Answers
The box is moving at a 2.06 m/s rate.
What causes acceleration?Acceleration is the rate at which velocity changes over time in both the direction and the speed. Anything is said to have been accelerated when it goes faster or slower in a straight line. Even travel on a circle accelerates steadily since the direction is continuously changing.
What metrics are used to quantify acceleration?Acceleration is measured in meters per second per second (m/s2).
Formulas for
F NET are F NET = m and F NET = F1 + F2.
3 + 3 + 7 Equals 13 when F NET is used.
F NET = m * a then,
where a = F NET/m and
a = 13N / 6.3 kg and 2.06m/s respectively.
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Related Questions
Place the red, 100 g ball at the 60 cm mark on the ramp. How far did the box move? a90 cm b0cm cno more that 100 cm
Answers
Answer:
place it on the 50 cm mark
please help me with this homework question I really need help I have till tomorrow to do it
Relate scientific theories to the law of parsimony
Answers
In science, the law of parsimony is used to select between related scientific theories to those that contain a minor number of assumptions.
What is the law of parsimony?The law of parsimony is a well-sustained body of information that shows how the theories that contain a minor number of assumptions before experimentation are generally the correct ones.
Therefore, with this information, we can conclude that the law of parsimony can be used to select scientific theories and this approach is generally accurate to obtain the correct theory to be used due to assumptions that may hamper the scientific results.
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Which path in the figure below would the ball most closely follow after it exits the channel at "y" and moves across the frictionless table top?(B)OBOf(C)*(D)(E)
Answers
Answer:
(B)
Explanation:
When an object ends a circular path, the next path is tangential to the circular path, in this case, the tangential path is (B), so the ball most closely follow path (B).
A ball is thrown up in the air, it reaches its maximum height and falls back. It’s acceleration is:A - same up and down but zero at the topB- less on the way up than on the way downC- the same ally all points of motionD- less on the way down than on the way up
Answers
When the ball is thrown up in the air, it is called a Freefall motion.
In freefall motion, the acceleration remains constant at all times because the acceleration due to gravity is always constant.
The acceleration due to gravity is 9.81 m/s^2
The ball has zero velocity (not acceleration) at the maximum height.
Therefore, the correct answer is option C
"Its acceleration is the same at all points of motion".
Solving For Temperature (T)
7. How many degrees would the temperature of a 450 g piece of iron increase if 7600 J of
energy are applied to it? (The specific heat of iron is0.4494 J/g x °C)
Answers
Temperature is a unit used to represent how hot or cold something is. It can be stated using the Celsius or Fahrenheit scales, among others. Temperature shows which way heat energy will naturally flow, i.e., from a hotter (body with a higher temperature) to a colder (body with a lower temperature) (one at a lower temperature)
Additionally, we are provided the iron's particular heat as well as the iron skillet's mask.
We must determine the required quantity of heat based on this information. It will be Q = c x mass x delta P using this method.
That is the temperature change. Therefore, we can replace the value here. The c represents the iron's particular temperature. That comes to 0.4499.
The supplied mass is 5.07, and the resulting temperature change will be 250 - 25 °C. If we can solve this, we can determine what Q is worth.
Alternately, we might state that the required amount of heat is 512.19 Joules.
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A particle changed q= 3,10x10^-6 C stays still on point P, a second particle with the same value q and a mass of 1,80x10^-2 kg is initially in repose at a distance of r1 = 9,00 cm from point P. This is second particle is released and repelled by the first. Determine the velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P.
note 1: from what i know i have to use the potential energy formula (U= mV^2/2), and possible calculate the electric force ? but from there i get lost
note 2: sorry if this isn't grammatically correct, i translated it from spanish
Answers
The velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P is 17.22 m/s.
What is the electric force between the two particles?The electric force between the two particles is calculated from Coulomb's law of electrostatic force.
F = kq₁q₂/r²
where;
k is Coulomb's constantq₁ is magnitude of first chargeq₂ is magnitude of second charger is the distance between the two chargesF = (9 x 10⁹ x 3.10 x 10⁻⁶ x 3.10 x 10⁻⁶) / (0.09 m)²
F = 10.68 N
The velocity in which this second particle finds itself at a distance r2 = 25,0 cm from point P is calculated by applying the principle of conservation of energy.
