Answers
Answer:
point B
Explanation:
as you may see that's where the two color lines meet and there only
Related Questions
CAN SOMEONE HELP WITH THIS QUESTION?
If the solution in part B was made by taking 10.00 mL of a stock solution and diluting it to 100.00 mL, what is the concentration of the dye in the stock solution?
Answers
The concentration of the dye in the stock solution is 0.0250 M when solution in part B was made by taking 10.00 mL of a stock solution .
What is Concentration?The amount of a solute dissolved in a given amount of a solvent or solution is referred to as concentration. It is usually represented in terms of the amount of solute per unit volume or mass of solution.
We can use the following equation to compute the dye concentration in the stock solution:
C₁V₁ = C₂V₂
C₁ =concentration of the stock solution,
V₁ = volume of the stock solution used,
C₂ = concentration of the diluted solution,
V₂= Total volume of the diluted solution.
In this scenario, V₁ = 10.00 mL, V₂ = 100.00 mL, and C₂ = 0.00250 M (as determined in part B). When we plug these numbers into the equation and solve for C₁, we get:
C₁ = (C₂V₂) / V₁
= (0.00250 M x 100.00 mL) / 10.00 mL
= 0.0250 M
Therefore, the concentration of the dye in the stock solution is 0.0250 M.
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a week tribasic acid of relative molecular mass of 210 insoluble in benzene and in water with the same molecular state at the same temperature after 2.8 g of x had been shaken with 100 cm cubic of benzene and 50 cm cubic of water, it was found that 25 cm cubic of aqueous layer needed 14.5 cm cubic of one mole sodium hydroxide solution for neutralization .Calculate partition coefficient of x between benzene and water
Answers
Answer: The partition coefficient of X between benzene and water is 0.
Explanation: To find the partition coefficient (K) of the tribasic acid (X) between benzene and water, we first need to calculate the amount of X that dissolves in each solvent.
Let's start by finding the amount of X that dissolves in water:
2.8 g of X is shaken with 50 cm^3 of water, which is equivalent to a mass/volume concentration of 0.056 g/cm^3.
Let's assume that x g of X dissolves in 50 cm^3 of water. This means that the concentration of X in water is x/50 g/cm^3.
Since the acid is tribasic, it reacts with sodium hydroxide in a 1:3 stoichiometric ratio. Therefore, the amount of sodium hydroxide needed to neutralize X in water is (1/3) * (x/50) = x/150 moles/cm^3.
We are given that 14.5 cm^3 of 1M NaOH solution is needed to neutralize the X in 25 cm^3 of aqueous layer. This means that the concentration of X in the aqueous layer is (14.5/25) moles/cm^3.
Setting the two expressions for concentration of X equal to each other and solving for x gives:
x/50 = 14.5/25 * 150
x = 261 g
Next, let's find the amount of X that dissolves in benzene:
We are given that X is insoluble in benzene, so the amount of X that dissolves in benzene is effectively zero.
Finally, we can calculate the partition coefficient:
K = (concentration of X in benzene) / (concentration of X in water)
Since the concentration of X in benzene is effectively zero, we have:
K = 0 / (261/50)
K = 0
Therefore, the partition coefficient of X between benzene and water is 0.
At constant pressure, the temperature of a 3 L sample of gas is increased from 250 K to 300 K. What is the new volume of the gas sample?
Answers
The new volume of the gas sample is approximately 3.6 L.
According to the ideal gas law, PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is temperature in Kelvin. If pressure is constant, we can use the formula V1/T1 = V2/T2 to find the new volume of the gas sample.
V1/T1 = V2/T2
V2 = (V1 x T2)/T1
V2 = (3 L x 300 K) / 250 K
V2 = 3.6 L
Therefore, the new volume of the gas sample is approximately 3.6 L. As the temperature of the gas sample increased from 250 K to 300 K, the volume increased proportionally since pressure was held constant.
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.A cylinder of compressed gas has a pressure of 4.9 atm in one day. The next day, the same
cylinder of gas has a pressure of 4.7 atm, and its temperature is 8°C. What was the
temperature on the previous day in °C?
Answers
Answer:
We can use the ideal gas law to solve for the initial temperature of the gas:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.
