if an experimenter conducts a t test for dependent means with 10 participants and the estimated population variance of difference scores is 20, the variance of the comparison distribution is

The average daily capacity factor for a MOD-2 WTG operating in Cherry Point, NC in March is approximately 0.13%.

To find the average daily capacity factor for a MOD-2 WTG in Cherry Point, NC in March using the Weibull distribution, calculate the probability of wind speeds exceeding the rated speed and power output exceeding the rated power. Multiply these probabilities to get the capacity factor, which is approximately 0.13%.

To calculate the average daily capacity factor using the Weibull distribution for a MOD-2 WTG operating in Cherry Point, NC in March, we will need to use the following parameters:

PR = 2,500 kW
VC = 6.26 m/s
VR = 12.5 m/s
VF = 26.83 m/s
Vmax = 30 m/s

Using the approximate method, we can calculate the capacity factor as follows:

1. Determine the shape and scale parameters of the Weibull distribution for the given wind speed range:

k = (VF/VC)^2 x ln(VR/VC) = (26.83/6.26)^2 x ln(12.5/6.26) = 3.27
c = VC / Γ(1 + 1/k) = 6.26 / Γ(1 + 1/3.27) = 3.43

where Γ is the gamma function.

2. Calculate the probability of wind speed exceeding the rated wind speed VR:

P(V > VR) = (Vmax/VR)^k = (30/12.5)^3.27 = 0.073

3. Calculate the probability of power output exceeding the rated power PR:

P(P > PR) = exp(-(PR/c)^k) = exp(-(2,500/3.43)^3.27) = 0.018

4. Calculate the average daily capacity factor as the product of the two probabilities:

CF = P(V > VR) x P(P > PR) = 0.073 x 0.018 = 0.0013

Therefore, the average daily capacity factor for a MOD-2 WTG operating in Cherry Point, NC in March is approximately 0.13%.

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AB is approximately 992.2 meters.

To find AB, we can use the law of cosines.

First, we need to find the length of BC. Using the fact that the sum of angles in a triangle is 180 degrees, we can find that ZCAB = 180 - 859 - 66 = 55 degrees.

Now, using the law of cosines:

AB^2 = AC^2 + BC^2 - 2(AC)(BC)cos(ZCAB)

AB^2 = (25)^2 + BC^2 - 2(25)(BC)cos(55)

We still need to find BC. Using the law of sines:

BC/sin(ZBAC) = AC/sin(ZBCA)

BC/sin(859) = 25/sin(66)

BC = (25sin(859))/sin(66)

Now we can substitute this value for BC in the first equation:

AB^2 = (25)^2 + ((25sin(859))/sin(66))^2 - 2(25)((25sin(859))/sin(66))cos(55)

AB^2 = 625 + (625sin^2(859))/sin^2(66) - (1250sin(859))/sin(66)cos(55)

AB^2 = 625 + (625sin^2(859))/sin^2(66) - (1250cos(859))/tan(66)

AB^2 = 625 + (625sin^2(859))/sin^2(66) - (1250cos(859))/1.9199

AB^2 = 625 + (625sin^2(859))/sin^2(66) - 651.8cos(859)

AB^2 = 625 + 1443.8 - 651.8cos(859)

AB^2 = 1417.8 - 651.8cos(859)

AB = sqrt(1417.8 - 651.8cos(859))

AB is approximately 992.2 meters.

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7a) The area of the base of the monument would be = 400m²

To calculate the base of the monument the area of a square is used. That is;

= Length×width.

Where;

Length = 20m

width = 20m

area = 20×20 = 400m²

Therefore, the area of the base of the monument = 400m²

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The linear combination of f1, f2, and f3 can be expressed as: v = −1 f1 + 1 f2 − 2 f3.

Since f1, f2, and f3 form an orthogonal basis of ℝ3, we can express any vector in ℝ3 as a linear combination of these three vectors. Let's find the coefficients of the linear combination for v.

