HELP ME WITH THIS PLEASEEEE

The  x and y-intercept of the equation [8x - 9y = 15] are ( 15/8, 0 ) and ( 0, -5/3 ) respectively.

Given the equation;

8x - 9y = 15

First, we find the x-intercepts by simply substituting 0 for y and solve for x.

8x - 9y = 15

8x - 9(0) = 15

8x = 15

Divide both sides by 8

8x/8 = 15/8

x = 15/8

Next, we find the y-intercept by substituting 0 for x and solve for y.

8x - 9y = 15

8(0) - 9y = 15

- 9y = 15

Divide both sides by -9

- 9y/(-9) = 15/(-9)

y = -15/9

y = -5/3

We list the intercepts;

x-intercept: ( 15/8, 0 )

y-intercept: ( 0, -5/3 )

Therefore, the  x and y-intercept of the equation [8x - 9y = 15] are ( 15/8, 0 ) and ( 0, -5/3 ) respectively.

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Fraction is a topic that deals with expressing the relationship between two numbers or terms in the form of a ratio. So that the required symbolic language required in the question is: 17 - [tex]\frac{x}{17}[/tex] = [tex]\frac{17}{3}[/tex] + 6

Thus the value of x is 90[tex]\frac{2}{3}[/tex].

Fraction is a topic that deals with expressing the relationship between two numbers or terms in the form of a ratio. Some types of fractions are mixed fractions, proper fractions, and improper fractions.

Thus to express the given question in a symbolic language, let the fraction of 17 taken away be represented by x.

So that;

i. a fraction of 17 is taken away from 17 can be expressed as 17 - [tex]\frac{x}{17}[/tex].

ii. remains exceeds one-third of seventeen by six can be expressed as  [tex]\frac{17}{3}[/tex] + 6

Therefore the required symbolic language to the question is:

                  17 - [tex]\frac{x}{17}[/tex]  =  [tex]\frac{17}{3}[/tex] + 6

So that,

[tex]\frac{289 - x}{17}[/tex] = [tex]\frac{17 + 18}{3}[/tex]

cross multiply to have

3(289 - x) = 17(17 + 180)

867 - 3x = 595

3x = 867 - 595

    =272

x = [tex]\frac{272}{3}[/tex]

  = 90[tex]\frac{2}{3}[/tex]

x = 90[tex]\frac{2}{3}[/tex]

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Answer:

(6 / 4) * (7 + 9)

Step-by-step explanation:

sry that took me so long lol

Answer:

[tex]\bold{495\pi} \approx \bold{1555.088 cm^3}[/tex]

Step-by-step explanation:

There was no figure but the question is clear

Volume of a cylinder is given by the formula [tex]\bold{\pi r^2h}\\[/tex]

where r is radius of base of cylinder, h is the height

Volume of a cone is given by [tex]\bold{\frac{1}{3} \pi r^2 h}[/tex]

where r is the radius of base of cone, h is the height

The radius of the cylinder = [tex]\frac{1}{2}[/tex](diameter) = [tex]\frac{1}{2}[/tex](12) = 6cm

Height of cylinder = 15cm

Volume of cylinder [tex]V_{cyl} = \pi (6)^2 15 = \pi (36)15 = \bold{540\pi}[/tex]

Radius of cone = [tex]\frac{1}{2}[/tex] (radius of cylinder) = [tex]\frac{1}{2}[/tex](6) = 3 cm

Height of cone same as height of cylinder = 15cm

Volume of cone, [tex]V_{cone} = \frac{1}{3}\pi r^2 h = \frac{1}{3}\pi (3)^2 15 = \frac{1}{3}(9)15\pi = \bold{45\pi}\\[/tex]

Difference is the volume of the remaining solid

[tex]V_{cyl} - V_{cone} = 540\pi - 45\pi = \bold{495\pi} \approx \bold{1555.088 cm^3}[/tex]

Answer:

84

Step-by-step explanation:

Since we are given line OP perpendicular to line DR, then angles PDR and ODR are right angles.

Angles PDA and ADR are complementary.

Angles ODU and UDR are complementary.

Angles ADR and UDR are given as congruent.

We can conclude that angles PDA and ODU are congruent.

By AA Similarity, triangles APD and UMD are similar.

