The induced current flows the other way around. The electromagnet is closed when the switch is turned on. which way the wire loop's induced current is flowing as soon as the switch is closed.
The current that results from electromagnet induction is known as the induced current. The production of electric power relies heavily on electromagnet induction. Lenz's law, which states that the magnetic field produced by induced current opposes the magnetic field initially created by changing induced current, can be used to determine the direction of induced current.
A magnet type known as an electromagnet is one in which an electric current creates the magnetic field. Wire wound into a coil typically makes up electromagnets.
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.
What is the fastest speed a tennis ball can cross the net horizontally and still land in the court? from the net to the end line is 12 m, and the height of the net is 1 m. neglect air resistance and spin of the ball.
The maximum velocity of the tennis ball when it cross the net in order to still land in the court is 26.7 m/s
The trajectory of the tennis ball follow a projectile motion. When it cross the net, it can be considered it is at its maximum height.
At this position, the component of the velocity is only in x direction.
Vertical direction:
h = 1/2 . g t²
Where:
h = maximum height
g = acceleration due to gravity = 9.8 m/s²
t = time to land
Substitute h = 1 m
t² = 2/g = 0.204
t = 0.45 seconds
Horizontal direction:
x = v . t
12 = v . 0.45
v = 12 / 0.45 = 26.7 m/s
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How many electrons are located in the outermost orbit in the bohr model of a boron atom?.
Electrons that are located in the outermost orbit in the Bohr model of a boron atom will be 3.
A nucleus with six neutrons and five protons makes up the Bohr model of boron. The K-shell and L-shell electron shells around the nucleus The valence electrons, which make up three of the electrons in the outermost shell of the Bohr diagram, are also present. The orbits of the electrons around the small nucleus are described by the Bohr model of boron.
It utilizes a number of different electron shells, including K, L, M, and N. The number of electrons that each shell can hold varies, with the shell closest to the nucleus having the least energy. The energy levels increase as the shell recedes more. According to the Bohr model, the electrons in an atom may be seen to orbit the nucleus in a variety of orbits with differing energies.
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(ii) a spring with hangs vertically next to a ruler. the end of the spring is next to the 15-cm mark on the ruler. if a 2.5-kg mass is now attached to the end of the spring, and the mass is allowed to fall, where will the end of the spring line up with the ruler marks when the mass is at its lowest position?
If a 2.5 kg mass is attached to a spring with k = 53 N/m, the spring will stretch to 61 cm.
Missing data from the problem:
A spring with spring constant (k) 53 N/m is hang vertically.
Original length of the spring = 15 cm = 0.15 m
A mass of 2.5 kg is attached to the end of the spring.
According to the Hooke's Law:
F = - kx
Where:
F = force applied on the spring
x = spring displacement
From the problem, the only force is the weight of the mass:
F = w = m . g (g = 9.8 m/s²)
F = 2.5 . 9.8 = 24.5 N
Substitute k = 53 N/m,
24.5 = 53 . x
x = 24.5/53 = 0.46 m = 46 cm
Therefore the final length of the spring = 15 + 46 = 61 cm
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Which of these is true for both natural and artificial selection?
A. They both occur randomly and spontaneously.
B. They both involve the extinction of unfit species.
C. They both result in the enrichment of certain alleles over others.
D. They both require human involvement to choose the most desirable traits
Answer:
c is answer
Explanation:
Humans allow only organisms with favorable traits to reproduce. Is this true of natural selection, artificial selection or both? Competition for resources determines reproductive success.
these stick figures are each in a hurry to catch a flight. they are both walking at a speed of 1 m/s on a walkway that has a velocity of 0.5 m/s to the west. explain which stick figure is moving more quickly relative to the ground.
The stick figure that is walking at a velocity of 1 m / s to the west is moving quickly relative to the ground than the stick figure that is walking at a velocity of 1 m / s to the east.
Vsg = Vsw + Vwg
Vsg = Relative velocity of stick figure wrt ground
Vsw = Relative velocity of stick figure wrt walkway
Vwg = Relative velocity of walkway wrt ground
Let the stick figure that is walking to the west be A and the stick figure that is walking to the east be B.