Let a, b, and c be the coefficients of f1, f2, and f3, respectively, in the linear combination. Then we have:

v = a f1 + b f2 + c f3

Substituting the given values, we get:

0 −9 0 = a (−1 −2 −2) + b (−2 −1 2) + c (−2 2 −1)

Simplifying this equation, we get a system of three linear equations:

−a − 2b − 2c = 0

−2a − b + 2c = −9

−2a + 2b − c = 0

Solving this system of equations, we get:

a = −1, b = 1, c = −2

Therefore, we can express v as a linear combination of f1, f2, and f3 as:

v = −1 f1 + 1 f2 − 2 f3

In other words, v is orthogonal to f1, f2, and f3, and can be expressed as a linear combination of them.

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2 plus 2 divided by 96 x 3 is equal to 2.00694444.

What is the order of operations?

The order of operations is a set of rules that dictate the order in which mathematical operations should be performed when evaluating an expression. These rules are also known as PEMDAS, which stands for Parentheses, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right).

The order of operations dictates that we first perform the division before the addition and multiplication. So we have:

2 + (2 ÷ (96 x 3))

Next, we perform the multiplication:

2 + (2 ÷ 288)

Finally, we perform the division:

2 + 0.00694444

This gives us the answer:

2.00694444

Therefore, 2 plus 2 divided by 96 x 3 is approximately equal to 2.00694444.

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Based on the data, the number closest to zero on number line A would be +4 and the farthest would be -15; on number line B those closest to -3 would be -2 and -4; and on number line C the closest to +10 would be +14, while the furthest away is -12.

To make the number lines we must draw a line and establish an interval for each number, in this case each interval is equal to one unit. We must also put zero in the middle as a reference point and from this number locate the rest, the negative numbers on the left and the positive numbers on the right.

Based on this information, the number closest to zero on number line A would be +4 and the farthest would be -15; on number line B those closest to -3 would be -2 and -4; and on number line C the closest to +10 would be +14, while the furthest away is -12.

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To find the volume of the part of the ball that lies between the cones ϕ=π/6 and ϕ=π/3 and with a radius of rho≤7, we first need to find the limits of integration for rho, theta, and phi.

Since the radius is given as rho≤7, the limits of integration for rho are 0 to 7.

The angle theta is not given in the question, which means we can integrate over the entire range of 0 to 2π.

For phi, the limits of integration are π/6 to π/3.

Using these limits, we can set up the integral for the volume as:

V = ∫∫∫ rho^2sin(ϕ) dρ dθ dϕ

with the limits of integration as mentioned above.

Evaluating the integral, we get:

V = ∫0^7 ∫0^2π ∫π/6^π/3 (ρ^2sin(ϕ)) dϕ dθ dρ

V = (2π/3) ∫0^7 ρ^2 (sin(π/3)-sin(π/6)) dρ

V = (2π/3) ∫0^7 ρ^2 (sqrt(3)/2-1/2) dρ

V = (π/3) [ (7^3)/3 (sqrt(3)/2-1/2) ]

V = 1264.27 cubic units (rounded to two decimal places)

Therefore, the volume of the part of the ball rho≤7 that lies between the cones ϕ=π/6 and ϕ=π/3 is approximately 1264.27 cubic units.
To find the volume of the part of the ball with ρ ≤ 7 that lies between the cones with ϕ = π/6 and ϕ = π/3, you can use the triple integral in spherical coordinates. The volume element in spherical coordinates is given by dV = ρ^2 sin(ϕ) dρ dϕ dθ.

Integrating over the given limits:

Volume = ∫∫∫ ρ^2 sin(ϕ) dρ dϕ dθ

The limits of integration are:
- ρ: 0 to 7
- ϕ: π/6 to π/3
- θ: 0 to 2π

Volume = ∫(from 0 to 2π) dθ * ∫(from π/6 to π/3) sin(ϕ) dϕ * ∫(from 0 to 7) ρ^2 dρ

Evaluating the integrals and simplifying, you get:

Volume = (2π) * (-cos(π/3) + cos(π/6)) * (1/3 * 7^3)

Volume ≈ 239.47 cubic units.