DP/DM = PA/MU

3.75/10 = 4.5/MU

3.75MU = 10 × 4.5

MU = 12 (altitude of triangle DUO)

OD = OM + MD =  4 + 10 = 14 (base of triangle DUO)

area = base × height / 2

area = 14 × 12 / 2

area = 84

Answer:

84

Step-by-step explanation:

correct me if im wrong

Using the triangle midsegment theorem, the length of AC in the given triangle is: 40 units.

The midsegment of a triangle can be defined as the line segment that intersects two sides of a triangle at their midpoints. This means that, the sides they intersect is bisected forming two equal halves.

In a typical triangle, there are three midsegments in the triangle. For example, in the image given in the attachment below, the midsegments of the triangle are: DF, FB, and BD. All midsegments are parallel to the third sides of a triangle.

What is the Triangle Midsegment Theorem?

According to the triangle midsegment theorem, the length of the midsegment (i,e. DF) is parallel to the third side (i.e. AC) and also half the length of the third side (AC).

We are given the following:

EC = 30

DF = 20

Applying the triangle midsegment theorem, we have:

DF = 1/2(AC)

Substitute

20 = 1/2(AC)

2(20) = AC

40 = AC

AC = 40 units.

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it is that wich is klweijxmpx

a. The value of v is 9.2

b. The value of u is 9.9

Vectors are physical quantities that have both magnitude and direction

Since we have vectors

We resolve them into component form

So, u = -(ucos70°)i - (usin70°)j

u = -(0.3420u)i - (0.9397u)j

v = -(vcos47°)i + (vsin47°)j

v = -(0.6820v)i - (0.7314v)j

w = (wcos15°)i + (wsin15°)j

w = (0.9659w)i + (0.2588w)j

w = (9.659)i + (2.588)j

Since the sum of the three vectors is zero, we have that

u + v + w = 0

u + v = -w

So,

-(0.3420u)i - (0.9397u)j + [-(0.6820v)i - (0.7314v)j] = -[(9.659)i + (2.588)j]

-(0.3420u)i - (0.9397u)j -(0.6820v)i - (0.7314v)j = -(9.659)i - (2.588)j]

-(0.3420u)i -(0.6820v)i - (0.9397u)j - (0.7314v)j = -(9.659)i - (2.588)j]

-[0.3420u + 0.6820v]i - [0.9397u + 0.7314v]j = -(9.659)i - (2.588)j

Equating i components, we have

-[0.3420u + 0.6820v]i = -9.659i

0.3420u + 0.6820v = 9.659

Dividing through by 0.3420. we have

u + 1.994v = 28.242 (1) and

Also, equating j components, we have

- [0.9397u + 0.7314v]j = -2.588j

0.9397u + 0.7314v = 2.588  

Dividing through by 0.9397 we have

u + 0.778v = 2.754 (2)

Subracring equation (2) from(1),we have

u + 1.994v = 28.242 (1)

-

u + 0.778v = 2.754 (2)

2.772v = 25.488

v = 25.488/2.772

v = 9.19

v ≅ 9.2

The value of v is 9.2

Substituting v into (1), we have

u + 1.994v = 28.242 (1)

u + 1.994(9.19) = 28.242

u + 18.325 = 28.242

u = 28.242 - 18.325

u = 9.917

u ≅ 9.9

The value of u is 9.2

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Answer:

[1 , +∞)

Step-by-step explanation:

Solving the inequality 6x ≥ 6

6x ≥ 6

⇔ x ≥ 1   (Divide both sides by 6)

⇔ x ∈ [1 , +∞)

Answer:

x=70, y=55

Step-by-step explanation:

Since the angle "y" and 2x-15 form a straight line, that means the sum of the angles, must be 180 degrees.

So using this we can derive the equation: [tex]y+2x-15=180[/tex]

The next thing you need to know is that the sum of interior angles of a triangle is 180 degrees, so if we add all the angles, we should get 180.

So using these we can derive the equation: [tex]x+2y=180[/tex]

So, in this case we simply have a systems of equations. We can solve this by solving for x in the second equation (sum of interior angles), and plug that into the first equation.