For A,
Vsw = - 1 m / s
Vwg = - 0.5 m / s
Vsg = - 1 - 0.5
Vsg = - 1.5 m / s
For B,
Vsw = 1 m / s
Vwg = - 0.5 m / s
Vsg = 1 - 0.5
Vsg = 0.5 m / s
The negative symbol indicates direction. So Vsg for A > Vsg for B
Therefore, the stick figure that is walking at a velocity of 1 m / s to the west is moving quickly relative to the ground than the stick figure that is walking at a velocity of 1 m / s to the east.
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two snowmen, one having a mass of 15.0 kg and one having a mass of 20.0 kg, are sitting in a backyard 4.00 m away from each other. where could a third snowman be placed such that the net gravitational force on it by the other two is zero? treat each snowman as an object.
The third snowman will be placed at a distance of 2.1m from the 15.0 kg mass such that the net gravitational force on it by the other two is zero .
Mass of the snowman 1 = M1 = 15 kg
Mass of the snowman 2 = M2 = 20 kg
Distance between both the masses = r = 4 m
Gravitational force is the force that attracts any two objects of mass.
It is also called as attractive force because it always tries to pull masses together, never pushes them apart.Every object in the universe pull each other with the attractive force.Mathematically, Gravitational force, F = [tex]\frac{GM1M2}{r^{2} }[/tex]where G is the gravitational force constant,
M1 and M2 are the masses of the two different bodies respectively,
r is the distance between the masses.
F = [tex]\frac{GM1M2}{r^{2} }[/tex]
Let the mass M3 be the mass which lies between the masses such that the net gravitational force on it by the other two is zero.
F = [tex]\frac{GM1M3}{(r-d)^{2} }[/tex] = [tex]\frac{GM2M3}{(d)^{2} }[/tex]
here 'd' is the distance at which the mass M3 will be placed such that the net gravitational force on it by the other two is zero.
[tex]\frac{GM1M3}{(r-d)^{2} }[/tex] = [tex]\frac{GM2M3}{(d)^{2} }[/tex]
[tex]\frac{M1}{(r-d)^{2} }[/tex] = [tex]\frac{M2}{(d)^{2} }[/tex]
[tex]\frac{15}{(4-d)^{2} }[/tex] = [tex]\frac{20}{(d)^{2} }[/tex]
3[tex]d^{2}[/tex] = 4[tex](4-d)^{2}[/tex]
3[tex]d^{2}[/tex] = 4 (16 + [tex]d^{2}[/tex] - 2*4*d)
3[tex]d^{2}[/tex] = 64 + 4[tex]d^{2}[/tex] - 32d
[tex]d^{2}[/tex] - 32d + 64 = 0
On solving the above quadratic equation we get the values of d as;
d1 = 29.
d2 = 2.1
Since the d is the distance between the two masses therefore it must be less than 4 m, therefore d2 will be considered as the value of d.
Hence the mass M3 should be placed at a distance of 2.1 m away from the mass M1 to get zero as the net gravitational force
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If you drive at 120km/hr for 5 hours, how far will you go?
Distance:
Speed:
Time:
The distance of the travel covered within 5 hours with a speed of 120km/hr is the product of time and this speed and it is 600 km.
What is velocity?Velocity of a substance is the measure of distance travelled per unit time. Thus it is the ratio of distance to time.In physics, velocity is the rate of speed.
Velocity = distance/time.
Hence, as the time taken for the travel increases velocity will decreases. The time given here is 5 hours and the speed of the vehicle is 120 km/hr. Hence, the distance can be calculated as follows:
Distance = time × speed
= 5 hr × 120 km/hr
= 600 km.
Hence, if you drive at a speed of 120 km/hr for 5 hours you will cover a distance of 600 km.
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Calculate the velocity of the 2.0 kg mass just before it hits the
rocks when it is dropped from a height of 16 m above the surface
of the rocks. Give the unit.
Velocity:........
Unit: .......
The velocity of the 2.0 kg mass just before it hits the rocks when it is dropped from a height of 16 m above the surface of the rocks will be 17.738 m/s in downward direction
given
u = 0
m= mass = 2 kg
height = 16 m
v = ?
using kinematics equation
-s = ut - 1/2* g * [tex]t^{2}[/tex]
t = [tex]\sqrt{2s/g}[/tex]
time = [tex]\sqrt{(2*16) / 9.8}[/tex]
= [tex]\sqrt{3.27}[/tex]
= 1.81 seconds
v = u - gt
v = -g t = -9.8 * 1.81 = -17.738 m/s
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You are fighting with your sibling over a 2 kg toy. you apply a force of tension on the toy equal to 8n. your sibling causes the toy to experience an acceleration of 4m/s2 in the opposite direction. what is the net force that the toy feels?