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Answer:b 6

Step-by-step explanation:

it just is

1.1. P(x, B, B) and P(A, y, z)
These two expressions are unifiable. The most general unifier is {x/A, y/B, z/B}.

2. P(g(f (v)), g(u)) and P(x, x)
These two expressions are not unifiable. There is no substitution that can make them equal.
3. P(x, f (x)) and P(y, y)
These two expressions are unifiable. The most general unifier is {x/y, f (x)/y}.
4. P(y, y, B) and P(z, x, z)
These two expressions are unifiable. The most general unifier is {y/z, x/z, B/z}.
5. 2 + 3 = x and x = 3 + 3
These two expressions are unifiable. The most general unifier is {x/6}.
1. The pair P(x, B, B) and P(A, y, z) is unifiable. The most general unifier is {x=A, y=B, z=B}.
2. The pair P(g(f(v)), g(u)) and P(x, x) is not unifiable, as g(f(v)) and g(u) are different and cannot be made identical.
3. The pair P(x, f(x)) and P(y, y) is not unifiable, as f(x) cannot be the same as x, and similarly, y cannot be the same as f(y).

4. The pair P(y, y, B) and P(z, x, z) is not unifiable, as in the first expression, the first and second terms are the same (y), but in the second expression, the first (z) and second (x) terms are different.
5. The pair 2 + 3 = x and x = 3 + 3 is unifiable. The most general unifier is {x=5}, as 2+3=5, which makes both expressions equal.

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The limit of the function as x approaches 0 is 1/6.

To find the limit of the function as x approaches 0, you can use l'Hospital's Rule if the function is in the indeterminate form (0/0 or ∞/∞). In this case, lim (x→0) sin^(-1)(x) / 6x, the function is in the indeterminate form (0/0). Therefore, you can apply l'Hospital's Rule.

To apply l'Hospital's Rule, differentiate both the numerator and the denominator with respect to x.

For the numerator:
d/dx [sin^(-1)(x)] = 1/√(1-x^2)

For the denominator:
d/dx [6x] = 6

Now, find the limit as x approaches 0 for the derivative of the numerator over the derivative of the denominator:

lim (x→0) (1/√(1-x^2))/6

As x approaches 0, the expression simplifies to:

(1/√(1-0^2))/6 = 1/6

The limit of the function as x approaches 0 is 1/6.

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The puppy's weight at 6.5 months, to at least 4 significant figures, is 8.229 kg.

How many six month old puppy weighs?

The Euler method of integration, we can approximate the puppy's weight at 6.5 months by first finding its weight at 6 months and then iteratively applying the given equation.

Starting at t = 6 months, we know the puppy's weight is x = 7.0 kg.

At each time step of delta t = 0.1 months, we can use the equation dx/dt = 10 - x to find the change in weight:

dx/dt = 10 - x
dx = (10 - x) dt

Using Euler's method, we can approximate the change in weight over a small time step as:

delta x = dx/dt * delta t
delta x = (10 - x) * 0.1

We can then update the puppy's weight by adding the change in weight to its current weight:

x_new = x + delta x

Repeating this process iteratively, we can find the puppy's weight at 6.5 months:

t = 6 months:
x = 7.0 kg

t = 6.1 months:
delta x = (10 - 7.0) * 0.1 = 0.3
x_new = 7.0 + 0.3 = 7.3 kg

t = 6.2 months:
delta x = (10 - 7.3) * 0.1 = 0.27
x_new = 7.3 + 0.27 = 7.57 kg

t = 6.3 months:
delta x = (10 - 7.57) * 0.1 = 0.243
x_new = 7.57 + 0.243 = 7.813 kg

t = 6.4 months:
delta x = (10 - 7.813) * 0.1 = 0.2197
x_new = 7.813 + 0.2197 = 8.0327 kg

t = 6.5 months:
delta x = (10 - 8.0327) * 0.1 = 0.19673
x_new = 8.0327 + 0.19673 = 8.2294 kg

Therefore, the puppy's weight at 6.5 months, to at least 4 significant figures, is 8.229 kg.

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The correct answer is d. Sometimes it is difficult to assign random numbers.

Systematic random sampling is often used in place of simple random sampling when it is difficult or impractical to assign random numbers. In systematic random sampling, a starting point is randomly chosen from the population, and then every nth element is selected to be part of the sample.