We can assume that the number of moles and volume of gas are constant, since the problem states that it is the same cylinder of gas. Therefore, we can write:
P1/T1 = P2/T2
where P1 is the initial pressure, T1 is the initial temperature, P2 is the final pressure, and T2 is the final temperature.
Substituting the values given in the problem, we get:
4.9/T1 = 4.7/281
Solving for T1, we get:
T1 = 4.9 × 281 / 4.7
T1 = 293 K
Converting to Celsius, we get:
T1 = 20°C
Therefore, the initial temperature of the gas was 20°C.
Generate the heating graph for H2O. Determine the quantity of energy transfer required to heat 1.0g solid H2O from -50 C to the melting point 0C
Answers
Here is a rough sketch of the heating graph for H2O:
/\
/ \
_____/ \_____
Q
In this graph, the x-axis represents the quantity of heat added or removed (Q), and the y-axis represents the temperature (T). The graph consists of three main regions:
1. Solid region: H2O is in the solid phase, and its temperature is below the melting point (0°C). During this region, the heat added to the H2O is used to increase its temperature, and the slope of the graph is positive but less steep than the liquid region.
2. Melting region: H2O is in the process of melting, and its temperature remains constant at 0°C. During this region, the heat added to the H2O is used to break the intermolecular bonds between the H2O molecules, and the slope of the graph is zero.
3. Liquid region: H2O is in the liquid phase, and its temperature is above the melting point (0°C). During this region, the heat added to the H2O is used to increase its temperature, and the slope of the graph is positive but steeper than the solid region.
To determine the quantity of energy transfer required to heat 1.0g solid H2O from -50°C to the melting point 0°C, we need to calculate the heat required to raise the temperature of the H2O from -50°C to 0°C and the heat required to melt the H2O at 0°C. We can use the following equations:
For the solid region:
Q1 = m * Cp * ΔT
Where Q1 is the heat required, m is the mass of the H2O (1.0g), Cp is the specific heat capacity of ice (2.09 J/g°C), and ΔT is the change in temperature (0°C - (-50°C) = 50°C).
Q1 = 1.0g * 2.09 J/g°C * 50°C = 104.5 J
For the melting region:
Q2 = m * ΔHfus
Where Q2 is the heat required, m is the mass of the H2O (1.0g), and ΔHfus is the enthalpy of fusion of ice (6.01 kJ/mol or 333.6 J/g).
Q2 = 1.0g * 333.6 J/g = 333.6 J
Therefore, the total heat required to heat 1.0g of solid H2O from -50°C to the melting point 0°C is:
Qtotal = Q1 + Q2 = 104.5 J + 333.6 J = 438.1 J
So, 438.1 J of energy transfer is required to heat 1.0g solid H2O from -50°C to the melting point 0°C.
if a sample x contains 2.3x10^22 molecules of sample x, what is the identity of sample x?
Answers
If sample X contains 2.3 * 10²² molecules of sample X, the identity of sample x is 0.038 moles of sample X molecules.
What is the mole of a substance?The mole of a substance is the amount of a substance that contains exactly as many molecules, atoms, radicals, ions, or electrons as there are in 12 grams of Carbon-12.
Experimentally, it was discovered that 12 grams of Carbon-12 contain 6.02 * 10²³ atoms. Hence, a mole of every substance contains 6.02 * 10²³ particles of that substance
The moles of molecules present in sample X = 2.3 * 10²²/ 6.02 * 10²³ * 1 mole
The moles of molecules present in sample X = 0.038 moles of sample X molecules.
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Which of the following best describes the number of atoms for each element in the chemical reaction? A. There are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms on the reactant side and 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms on the product side. B. There are 6 carbon atoms, 12 hydrogen atoms and 8 oxygen atoms on the reactant side and 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms on the product side. C. There are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms on the reactant side and 6 carbon atoms, 12 hydrogen atoms, and 3 oxygen atoms on the product side. D. There are 6 carbon atoms, 12 hydrogen atoms and 12 oxygen atoms on the reactant side and 1 carbon atom, 2 hydrogen atoms, and 3 oxygen atoms on the product side.
Answers
The correct answer is A. There are 6 carbon atoms, 12 hydrogen atoms, and 18 oxygen atoms on the reactant side, and 6 carbon atoms, 12 hydrogen atoms, and 18 oxygen atoms on the product side.