Original Equation:

[tex]x+2y = 180[/tex]

Subtract 2y from both sides

[tex]x = 180-2y[/tex]

Now let's plug this into the first equation

[tex]y+2x-15=180[/tex]

Plug in 180-2y as x

[tex]y+2(180-2y)-15=180[/tex]

Distribute the 2

[tex]y+360-4y-15=180[/tex]

Combine like terms

[tex]-3y + 345 = 180[/tex]

Subtract 345 from both sides

[tex]-3y = -165[/tex]

Divide both sides by -3

[tex]y=55[/tex]

So we can plug this into either equation to solve for x

[tex]x+2y=180[/tex]

Substitute in 55 as y

[tex]x+2(55)=180[/tex]

[tex]x+110=180[/tex]

Subtract 110 from both sides

[tex]x=70[/tex]

Answer:

  x = 70°

  y = 55°

Step-by-step explanation:

The angle sum theorem and the definition of a linear pair can be used to write two equations in the two unknowns. Those can be solved for the angle values.

  x + y + y = 180° . . . . . . angle sum theorem

  y + (2x -15) = 180° . . . . definition of linear pair

We can use the first equation to write an expression for x that can be substituted into the second equation:

  x = 180 -2y

  y +(2(180 -2y) -15) = 180 . . . . substitute for x

  345 -3y = 180 . . . . . . . . . . . collect terms

  115 -y = 60 . . . . . . . . . . . . .divide by 3

  y = 55 . . . . . . . . . . . . . . add (y-60)

  x = 180 -2(55) = 70

The values of the variables are ...

  x = 70°

  y = 55°

  exterior angle = 125°

Answer:

[tex]\frac{15}{49}[/tex]

Step-by-step explanation:

[tex]\frac{3}{14} /\frac{7}{10} =\frac{3}{14} *\frac{10}{7} = \frac{3}{7} *\frac{5}{7} =\frac{15}{49}[/tex]

The percentage of people who preferred cheesecake if 50% prefferd fruit cake 1/5 preferred sponge is 40%.

Percentage remaining = 100% - 50%

= 50%

Sponge cake = 1/5

Percentage of sponge cake = 1/5 × 50%

= 1/5 × 0.5

= 10%

Percent that likes cheesecake = Total - (fruits cake + sponge cake)

= 100% - (50% + 10%)

= 100% - (60%)

= 40%

Therefore, the percentage of people who preferred cheesecake if 50% prefferd fruit cake 1/5 preferred sponge is 40%.

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Based on the residual plot given, the statement that describes if the model is good is B. The regression line is a good model because the residuals are randomly distributed.

For a model to be considered ideal or good, the residuals from the model should be randomly distributed in an equal manner around the regression line.

The residual plot shows that the residuals are randomly distributed which means that the regression line is a good model.

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sinE is 0.5

What are similar triangles?

Two triangles will be similar if the angles are equal (corresponding angles), and sides are in the same ratio or proportion (corresponding sides). Similar triangles may have different individual lengths of the sides of triangles, but their angles must be equal and their corresponding ratio of the length of the sides must be the same.

Clearly, given triangle AFB and triangle DFE are similar.

We know that Similar Triangles have the same corresponding angle

We can find sinE as show below:

From diagram clearly

∠A=∠E

and ∠B=∠D

Since, ∠A=∠E

Taking sin on both sides

sinA=sinE

Give, sinA=0.5

sinA=sinE=0.5

⇒ sinE=0.5

Hence, sinE is 0.5

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Since the Dilating polygon WXYZ will alter the side lengths of the polygon. The correct option is option  (b) the slope of WX is 3/4, and the length of W'X' is 15.

The coordinates in the question were:

(3,2), and  (7,5).

Then the slope of WX is:

[tex]\frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]

So m   = [tex]\frac{{5} - 2 }{7-3} }[/tex]

    =3/4

The length of WX is calculated by:

[tex]WX = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1}) ^ 2}[/tex]

[tex]\sqrt{(7-3)^2 + (5-2)^2} \\\\= \sqrt{25} \\\\= 5[/tex]

Since, The scale factor is  =  3.

Hence, WX = 3 x 5 = 15

Therefore, Since the Dilating polygon WXYZ will alter the side lengths of the polygon. The correct option is option  (b) the slope of WX is 3/4, and the length of W'X' is 15.

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Answer:    slope 3/4 and length 15

Step-by-step explanation: plato

D

Step-by-step explanation:

The correct answer is option D, which is 105, 90, 75, 60, 45.

For this, let's go through each problem carefully and step-by-step.

According to the question, the rate of change of the temperature of any object that is defined by T, is directly proportional to the difference of T and the temperature of the environment around it, which we'll denote as X.

