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Answer: (2,9)

Step-by-step explanation:

The point lies in the region that is shaded by both inequalities.

Answer: 1208.96

Step-by-step explanation:

The volume of the cylinder is [tex](\pi)(4^2)(4)=64\pi[/tex]

The volume of the prism is [tex](6)(12)(14)=1008[/tex]

So, the total volume is [tex]1008+64\pi=\boxed{1208.96}[/tex]

Answer:

Step-by-step explanation:

Quick Answer 1

Solution

x = 0.747 / 0.0747

When you do the division, you get 10. That means that you need to divide 0.747 by just 1 ten to get 0.0747

Answer:

Once

Step-by-step explanation:

You have to divide once because if you divide a decimal by 10, you add a zero before the decimal point

The degrees of freedom for the numerator and denominator for the critical value of F are _3 and 56, respectively_.

The samples, each comprised of 15 observations, were taken from the four populations.

The determine the degrees of freedom for the numerator and denominator for the critical value of F is given below:

k = 4

n = 15

Total degree of freedom;

= nk - 1

= 59

For numerator, it is

= k -1

= 4 - 1

= 3

For denominator it is

= T - (k -1 )

= 59 - 3

= 56

The degrees of freedom for the numerator and denominator for the critical value of F are _3 and 56, respectively_.

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So by direct evaluation we can see that the limit when x tends to 2 is equal to 1.

Here we want to get the limit:

[tex]\lim_{x \to \ 2} \frac{x^2 + 3x + 1}{x^3 + x + 1}[/tex]

First, we can try to evaluate directly in x = 2 and see if it does not generate any problem, we will get:

[tex]\lim_{x \to \ 2} \frac{x^2 + 3x + 1}{x^3 + x + 1} = \frac{2^2 + 3*2 + 1}{2^3 + 2 + 1} = 1[/tex]

So by direct evaluation we can see that the limit when x tends to 2 is equal to 1.

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Answer: 8

Step-by-step explanation:

PEMDAS

Answer:

[tex]f(x)=-2(x-3)^2+2[/tex]

Step-by-step explanation:

To find the x-intercept, substitute 0 for y and solve for x. To find the y-intercept, substitute 0 for x and solve for y.

x-intercept(s): (2,0),(4,0)

y-intercept(s): (0,−16)

Answer:

D     f(x) = -2(x - 3)² + 2

Step-by-step explanation:

The y-intercept occurs at x = 0.

A

f(x) = 2x(x + 14) - 64

f(0) = -64     Not -16

B

f(x) = (x + 4)² + 2x

f(0) = 16     Not -16

C

f(x) = (x - 16)² + 4

f(0) = 260      Not -16

D

f(x) = -2(x - 3)² + 2

f(0) = -18 + 2 = -16   <-------------------- this is it

When followers' needs for security and certainty, belonging, and feeling chosen or special are strong, it makes them vulnerable to the dictates of abusive leaders.

The epistemic attribute of beliefs that one cannot rationally reject is certainty, often known as epistemic certainty or objective certainty. Epistemic certainty is commonly defined as a belief being certain if and only if the person holding it could not be wrong in holding it.

In both public and private markets, securities are fungible, tradeable financial instruments used to raise capital.

The three main categories of securities are: equity, which gives holders ownership rights; debt, which is effectively a loan returned with recurring payments; and hybrids, which include features of both debt and equity.

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The slope of the red line that is perpendicular to the green line is: -5/2.

When one line lies perpendicular to another line, the slope of one must be the negative reciprocal of the other line.

If given a number, i.e. a/b, the negative reciprocal of a/b would the opposite value of the reciprocal of a/b.

Reciprocal of a/b is b/a. Negative reciprocal of a/b would therefore be: -b/a.

Given that the slope of the green line is: 2/5. And it is perpendicular to the red line. The slope of the red line would be the negative reciprocal of 2/5.

Negative reciprocal of 2/5 is -5/2.

Therefore, the slope of the red line is: -5/2.

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The quadratic equation exists [tex]$x^{2}+3 x+2=0$[/tex].

If a quadratic equation exists [tex]$a x^{2}+b x+c=0$[/tex], the utilizing the quadratic equation the solutions for x will be given by

[tex]$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$$[/tex]

The solution for x exists

[tex]$x=\frac{-3 \pm \sqrt{3^{2}-4(1)(2)}}{2(1)}[/tex]

Comparing equations (1) and (2) we get, a = 1, b = 3 and c = 2.

Therefore, the quadratic equation exists [tex]$x^{2}+3 x+2=0$[/tex].

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Answer:

One guy said it was B. but I'm going with A.

Step-by-step explanation:

Ramiya is using the quadratic formula to solve a quadratic equation. her equation is x = startfraction negative 3 plus or minus startroot 3 squared minus 4(1)(2) endroot over 2(1) endfraction after substituting the values of a, b, and c into the formula. which is ramiya’s quadratic equation?

