Answer:
B
Step-by-step explanation:
Need help on this!!!!
Answer:
D
Step-by-step explanation:
First find h(3)
2(3)-2= 4
then find g(4)
4³-5= 59
Find the missing side or angle. Round to the nearest tenth. C=95° a=5 c=6 A=[?]°
Answer:
Missing angle A = 56.1° (approximately)
Step-by-step explanation:
<A = arcsin(a×sin(C)/c)
= arcsin(5×sin 95/6)
= 56.1154084° ≈ 56.1°
Answered by GAUTHMATH
PLEASE HELP!!! Urgent. Will mark as brainliest
Answer:
Step-by-step explanation:
m∠2 = [tex]\frac{1}{2}[/tex](55+41)
m∠2 = [tex]\frac{1}{2}[/tex](96)
m∠2 =48°
m∠1 = 180-48 = 132°
daca cel mai mare divizor comun al lor a si b este 21 iar produsul lor este 15435 cat sunt a si b
Answer:
[tex]{\dag{\underline{{\sf{\red{t {}^{2} = \: \dfrac{4.05}{5} \: = 0.81 \: , \: \: t = 0.9s}}}}}}[/tex]
Log problem below in the picture
Your answer is 2.98004491789381.
if p-1/p = 4 Find (p+1/p)²
Answer:
4
Step-by-step explanation:
[tex] \frac{p - 1}{p} = 4[/tex]
Solve for p.
The numerator. difference has to be 4 times the answer of the denomiator.
So we can say
[tex]p - 1 = 4p[/tex]
Solve for p
[tex] - 1 = 3p[/tex]
[tex]p = - \frac{1}{3} [/tex]
Now plug this in for the other formula.
[tex]( \frac{ - \frac{1}{3} +1}{ \frac{1}{3} } ) {}^{2} = 2 {}^{2} = 4[/tex]
So
What is the slope of the graph shown below
Answer:
B=-5
Step-by-step explanation:
Slope=rise/run
The line passes in
P1(-1,3)
and
P2(0,-2)
So slope=(3-(-2))/(-1-0)=5/-1=-5
c) What should be subtracted from 5m - 3n to get 2m + 5n?
What she hechosomoce 2-59
Answer:
3m-8n
Step-by-step explanation:
Set up an equation:
(5m-3n)-(2m+5n) = ?
Solve:
5m-3n
- 2m+5n
3m-8n
Hope this helps!
Find x and y
Help me please
Answer:
x = 70 y = 140
Step-by-step explanation:
Apologies if I get any names of vocabulary terms wrong, I never pay much attention to the names.
The central angle measure of an arc is the same as the arc's measure. In this case, y is the central angle and 140 is the arc's measure, so y = 140.
The inscribed angle measure of an arc is 1/2 the arc's measure. An inscribed angle lies on the circle. So 140/2 = 70 = x.
Are the two triangles similar. If so, State how
Answer:
Yes by AAA
Step-by-step explanation:
Angle A is the same for both triangles. Angle D is congruent to Angle A since BC and DE are parallel lines and same with angle E. So by AAA the triangles are similar
The weights of certain machine components are normally distributed with a mean of 8.04 g and a standard deviation of 0.08 g. Find the two weights that separate the top 3% and the bottom 3%. (These weights could serve as limits used to identify which components should be rejected)
Answer:
The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.
Step-by-step explanation:
We are given that
Mean, [tex]\mu=8.04 g[/tex]
Standard deviation, [tex]\sigma=0.08g[/tex]
We have to find the two weights that separate the top 3% and the bottom 3%.
Let x be the weight of machine components
[tex]P(X<x_1)=0.03, P(X>x_2)=0.03[/tex]
[tex]P(X<x_1)=P(Z<\frac{x_1-8.04}{0.08})[/tex]
=0.03
From z- table we get
[tex]P(Z<-1.88)=0.03, P(Z>1.88)=0.03[/tex]
Therefore, we get
[tex]\frac{x_1-8.04}{0.08}=-1.88[/tex]
[tex]x_1-8.04=-1.88\times 0.08[/tex]
[tex]x_1=-1.88\times 0.08+8.04[/tex]
[tex]x_1=7.8896[/tex]
[tex]\frac{x_2-8.04}{0.08}=1.88[/tex]
[tex]x_2=1.88\times 0.08+8.04[/tex]
[tex]x_2=8.1904[/tex]
Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.