W = ΔK.E
where;
W is work doneΔK.E is kinetic energy of the particleFr = ¹/₂mv²
2Fr = mv²
v² = 2Fr/m
v = √(2Fr/m)
v = √(2 x 10.68 x 0.25 / 1.8 x 10⁻²)
v = 17.22 m/s
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Johnny and Francis are participating in the Roller Skating dance championship. While 73.0-kg Johnny roller skates backwards at 3.0 m/s, 57.0-kg Francis jumps into his arms with a velocity of 5.0 m/s in the same direction. How fast do they roll backwards together?
Answers
Given,
The mass of Johnny, m₁=73.0 kg
The mass of Francis, m₂=57.0 kg
The initial velocity of Johnny, u₁=3.0 m/s
The initial velocity of Francis, u₂=5.0 m/s
From the law of conservation of momentum, the total momentum of a system will always remain the same.
Therefore,
[tex]m_1u_1+m_2u_2=(m_1+m_2)v[/tex]Where v is the velocity with which they roll backward together.
On substituting the known values in the above equation,
[tex]\begin{gathered} 73.0\times3.0+57.0+5.0=(73.0+57.0)v \\ v=\frac{219+285}{130} \\ =3.88\text{ m/s} \end{gathered}[/tex]Thus the velocity with which they roll backward together is 3.88 m/s
2. Name the force or forces that cause these objects to
experience changes in motion. Neglect air resistance. Rw
(a) A ball falls toward the ground.
(b) A person accelerates up in an elevator.
(c) A car gradually slows down while approaching a red
light.
Answers
a) A ball falls toward the ground:
The force of gravity is acting on the falling ball. On the surface of the earth, the direction of this force is always downward, towards the ground. It pulls on all objects with mass.
b)A person accelerates up in an elevator:
On the person in the elevator, there are two forces:
1) Normal Force upward, exerted by the floor on the person perpendicular to the surface (“normal” means perpendicular).
2) Gravitational Force downward, exerted by the Earth on the person. This is also called the person’s “weight”.
c) A car gradually slows down while approaching a red light.:
Friction may slow the car down as it moves along the road, but it also is the force that enables the car to move forward at all. It is the friction force that keeps the tires from sliding on the road. By the same token, it is friction that makes the car come to a stop when the brakes are applied.
What is Force ?
An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force. The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force. A spring balance can be used to calculate the Force. Newton is the SI unit of force (N).
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A large truck with mass 30 m crashes into a
small sedan with mass m. If the truck exerts a
force F on the sedan, what force will the
sedan exert on the truck?
A. F
B. 2F
C. F/30
D. 30F
Answers
Option A. F . The force will be the same as the large truck exerts on the small sedan but in opposite direction. according to Newton's third law of motion.
In physics, a force is an influence that can exchange the motion of an item. A pressure can cause an item with mass to trade its velocity, i.e., to boost up. pressure can also be defined intuitively as a push or a pull. A pressure has both significance and course, making it a vector quantity.
The word 'Force' has a specific which means. At this stage, it is completely suitable to describe a force as a push or a pull. Pressure isn't something that an object consists of or 'has in it. Pressure is exerted on one item with the aid of every other. The idea of a force isn't always restrained to living matters or non-living things.
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Given a circuit consisting of a DC battery connected to a single resistor of resistance 16.0 ohms. If the electric current through the resistor is 5.00 Amperes, then which of these is the voltage of the battery in SI units?A)0.00625B)80C)0.00417D)240E)0.00313
Answers
Given:
The resistance in the circuit is R = 16 ohm
The current in the circuit is I = 5 A.
To find the voltage in the circuit.
Explanation:
The voltage in the circuit can be calculated using Ohm's law,
[tex]\begin{gathered} V=5\times16 \\ =80\text{ V} \end{gathered}[/tex]Final Answer: The voltage in the circuit is 80 V.
Draw a supply graph for pizzas. Show what would happen to the supply of pizzas if two more pizzerias open up in town. Identify the determinant of supply that caused the shift.
Answers
Pizza delivery when two more pizzerias in the city start changing their product prices.
All other things being equal an increase in demand will increase the equilibrium price. You will have more to deliver. A decrease in demand leads to a decrease in the equilibrium price. Less quantity to deliver. An increasing change in supply shifts the supply curve to the right, and a decreasing change in supply shifts the supply curve to the left.
Essentially it is an increase or decrease in quantity offered with a higher or lower offer price. As the price of pizza slices rises consumers are more likely to purchase one of these alternatives as a replacement for pizza. This reduces the amount of pizza requested. Higher prices tend to increase supply as more profits are made available.