[tex]\frac{dT}{dt}[/tex][tex]= k (T-X)[/tex]

K is a constant of proportionality here. And the temperature of the surrounding environment is said to be (-18°C). Thus,

[tex]\frac{dT}{dt} = k(T+18)[/tex].

For part A, in order to find the differential equation for T, we need to solve for k. So we separate the variables and then integrate to solve the equation.

[tex]\int\limits{\frac{dT}{T+18} } = \int\limits {k} \, dt[/tex]

[tex]ln(T+18) = kt+c[/tex]

Now thw inital temperature of a pot of chili is 23°C, so at [tex]t = 0, T_0 = 23*C[/tex].

Substituting 23 for T and 0 for t, we have the following:

[tex]ln(23+18) = k(0)+c[/tex]

[tex]ln(41) = c[/tex]

We know the temperature of chili after 2 hours is 7°C, so we know that when [tex]t = 2, T_1 = 7[/tex]

Substituting t for 2, and T for 7, we get:

[tex]ln(7+18) = 2k+ln(41)[/tex]

[tex]ln(25) = 2k + ln(41)[/tex]

Solving for 2k

[tex]2k = ln(25) -ln(41)[/tex]

[tex]2k = ln(\frac{25}{41})[/tex]

[tex]k = \frac{1}{2}ln(\frac{25}{41})[/tex].

Substituting the value of [tex]\frac{dT}{dt} = k (T+18)[/tex], the differential equation obtained is [tex]\frac{dT}{dt} = \frac{1}{2}ln(\frac{25}{41})(T+18)[/tex].

For part B, to find the temperature of the chili after four hours, we first need to solve the above differential equation.

The solution of the differential equation is given by the equation [tex]ln(T+18) = kt+c[/tex]. Substituting the values of k and c, we have:

[tex]ln(T+18) = \frac{1}{2}ln(\frac{25}{41})t+ln(41)[/tex].

Using the above relation, at any time (t), the temperature (T) can be found out in the following.

At [tex]t = 4, T_2 = \phi[/tex]

[tex]ln(T_2+18)=\frac{1}{2}ln(\frac{25}{41})*4+ln(41)[/tex]

[tex]ln(T_2+18)=2ln(\frac{25}{41})+ln(41)[/tex]

[tex]ln(T_2+18)=-0.989 + 3.714[/tex]

[tex]ln(T_2+18)[/tex] ≅ [tex]2.725[/tex]

Solving the natural logarithm,

[tex]T_2+18 = e^{2.725} = 15.256[/tex]

[tex]T_2 =15.256 - 18[/tex]

[tex]T_2 = -2.744[/tex].

So the temperature of the chili after four hours would be -2.744°C approximately.

To find part C in what time the chili would be 10°C, we need to substitute again.

[tex]t = \phi[/tex][tex], T = -10[/tex]

[tex]ln(-10 + 18) = \frac{1}{2}ln(\frac{25}{41})t + ln(41)[/tex]

[tex]ln(8) = \frac{1}{2}ln(\frac{25}{41})t + ln(41)[/tex]

Solving for [tex]\frac{1}{2}ln(\frac{25}{41})t[/tex],

[tex]\frac{1}{2}ln(\frac{25}{41})t = ln(8) - ln(41)[/tex]

[tex]\frac{1}{2}ln(\frac{25}{41})t = ln(\frac{8}{41})[/tex]

[tex]\frac{1}{2}ln(\frac{25}{41})t = -1.634[/tex]

[tex]ln(\frac{25}{41})t[/tex][tex]= -1.634 * 2[/tex]

[tex](-0.494)t=-3.268[/tex]

[tex]t = \frac{-3.268}{-0.494}[/tex]

[tex]t=6.615[/tex] hours, approximately.

Thus, the chili would reach -10°C at around 6.615 hours.

Hope this helped. This took me a long time.

Step-by-step explanation:

chicken nuggets are so bussing that the answer is c

a. Central angle: Angle BAC

b. A major arc is: Arc BEC

c. A minor arc is: Arc BC

d. Measure of arc BEC in circle A = 260°

e. Measure of arc BC = 100°

According to the central angle theorem the measure of central angle (i.e. angle BAC in circle A) is the same as the measure of the intercepted arc (i.e. arc BC in circle A).

Referring to the image given, a central angle (i.e. angle BAC) is formed by two radii of a circle (i.e. AB and AC in circle A), where the vertex of the angle (i.e. vertex A in circle A) is at the center of the circle.

