John, Jim and Joe each went for a medical examination. Their combined height was 5.25 m. If John was 12 cm shorter than Jim and Jim was 0.09 m taller than Joe, how tall, in metres, was Joe?

Samantha and Mia are 13 km apart from each other.

A right triangle's squared sides add up to the hypotenuse's squared length, according to the Pythagorean Theorem.

Mia is 7 kilometers north of Julia's home as she walked at a speed of 7 kilometers per hour.

Samantha walked at an average speed of 11 km/h, and she is now 11 kilometers west of Julia's home.

A right-angled triangle is formed by Julia's house, Mia and Samantha's locations after one hour, and the figure's points.

Hypotenuse of the triangle, which measures distance between the females

the Pythagorean theorem,

H² = P² + B²

H² = 7² + 11²

H² = 49 + 121

H = √170

H = 13.038

H = 13km

Between them, there is a 13 kilometer distance.

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Answer:

x=3

y = -2

Step-by-step explanation:

2x+5y = -4

y = x-5

We want to use substitution

In the first equation, every time we see y, substitute x-5

2x + 5( x-5) = -4

Distribute

2x + 5x -25 = -4

Combine like terms

7x -25 = -4

Add 25 to each side

7x -25+25 = -5+25

7x = 21

Divide each side by 7

7x/7 = 21/7

x=3

Now we can find y

y = x-5

y = 3-5

y = -2

The answer is x = 3, y = -2 or (3, -2).

We are given that :

Let us substitute the 2nd equation's value of y in the 1st equation.

Now, substitute for x in the 2nd equation.

The group that would best represent a sample of the study population is: C: one thousand of their customers with a current smart phone data plan.

A sample that best represents a population under study is a sample that is a subset of the entire population, that is, research subjects that are drawn as samples should reflect the general characteristics of the entire population without leaving out any part of the population. Also, a good sample should enable a researcher make generalization.

A sample that is a subset of a population and reflects the characteristics of the general population would not be biased.

Given the situation above, the population of the study are smart phone customers that use dat in the cell phone company. So, a sample that would better represent this general population would be customers that currently have a smart phone plan, since the average amount of data they use is what the cell pone company wants to ascertain.

Therefore, the group that would best represent a sample of the study population is: C: one thousand of their customers with a current smart phone data plan.

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The numerical expression, 2/3 ÷ 2⁴ + (3/4 + 1/6) ÷ 1/3 = 67/24 on simplification using the BODMAS rule.

In the question, we are asked to simplify the numerical expression:

2/3 ÷ 2⁴ + (3/4 + 1/6) ÷ 1/3.

To simplify the expression, we will follow the BODMAS rule, where B means Brackets, O means Of, D means Divide, M means Multiplication, A means Addition, and S means Subtraction.

2/3 ÷ 2⁴ + (3/4 + 1/6) ÷ 1/3

= 2/3 ÷ 16 + (3/4 + 1/6) ÷ 1/3 {Solving 2⁴ = 16, before proceeding BODMAS}.

= 2/3 ÷ 16 + ((9+2)/12) ÷ 1/3 {Solving Brackets by taking LCM}

= 2/3 ÷ 16 + 11/12 ÷ 1/3 {Simplifying}

= 2/3 * 1/16 + 11/12 * 3/1 {Solving divisions by taking reciprocals}

= 1/24 + 11/4 {Multiplying}

= (1 + 66)/24 {Adding using LCM}

= 67/24 {Simplifying}.

Thus, the numerical expression, 2/3 ÷ 2⁴ + (3/4 + 1/6) ÷ 1/3 = 67/24 on simplification using the BODMAS rule.

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The provided question is incomplete. The complete question is:

"Type the correct answer in the box. Use numerals instead of words. For this item, a non-integer answer should be entered as a fraction using / as the fraction bar.

Simplify the numerical expression.

2/3 ÷ 2⁴ + (3/4 + 1/6) ÷ 1/3

The expression has a value equal to."

The above pattern follows an arithmetic sequence with a common difference of 14 and first term of 13

The pattern can be represented as follows:

13, 27, 41, 55

The first term of the sequence is 13 and the common difference is 14.