This is because of the law of conservation of matter, which states that matter cannot be created or destroyed by a chemical reaction. Therefore, the number of atoms of each element must remain the same on both sides of the reaction.
In this case, the number of carbon, hydrogen, and oxygen atoms must remain the same on both the reactant and product sides.
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What volume, in mL, of 0.319 M Li2CO3 solution is required to react with 58.4 mL of 0.352 M HNO3.
2HNO3(aq) + Li2CO3(aq) → H2O(l) + LiNO3(aq) + CO2(g)
Answers
To react with 58.4 mL of 0.352 M HNO₃, 32.29 mL of a 0.319 M Li₂CO₃ solution is needed.
What is Volume?The quantity of space a three-dimensional item or substance takes up is measured by its volume. It is a term used in physical measurement to indicate how much physical space an object or substance occupies. Volume can be expressed in several quantities, including liters, cubic meters, gallons, and cubic feet.
The balanced chemical equation for the reaction between HNO₃ and Li₂CO₃ is: 2HNO₃(aq) + Li₂CO₃(aq) → H₂O(l) + LiNO₃(aq) + CO₂(g)
We can see from the equation that the mole ratio of Li₂CO₃ to HNO₃ is 2:1.
Therefore, we must first determine the quantity of HNO₃ and then use the mole ratio to get the quantity of Li₂CO₃ needed. When we know the quantity of Li₂CO₃ in moles, we may utilize its molarity to determine the volume of solution needed.
Step 1: Determine the number of moles of HNO₃
n(HNO₃) = C(HNO₃) x V(HNO₃)
n(HNO₃) = 0.352 mol/L x 58.4 mL x 1 L/1000 mL
n(HNO₃) = 0.0206 mol
Step 2: Determine how many moles of Li₂CO₃ are needed using the mole ratio.
We can infer from the balanced chemical equation that 2 moles of HNO₃ react with 1 mole of Li₂CO₃. So, n(Li₂CO₃) = 0.0206 mol HNO₃ x (1 mol Li₂CO₃/2 mol HNO₃)
n(Li₂CO₃) = 0.0103 mol
Step 3: Calculate the volume of 0.319 M Li₂CO₃ solution required
n(Li₂CO₃) = C(Li₂CO₃) x V(Li₂CO₃)
V(Li₂CO₃) = n(Li₂CO₃) / C(Li₂CO₃)
V(Li₂CO₃) = 0.0103 mol / 0.319 mol/L
V(Li₂CO₃) = 32.29 mL
In order to react with 58.4 mL of 0.352 M HNO3, 32.29 mL of a 0.319 M Li₂CO₃ solution is needed.
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A patient received 3.0 g of NaCl in 8 hours. How many milliliters of a 0.90% (m/v) NaCl (saline) solution were delivered
Answers
The patient received 37,037.04 mL of a 0.90% (m/v) NaCl solution.
What is a saline solution?
A saline solution is sodium chloride, salt, and water mixture. It is frequently utilised in medicine, especially for intravenous (IV) drips and injections that replenish the body's electrolytes and fluids.
We must apply the following formula to this issue in order to find a solution:
amount of solute = concentration x volume
where volume is in milliliters and concentration is expressed as a percentage (m/v).
Since concentration is specified as a percentage by mass, we must first change 3.0 g to milligrams (mg):
3.0 g = 3000 mg
In order to solve for volume, we may then plug in the given values:
3000 mg = 0.90% x volume
volume = 3000 mg / 0.009
volume = 333,333.33 mL
But this volume is for a saline solution that is 100% saline. We must modify the volume in accordance with the concentration, which is 0.90% (m/v):
0.90% x volume = 333,333.33 mL
volume = 333,333.33 mL / 0.009
volume = 37,037.04 mL
Therefore, the patient received 37,037.04 mL of a 0.90% (m/v) NaCl solution.
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Explain the qualifications that must be met for any vehicle to go in space. Write your response in the essay box below.
Answers
Answer:
1) Capable of withstanding the extreme conditions of space: Spacecraft must be designed and constructed to withstand the harsh conditions of space, including extreme temperatures, vacuum, radiation, and more. The materials used in spacecraft must be durable and able to withstand the rigors of spaceflight.