In one week, Alex worked 35 hours at $ 12.50 per hour plus 5 hours overtime at 'time and half'. How much would Alex have earned for the week? *
what is the length of segment SR?
ST = ST (Common)
RT = TQ (Given)
∠ RTS = ∠ SQT (Both 90°)
So, ∆ RTS ≅ ∆ QTS (By SAS congruency rule)
So, RS = QS (By C.P.C.T.)
=> 2x + 8 = 8x - 4
=> 8 + 4 = 8x - 2x
=> 12 = 6x
=> 12/6 = x
=> 2 = x
SR = 2x + 8 (Given)
=> SR = 2(2) + 8 (Putting the value of x)
=> SR = 4 + 8
=> SR = 12
Answer:
Step-by-step explanation:
Write the expression as an exponent:
5^8 x 25
6^15 x 36
Answer:
a.) 5¹⁰
b.) 6¹⁷
Step-by-step explanation:
a.) 5⁸ × 25
Write 25 in the exponential form with the base of 5.
5⁸ × 5²To calculate product use exponent rule
5⁸+²5¹⁰b.) 6¹⁵ × 36
Similarly, 6¹⁵ × 36
Write 25 in the exponential form with the base of 6.
6¹⁵ × 6²To calculate product use exponent rule.
6¹⁵ + ²6¹⁷Answer:
[tex] \displaystyle {5}^{10} [/tex]
[tex] \displaystyle {6}^{17} [/tex]
Step-by-step explanation:
Question-1:we want to rewrite the following expression as an exponent
[tex] \displaystyle {5}^{8} \times {25}[/tex]
remember that 25 is the square of 5 therefore
[tex] \displaystyle {5}^{8} \times {5}^{2} [/tex]
recall that,
[tex] \displaystyle {x}^{m} \times {x}^{n} = {x}^{m + n} [/tex]
with that law we obtain:
[tex] \displaystyle {5}^{8 + 2} [/tex]
simplify addition:
[tex] \displaystyle {5}^{10} [/tex]
Question-2:likewise Question-1 36 is the square of 6 Thus,
[tex] \displaystyle {6}^{15} \times {6}^{2} [/tex]
similarly apply law of exponent:
[tex] \displaystyle {6}^{15 + 2} [/tex]
simplify addition:
[tex] \displaystyle {6}^{17} [/tex]
hence,
we have written the expression as an exponent
out of 1300 students in a school , only 60% passed . find the number of students failed .
Hi there!
»»————- ★ ————-««
I believe your answer is:
520 students.
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
60% of the 1300 students passed. This means that 40% of the students failed.
⸻⸻⸻⸻
[tex]1300 * 0.4= 520[/tex]
⸻⸻⸻⸻
520 students failed school.
⸻⸻⸻⸻
[tex]\boxed{\text{Another way to find this...}}\\\\\text{Take 60}\% \text{ of 1300:}\\\\1300 * 0.6 = 780\\\\\text{780 students passed school.}\\\\\text{Subtract 780 from 1300:}\\\\1300 - 780 = \boxed{520}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
Find angle D if angle B = 50
============================================================
Explanation:
I'm assuming that segments AD and CD are tangents to the circle.
We'll need to add a point E at the center of the circle. Inscribed angle ABC subtends the minor arc AC, and this minor arc has the central angle AEC.
By the inscribed angle theorem, inscribed angle ABC = 50 doubles to 2*50 = 100 which is the measure of arc AC and also central angle AEC.
----------------------------
Focus on quadrilateral DAEC. In other words, ignore point B and any segments connected to this point.
Since AD and CD are tangents, this makes the radii EA and EC to be perpendicular to the tangent segments. So angles A and C are 90 degrees each for quadrilateral DAEC.
We just found angle AEC = 100 at the conclusion of the last section. So this is angle E of quadrilateral DAEC.
---------------------------
Here's what we have so far for quadrilateral DAEC
angle A = 90angle E = 100angle C = 90angle D = unknownNow we'll use the idea that all four angles of any quadrilateral always add to 360 degrees
A+E+C+D = 360
90+100+90+D = 360
D+280 = 360
D = 360-280
D = 80
Or a shortcut you can take is to realize that angles E and D are supplementary
E+D = 180
100+D = 180
D = 180-100
D = 80
This only works if AD and CD are tangents.