The above pattern is an arithmetic sequence.

Therefore, the following can be used to find the nth term.

nth term = a + (n - 1)d

where

Therefore,

a = 13

d = 27 - 13 = 14

Let's find the next term

5th term = 13 + (5 - 1)14

5th term = 13 +(4)14

5th term = 13 + 56

5th term = 69

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There were 204 participants from the three schools

The given parameters are:

X = 12 + Y

X = Z - 18

Girls = Boys + 50

The ratios of the number of boys to girls in the schools are:

1 : 2

1 : 5

2 : 1

This means that:

So, we have:

Boys = 1/3X + 1/6Y + 2/3Z

Girls = 2/3X + 5/6Y + 1/3Z

Substitute the above equations in Girls = Boys + 50

2/3X + 5/6Y + 1/3Z = 1/3X + 1/6Y + 2/3Z + 50

Evaluate the like terms

1/3X + 2/3Y - 1/3Z = 50

Multiply through by 3

X + 2Y - Z = 150

So, we have:

X = 12 + Y

X = Z - 18

X + 2Y - Z = 150

Substitute X = 12 + Y in X = Z - 18 and X + 2Y - Z = 150

12 + Y = Z - 18 ⇒ Y - Z = 30

12 + Y + 2Y - Z = 150 ⇒ 3Y - Z = 138

Subtract Y - Z = 30 from the equation 3Y - Z = 138 to eliminate Z

2Y = 108

Divide by 2

Y = 54

Substitute Y = 54 in X = 12 + Y

X = 12 + 54

X = 66

Substitute X = 66 in X = Z - 18

66 = Z - 18

Solve for Z

Z = 66 + 18

Z = 84

So, the total number of participants from the 3 schools is

Total = X + Y + Z

This gives

Total = 66 + 54 + 84

Evaluate the sum

Total = 204

Hence, there were 204 participants from the three schools

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[tex]r = \frac{15}{7} [/tex]

Answer: Option 2

Step-by-step explanation:

Let f(y)=x.

[tex]x=2y+3\\\\x-3=2y\\\\y=\frac{1}{2}x-\frac{3}{2}\\\\f^{-1}(x)=\frac{1}{2}x-\frac{3}{2}[/tex]

The inverse of the function is,

⇒ f ⁻¹(x) = 1/2 (x - 3)

A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

Given that;

The function is,

⇒ f (x) = 2x + 3

Now,

We can find the inverse of function as;

⇒ f (x) = 2x + 3

Put y = f (x);

⇒ y = 2x + 3

Solve for x;

⇒ y - 3 = 2x

⇒ x = 1/2 (y - 3)

⇒ f ⁻¹(x) = 1/2 (x - 3)

Thus, The inverse of the function is,

⇒ f ⁻¹(x) = 1/2 (x - 3)

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Answer:

Using the usual notations and formulas,

Using the usual notations and formulas,mean, mu = 3550

Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870

Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000

Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculate

Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839

Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839Probability of weight below 3000 lbs

Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839Probability of weight below 3000 lbs=P(X < 3000) = P(z < Z) = P(z < - 0.6321839) =

Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839Probability of weight below 3000 lbs=P(X < 3000) = P(z < Z) = P(z < - 0.6321839) =0.2636334

Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839Probability of weight below 3000 lbs=P(X < 3000) = P(z < Z) = P(z < - 0.6321839) =0.2636334Answer:

Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839Probability of weight below 3000 lbs=P(X < 3000) = P(z < Z) = P(z < - 0.6321839) =0.2636334Answer:Probability that a car randomly selected is less than 3000

Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839Probability of weight below 3000 lbs=P(X < 3000) = P(z < Z) = P(z < - 0.6321839) =0.2636334Answer:Probability that a car randomly selected is less than 3000=P(X < 3000) = 0.2636 (to 4 decimals)

Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839Probability of weight below 3000 lbs=P(X < 3000) = P(z < Z) = P(z < - 0.6321839) =0.2636334Answer:Probability that a car randomly selected is less than 3000=P(X < 3000) = 0.2636 (to 4 decimals)Probability that a car randomly selected is greater than 3000