2) Safety systems: Spacecraft must have safety systems in place to protect the crew in case of emergencies or malfunctions, including escape systems and redundant systems.
3) Navigation and guidance systems: Spacecraft must have accurate navigation and guidance systems that can determine the vehicle's position in space.
4) Communication systems: Spacecraft must have reliable communication systems that allow the crew to communicate with mission control on Earth and with other spacecraft and satellites in space.
5) Life support systems: Spacecraft must be equipped with life support systems to sustain the crew during the mission such as systems for providing oxygen, water, and food, as well as waste management systems.
According to Niels Bohr, electrons travel around an atom's nucleus in well-defined orbits. Why did Bohr's model of atoms need to be revised?
A. Electrons were discovered to have the same charge.
B. Atomic nuclei were discovered to contain protons and neutrons.
C. Electrons were discovered to exhibit wave-like behavior.
D. Elements were discovered to emit unique line spectra.
Answers
The Bohr model of atoms needed to be revised because electrons were discovered to exhibit wave-like behavior. Hence, option C is correct.
The classical mechanics-based Bohr model was unable to account for this wave-like activity of electrons. The Schrödinger equation and the progress done in quantum mechanics contributed a very significant amount of knowledge for understanding the wave behavior of atomic electrons.
Instead than describing a particular orbit or path, the Schrödinger equation allowed us to describe the probability distribution of the electrons within an atom.
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Vitamins vs minerals
Answers
Vitamins are organic substances, which means they're made by plants or animals. Minerals are inorganic elements that come from soil and water, and are absorbed by plants or eaten by animals. Your body needs larger amounts of some minerals, such as calcium, to grow and stay healthy.
Which reaction would occur at the anode in a voltaic cell?
Cd2+(aq)+Zn(s)→Zn2+(aq)+Cd(s)
K+(aq)+e−→K(s)
Cu2+(aq)+2e−→Cu(s)
Ca(s)→Ca2++2e−
Answers
In a voltaic cell, the anode is the electrode where oxidation takes place. So, among the given reactions, the reaction that involves oxidation at the anode is: Ca(s) → Ca2+ + 2e-.
In a voltaic cell, the reaction at the anode is an oxidation reaction, wherein a substance loses electrons. From the provided reactions, the reaction of calcium (Ca) transforming to a calcium ion by losing two electrons (Ca(s)→Ca2+ + 2e−) occurs at the anode.
Explanation:In a voltaic cell, oxidation occurs at the anode. Therefore, the reaction that would take place at the anode would be the one in which the substance loses electrons, transforming from a neutral state to an ion. From the provided reactions, Ca(s)→Ca2+ + 2e− represents this process as calcium (Ca) loses two electrons (2e−) and becomes a cation (Ca2+). This reaction is called an oxidation reaction, characteristic of what occurs at the anode in a voltaic cell.
This equation represents the oxidation of calcium (Ca) as it loses two electrons (2e⁻) and becomes a calcium ion (Ca²⁺). This process is indeed an oxidation reaction, and it accurately represents what occurs at the anode in a voltaic cell.
The anode is where electrons are generated and flow through an external circuit to the cathode, where reduction reactions take place. In this electrochemical setup, the anode and cathode are essential components that drive the flow of electrons and generate electrical energy.
Therefore, the given reaction involving the oxidation of calcium (Ca) at the anode accurately reflects the principles of electrochemical cells, including voltaic cells, where oxidation reactions occur at the anode.
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An equilibrium constant (Keq) is a numerical expression of the ratio of the reactant concentration to the product concentration.
True
False
Answers
Answer: False
Explanation: The equilibrium constant (K<sub>eq</sub>) is the ratio of product and reactant concentrations (or activities) at equilibrium, expressed as [products]/[reactants]. K<sub>eq</sub> is a constant that shows the extent of a reaction at equilibrium.
Answer:
For example, the equilibrium constant of concentration (denoted by Kc) of a chemical reaction at equilibrium can be defined as the ratio of the concentration of products to the concentration of the reactants, each raised to their respective stoichiometric coefficients.
Explanation:
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Use the chemical equation below to answer the following question: The system is at equilibrium, but then it is subjected to a decrease in pressure. Which change will happen?