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Science AssignmentQuestion: Give 20 example each on scalar & vector quantities...
Answers
Scalar: Temperature, mass, distance, time, speed, volume, area, voltage, current, resistance, work, density, energy, amount of substance, luminous intensity, area density, chemical potential, electric current density, capacitance, inductance.
Vector: Displacement, velocity, acceleration, force, position, eletric field, magnetic field, linear momentum, angular momentum, torque, angular velocity, angular acceleration, electric field density, magnetic field density, roll, pitch, yaw, surge, sway, heave.
A vector A has components Ax = −5.50 m and Ay = 7.50 m. Find the magnitude (in m) and the direction (in degrees counterclockwise from the +x-axis) of the vector.magnitude mdirection ° counterclockwise from the +x-axis
Answers
The x-component of vector A is Ax = -5.50 m
The y-component of vector A is Ay = 7.50 m
We are asked to find the magnitude and the direction of the vector (counterclockwise from the +x-axis)
The magnitude of vector A is given by
[tex]\begin{gathered} |A|=\sqrt[]{A_x+A_y} \\ |A|=\sqrt[]{(-5.50)^2+(7.50)^2_{}} \\ |A|=\sqrt[]{30.25+56.25} \\ |A|=\sqrt[]{86.50} \\ |A|=9.3\; m \end{gathered}[/tex]So, the magnitude of vector A is 9.3 m
First, let us draw a diagram to better understand the problem.
The direction of vector A is given by
[tex]\begin{gathered} \tan \theta=\frac{A_y}{A_x} \\ \tan \theta=\frac{7.50}{-5.50} \\ \theta=\tan ^{-1}(\frac{7.50}{-5.50}) \\ \theta=-53.75\degree \end{gathered}[/tex]From the diagram, notice that θ lies in the second quadrant.
So, the counterclockwise direction from the positive x-axis is given by
[tex]180\degree-53.75\degree=126.25\degree[/tex]So, the direction is 126.25° counterclockwise from the +x-axis.
Light normally travels in straight lines. What term is used to describe the bending of light when it crosses from one medium to another?
Answers
The term refraction is used to describe the bending of light when it crosses from one medium to another. The bending of light happens due to the different densities of the two substances.
The position of a particle is given by the vector < 3.3t2 , 3.2 , - 2.4t >. What is the magnitude of the acceleration at t=0?
Answers
The position of a particle is given by the vector < 3.3t² , 3.2 , - 2.4t >. The magnitude of the acceleration at t=0 is 3.3 m/sec².
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.
Given in the question The position of a particle is given by the vector
< 3.3t² , 3.2 , - 2.4t >. The magnitude of the acceleration at t=0.
Differentiating position vector for two times we get acceleration vector,
so acceleration is 3.3 m/sec²
.The position of a particle is given by the vector < 3.3t² , 3.2 , - 2.4t >. The magnitude of the acceleration at t=0 is 3.3 m/sec²
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A puck of mass m = 0.065 kg is moving in a circle on a horizontal frictionless surface. It is held in its path by a massless string of length L = 0.65 m. The puck makes one revolution every t = 0.55 s. what is the magnitude of the tension in the string while the pack is revolving?if the string breaks how fast will the pack move away?
Answers
The centripetal acceleration of an object in circular motion with tangential velocity v if the radius of the trajectory is r, is:
[tex]a_c=\frac{v^2}{r}[/tex]On the other hand, if the period of one revolution is T, then the distance traveled is 2πr (which is the circumference of the trajectory) and the tangential velocity is:
[tex]v=\frac{2\pi r}{T}[/tex]In this case, the radius of the trajectory is the length of the string, 0.65m, and the period is T=0.55s. Substitute these data into the formula to find v:
[tex]v=\frac{2\pi(0.65m)}{0.55s}=7.4256\frac{m}{s}[/tex]Plug in v=7.4256m/s and r=0.65m to find the centripetal acceleration of the puck:
[tex]a_c=\frac{(7.4256\frac{m}{s})^2}{0.65m}=84.83\frac{m}{s^2}[/tex]According to Newton's Second Law of Motion, there must be a net force acting on the object responsible for the centripetal acceleration. That force F is the tension of the string. Then:
[tex]F=m\cdot a_c[/tex]Substitute the value for a and m=0.065kg to find the tension of the string:
[tex]\begin{gathered} F=0.065\operatorname{kg}\times84.83\frac{m}{s^2} \\ =5.51N \end{gathered}[/tex]If the string breaks, the puck will move as fast as its tangential velocity, which is 7.4 m/s.