An arc that is bigger than a semicircle (half a circle) or with a measure greater than 180 degrees is called a major arc of a circle.  

An arc that is smaller than a semicircle (half a circle) or with a measure less than 180 degrees is called a minor arc of a circle.  

a. Central angle in circle A is: ∠BAC

b. Major arc in circle A is: Arc BEC

c. Minor arc in circle A is: Arc BC.

d. Based on the central angle theorem, we have:

Measure of arc BEC in circle A = 360 - 100

Measure of arc BEC in circle A = 260°

e. m∠BAC = 100° [given]

Based on the central angle theorem, we have:

m(arc BC) = m∠BAC

Measure of arc BC = 100°

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The slopes of OA, OB and OC are integer values.

According to the statement

we have given that the some points on the graph and we have to find that the slopes of these points have integer value or not.

So, For this we know that the

If a line passing through two points then the slope of the line is

So, [tex]m = \frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]

Then

The slope of line OA is 4 because 8/2 = 4.

And

The slope of line OB is 3 because 9/3 = 3.

And

The slope of line OC is 2 because 8/4 is 2.

And

The slope of line OD is 8/5 because it is 8/5.

And

The slope of line OE is 7/6 because it is 7/6.

And

The slope of line OE is 6/7 because it is 6/7.

From all this it is clear that

So,The slopes of OA, OB and OC are integer values.

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The contract price is $8,750,000

What is contract price?

Contract price means the amount Lao Construction Company charged the customer for total contract's execution.

We need to ascertain the percentage completion of the project first and foremost, which is the total costs incurred to date divided by the contract's total costs.

cost incurred to date=$ 1,500,000

total contract's cost=cost incurred to date+ expected future costs

total contract's cost=$1,500,000+$6,000,000

total contract's cost=$7,500,000

% completion=$1,500,000/$7,500,000

% completion=20%

gross profit recognized=(contract price*% completion)-costs incurred till date

gross profit recognized=$250,000

contract price=unknown(assume it is X)

% completion=20%

cost incurred to date=$ 1,500,000

$250,000=(20%*X)-$1,500,000

$250,000+$1,500,000=0.20X

$1,750,000=0.20X

X=$1,750,000/0.20

X=$8,750,000

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The company sells all that it produces, the profit function is:-0.5x2+60x-250.

P(x)= R(x)-C(x)      

=-0.5(x-110)2 +6050-(50x+250)

Let Distribute Negative Sign      

P(x)= -0.5(x-110)2 + 6050 +-1(50x+250)

P(x)= -0.5(x-110)2 + 6050 +-1(50x) + (-1) (250)

P(x)= -0.5(X-110)2 +6050 +-50x + -250

Distribute P(x)= -0.5x2+110x+-6050+6050+-50x+-250

Combine Like Terms

P(x)= -0.5x2 +110x+-6050+6050+-50x+-250

P(x)=(-0.5x2) + (110x+-50x) + (-6050+6050+-250)  

P(x)= -0.5x2+60x-250

Therefore the company sells all that it produces, the profit function is:-0.5x2+60x-250.

The missing requirement is:

Assuming that the company sells all that it produces, what is the profit function?

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Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.

The steps involved in inscribing a square in a circle include;

Alicia deductions were;

Draws two diameters and connects the points where the diameters intersect the circle, in order, around the circle

Benjamin's deductions;

The diameters must be perpendicular to each other. Then connect the points, in order, around the circle

Caleb's deduction;

No need to draw the second diameter. A triangle when inscribed in a semicircle is a right triangle, forms semicircles, one in each semicircle. Together the two triangles will make a square.

It can be concluded from their different postulations that Benjamin is correct because the diameter must be perpendicular to each other and the points connected around the circle to form a square.

Thus, Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.

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If the trains meet in 4 hours then the speed of the trains is 150 miles per hour and the speed of second train be 166 miles per hour.

Given the distance between trains be 664 miles and the speed of one train is 16 miles more than the other train.

We are required to find the speed of both the trains.

Speed is basically the distance that a thing covers in a particular time period.

Speed=Distance/Time

let the speed of first train be x miles per hour.

According to question the speed of the second train be (x+16) miles per hour.

Taking first train:

Speed =Distance/Time

x=664/4

=166

Taking second train:

Speed=Distance/Time

x+16=664/4

x+16=166

x=150

Hence if the trains meet in 4 hours then the speed of the trains is 150 miles per hour and the speed of second train be 166 miles per hour.