This method provides a more representative sample than other non-random methods and can be more efficient than simple random sampling in certain situations. However, it is still prone to bias if the pattern of the sampling interval coincides with any underlying patterns in the population.

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To find the average velocity for a given time interval, we need to find the change in position divided by the change in time over that interval.

a) For the interval [1, 1.5], the change in time is 0.5 seconds, and the change in position is h(1.5) - h(1) = (33(1.5) - 4.9[tex](1.5)^{2}[/tex]) - (33(1) - 4.9[tex](1)^{2}[/tex]) = 14.175 meters. Therefore, the average velocity for this interval is:

average velocity = change in position / change in time

= 14.175 / 0.5

= 28.35 m/s

b) For the interval [1, 1.25], the change in time is 0.25 seconds, and the change in position is h(1.25) - h(1) = (33(1.25) - 4.9[tex](1.25)^{2}[/tex]) - (33(1) - 4.9[tex]1^{2}[/tex]) = 8.425 meters. Therefore, the average velocity for this interval is:

average velocity = change in position / change in time

= 8.425 / 0.25

= 33.7 m/s

c) For the interval [1, 1.1], the change in time is 0.1 seconds, and the change in position is h(1.1) - h(1) = (33(1.1) - 4.9[tex](1.1)^{2}[/tex]) - (33(1) - 4.9[tex](1)^{2}[/tex]) = 3.685 meters. Therefore, the average velocity for this interval is:

average velocity = change in position / change in time

= 3.685 / 0.1

= 36.85 m/s

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The statement "Since the integral is finite, the series is convergent" is incorrect.

To use the integral test to determine whether the series [infinity] 7 n4 n = 1 is convergent or divergent, we need to evaluate the following integral: [infinity] 1 7 x4 dx.

Integrating 7 x4 with respect to x gives us (7/5) x5. Evaluating this from 1 to infinity gives us [(7/5) (infinity)5] - [(7/5) 1^5] = infinity, which means the integral is divergent.

Since the integral is divergent, the series [infinity] 7 n4 n = 1 is also divergent.

The statement "Since the integral is finite, the series is convergent" is incorrect.

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The mass of the wire is approximately 2.121 units.

To find the mass of the wire, we need to integrate the density over the length of the wire. The length of the wire can be found using the arc length formula

L = ∫[a,b] ||r'(t)|| dt

where r'(t) is the derivative of r(t), ||r'(t)|| is the magnitude of r'(t), and [a,b] is the interval of t values that defines the wire.

In this case, we have

r(t) = (t^2 - 1)j + 2tk

r'(t) = 2tj + 2k

||r'(t)|| = sqrt((2t)^2 + 2^2) = sqrt(4t^2 + 4) = 2sqrt(t^2 + 1)

Therefore, the length of the wire is

L = ∫[0,1] 2sqrt(t^2 + 1) dt

This integral can be evaluated using a trigonometric substitution:

Let t = tan(theta), then dt = sec^2(theta) d(theta), and sqrt(t^2 + 1) = sqrt(sec^2(theta)) = sec(theta)

Substituting, we have

L = ∫[0,π/4] 2sec^2(theta) sec(theta) d(theta)

L = 2 ∫[0,π/4] sec^3(theta) d(theta)

This integral can be evaluated using integration by parts

u = sec(theta), du/d(theta) = sec(theta) tan(theta)

dv/d(theta) = sec^2(theta), v = tan(theta)

∫ sec^3(theta) d(theta) = sec(theta) tan(theta) - ∫ sec(theta) tan^2(theta) d(theta)

Using the identity tan^2(theta) = sec^2(theta) - 1, we have

∫ sec^3(theta) d(theta) = sec(theta) tan(theta) - ∫ sec(theta) (sec^2(theta) - 1) d(theta)

∫ sec^3(theta) d(theta) = sec(theta) tan(theta) + ln|sec(theta) + tan(theta)| + C

where C is the constant of integration.