The numeric values from the function are given by:

The function is:

f(x) = 4 - 2x + 6x².

When x = a:

f(a) = 4 - 2a + 6a².

When x = a + h:

f(a + h) = 4 - 2(a + h) + 6(a + h)² = 6a² + 12ah + 6h² - 2a - 2h + 4.

For the last question

[f(a + h) - f(a)]/h = [6a² + 12ah + 6h² - 2a - 2h + 4 - 4 + 2a - 6a²]/h = [12ah + 6h² - 2h]/h = h(12a + 6h - 2)/h

Hence:

[f(a + h) - f(a)]/h = 12a + 6h - 2.

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The value placed in the box that makes the system of equation with infinitely many solution is 12.

An infinite solution has both sides equal. For example, 6x + 2y - 8 = 12x +4y - 16.  If we simplify the equation we will notice both sides are equal. This means the equation has an infinitely many solution.

Hence,

y = -2x + 4

Therefore,

6x + 3y = 12

divide the equation(ii) by 3

2x + y = 4

y = -2x + 4

Therefore, both equation are equal if the the box is filled with 12. This means for the value placed in the box that makes the system of equation with infinitely many solution is 12.

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Step-by-step explanation:

every single person will do 1/4 of each job.

divide into 2 group and each person will do half of one job and half of another.

The polynomial A is represented as x - 2, making option A the right choice.

In the question, we are asked to find the correct representation of A, when the algebraic expression (x² + x)/(x + 3) can be rewritten as the algebraic expression A + 6/(x + 3), where A is a polynomial.

Thus, we can write an equation,

A + 6/(x + 3) = (x² + x)/(x + 3),

or, A + 6/(x + 3) - 6/(x + 3) = (x² + x)/(x + 3) - 6/(x + 3) {Subtracting 6/(x + 3) from the both sides of the equation}

or, A = (x² + x)/(x + 3) - 6/(x + 3) {Simplifying},

or, A = (x² + x - 6)/(x + 3) {Subtracting the two fractions with the same denominator (x + 3)},

or, A = (x² + 3x - 2x - 6)/(x + 3) {Mid-term factorization},

or, A = {x(x + 3) - 2(x + 3)}/(x + 3) {Taking common},

or, A = {(x - 2)(x + 3)}/(x + 3) {Taking (x + 3) common},

or, A = x - 2 {Cancelling (x + 3) from the numerator and the denominator}.

Thus, the polynomial A is represented as x - 2, making option A the right choice.

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If the faster car is travelling 20 mph faster then slower car then the speed of slower car is 55mph and faster car is 75 mph.

Given that the faster car is travelling 20 mph faster than slower car and when slower car travels 165 miles the faster car travels 225 miles.

We are required to find the speed of slower car and faster car.

let the speed of slower car be x mph.

In this way the speed of faster car be (x+20) mph.

Speed=Distance/ time

We have to first take slower car.

x=165/Time

Time=165/x-----------1

Now by taking faster car.

x+20=225/time

Time=225/(x+20)-------2

From equation 1 an equation 2.

165/x=225/(x+20)

225x=165x+3300

225x-165x=3300

60x=3300

x=55 mph

Faster car=55+20

=75 mph.

Hence if the faster car is travelling 20 mph faster then slower car then the speed of slower car is 55mph and faster car is 75 mph.

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Answer:

a = 12

x = 5.714

Step-by-step explanation:

sf = 15 / 9

20 / (15 / 9) = 12

a = 12

sf = 21 / 6

20 / (21 / 6)

x = 5.714

Answer:

w = -11

Step-by-step explanation:

[tex]\sqrt{3 - 2w} = w + 6[/tex]

[tex](\sqrt{3 - 2w})^2 = (w + 6)^2[/tex]

[tex] 3 - 2w = w^2 + 12w + 36 [/tex]

[tex] w^2 + 14w + 33 = 0 [/tex]

[tex] (w + 11)(w + 3) = 0 [/tex]

[tex] w + 11 = 0 [/tex]   or   [tex] w + 3 = 0 [/tex]

[tex] w = -11 [/tex]   or   [tex] w = -3 [/tex]

When you square both sides of an equation, you must check all solutions for extraneous solutions.

Check w = -11.

[tex]\sqrt{3 - 2w} = w + 6[/tex]

[tex] \sqrt{3 - 2(-11)} = -11 + 6 [/tex]

[tex] \sqrt{3 + 22} = -5 [/tex]

[tex] \sqrt{25} = -5 [/tex]

[tex] 5 = -5 [/tex]

This is a false statement, so the solution w = -11 is extraneous since it does not satisfy the original equation.

Check w = -3.