N2O4(g)+energy><2NO2(g)
The rate of the forward reaction will increase, collisions will decrease.
The rate of the forward reaction will increase, collisions will increase.
The rate of the reverse reaction will increase, collisions will decrease.
The rate of the reverse reaction will increase, collisions will increase.
Answers
Answer:
The rate of the forward reaction will increase, collisions will increase.
Explanation:
According to Le Chatelier's principle, if a system at equilibrium is subjected to a change in conditions, the system will shift in a direction that counteracts the change. In this case, if the system at equilibrium is subjected to a decrease in pressure, it will shift in a direction that increases the total number of moles of gas to counteract the decrease in pressure.
In the given chemical equation, the forward reaction involves the conversion of one mole of N2O4 (a gas) into two moles of NO2 (also gases), while the reverse reaction involves the conversion of two moles of NO2 into one mole of N2O4. Therefore, increasing the number of moles of gas favors the forward reaction, while decreasing the number of moles of gas favors the reverse reaction.
Since a decrease in pressure will decrease the total number of moles of gas in the system, the system will shift in a direction that increases the total number of moles of gas. Therefore, the equilibrium will shift towards the side with more moles of gas, which is the forward reaction.
As a result, the rate of the forward reaction will increase and the rate of the reverse reaction will decrease. However, the collisions between the gas molecules will increase due to the shift towards the forward reaction, as there are more gas molecules in the system.
Therefore, the correct answer is: The rate of the forward reaction will increase, collisions will increase.
properties of gases lab
Answers
Four properties of gases will be investigated: pressure, volume, temperature, and number of molecules. By assembling the equipment, conducting the appropriate tests, and analyzing your data and observations, you will be able to describe the gas laws, both qualitatively and mathematically.
I WILL GIVE 35 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE
Answers
The grams of [tex]Cu(OH)_{2}[/tex] produce by reaction of copper chloride with sodium hydroxide if you mix 0.9L of 0.557 M copper chloride with 1.35 L of 0.458 M sodium hydroxide is 41.55 g.
How to calculate grams?The balanced chemical equation describing this double replacement reaction should be written first.
[tex]CuCl_{2} + 2NaOH > > Cu(OH)_{2} + 2NaCl[/tex]
You should be aware that 1 mole of copper chloride requires 2 moles of sodium chloride to react with it to form 1 mole of copper(II) hydroxide.
Calculate how many moles of each reactant you are mixing together by comparing the molarities and volumes of the two solutions.
Moles of[tex]NaOH[/tex]= [tex]1.35*0.458[/tex]
Moles of [tex]NaOH[/tex]= 0.6183
Moles of [tex]CuCl_{2}[/tex]= [tex]0.9*0.557[/tex]
Moles of [tex]CuCl_{2}[/tex] = 0.5013
You are conscious that 0.5013 moles of copper chloride will be needed.
[tex]0.5013*\frac{2 moles of NaOH}{1 mole of CuCl_{2} }[/tex]
1.0026 moles of [tex]NaOH[/tex] (what we need)>> 0.6183 moles of [tex]NaOH[/tex] (what we have)
Thus , This implies that sodium hydroxide will operate as a limiting reagent and that it will be completely consumed before all of the moles of copper(II) sulfate have an opportunity to react.
The reaction will therefore use 0.618 moles of sodium hydroxide and result in
[tex]0.618 moles of NaOH * \frac{1 mole of Cu(OH)_{2} }{2 moles of NaCl}[/tex]
= 0.309
To convert moles to grams molecular mass of copper hydroxide is
[tex]0.309 moles of Cu(OH)_{2}*\frac{134.45 g/mol}{1}[/tex]
= 41.55 g
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Propose describe in your own words a situation where chemical energy is transformed to potential energy
Answers
Chemical energy is stored in the bonds that connect atoms with other atoms and molecules with other molecules. Because chemical energy is stored, it is a form of potential energy. When a chemical reaction takes place, the stored chemical energy is released.
Given the following equation, Na+ + Cl → NaCl, how many grams
of sodium would need to react with 4.5 moles of chloride?
A. 15.6 g
B. 103.5 g
C. 5.1 g
D. 157.55 g
E. 53.5 g
Answers
103.5 g of sodium would be needed to react with 4.5 moles of chloride ions. Therefore, the correct option is (B).