Using the usual notations and formulas,mean, mu = 3550standard deviation, sigma = 870Observed value, X = 3000We calculateZ= (X-mu)/sigma = (3000-3550)/870 = -0.6321839Probability of weight below 3000 lbs=P(X < 3000) = P(z < Z) = P(z < - 0.6321839) =0.2636334Answer:Probability that a car randomly selected is less than 3000=P(X < 3000) = 0.2636 (to 4 decimals)Probability that a car randomly selected is greater than 3000=1 - P(X < 3000) = 1 - 0.2636 (to 4 decimals) =0.7364 (to 4 decimals)

Answer: Friday

Step-by-step explanation:

Using the law of sines, it is found that the measure of angle x is given as follows:

x = 69.9º.

Suppose we have a triangle in which:

The lengths and the sine of the angles are related as follows:

sin(A)/A = sin(B)/B = sin(C)/C

Considering the given triangle, the following relation can be established:

sin(x)/11 = sin(28º)/x

Hence, applying cross multiplication:

sin(x) = 2sin(28º)

sin(x) = 0.938943126

x = arcsin(0.938943126)

x = 69.9º.

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Step-by-step explanation:

using gp formula

tn=ar^n-1

which our a which is the first term is = -3

our r which is t2/t1=-6

t8=(-3)(-6)^8-1

=(-3)(-6)^7

=(-3)(-279936)

=839808

The end behavior of the given polynomial is that as x → -∞ or  x → ∞, then, f(x) → 5

We are given the polynomial;

f(x) = 5x/(x - 25)

Now, we want to find the limits as x → ±∞. Let us rearrange the given polynomial to get; f(x) = 5/(1 - (25/x))

Thus, applying limits we have;'

lim x → ±∞ [5/(1 - (25/x))]

From algebraic limit laws we know that;

If f(x) = k, then;

lim x → +∞ [f(x)] = k

Also, lim x → -∞ [f(x)] = k

Thus, applying limits at infinity to our polynomial gives;

lim x → ±∞ [5/(1 - (25/x))] = 5/(1 - 0) = 5

This is because lim x → ∞ for 1/x is 0.

Thus, f(x) has horizontal asymptotes at y = 5

Thus, we conclude that the end behavior is that as x → -∞ or  x → ∞, then, f(x) → 5

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Using a linear function, the total charge from parking in the lot for 72 hours is of:

b. $146.

A linear function is modeled by:

y = mx + b

In which:

Both the basic fee, which is the y-intercept, and the hourly fee, which is the slope, are of $2, hence the cost of parking x hours is given by:

C(x) = 2x + 2

Hence the cost for parking 72 hours is:

C(72) = 2 x 72 + 2 = 2 x 73 = $146.

Which means that option b is correct.

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The 90% confidence interval for the true difference between the population proportions is [ - 0.0908, - 0.0092]

Given,

[tex]N_{1}[/tex] = 731

[tex]N_{2}[/tex] = 644

[tex]P_{1}[/tex] = 0.33

[tex]P_{2}[/tex] = 0.28

z score for 90% confidence interval = 1.645

Here, the confidence interval formula :

( [tex]P_{1} -P_{2}[/tex]) ± z [tex]\sqrt{\frac{P_{1}(1-P_{1}) }{N_{1} }+ \frac{P_{2}(1-P_{2}) }{N_{2} } }[/tex]

Substituting the values, we get

    (0.33 - 0.28) ± 1.645 [tex]\sqrt{\frac{0.33(1-0.33)}{731}+\frac{0.28(1-0.28)}{644} }[/tex]

=   0.05 ± 1.645 [tex]\sqrt{0.0003024624+0.0003130435}[/tex]

=   0.05 ± 1.645 [tex]\sqrt{0.0006155059}[/tex]

=    0.05 ± 1.645 × 0.0248093914

=    0. 05 ± 0.0408114489

Confidence interval:

- 0.05 - 0.0408114489 = - 0.0908114489 ≈ - 0.0908

- 0.05 + 0.0408114489 = - 0.0091885511 ≈ - 0.0092

The confidence interval for the true difference between the population proportions is [ - 0.0908, - 0.0092]

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Based on the amount of money that Jerl had and then the amount that she put away, the possible values of the number of dollars in the original pile of money was ( 200, 440).