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Angles 2 and 4 are corresponding angles. They are congruent, not supplementary because they have the same measure and do not add up to 180 degrees. Therefore, the answer is the third option. Corresponding angles are congruent.

Step-by-step explanation:

Divide, the same as ÷

divide 6 by 3

by is the same as the symbol

6 ÷ 3 = 2

Difference, This is another way of saying take away or minus

the difference of 6 and 3 is

6 - 3 = 3

Product, This is another word for multiply or times

the product of 2 and 3 is

2 × 3 = 6

divide (÷)  the difference of 20 and 6 (20 - 6) by the product of 7 and 2       (7 × 2)

so

(20 - 6) ÷ (7 × 2)

can you do the rest???

Answer:

f(g(x)) = f(2x - 3) = 3(2x - 3) + 5 = 6x - 9 + 5 = 6x - 4

f(g(2)) = f(2*2 - 3) = f(4 - 3) = f(1) = 3*1 + 5 = 3 + 5 = 8

The composite function values:

f(g(x)) = 6x- 4

f(g(2)) = 8.

Any function that is created by combining two or more other functions is referred to as a composite function. To put it another way, given two functions, f, and g, the composite function of f and g, denoted as f(g(x)), is a new function that applies g to the input x before applying f to the output of g. (x).

To find the value of fg(x), we need to compute g(x) first and then substitute it into f(x).

g(x) = 2x - 3

Substitute g(x) into f(x):

f(g(x)) = 3(2x - 3) + 5

f(g(x)) = 6x - 4

Therefore, fg(x) = 6x - 4.

To find the value of fg(2), substitute 2 into fg(x):

fg(2) = 6(2) - 4

fg(2) = 8

Therefore, fg(2) = 8.

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The solutions for the given equations are:

Writing a number or an equation as a product of its factors is said to be the factorization.

A linear equation has only one factor, a quadratic equation has 2 factors and a cubic equation has 3 factors.

1. Solving x² - 49 = 0; (quadratic equation)

⇒ x² - 7² = 0

This is in the form of a² - b². So, a² - b² = (a + b)(a - b)

⇒ (x + 7)(x - 7) =0

By the zero-product rule,

x = -7 and 7.

2. Solving 3x³ - 12x = 0

⇒ 3x(x² - 4) = 0

⇒ 3x(x² - 2²) = 0

⇒ 3x(x + 2)(x - 2) = 0

So, by the zero product rule, x = -2, 0, 2

3. Solving 12x² + 14x + 12 = 18; (quadratic equation)

⇒ 12x² + 14x + 12 - 18 = 0

⇒ 12x² + 14x - 6 = 0

⇒ 2(6x² + 7x - 3) = 0

⇒ 6x² + 9x - 2x - 3 = 0

⇒ 3x(2x + 3) - (2x + 3) = 0

⇒ (3x - 1)(2x + 3) = 0

∴ x = 1/3, -3/2

4. Solving -x³ + 22x² - 121x = 0

⇒ -x³ + 22x² - 121x = 0

⇒ -x(x² - 22x + 121) = 0

⇒ -x(x² - 11x - 11x + 121) = 0

⇒ -x(x(x - 11) - 11(x - 11)) = 0

⇒ -x(x - 11)² = 0

∴ x = 0, 11, 11

5. Solving x² - 4x = 5; (quadratic equation)

⇒ x² - 4x - 5 = 0

⇒ x² -5x + x - 5 = 0

⇒ x(x - 5) + (x - 5) = 0

⇒ (x + 1)(x - 5) =0

∴ x = -1, 5

Hence all the given equations are solved.

Learn more about the factorization here:

https://brainly.com/question/25829061

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Answer:

C

Step-by-step explanation:

32/sqrt(2) = 32sqrt(2)/2 = 16sqrt2

Answer:

C.

Step-by-step explanation:

It is a right triangle with hypotenuse c = 12, also for having two equal angles is an isosceles triangle, the missing sides (catethus) are equal (a and b)
a = b = the legs

Apply the Pythagorean theorem

[tex]c^{2}=a^{2} +b^{2} \\c^{2} =2a^{2}[/tex]

[tex]a^{2} =\frac{c^{2} }{2}=\frac{(32)^{2} }{2} =512[/tex]

[tex]a=\sqrt{512} =\sqrt{256(2)} =16\sqrt{2}[/tex]

Hope this helps