Substituting back to our original integral, we have

L = 2 [sec(theta) tan(theta) + ln|sec(theta) + tan(theta)|]_0^π/4

L = 2 [1 + ln(1 + sqrt(2))] ≈ 4.885

Now, we can find the mass of the wire using the formula

M = ∫[a,b] δ ||r'(t)|| dt

In this case, δ = 3/2t and [a,b] = [0,1], so we have

M = ∫[0,1] (3/2t) (2sqrt(t^2 + 1)) dt

M = 3 ∫[0,1] t sqrt(t^2 + 1) dt

We can evaluate this integral using a substitution similar to before:

Let t = sinh(u), then dt = cosh(u) du, and sqrt(t^2 + 1) = sqrt(sinh^2(u) + cosh^2(u)) = cosh(u)

Substituting, we have

M = 3 ∫[0,arsinh(1)] sinh(u) cosh^2(u) du

M = 3/2 ∫[0,arsinh(1)] (sinh(2u))' du

M = 3/2 [sinh(2u)]_0^ars

Using the formula for hyperbolic sine, we have:

M = 3/2 [sinh(2arsinh(1))] = 3/2 [sqrt(2^2 + 1^2) - 1] = 3/2 (sqrt(5) - 1) ≈ 2.121

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The given question is incomplete, the complete question is:

Find the mass of a wire that lies along the curve r(t) =(t^2 - 1)j + 2tk, 0<=t<=1, if the density is δ=3/2t.

To prove that vector w = ||v||u + ||u||v bisects the angle between u and v, we need to show that the angle between u and w is equal to the angle between w and v.

Let α be the angle between u and v, and let θ be the angle between u and w. Then we have:

cos(α) = u·v / (||u|| ||v||)

cos(θ) = u·w / (||u|| ||w||)

We can express w in terms of u and v:

w = ||v||u + ||u||v

||w|| = ||v|| ||u|| + ||u|| ||v||

||w|| = 2 ||u|| ||v||

Substituting ||w|| in the expression for cos(θ), we get:

cos(θ) = u·w / (||u|| ||w||)

cos(θ) = u·(||v||u + ||u||v) / (||u|| 2||v||)

cos(θ) = ||v|| u·u / (||u|| 2||v||) + ||u|| u·v / (||u|| 2||v||)

cos(θ) = (||v|| ||u|| cos(α) + ||u|| ||v||) / (2 ||u|| ||v||)

cos(θ) = (cos(α) + (||u||/||v||)) / 2

Similarly, we can find the angle between w and v:

cos(φ) = w·v / (||w|| ||v||)

cos(φ) = (||v||u + ||u||v)·v / (2||u|| ||v|| ||v||)

cos(φ) = (||u|| ||v|| cos(α) + ||v|| ||v||) / (2 ||u|| ||v||)

cos(φ) = (cos(α) + (||v||/||u||)) / 2

Since cos(θ) and cos(φ) are equal, we have:

(cos(α) + (||u||/||v||)) / 2 = (cos(α) + (||v||/||u||)) / 2

Simplifying and cross-multiplying, we get:

||v|| ||u|| = ||u|| ||v||

This is true, so we have shown that vector w = ||v||u + ||u||v bisects the angle between u and v.

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It is true that there exists a function f with continuous second partial derivatives such that fr(x, y) = x + y² and fy(x, y) = x - y².

True. There exists a function f with continuous second partial derivatives such that fx(x, y) = x + y² and fy(x, y) = x - y². To verify this, we can find the second partial derivatives and check for continuity:
fxy(x, y) = ∂^2f/∂x∂y = ∂/∂x(fy(x, y)) = ∂/∂x(x - y²) = 1
fyx(x, y) = ∂^2f/∂y∂x = ∂/∂y(fx(x, y)) = ∂/∂y(x + y²) = 2y
Since fxy(x, y) = fyx(x, y) for all (x, y) and both second partial derivatives are continuous, the given statement is true.

True. If we take the partial derivative of fr(x, y) with respect to y, we get fy(x, y) = x - 2y. Therefore, we know that the second partial derivative of f with respect to y exists and is continuous. Similarly, if we take the partial derivative of fy(x, y) with respect to x, we get fx(x, y) = 1. Therefore, we know that the second partial derivative of f with respect to x exists and is continuous. Therefore, we can conclude that there exists a function f with continuous second partial derivatives such that fr(x, y) = x + y² and fy(x, y) = x - y².