The net force on the toy is 0 Newton.
The mass of the toy is 2 kg.
The force F₁ is the tension applied by one of the siblings on the toy is 8N.
Let us assume that the force applied by the other sibling is F₂, which is produced by the acceleration is 4m/s².
We know,
Force = Mass x acceleration
Putting values,
F₂ = 2 x 4
F₂ = 8N.
As we know that the forces are in opposite directions because the toy is being pulled by both the siblings in their respective directions which are opposite to each other.
Hence, the net force F is given by,
F = F₁ - F₂
F = 8-8
F 0N.
Hence, there is no net force on the toy.
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part beach child holds the end of a rope and child b pulls on the rope so that he moves toward child a. how far will child b have moved when he collides with child a?
3.813m far will child b have moved when he collide with child a.
We know that,
[tex]x_{cm}[/tex]=[tex]\frac{m_{a} x_{a} +m_{b} x_{b} }{m_{a}+x_{b} }[/tex]
[tex]x_{cm}[/tex]=26(0)+49(11)/26+49=7.187
A=From a is 7.187m
B=we forces know that, the internal can't change the motion of CM. SO they will meet Collide at their C.M.
B has to move the distance from B→C.M. So they will meet Collide at their C.M B will forces.
11-7.187 = 3.863
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A student determines the speed of three cars on a straight road.
The student measured the time for the cars to travel 50m.
Answer:
5.102 m/s
Explanation:
50/9.8=5.102m/s
How much net force is required to accelerate a 2000 kg car at 3.00 m/s^2
The net force required to accelerate a car is 6000 N.
Force is defined as the product of the mass and acceleration of the body. Force is used to changing the velocity that is to accelerate an object or a body of a particular mass. The unit of Force is Newton or kg m/s^2.
The formula used to calculate the net force is :
F = ma
where, F = Force
m = mass = 2000 kg
a = acceleration = 3.00 m/s^2
∴ F = 2000*3
F = 6000 N
Thus, to accelerate the car at 3.00 m/s^2 of mass 2000 kg net force required is 6000 N.
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A Mexican Jumping Bean jumps with the aid of a small worm that lives inside the bean. The bean and the worm have a combined mass of 0.002
kg. The bean can jump to a height of 0.01 m.
a. Calculate the potential energy at the maximum height.
b. Determine the total mechanical energy at the maximum height.
c. Determine the potential energy at a height of 0 m (before it lands).
d. Determine the total mechanical energy at a height of 0 m (before it lands).
e. Determine the kinetic energy at a height of 0 m (before it lands).
f. Calculate the velocity at a height of 0 m (before it lands).
The potential energy at the maximum height is 0.000196 J, the total mechanical energy at the maximum height is 0.000196 J, the potential energy at a height of 0 m is 0 J, the total mechanical energy at a height of 0 m is 0.0001936 J, the kinetic energy at a height of 0 m is 0.0001936 J and the velocity at a height of 0 m (before it lands) is 0.44 m/s.
What is potential energy?Potential energy is stored energy that depends on the relative positions of the various parts of the system. When a spring is compressed, its potential energy is increased.A steel ball has more potential energy lifted off the ground than after it hits the ground. Potential energy is the energy stored in an object or matter. This stored energy is based on the position, placement, or state of an object or matter. Rocks at the edge of cliffs have potential energy. Potential energy is converted into kinetic energy when the stone falls. High branches of a tree have potential energy because they can fall to the ground.To learn more about potential energy from the given link :
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allison has to design a device that converts energy between two different forms. she decides she wants to convert electrical energy into motion and sound. which invention should she model her design after?
The motor is an excellent invention for Allison to use as a model for her device.
People use both interchangeably, but the difference is that motors run on electricity and engines run on combustion. The engine converts various forms of fuels into mechanical force, while the motor transforms electrical energy into mechanical energy.