The balanced chemical equation Na+ + Cl → NaCl tells us that 1 mole of sodium ions (Na+) reacts with 1 mole of chloride ions (Cl-) to produce 1 mole of sodium chloride (NaCl). Therefore, to react with 4.5 moles of chloride, we need an equal number of moles of sodium. This is because the reactants must be present in the stoichiometric ratio of 1:1 to ensure complete reaction.
Moles of Na+ required = moles of Cl- = 4.5 mol
The molar mass of Na+ is 23 g/mol, so the mass of sodium required is:
Mass of Na+ = Moles of Na+ x Molar mass of Na+
Mass of Na+ = 4.5 mol x 23 g/mol = 103.5 g
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HELPPPP ME PLEASEEEEE
Answers
Oxidation half equation;
Mg(s) ----> Mg^2+(aq) + 2e
Reduction half equation;
2H^+(aq) + 2e ---->H2(g)
The balanced reaction equation is;
Mg(s) + 2HCl(aq) ---->MgCl2(aq) + H2(g)
What is oxidation and reduction half equations?Whereas reduction involves the acquisition of electrons, oxidation involves the loss of electrons. Redox reactions are the term used to describe these two processes, which frequently take place in tandem.
The species that is losing electrons is described by an oxidation half-equation, whereas the species that is gaining electrons is described by a reduction half-equation.
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A 65.00 gram piece of Aluminum is heated to 80.0 °C. It is then placed in 135.00 mL of 26.00 °C water. The final temperature of the water with the metal in it is 31.0 °C. What is the specific heat of the aluminum?
Answers
According to specific heat capacity, the specific heat of the aluminum is 0.807 J/gK .
Specific heat capacity is defined as the amount of energy required to raise the temperature of one gram of substance by one degree Celsius. It has units of calories or joules per gram per degree Celsius.
It varies with temperature and is different for each state of matter. Water in the liquid form has the highest specific heat capacity among all common substances .Specific heat capacity of a substance is infinite as it undergoes phase transition ,it is highest for gases and can rise if the gas is allowed to expand.
It is given by the formula ,
Q=mcΔT in case of 2 substances, aluminium and water it is m₁c₁ΔT₁=m₂c₂ΔT₂, thus, c₁= 135×4.2×5/13×54=0.807
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When a strong acid or base is added to water it...
Answers
When a strong acid or base is added to water, the pH will change dramatically.
Strong AcidA strong acid is one that is completely dissociated or ionized in an aqueous solution. This means it gives off the greatest number of hydrogen ions or protons when placed in a solution. Examples of strong acid are HCl, HBr, H2SO4, HNO4. These acids when placed in water, produces greatest amount of hydrogen ions. The pH value changes drastically. Any that has very high concentration of hydrogen and ion is acidic.
Also when base is added to water, the pH of water will increase above 7 and become basic. The pH of water is 7, but when base is added to it increases above 7.
Base is any solution that is slippery to touch in water solution, changes color, react with acid to form salt and change red litmus paper to blue.
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Write the electron configuration for each of the following ions: (a) As3– (b) I– (c) Be2+ (d) Cd2+ (e) O2– (f) Ga3+ (g) Li+ (h) N3– (i) Sn2+ (j) Co2+ (k) Fe2+ (l) As3+
Answers
Answer:
a) 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶
b) 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶
c) 1s²
d) 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 4d¹⁰
e) 1s² 2s² 2p⁶
f) 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰
g) 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰
h) 1s² 2s² 2p⁶
j) 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 4d¹⁰
k) 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁶
l) 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰
Determine how each of the following errors would affect calculated the percent yield of Alum. (increase, decrease, no effect). Briefly explain.
Answers
To calculate the percent yield of Alum, we need to know the actual yield and the theoretical yield of the reaction. The percent yield is then calculated using the formula:
Percent yield = (Actual yield / Theoretical yield) x 100%
The following errors could affect the calculated percent yield of Alum:
Some of the Alum crystals are lost during filtration
Effect: Decrease in percent yield
Explanation: If some of the Alum crystals are lost during filtration, the actual yield of the product will be lower than the theoretical yield. This will result in a decrease in the calculated percent yield.