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a. ∫2^4 f(x) dx = ∫2^4 c dx = c(4-2) = 2c = 1
Therefore, c = 1/2.

b. ∫3^4 f(x) dx = ∫3^4 (1/2) dx = (1/2)(4-3) = 1/2
So, 1/2 or 50% of actual tracking weights exceed the target weight.

c. ∫2.75^3.25 f(x) dx = ∫2.75^3.25 (1/2) dx = (1/2)(3.25-2.75) = 1/4
So, 1/4 or 25% of actual tracking weights are within .25g of the target weight.

a. To determine the value of c, we need to make sure that the density function integrates to 1 over its range. Since f(x) = c for 2 < x < 4, we have:
∫(from 2 to 4) c dx = 1
Integrating c with respect to x gives:
cx ∣ (from 2 to 4) = 1
Substituting the limits:
c(4) - c(2) = 1
2c = 1
So, c = 1/2. Therefore, the density function f(x) is:
f(x) = 1/2 for 2 < x < 4, and f(x) = 0 otherwise.

b. To find the proportion of actual tracking weights that exceed the target weight (3g), we need to integrate the density function over the range 3 < x < 4:
∫(from 3 to 4) (1/2) dx
Integrating (1/2) with respect to x gives:
(1/2)x ∣ (from 3 to 4)
Substituting the limits:
(1/2)(4) - (1/2)(3) = 1/2
So, the proportion of actual tracking weights that exceed the target weight is 1/2, or 50%.

c. To find the proportion of actual tracking weights within 0.25g of the target weight, we need to integrate the density function over the range 2.75 < x < 3.25:
∫(from 2.75 to 3.25) (1/2) dx
Integrating (1/2) with respect to x gives:
(1/2)x ∣ (from 2.75 to 3.25)
Substituting the limits:
(1/2)(3.25) - (1/2)(2.75) = 0.25
So, the proportion of actual tracking weights within 0.25g of the target weight is 0.25, or 25%.

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Answer:

Step-by-step explanation:

To find the values of a, B, and C, we can use the Law of Cosines, which relates the lengths of the sides of a triangle to the cosine of one of its angles. Specifically, we can use the formula:

c^2 = a^2 + b^2 - 2ab*cos(C)

where c is the length of the side opposite angle C, and a and b are the lengths of the other two sides.

Substituting the given values, we get:

15^2 = a^2 + 30^2 - 2a30*cos(140)

Simplifying and solving for a, we get:

a^2 = 15^2 + 30^2 - 21530*cos(140)

a^2 = 1275.8476

a ≈ 35.7

So, we have found that a ≈ 35.7. Now, to find the angle B, we can use the Law of Sines, which relates the lengths of the sides of a triangle to the sines of its angles. Specifically, we can use the formula:

sin(B) / b = sin(C) / c

Substituting the given values, we get:

sin(B) / 30 = sin(140) / 15

Simplifying and solving for sin(B), we get:

sin(B) = (30*sin(140)) / 15

sin(B) = 1.982

However, since the sine function is only defined between -1 and 1, we can see that there is no angle B that satisfies this equation. This means that the given values do not form a valid triangle, and there is no solution for angle B.

Therefore, we can conclude that:

a ≈ 35.7

B = no solution

C = 140 degrees

The answer indicates that the supplied square's DEC measure is 90.

The square is a flat object in geometry with four equal sides and four right angles (90°). A square is a special sort of parallelogram that is both equilateral and equiangular, as well as a special kind of rectangle that is equilateral.

Properties of square:

1. Sides of the square are equal

2.The diagonal of the square cuts each other at half i.e at 90 degree

3.A square has 4 right angles along its edges.

GIVEN : DE = 7

             EC = 7

             ∠EDC = 45

             ∠ECD = 45

The sum of all angles of a triangle is 180 degree

∠DEC + ∠EDC + ∠ECD = 180

∠DEC + 45 + 45 = 180

∠DEC = 90 degree

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Option E. Chi-square test for independence because the data come from two independent random samples – those who are vegan/vegetarian and those who are not.

The suitable chi-square test for this situation is the Chi-square test for freedom in light of the fact that the information came from a solitary irregular example with the people characterized by two downright factors. The factors are age bunch and being veggie lover/vegan. The Chi-square test for freedom is utilized to decide whether there is a huge connection between two unmitigated factors.