They operate using principles of electromagnetism, which shows that a force is applied when an electric current is present in a magnetic field. This force creates a torque on a loop of wire present in the magnetic field, which causes the motor to spin and perform useful work.
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A boat crosses a river at 6.65 mph north through a current going 9.87 mph east. What is the resultant velocity of the boat?
Answer:
V = √ ( 6.65² + 9.87² ) ≈ √ 141.64 = 11.90 mph
To open a box, you apply 50 N of force to a crowbar. the crowbar applies 450 N of force to the lid of the chest. What is the mechanical advantage of the crowbar?
Answer: The mechanical advantage of the crowbar 9
Answer:
9
Explanation:
50N-load
450N-effort
m.a=load÷effort
450÷50=9
a player hits a baseball with mass of 0.145 kg over the outfield fence. the ball leaves the bat with a speed of 42.0 m/s and a fan in the bleachers catches it 14 m above the point where it was hit. neglect air resistance. what is the speed of the ball when it is caught?
When the ball is caught, it is moving at a speed of 3 m/s. Distance/time is the formula for calculating speed.
How do you tell the ball's speed?You must time how long it takes from when the ball is released until the pin is struck using a stopwatch. By dividing the distance by the time, one may calculate the ball's speed.
The average speed, if it was 3 seconds,
would be 42/14, or 3 feet per second .
Build a launcher for balls. I made use of an exercise rubber band and the legs of a patio chair.
horizontally when you shoot the ball. For this to operate, the camera angle must be horizontal.
Calculate how long the ball has been in the air.
The ball's distance traveled should be measured.
Simply dividing the distance by the launch time yields the launch speed.
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what is the compressive stress exerted on the soles of your feet by your body weight? assume that each foot has a contact area of 200 cm2, the stress spreads out evenly over that area and that your mass is 72 kg.
The stress that spreads over the soles of the feet by the body is 18000 N/m².
The compressive stress exerted on a body is given by the force applied to the body divided by the area,
So, we can write,
Stress = force/area
In this case, the force will be equal to the weight of the body.
F = Mg
M is the mass of the person,
g is the acceleration due to gravity.
F = 72×10
F = 720N
The area of the soles is given to be 200 cm²
Converting into meter square,
Area = 0.02 m²
As there are two soles,
Area = 0.04
Putting values to find stress,
Stress = 720/0.04
Stress = 18000N/m²
So, the stress on the soles is 18000 N/m².
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suppose you have two identical socks that exert a force of 10 n on each other. now you move them so they are three times as far apart as they were originally. (a) calculate the new force between the objects. (b) will this force be attractive or repulsive? please explain
(a) Since the separation is being tripled the force would go to 1/9 its original value if the charges remained constant because Coulomb's Law is an inverse square law. So, the new force is 10/9 N.
(b) because the pressure remains the equal and it became repulsive, initially, it will remain repulsive. One could also deduce this for the reason that the socks are equal.
Electrostatic repulsion can also be observed, for example, with an electroscope. It's a simple device consisting of a piece of metal sticking out of a glass jar and a thin metal leaf hanging inside. When the outer piece of metal touches the charged body, the Coulomb force causes the sheet to expand.
The repulsive force between oppositely oriented magnets. A compression material that repels the body on both sides. Repulsion is associated with involuntary vomiting such as in response to the ingestion of toxins.
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if you toss a ball to your friends when the ball reaches its maximum altitude it’s vertical acceleration is what? is it 0 m/s or -9.81?
The vertical acceleration of the ball at its highest altitude is 0 m/s.
Has the acceleration ever been zero?It is possible for an item to have both zero acceleration and non-zero velocity because acceleration is the change in velocity. Since there is no change in velocity while an object is moving at a constant speed, it experiences no acceleration.
At maximum height, is vertical velocity zero?The bullet reaches its highest point when its vertical velocity is zero. The vertical portion of the velocity vector will now point downward. The projectile's horizontal range, which is determined by the object's beginning velocity, is referred to as the projectile's range.
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the distance between x-ray tube and the bucky (the area that stores the film), is referred to as the .
An x-ray cassette is kept in a device called a "bucky" that resembles a drawer. It can be installed either on the wall or underneath the exam table.
