]10^{3}[/tex]/ 0.52[tex]\pi[/tex]
=4.9 x [tex]10^{7}[/tex] revolutions.
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what is the magnitude of its angular velocity, in radians per second, after a 23 kg child gets onto it by grabbing its outer edge? the child is initially at rest.
The magnitude of the angular velocity of the merry-go-round is equal to 2.39 rad/s after a 23 kg child gets onto it.
What is angular momentum?Angular momentum can be described as the rotational form of linear momentum. It is a physical conserved quantity as the total angular momentum remains constant.
Given, the mass of the child m = 23 Kg
The mass of the merry-go-round M = 125 Kg
The initial speed of the merry-go-round, ω₁ = 0.52 rev/s = 3.27 rad/s
The radius, r = 1.8 m
From the conservation of the angular momentum, we can find the angular velocity:
[tex]I_1\omega_1= (I_1+mr^2)\omega[/tex]
[tex](\frac{1}{2} Mr^2)\omega_1= (\frac{1}{2} Mr^2+mr^2)\omega[/tex]
[tex]\omega =\frac{M.\omega_1}{M+2m}[/tex]
[tex]\omega = \frac{125\times 3.27}{125 +2\times23}[/tex]
ω = 2.39 rad/s
Therefore, the magnitude of its angular velocity after a 23 kg child gets onto it by grabbing its outer edge is 2.39 rad/s.
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Your question was incomplete, but the most probably complete question was,
A playground merry-go-round with a mass of 125 Kg and a radius of 1.8 m is rotating with a frequency of 0.52 rev/s. what is the magnitude of its angular velocity, in radians per second, after a 23 kg child gets onto it by grabbing its outer edge? the child is initially at rest.
an object moves in an xy - plane and has the following coordinates
The x component of the object's velocity is -8 m/s and the y component of the object's velocity at the given time is 7 m/s.
option B is the correct answer
What is the x and y components of the object's velocity?
The x and y components of the object's velocity at the given time is calculated as follows;
x = -3t³ - 5t²
y = 4t² + 3
where;'
x is the x componenty is the y componentt is the timeAt the given time, t = 1 second, the x and y components of the object's velocity is;
x = -3(1)³ - 5(1) = -8
y = 4(1)² + 3 = 7
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For a skateboard with a negative acceleration, which of the following statements is always true?
1. The initial velocity of the skateboard will be greater than it’s final velocity.
2. The skateboard will have a negative displacement.
3. The final velocity of the skateboard will be positive.
4. The final velocity of the skateboard will be negative
5. The skateboard is losing speed
With a negative acceleration, the skateboard's beginning velocity will be higher than its end velocity.
The correcty answer is 1
How do you calculate beginning velocity in the absence of time?Based on the assumption that the object's energy is conserved, its velocity equals the square root of twice square product of the its acceleration or the distance it travels. This relationship also depends on the object's initial velocity.
What are starting and final velocities?When gravity first exerts force on an object, its initial velocity indicates how quickly it moves. The final velocity, on the other hand, is a vector quantity that determines the rate and direction of the a moving body when it has reached its maximum velocity.
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when astronomers have examined rich clusters of galaxies with their instruments, they have found that these clusters
Astronomers have examined rich clusters of galaxies with their instruments, They have found that these clusters have giant elliptical galaxies than poor clusters
what are giant elliptical galaxies?Elliptical galaxies are the most abundant type of galaxies found in the universe but because of their age and dim qualities, they're frequently outshone by younger, brighter collections of stars.
Elliptical galaxies lack the swirling arms of their more well-known siblings, spiral galaxies. Instead, they bear the rounded shape of an ellipse, a stretched-out circle.
One of the most famous elliptical galaxies is Cygnus A, which is located roughly 600 million light-years from Earth and is an extremely bright radio source. Cygnus A is not only well-known to astronomers, but has a place in science fiction; it was featured in the 1985 novel "Contact," a Carl Sagan story that later inspired a Hollywood movie of the same name.
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one way to avoid emi problems is to . select one: a. run low-voltage cable close to power cables b. use fluorescent lights c. use ungrounded metal pathways d. terminate unused conductors at both ends
One way to avoid EMI problems is to use fluorescent lights. Option B.
Fluorescent lights deteriorate quickly especially if they are installed in a place where they are turned on and off frequently. Fluorescent lights shorten their life each time they are turned off and on. This can lead to premature failure and you will end up spending more money replacing bulbs more often.
EMI from fluorescent lighting systems is rare. Designers considering the use of electronic ballasts can greatly reduce the potential for EMI problems with careful planning. EMI is caused by the close relationship between electricity and magnetism. Any flow of electricity creates a small magnetic field. Conversely when the magnetic field moves an electric current is generated.
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A 1.5 kg ball is kicked with an initial velocity of 26 m/s at an angle of 30 degrees above the horizontal. How far did the ball go before returning to the ground? Answer in meters.
The maximum height travelled by the ball before returning to the ground is 8.62 m.
What is the maximum height travelled by the ball?
The maximum height travelled by the ball before returning to the ground is calculated by applying the following kinematic equation as shown below.
H = (u²sin²θ) / 2g
where;
u is the initial velocity of the ballθ is the angle of projection of the ballg is acceleration due to gravityH = (26² (sin 30)²) / (2 x 9.8)
H = 8.62 m
Thus, the maximum height travelled by a projectile depends on the initial velocity and angle of projection.
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Which of acceleration, age, speed, temperature, and velocity are vector quantities?.
Velocity and acceleration are vector quantities whereas speed, temperature and age are not.
What is a vector quantity?Vector is a quantity that has both magnitude and direction and is represented by an arrow whose direction is same as that of the quantity and length is proportional to the quantity's magnitude.
Vector has magnitude and direction but it does not have position. Velocity and acceleration both are vector quantities as they have magnitude and direction.
If the speed of an object remains same but direction changes then the object is accelerating. It is important to remember that acceleration and velocity aren't always in the same direction.
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what is the moment of inertia for a disk with mass of 500g and radius of 12 cm rotated about its diameter? group of answer choices
The moment of inertia for a disk with mass of 500g and radius of 12cm rotated about its diameter is 7.2 × 10-³kgm².
How to calculate moment of inertia?Moment of inertia is a measure of a rigid body's resistance to change in its angular velocity around a given axis.
The formula for the moment of inertia is the “sum of the product of mass” of each particle with the “square of its distance from the axis of the rotation”. The formula of Moment of Inertia is expressed as follows:
I = mr²
Where;
I = moment of inertiam = mass r = radiusAccording to this question, a disk with mass of 500g and radius of 12 cm rotated about its diameter. The moment of inertia can be calculated as follows:
I = 0.5kg × 0.12²m
I = 7.2 × 10-³kgm²
Therefore, 7.2 × 10-³kgm² is the moment of inertia of the disk.
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