Therefore, the answers are:
Tension in the string: 5.51N
Speed of the puck if the string breaks: 7.43 m/s
9. How much change in temperature would the addition of 35 000 Joules of heat have ona
538.0 gram sample of copper? (Look up specific heat of copper)
Answers
The change in temperature would be 168.97 °C
Q = cm∆t
Where
Q = Amount of heat energy
c = specific heat capacity of copper metal = 0.385 J/g°C
m = mass of copper
∆t = change in temperature
From the question,
Given:
m = 538 g
c = 0.385 J/g°C
Q = 35 000 Joules
Q = cm∆t
35000 = 0.385 x 538 x ∆t
∆t = 168.97 °C
Hence, change in temperature would be 168.97 °C
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A 150-pound person uses 6.2 calories per minute when walking at a speed of 4 mph. How long must a person walk at this speed to use at least 230 calories?
Answers
The time taken by person to use 6.2 calories is 1 min.
Therefore, the time taken to use 230 calories can be calculated as,
[tex]\begin{gathered} t=\frac{(230\text{ calories)(1 min)}}{(6.2\text{ calories)}} \\ \approx37.1\text{ min} \end{gathered}[/tex]Thus, the time taken to use 230 calories is 37.1 min.
Find the answer to the problem
Answers
Box accelerates at a rate of 3.46 m/s.
How does acceleration work?Acceleration is the rate at which velocity changes over time in both the direction and the speed. Anything is said to have been accelerated when it goes faster or slower in a straight line. Even travel on a circle accelerates steadily since the direction is continuously changing.
What metrics are used to quantify acceleration?meters per second per second (m/s2).
Formula,
F NET = m, F NET = F1 + F2, etc.
F NET equals 33 + 3 = 36 .
Then,
a = F NET/m, where F NET = m. a
a = 36 /10.4
a = 3.46 m/s.
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A wave is represented by the equation y=0.5sin 0.4π(x-60t) where the distance x is measured in cm and time(t) in seconds. what is the wave length of the wave,amplitude and frequency
Answers
The amplitude = 0.5 m
The wavelength = 5 m
The frequency = 12 Hz
Explanation:The given wave function is:
y=0.5sin 0.4π(x-60t)
This can be rewritten as:
y=0.5sin (0.4πx-24πt)................(1)
Comparing the equation above with the general wave function:
y = A sin(kx - wt).................(2)
where A represents the amplitude
k represents the wave number
w represents the angular frequency
By comparing equations (1) and (2):
the amplitude, A = 0.5 m
k = 0.4π
Also k = 2π/λ
0.4π = 2π/λ
λ = 2π/0.4π
λ = 5 m
The wavelength = 5 m
w = 24π
Also, w = 2πf
Therefore, 2πf = 24π
f = 24π/2π
f = 12 Hz
The frequency = 12 Hz
options are 1183420 J730,575 J-452,845 J1183420 Ek730575 Ek-452,845452,845 J-730,575 J-118342p J
Answers
Given:
The initial speed of car is: u = 140 km/h = 140 × 5/18 m/s= 38.889 m/s
The final speed of the car is: v = 110 km/h = 110 × 5/18 m/s = 30.5556 m/s
The mass of the car is: m = 1565 kg
To find:
A) Initial kinetic energy of the car.
B) The final kinetic energy of the car.
C) Work done during the deceleration.
Explanation:
A) The initial kinetic energy of the car can be calculated as:
[tex]KE_i=\frac{1}{2}mu^2[/tex]Substituting the values in the above equation, we get:
[tex]\begin{gathered} KE_i=\frac{1}{2}\times1565\text{ kg}\times(38.889\text{ m/s})^2 \\ \\ KE_i=1183417.27\text{ J} \end{gathered}[/tex]The value of initial kinetic energy is very close to the value 1183420 J given in the options. Thus, the initial kinetic energy of the car is 1183420 J.
B) The final kinetic energy of the car can be calculated as:
[tex]KE_f=\frac{1}{2}mv^2[/tex]Substituting the values in the above equations, we get:
[tex]\begin{gathered} KE_f=\frac{1}{2}\times1565\text{ kg}\times(30.5556\text{ m/s})^2 \\ \\ KE_f=730576.971\text{ J} \end{gathered}[/tex]The value of final kinetic energy is very close to the value 730575 J given in the options. Thus, the final kinetic energy of the car is 730576 J.