For this situation, it will help decide whether there is a critical relationship between age bunch and being veggie lover/vegan. In the event that the test shows a critical affiliation, it would propose that age bunch is an indicator of being veggie lover/vegan. This test is proper in light of the fact that it can decide whether the factors are free or on the other hand assuming they have a critical relationship.

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The complete question is:

Are younger people more likely to be vegan/vegetarian? To investigate, the Pew Research Center classified a random sample of 1480 U.S. adults according to their age group and whether or not they are vegan/vegetarian. Determine which chi-square test is appropriate for the given setting. Which response below gives the correct test with appropriate reasoning?

A. Chi-square goodness of fit test because the data came from a single random sample with the individuals classified by their chocolate consumption.

B. Chi-square test for homogeneity because the data come from two independent random samples – those who are vegan/vegetarian and those who are not.

C. Chi-square test for homogeneity because the data came from a single random sample with the individuals classified according to two categorical variables.

D. Chi-square test for independence because the data came from a single random sample with the individuals classified according to two categorical variables.

E. Chi-square test for independence because the data come from two independent random samples – those who are vegan/vegetarian and those who are not.

The required tally table and frequencies are  

Interval     Tally       Frequency

0-4                -                   0

5-9               | |                   2

10-14            | |                   2

15-19            ||||                  4

20-24         ||||| ||||               9

25-29            |||                  3

A tally table is a table used for counting occurrences of data that belong to different intervals. It is used to organize data in a way that makes it easy to count and analyze.

Tally tables are commonly used to create frequency tables, which show the number of times each data value appears in a data set.

Here we have

The data

20, 27, 5, 6, 29, 7, 17, 11, 18, 5, 15, 17, 20, 27, 22, 13, 6, 28, 27, 23, 24, 17

To calculate the frequency, we count the number of tallies in each row:

Value 2: 2 occurrences

Value 3: 3 occurrences

Value 5: 4 occurrences

Value 6: 4 occurrences

Value 7: 4 occurrences

Value 8: 1 occurrence

Hence,

The required tally table and frequencies are

Interval     Tally       Frequency

0-4                -                   0

5-9               | |                   2

10-14            | |                   2

15-19            ||||                  4

20-24         ||||| ||||               9

25-29            |||                  3

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Answer:

109

Step-by-step explanation:

217-108=109

Use your calculator...

The ratio of the corresponding dimensions of the smaller pyramid to the larger pyramid is [tex]\frac{1}{4}[/tex] .

In real-world circumstances, ratios are employed to compare quantities quantitatively. A ratio can be used to compare the magnitude of one quantity to another.

The ratio of identical shapes' corresponding dimensions is equal to the square root of the ratio of their respective areas or volumes.

In this situation, the surface area ratio of the two triangular pyramids is

[tex]\frac{25}{400} = \frac{1}{4} .[/tex]

As a result, the equivalent dimension to [tex]\frac{1}{4}[/tex] .

This indicates that the smaller pyramid's corresponding dimensions are one-fourth the size of the larger pyramid's corresponding dimensions.

In conclusion:

related dimension ratio equals the square root of (ratio of corresponding areas)

related dimension ratio =[tex]\sqrt{\frac{25}{400} }[/tex]

equivalent size ratio = 1/4

As a result, the ratio of the smaller pyramid's equivalent dimensions to the largest pyramid is a quarter.

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The mistake is in the formula, the correct formula for the volume of a sphere is V = 4/3πr³ and likewise, the result is 15 inches.

The student made an error in the calculation of the volume formula for a sphere. The correct formula for the volume of a sphere is V = 4/3πr³, not 43πr³. To correct this mistake, the student should use the correct formula and solve for the radius as follows:

V = 4/3πr³

4500π = 4/3πr³ (substitute given volume)

4500π / (4/3π) = r³ (divide both sides by 4/3π)

r³ = 3375 (simplify)

r = 15 (take the cube root of both sides)

Therefore, the correct radius of the sphere is 15 inches.

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the value of x is 3.

What is are of triangle?