[tex]\sqrt{3 - 2w} = w + 6[/tex]

[tex] \sqrt{3 - 2(-3)} = -3 + 6 [/tex]

[tex] \sqrt{3 + 6} = 3 [/tex]

[tex] \sqrt{9} = 3 [/tex]

[tex] 3 = 3 [/tex]

This is a true statement, so the solution w = -3 is valid.

Answer: w = -11

It will cost $375 to hire the doctor for 45 minutes

The doctor charges $500 for an hour

60 minutes makes 1 hour

60 minutes= $500

Therefore the amount that will be charged for 45 minutes can be calculated as follows

60 minutes= $500

45 minutes= x

Cross multiply both sides

60x= 500×45

60x= 22500

x= 22500/60

x= 375

Hence it will cost $375 to hire the doctor for 45 minutes

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Answer: 243

Step-by-step explanation:

If you divide the 18 inch by two to get the r, you will get 9. So you should multiple the 3 and the 9 square. So it should be 3x81=243

Answer:

70

Step-by-step explanation:

8 choose 4: 8!/(4!*4!)=70

Answer:

1680

Step-by-step explanation:

the order matters so 8P4

Answer:

Point A

Step-by-step explanation:

See attached worksheet.

Answer:

Step-by-step explanation:

4.5x + 40 < 75

4.5x < 35

x<7.7

Answer:

MO = 12

PR = 3

Step-by-step explanation:

The perimeter of a triangle is calculated by adding all side lengths up:

The perimeter of triangle MNO is given as 48

The perimeter of triangle PQR is given as 12

The ratio is 1/4 (simplified ratio of 12/48)

we can write the following equation using this information:

[tex]\frac{x+2}{12x} = \frac{1}{4}[/tex]

cross multiply fractions

12x = 4x + 8

subtract 4x from both sides

8x = 8

divide both sides by 8

x = 1

Now to find the measure of side lengths in question we replace x with 1

for MO = 12x

12*1 = 12

for PR = x + 2

1 + 2 = 3

Answer:

300 degrees

Step-by-step explanation:

pi should be 180 degrees so 5*180/3 = 5*60=300

The solution to the system of equations y = 1/2x - 6, x = -4 is x = -4 and y = -8. (x, y) = (-4, -8)

There are different types of equation. Namely;

y = 1/2x - 6

x = -4

y = 1/2x - 6

y = 1/2(-4) - 6

= -4/2 - 6

= -2 - 6

y = -8

Therefore,

The solution to the system of equations y = 1/2x - 6, x = -4 is x = -4 and y = -8. (x, y) = (-4, -8)

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Answer:

a)0.00

b)13year,8month,2weeks and 6day

Answer:

  m∠B ≈ 70.8°

Step-by-step explanation:

The Law of Cosines relates three sides of a triangle and the angle opposite one of them.

The law of cosines tells you ...

  b² = a² +c² -2ac·cos(B)

Solving for angle B, we get ...

  B = arccos((a² +c² -b²)/(2ac))

where 'a' and 'c' are the sides adjacent to the angle of interest. We want angle B, so we can fill this formula as follows:

  B = arccos((13² +11² -14²)/(2·13·11))

  B = arccos(94/286)

  B ≈ 70.812°

__

Additional comment

Another angle can be found using the Law of Sines.

  A = arcsin(sin(70.812°)×13/14) ≈ 61.281°

Then angle C is ...

  C = 180° -70.812° -61.281° = 47.907°

Answer:

Step-by-step explanation:

The relevant relations here are ...

The given arc CD is part of the semicircular arc CDA. The remaining arc, DA, is the supplement of CD:

  arc DA = 180° -CD = 180° -125° = 55°

Central angle AOD has the same measure, 55°. That is one of the acute angles in right triangle AOB, so the other one is the complement of 55°.

 ∠ABO = 90° -∠AOB = 90° -55°

  ∠ABO = 35°

In right triangle ABC, angle ABC is given as 55°. The other acute angle, ACB, will be the complement of this.

  ∠ACB = 90° -∠ABC = 90° -55°

  ∠ACB = 35°

In the figure, angles ABO and ACB have measures of 35°.

Step-by-step explanation:

Answer:

The answer is cot(x)

Step-by-step explanation:

[tex] \tan(x) \csc {}^{2} (x) - \tan(x) [/tex]

Rewrite using trig identity

[tex] - \tan(x) + \csc {}^{2} (x) \tan(x) [/tex]

use the Pythagorean idea

[tex] \csc {}^{2} (x) = 1 + \cot {}^{2} (x) [/tex]

[tex] - \tan(x) + (1 + \cot {}^{2} (x)) \tan(x) [/tex]

simplify

[tex] \cot {}^{2} (x) \tan(x) [/tex]

use basic trigonometric identity

[tex] \tan(x ) = \frac{1}{ \cot(x) } [/tex]

simplify

[tex] \cot {}^{2} (x) \frac{1}{ \cot(x) } [/tex]

gives you

[tex] \cot(x) [/tex]

Hope it helps!