C) The work done in the deceleration of the car is calculated by applying the work energy theorem. Thus, we get:
[tex]\begin{gathered} W=KE_f-KE_i \\ \\ W=730575\text{ J}-1183420\text{ J} \\ \\ W=-452845\text{ J} \end{gathered}[/tex]The work done in the deceleration of the car is -452845 J. The work done is negative because the car is decelerating.
Final answer:
A) The initial kinetic energy of the car is 1183420 J.
B) The final kinetic energy of the car is 730575 J.
C) The work done in decelerating the car is -452845 J.
A Petrol flows at 4m/a through a hose of 10mm diameter. What nozzle diameter will dispense it at the rate of 16m/s?
Answers
1cm of the nozzle Diameter will dispense it at the rate of 16m/s.
The continuity equation is what.
A continuity equation, sometimes referred to as a transport equation, is an equation that describes the movement of a certain quantity.
Although it can be applied generally to any significant quantity, it is extremely simple and useful when used with preserved quantities. Continuity equations can be used to explain a variety of physical processes since, under the right conditions, mass, energy, momentum, electric charge, and other natural quantities all remain constant.
From the continuity formula: A 1 V 1 = A 2 V 2.
π(1) 2 ×1=4×πr^ 2 ⇒ 41 =r 2 ⇒r= 21 cm
Thus, the nozzle's diameter is 21 2 cm, or 1 cm.
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28 cubic inches of a gas with an absolute pressure of 35 psi is compressed to a volume of 5 cu.in, what is the new pressure of the gas. (Assume that there's no change in temperature.
Answers
First, we will write the formula we will be using: the Ideal gas law
[tex]PV=nRT[/tex]Now, let's see what is given to us
Volume: 28 Cubic Inches
Pressure: 35 PSI
New Volume: 5 cubic inches
New Pressure?
No change in temperature
Since we know that only the volume is changing, we can simplify the ideal gas law into Boyle's law
[tex]P_1V_1=P_2V_2[/tex]So now, we can subsititute in the values we got.
(28)(35) = 5(P2)
P2 = 196 PSI
With what angular speed, in rad/s, does the Earth rotate about its axis?
Answers
We know that it takes the earth approcimately 24 hours to complete one rotations about its axis.
This means that we can calcuate the angular speed using the following formula:
[tex]\omega=\frac{\theta}{t}[/tex]Where:
[tex]\begin{gathered} \theta=\text{ angle in radians} \\ t=\text{ time} \end{gathered}[/tex]We will convert the time from hours to second using the following conversion factor:
[tex]1h=3600s[/tex]Now, we mutiply noth sides by 24 and we get:
[tex][/tex] Two identical metallic spheres A and
B, each carrying a charge of q C, are fixed.
They repel each other with a force of
2x10-5 N. Another identical uncharged
sphere C is made to touch A, moved to
touch B, and placed halfway between A
and B. What is then the electric charge
and the electric force (in N) on each
sphere in terms of q?
Answers
The electric charge and the electric force on each sphere in terms of q is 2
The Electric Charge and Electric ForceThe ability of particles or objects to attract or repel one another without coming into contact is known as electric charge. Incompatiblely charged particles are drawn to one another. Like-charged particles repel one another. Electric force is the name given to the force of attraction or repulsion.
Two metallic spheres, a and b, with a charge of half and a force of two tens of five
F1=k(1/2)(1/2)/r2
Equation F1=k/4r
A and C are two metallic spheres, respectively, so
Equation F2=k/2rsquare
equ1/equ2
2×10^-5/F2=k/4r^2×2r^2/k
F2=4×10^-5
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L../IN10. An object of mass 60.986 kg is sliding on a horizontalsurface with a uniform speed. The coefficientof kinetic fiction of the surfaces is 0.15. Calculatethe force of friction exerted by the surface on the object. (1 point)A. O 101.798 NB. O114.077 NC. 050.2 ND. 145.451 NE. O 89.649 N
Answers
Given:
The mass of the object is,
[tex]m=60.986\text{ kg}[/tex]The coefficient of friction is,
[tex]\mu=0.15[/tex]The object is sliding on the horizontal surface at a uniform speed.
To find:
the force of friction exerted by the surface on the object
Explanation:
If we draw the free body diagram of the object we see,
The normal reaction is R, the applied force is F, and the frictional force isf.