These days, buckys have an internal grid that absorbs dispersed radiation to enhance the clarity of x-ray images. The oscillating option that modern buckys have added further aids in preventing scattered radiation from reaching the x-ray cassette and increases the quality of the x-ray image.To ensure that a high-quality x-ray image is created when using Bucky, an increase in radiation exposure parameters (kVp and mAs) is necessary. If Bucky is not utilized, the same x-ray technique can be carried out with lower exposure factors, but the image quality will suffer.To know more about x-ray
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how much work must be done by an external force on an object (sliding over a frictionless, horizontal surface) to accelerate the object from a speed vv to a speed 2v2v?
Using the concepts of work, we got that we need to work three times of the previous work to accelerate the object from a speed v to a speed 2v.
We know that to change the velocity of any object we need to do some work on it.
When an object having some mass m moving with velocity v, then the kinetic energy stored in that object is given by(KE₁) =(1/2)mv².
Now, When an object having some mass m moving with velocity 2v,then the kinetic energy stored in that object is given by(KE₂) =(1/2)m(2v)².
New kinetic energy is =4[(1/2)mv²] or 4KE₁
So, net work to accelerate the object is =KE₂-KE₁
W=4KE₁-KE₁=3KE₁.
Hence, the amount of work must be done by an external force on an object (sliding over a frictionless, horizontal surface) to accelerate the object from a speed v to a speed 2v is 3 times the energy stored on a object.
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The ball is about to hit the ground.
It has a kinetic energy store of 110 J.
Ignoring the effects of friction, what is the maximum elastic potential energy store of the ball when it is fully compressed after hitting the ground?
The maximum elastic potential energy store of the ball when it is fully compressed after hitting the ground is 110 J
Since the effects of friction is ignored, there is no loss of energy as heat. So the entire elastic potential energy store of the ball is converted into kinetic energy store.
Elastic potential energy = Kinetic energy
Kinetic energy = 110 J
Elastic potential energy = 1 / 2 k x²
Kinetic energy = 1 / 2 m v²
k = Spring constant
x = Displacement
m = Mass
v = Velocity
If friction is ignored,
1 / 2 k x² = 1 / 2 m v²
v / x = √ ( k / m )
Therefore, the maximum elastic potential energy store of the ball is 110 J
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what physical feature of mars is atypical compared with the other terrestrial planets? what physical feature of mars is atypical compared with the other terrestrial planets? its size its rotation rate its atmospheric content its density its surface composition
The answer of this is "Its surface composition"
Mars is the fourth planet from the Sun and the next planet beyond Earth. It is, on average, more than 142 million miles from the Sun.
Its surface is rocky, with canyons, volcanoes, dry lake beds and craters all over it. Red dust covers most of its surface. Mars has clouds and wind just like Earth. Sometimes the wind blows the red dust into a dust storm. Tiny dust storms can look like tornados, and large ones can be seen from Earth. Mars’ large storms sometimes cover the entire planet.
Mars has about one-third the gravity of Earth. A rock dropped on Mars would fall more slowly than a rock falls on Earth. A person who weighs 100 pounds on Earth would only weigh about 38 pounds on Mars because of the reduced gravity.
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PLS help confused. Will mark brainiest for the right answer.
Answer:
B
Explanation: You (with the ball in your hand)would move in the direction of the ball's initial motion. Momentum!
Answer: You would move backward.
Explanation: You would push back because you would move in the direction of the ball's initial motion. The ball's initial motion is to come toward you, so you would most likely move backward.
Let me know if this is right! :)
A ball is thrown from a 10 m high cliff at the velocity 20 ms-¹ with an angle of 30° to the horizontal plane as shown in the picture below. 40 m from the edge of the cliff is a 10 m high wall. a) Will the ball pass over the wall? b) If not, where will it hit the wall and with what velocity?
(a) The ball will not pass over the wall
(b) The velocity is 21.45m/s
It is the amount of change in velocity per unit time. The velocity change can be calculated using the formula: velocity change = final velocity - initial velocity. This is the time when: The rate of change in velocity is expressed in
Given
A ball is thrown from a 10 m high cliff at the velocity 20 ms-¹ with an angle of 30° to the horizontal plane as shown in the picture below. 40 m from the edge of the cliff is a 10 m high wall.
We have to determine
a) Will the ball pass over the wall?
b) If not, where will it hit the wall and with what velocity?