The Alum crystals are not completely dry before weighing
Effect: Increase in percent yield
Explanation: If the Alum crystals are not completely dry before weighing, the crystals will contain some water. This will increase the weight of the crystals, and therefore increase the actual yield of the product. This will result in an increase in the calculated percent yield.
The reactants are not mixed thoroughly before the reaction
Effect: No effect on percent yield
Explanation: If the reactants are not mixed thoroughly before the reaction, the reaction may not go to completion and some of the reactants may be left unreacted. However, this will affect both the actual yield and the theoretical yield in the same way, resulting in no effect on the calculated percent yield.
The balance used to measure the mass of the Alum crystals is not calibrated properly
Effect: Uncertain effect on percent yield
Explanation: If the balance used to measure the mass of the Alum crystals is not calibrated properly, the measured mass may be either too high or too low. This will affect the actual yield of the product, which will affect the calculated percent yield. However, the direction and magnitude of the effect on the percent yield will be uncertain, since it depends on the direction and magnitude of the error in the measured mass.To calculate the percent yield of Alum, we need to know the actual yield and the theoretical yield of the reaction. The percent yield is then calculated using the formula:
Percent yield = (Actual yield / Theoretical yield) x 100%
The following errors could affect the calculated percent yield of Alum:
Some of the Alum crystals are lost during filtration
Effect: Decrease in percent yield
Explanation: If some of the Alum crystals are lost during filtration, the actual yield of the product will be lower than the theoretical yield. This will result in a decrease in the calculated percent yield.
The Alum crystals are not completely dry before weighing
Effect: Increase in percent yield
Explanation: If the Alum crystals are not completely dry before weighing, the crystals will contain some water. This will increase the weight of the crystals, and therefore increase the actual yield of the product. This will result in an increase in the calculated percent yield.
The reactants are not mixed thoroughly before the reaction
Effect: No effect on percent yield
Explanation: If the reactants are not mixed thoroughly before the reaction, the reaction may not go to completion and some of the reactants may be left unreacted. However, this will affect both the actual yield and the theoretical yield in the same way, resulting in no effect on the calculated percent yield.
The balance used to measure the mass of the Alum crystals is not calibrated properly
Effect: Uncertain effect on percent yield
Explanation: If the balance used to measure the mass of the Alum crystals is not calibrated properly, the measured mass may be either too high or too low. This will affect the actual yield of the product, which will affect the calculated percent yield. However, the direction and magnitude of the effect on the percent yield will be uncertain, since it depends on the direction and magnitude of the error in the measured mass.
determine the structural formula of a substance C4H4O4, which is acidic, forms succinic acid upon hydrogenation, and releases water upon heating with the formation of C4H2O3, which discolours bromine water and an aqueous solution of KMnO4
Answers
The given information allows us to conclude that the substance is an unsaturated dicarboxylic acid that undergoes hydrogenation to form succinic acid, which is a saturated dicarboxylic acid. Also, the substance upon heating releases water and forms [tex]C_4H_2O_3[/tex] which is maleic acid.
From the molecular formula [tex]C_4H_4O_4,[/tex]we can deduce that there are two carboxylic acid functional groups [tex](-COOH[/tex]) and one C=C double bond in the molecule. The structural formula of the substance can be represented as:
[tex]HOOC-CH=CH-COOH[/tex]
This is maleic acid, an unsaturated dicarboxylic acid. Upon hydrogenation, it forms succinic acid as mentioned in the question. Upon heating, maleic acid loses a molecule of water and forms fumaric acid [tex](C_4H_4O_4)[/tex], which is also an unsaturated dicarboxylic acid. Fumaric acid isomerizes to maleic acid in the presence of water.
Therefore, the substance with the molecular formula [tex]C_4H_4O_4[/tex] is maleic acid [tex](HOOC-CH=CH-COOH).[/tex]
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Use the following balanced equation for problems 1–5. Molar masses are given below.
2 As + 3 H2 → 2 AsH3 + 150. kcal
molar masses 74.92 g 2.02 g 77.95 g
How many grams of AsH3 can be made from 22.22 g of H2?