As the object is continuing its constant speed, we can say the object is in equilibrium.
So,
[tex]R=mg[/tex]and
[tex]\begin{gathered} f=F=\mu R \\ f=\mu mg \\ f=0.15\times60.986\times9.8 \\ f=89.649\text{ N} \end{gathered}[/tex]Hence, the friction force exerted by the surface is 89.649 N.
A storage tank 20 m high is filled with pure water. (Assume the tank is open and exposed to the atmosphere at the top.)
(a) Find the gauge pressure at the bottom of the tank.
(b) Calculate the magnitude of the net force that acts on a square access hatch at the bottom of the tank that measures 0.6 m by 0.6 m.
PLEASE HELP ASAP!!!
Answers
A. The overpressure at the bottom of the tank is 297500 N/m².
B. The magnitude of the net force acting on the square access hatch at the bottom of the tank is 107100 N.
Multiplying the flow rate by the minimum operating time of the pump gives the descending capacity. As a rule of thumb for a minimum run time, a pump operating at 10 gallons per minute GPM or less should produce a run time of 1 gallon per minute. For example, 10 GPM flow rate x 1 = 10 gallon drawdown capacity.
This means that the gauge pressure is equal to the absolute pressure minus the atmospheric ambient pressure. If the absolute pressure is greater than the atmospheric pressure it is called positive overpressure. If the absolute pressure is lower than atmospheric pressure it is called negative overpressure. The hydrostatic pressure at any height below water is calculated by P = hdg. where h is the height below open water.
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Is nuclear energy apart of physics ?
Answers
Yes, the nuclear energy is a part of physics
Nuclear energy:
It basically originates from the splitting of uranium atoms. This is basically done by the process of fission. It is the energy that is released in significant amounts in processes that affect atomic nuclei, the dense cores of atoms
Bone has a Young's modulus of about1.8 x 10^10 Pa. Under compression, it canwithstand a stress of about 1.69 x 10^8 Pa be-fore breakingAssume that a femur (thigh bone) is 0.49 mlong, and calculate the amount of compressionthis bone can withstand before breaking.Answer in units of mm.
Answers
Answer:
4.6 mm
Explanation:
The Young's Modulus is defined as
[tex]Y=P\frac{L_0}{\Delta L}[/tex]Where
Y = Young's Modulus
P = pressure (stress) applied
L0 = inital length
ΔL = change in length
Now in our case, we know that the femur is 0.49 m long (L0 = 0.49) and it can withstand max stress of 1.69 x 10^8 Pa ( P = 1.69 x 10^8 Pa), and Young's Modulus for the bone is 1.8 x 10^10 Pa ( Y = 1.8 x 10^10 Pa ); therefore, the above formula gives
[tex]1.8\times10^{10}=1.69\times10^8\times\frac{0.49}{\Delta L}[/tex]We have to solve the above equation for ΔL, the amount of compression.
Multiplying both sides by ΔL gives
[tex]\Delta L\times1.8\times10^{10}=1.69\times10^8\times0.49[/tex]dividing both sides by 1.8 x 10^10 gives
[tex]\Delta L=\frac{1.69\times10^8\times0.49}{1.8\times10^{10}}[/tex]which we evaluate to get
[tex]\Delta L=\frac{1.69\times0.49}{1.8}\times\frac{10^8}{10^{10}}[/tex][tex]\begin{gathered} \Delta L=4.6\times10^{-3}m \\ \boxed{\Delta L=4.6\; mm\text{.}} \end{gathered}[/tex]Hence, the amount of compression a femur can withstand is 4.6 x 10^-3 m or 4.6 mm.
Consider two homogeneous bodies of the same volume is it necessary for them to have same mass why
Answers
No, two homogeneous bodies of the same volume do have not the same mass.
How do two bodies of the same volume have the different same mass?
No, two objects don't need to have same volume to have the same mass because the density of the objects they are made up of can be different from one another. Mass and volume are independent, two objects with the same volume can have different amounts of masses. So that's why the objects can have different densities. Density is defined as the mass of the substance divided by its volume.
Density = mass /volume
Mass is defined as the amount of matter that is present in an object, while on the other hand, volume is the space occupied by an object. For example, a bowling ball and a basketball have the same volume but the bowling ball has more mass.
So we can conclude that two homogeneous bodies of the same volume do have not the same mass because of the difference in their volume.
Learn more about volume here: https://brainly.com/question/1972490
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