From the given information
Initial velocity v =20m/s
Initial velocity along x direction vx = vcos300
= 20 cos300
= 20 x 0.866
= 17.32m/s
Initial velocity along y direction vy = v sin300
= 20 sin300
= 20 x 0.5
= 10m/s
Displacement along +ve x = 40m
Time required to travel t = x/vx
= 40/17.32
= 2.31seconds
At this time displacement of the ball along the y direction
Sy = vyt – 1/2gdt2
= 10x2.31 – ½ x 9.81 x (2.31)2
= 23.10 – 26.17
= - 3.07m
Since displacement is in a negative value, it will hit the wall and will not pass over the wall
The ball will hit at d distance from the ground
H = (10 – 3.07)
= 6.93m
Final velocity along +ve y = v’y = vy –gt
= 10 – 9.81 x 2.31
= 10 – 22.66
=-12.66m/s
velocity along +ve x = v’y = vx
= 17.32m/s
So-net velocity of the ball v’= √((v^' x)^2+(v^' y)^2 )
= √(〖(17.32)〗^2+〖(-12.66)〗^2 )
= 21.45m/s
Therefore
(a) The ball will not pass over the wall
(b) The velocity is 21.45m/s
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two forces whose resultant is 10N are perpendicular to each other. if one of them makes an angle of 60 with the resultant, calculate its magnitude
The magnitude of the resultant with respect to one of the vectors is [tex]10 \sqrt{3} \mathrm{~N}[/tex].
The resultant of two force is given by [tex]$F=\sqrt{A^2+B^2+2 A B \cos \theta}$[/tex] where, [tex]$A \& B$[/tex] are two vectors & [tex]$\theta$[/tex] is the angle between them.
Magnitude or resultant is [tex]$\sqrt{2 \times 10^2+2 \times 100 \cos 60^{\circ}}=10 \sqrt{3} \mathrm{~N}$[/tex].
A force is an influence in physics that can modify the velocity of an object. A force can cause a mass item to change its velocity, or accelerate. Intuitively, force can be described as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
The term "force" has a specific meaning in science. At this level, it is quite acceptable to refer to a force as a push or a pull. A force is not something that an object 'has in it.' Another object applies a force to another. The concept of a force is not limited to living or nonliving things.
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If a 50 N force is applied to a lever and the lever is then able to lift a 150 N object, what is the mechanical advantage of the lever?
Answer:
3
Explanation:
m.a=load÷effort
thus 150N÷50N=3
an air-filled parallel-plate capacitor has a capacitance of 1.5 pf. the separation of the plates is doubled and wax is inserted between them. the new capacitance is 3.0 pf. find the dielectric constant of the wax.
The dielectric constant of the wax is 2.
The dielectric constant of wax is the ratio of the capacitance of a capacitor that has wax between its plates to its capacitance when there is no wax between its plates.
This can be calculated by first finding the total capacitance of the capacitor with wax in between it:
C = 2 * pf * (0.5cm)^2
= 1.5 pf
Then, we can calculate the change in capacitance:
C' = C - C
= 2 pf * (0.5cm)^2 - 1.5 pf
= 0.5 pf
Finally, we divide 1/0.5 to find C'/C = 2, so we conclude that the dielectric constant for wax is 2, or twice as large as air's dielectric constant of 1!
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a resistor r is connected to the terminals of a battery with a potential difference v. as a result of the connection, a direct current i passes through the resistor. if the resistor is replaced by a different resistor with a resistance 3r, what effect, if any, will there be on the current passing through the resistor?
On the basic of Ohm's law , we can see that when resistance increase on replacing then current passing through resistance decreses.
In the given question we have,
resistor r is connected of a battery with potential difference v and a direct current i , passing through the resistor.
According to Ohm's law , the current passing through the condutor is directly proportional to the voltage applied to it and inversely proportional to resistance.
V = IR
where, I ---> current passing through resistor
R----> resistance
V ----> Voltage
or I = V/R ---(1)
Now, it is given that when resistor is replaced by other one and resistance become 3r. From (1) we see as resistance increases the current passing through resistor decreses.
So, as resistance increase by 3r then current passing through resistance decreses by 1/3r.
To learn more about Ohm's law, refer:
https://brainly.com/question/14296509
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