The territory included by a triangle's sides is referred to as its area. Depending on the length of the sides and the internal angles, a triangle's area changes from one triangle to another. Square units like m2, cm2, and in2 are used to express the area of a triangle.

The sum of all angle of triangle = 180

mYXZ = 62°

mVUW = (43 - 5x)°

Here (43 - 5x)° + 62 =90

-5x = 90-(43+62)

-5x = 90-105

x = 15/5

x=3

Hence the value of x is 3.

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To solve for s in the interval [-2 pi, pi) such that 3tan^2 s=1, we first need to isolate tan^2 s.

Dividing both sides by 3, we get:
tan^2 s = 1/3

Taking the square root of both sides, we get:
tan s = ±√(1/3)

Using the unit circle or a calculator, we can find the exact values of tan s that satisfy this equation.

Since tan s is positive in the first and third quadrants, we have:
tan s = √(1/3) in the first quadrant
tan s = -√(1/3) in the third quadrant

To find the values of s that correspond to these values of tan s, we use the inverse tangent function (tan^-1).

In the first quadrant:
s = tan^-1 (√(1/3)) ≈ 0.615 radians

In the third quadrant:
s = π + tan^-1 (-√(1/3)) ≈ 2.527 radians

Thus, the exact values of s in the interval [-2 pi, pi) that satisfy the equation 3tan^2 s = 1 are approximately 0.615 radians and 2.527 radians.

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To find the elasticity of demand at a price of $16, we need to use the formula: Elasticity of Demand = (Percentage Change in Quantity Demanded / Percentage Change in Price).

First, we need to find the quantity demanded at a price of $16 by plugging it into the demand function: D(16) = √(300 - 4(16)), D(16) = √244, D(16) ≈ 15.62. Next, we need to find the quantity demanded at a slightly higher price, say $17:
D(17) = √(300 - 4(17))
D(17) = √236
D(17) ≈ 15.36
Now we can calculate the percentage change in quantity demanded: Percentage Change in Quantity Demanded = [(New Quantity Demanded - Old Quantity Demanded) / Old Quantity Demanded] x 100%
Percentage Change in Quantity Demanded = [(15.36 - 15.62) / 15.62] x 100%
Percentage Change in Quantity Demanded ≈ -1.66%.

Next, we can calculate the percentage change in price: Percentage Change in Price = [(New Price - Old Price) / Old Price] x 100%. Percentage Change in Price = [(17 - 16) / 16] x 100%, Percentage Change in Price = 6.25%, Finally, we can plug these values into the elasticity of demand formula: Elasticity of Demand = (Percentage Change in Quantity Demanded / Percentage Change in Price)
Elasticity of Demand = (-1.66% / 6.25%)
Elasticity of Demand ≈ -0.266, Therefore, the elasticity of demand at a price of $16 is approximately -0.266.

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Find convergence & sum: Identify pattern, geometric series, test convergence, find sum with formula, multiply by factor to get 16.

To determine whether the series 4 + 3 + 9/4 + 27/16 + ... is convergent or divergent, and if convergent, find its sum, we will first identify the pattern and then apply the necessary tests.
1: Identify the pattern
Notice that the series can be rewritten as:
4(1) + 3(1) + 4(9/4) + 4(27/16) + ...
We can then factor out the 4 from each term, giving us:
4(1 + 3/4 + 9/16 + 27/64 + ...)
2: Recognize it as a geometric series
Now, we can see that the series inside the parenthesis is geometric, with the first term a = 1 and common ratio r = 3/4.
3: Test for convergence
For a geometric series to be convergent, the absolute value of the common ratio (|r|) must be less than 1:
|3/4| < 1
Since this inequality holds true, the series is convergent.
4: Find the sum
To find the sum of a convergent geometric series, we use the formula:
Sum = a / (1 - r)
Plugging in our values, we get:
Sum = 1 / (1 - 3/4) = 1 / (1/4) = 4
5: Multiply the sum by the factor we factored out earlier
Finally, multiply the sum by the factor we factored out in step 1:
Total sum = 4 * 4 = 16
So, the series 4 + 3 + 9/4 + 27/16 + ... is convergent, and its sum is 16.

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