The amount that was above $200 that she found can be x which means that the greater side of the inequality is:

= 200 + x

She then gave away $80:

= 120 + x

She gave away 1/3 of the money so the amount left is:

= 2/3 x (120 + x)

The lesser side of the inequality:

(x + 2) - 200 = x

So then:

((120 + x) x 2) / 3 > x

240 + 2x > 3x

240 > x

x < 240

The interval that shows the possible values of the original pile of money is therefore:

( 200, 440)

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Answer:  $10.8

Step-by-step explanation:  To do this, we need to find 90% of $12 because the cap is 10% off. We can do this by multiplying 12 by 0.9.  12 x0.9 = 10.8.

The total amount he would have at 69 is $343,347.81.

The formula that can be used to determine the future value of the deferred annuity is:

Future value = annuity factor x monthly deposit

Annuity factor = {[(1+r)^n] - 1} / r

Where:

Amount he would save every 6 months:

Future value : 900 x {[(1.0275^90) - 1] / 0.275}= $343,347.81

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Answer:

Maximum/Minimum Value:  (0,−2)   is a local minima (1/8,8)  is a local maxima

Explanation: Use the derivative to find the maximum and minimum

Answer:

Period = ¹/₄

Step-by-step explanation:

The cosine function is periodic, meaning it repeats forever.

Standard form of a cosine function:

f(x) = A cos(B(x + C)) + D

where:

Given function:

[tex]y=-5 \cos (8 \pi x)+3[/tex]

Comparing the given function with the standard form:

[tex]\implies \sf Period=\dfrac{2 \pi}{B}=\dfrac{2 \pi}{8 \pi}=\dfrac{1}{4}[/tex]

Therefore, the period of the given function is ¹/₄.

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Step-by-step explanation:

it is a line, so that is 1 point, where it cuts the x-axis.

in general that means y = 0.

so,

0 = 4x - 3

4x = 3

x = 3/4

the point, where the line cuts the x-axis is

(3/4, 0)

The value of the function w(5) is 53

The function is given as:

w(x) = 9x + 8

The expression w(5) implies that the value of x is 5

i.e. x = 5

Substitute the known values in the above equation

w(5) = 9 * 5 + 8

Evaluate the product

w(5) = 45 + 8

Evaluate the sum

w(5) = 53

Hence, the value of the function w(5) is 53

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Answer:

1178 because 31 dollars an hour for 38 hours you would multiply or times 31 and 38 and get 1178 for total money earned

The sequence [tex]a_n=\frac{n^2}{n^3+5n}[/tex] diverges.

For given question,

We have been given a sequence [tex]a_n=\frac{n^2}{n^3+5n}[/tex]

We need to determine whether the sequence converges or diverges.

From given sequence we have, [tex]a_{n+1}=\frac{(n+1)^2}{(n+1)^3+5(n+1)}[/tex]

We use Ratio Test.

According to Ratio Test, [tex]r=\frac{a_{n+1}}{a_n}[/tex], where sequence converges if and only if |r| < 1.

Consider,

[tex]\lim_{n \to \infty} |\frac{a_{n+1}}{a_n} |\\\\= \lim_{n \to \infty} |\frac{\frac{(n+1)^2}{(n+1)^3+5(n+1)}}{\frac{n^2}{n^3+5n}} |\\\\\\= \lim_{n \to \infty} |\frac{(n+1)^2(n^3+5n)}{n^2[(n+1)^3+5(n+1)]} |\\\\=\infty[/tex]

Since [tex]\lim_{n \to \infty} |\frac{a_{n+1}}{a_n} |[/tex] is not defined, the sequence [tex]a_n=\frac{n^2}{n^3+5n}[/tex] diverges.

Therefore, the sequence [tex]a_n=\frac{n^2}{n^3+5n}[/tex] diverges.

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