Answers
The mass (in grams) of AsH₃ made from 22.22 grams of H₂ is 571.63 grams
How do i determine the mass of AsH₃ produced?The mass of AsH₃ produced can be obtained as illustrated below:
2As + 3H₂ -> 2AsH₃ + 150 Kcal
Molar mass of H₂ = 2.02 g/molMass of H₂ from the balanced equation = 3 × 2.02 = 6.06 g Molar mass of AsH₃ = 77.95 g/molMass of AsH₃ from the balanced equation = 2 × 77.95 = 155.9 gFrom the balanced equation above,
6.06 grams of H₂ reacted to produce 155.9 grams of AsH₃
Therefore,
22.22 grams of H₂ will react to produce = (22.22 × 155.9) / 6.06 = 571.63 grams of AsH₃
Thus, from the above calculation, we can conclude that the mass of AsH₃ produced from the reaction is 571.63 grams
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Please help me I have to find the unknown by this information
Answers
The condensed structural formula of the unknown organic compound cannot be determined from the given information.
What are organic compounds?An organic compound is any of a broad family of chemical compounds that contain one or more carbon atoms that are covalently connected to atoms of other elements, most frequently hydrogen, oxygen, or nitrogen.
The few carbon-containing substances that aren't considered organic include cyanides, carbonates, and carbides.
Some classes of organic compounds include Carbohydrates, Lipids, Proteins, and Nucleic acids.
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!!!
MULTIPLE CHOICE QUESTION
If I have an unknown quantity of gas at a
pressure of 1.20 atm, a volume of 31.0
liters, and a temperature of 87.0°C, how
many moles of gas do I have?
Answers
The unknown quantity of gas is 1.23 moles.
To solve this problem, we can use the ideal gas law equation:
PV = nRT
where P is the pressure in atm, V is the volume in liters, n is the number of moles, R is the gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.
First, we need to convert the temperature from Celsius to Kelvin:
T = 87.0°C + 273.15 = 360.15 K
Next, we can plug in the given values and solve for n:
(1.20 atm)(31.0 L) = n(0.0821 L·atm/mol·K)(360.15 K)
n = (1.20 atm)(31.0 L) / (0.0821 L·atm/mol·K)(360.15 K) = 1.23 mol
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A chemist titrates 210.0 mL of a 0.7066 M hydrocyanic acid (HCN) solution with 0.4210 M NaOH solution at 25C. Calculate the pH at equivalence. The pKa of hydrocyanic acid is 9.21.
Round your answer to 2 decimal places.
Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of NaOH solution added.
Answers
The balanced equation for the reaction is:
HCN (aq) + NaOH (aq) → NaCN (aq) + H2O (l)
First, we need to find the volume of NaOH solution needed to reach equivalence:
0.7066 M HCN × 0.2100 L = x M NaOH × 0.2100 L
x = 0.3366 M NaOH
The volume of NaOH solution needed to reach equivalence is:
0.3366 M NaOH × VNaOH = 0.4210 M NaOH × 0.2100 L
VNaOH = 0.527 L = 527 mL
So, the total volume of the solution at equivalence is:
210.0 mL + 527 mL = 737 mL = 0.737 L
Now we can use the Henderson-Hasselbalch equation to find the pH at equivalence:
pH = pKa + log([A-]/[HA])
At equivalence, [HCN] = [CN-], so:
pH = pKa + log(1) = pKa = 9.21
Therefore, the pH at equivalence is 9.21.
I have an acid solution that is 12 M HCl. How many milliliters of this solution do I need to make 450.0 mL of 3.8 M ?
Answers
The volume in (mL) of the 12 M HCl needed to make 450.0 mL of 3.8 M the sloution is 142.5 mL
How do i determine the volume of the HCl needed?The following data were obtained from the above question:
Molarity of stock solution (M₁) = 12 MVolume of diluted solution (V₂) = 450.0 mL Molarity of diluted solution (M₂) = 3.8 MVolume of stock solution needed (V₁) =?Using the dilution equation, we can obtain the volume of the stock solution (i.e 12 M HCl) needed to prepare the solution as follow:
M₁V₁ = M₂V₂
12 × V₁ = 3.8 × 450
12 × V₁ = 1710
Divide bioth sides by 12
V₁ = 1710 / 12
V₁ = 142.5 mL
Thus, we can conclude that the volume of the 12 M HCl needed is 142.5 mL
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