Side note: you can use the hypotenuse leg (HL) theorem to prove that triangle EAD is congruent to triangle ECD; consequently it means that AD = CD.
PLEASE ANSWER ASAAPPPPPPPP
Answer:
3
Step-by-step explanation:
What is the equation of the following line?
(-4, 8)
(0,0)
Answer
Step-by-step explanation:
y = -2x + 0
Therefore; y = -2x
given the nth term of geometric expression is (as in the diagram)
a) state the value of k
b) the first term of progression
Step-by-step explanation:
a) k = 1
b) geometric progression formula:
Tn = ar^(n-1)
first term, a = 3/2
How long is JK?
Choose 1 answer:
A: 3
B: 2 square root 3
C: 3 square root 3
D: 6
E: 9
Answer:
C) 3 times the sq root of 3
Step-by-step explanation:
In a right angle triangle, the COS is definned as the ajacent side over the hypotenuse. So
COS 60 = JK/JL
COS 60 = JK/(6*sq root 3)
.5 = JK/(6*3**1/2)
JK = .5 *(6*3**1/2)
JK = 3*3**1/2
In a geometric progression, the first tern is 81 and the fourth term is 24. find the common ratio
Step-by-step explanation:
81/24= 27/8Hello,
Let's say a the first term and r the ratio of the G.P.
[tex]u_1=a=81\\u_2=a*r\\u_3=a*r^2\\u_4=a*r^3\\\\\dfrac{u_4}{u_1} =\dfrac{a*r^3}{a} =r^3=\dfrac{24}{81} =\dfrac{8}{27} \\\\r=\sqrt[3]{\dfrac{8}{27} } \\\\\boxed{r=\dfrac{2}{3}}\\[/tex]
A car and a bus were travelling towards each other at uniform speeds. They were 250 km apart at noon and passed each other at 2 p.m. If the speed of the car was 75 km/h, find the speed of the bus.
Answer:
50 km/hr
Step-by-step explanation:
speed = x + 75
distance = 250km
time = 2
250 = (x + 75) * 2
125 = x + 75
x = 50
If A = [tex]\left[\begin{array}{ccc}cosx&-sinx\\sinx&cosx\end{array}\right][/tex], then show that [tex](A^{-1} )^{-1}[/tex]
Given:
The matrix is:
[tex]A=\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]
To show:
[tex](A^{-1})^{-1}=A[/tex]
Solution:
If a matrix is:
[tex]M=\begin{bmatrix}a&b\\c&d\end{bmatrix}[/tex]
Then,
[tex]M^{-1}=\dfrac{1}{ad-bc}\begin{bmatrix}d&-b\\-c&a\end{bmatrix}[/tex]
We have,
[tex]A=\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]
Using the above formula, we get
[tex]A^{-1}=\dfrac{1}{(\cos x)(\cos x)-(-\sin x)(\sin x)}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]
[tex]A^{-1}=\dfrac{1}{\cos^2x+\sin^2x}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]
[tex]A^{-1}=\dfrac{1}{1}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]
[tex]A^{-1}=\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]
Now, the inverse of [tex]A^{-1}[/tex] is:
[tex](A^{-1})^{-1}=\dfrac{1}{(\cos x)(\cos x)-(\sin x)(-\sin x)}\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]
[tex](A^{-1})^{-1}=\dfrac{1}{\cos^2x+\sin^2x}\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]
[tex](A^{-1})^{-1}=\dfrac{1}{1}A[/tex]
[tex](A^{-1})^{-1}=A[/tex]
Hence proved.
If two people earn a total of $23, how many people will earn a total of $92
Answer:
8
Step-by-step explanation:
[tex] \frac{23}{2} = 11.5[/tex]
[tex]92 \div 11.5 = 8[/tex]
Can someone please help me really struggling
Answer:
your y-intercept is 5 and your slope is 1 hope this helps with translating into the form you want
Step-by-step explanation:
What percentage of temperatures are below 55°? A. 50% B. 25% C. 75% D. 20%
Step-by-step explanation:
C
im not sure of my answer. hope to help
the first day she walked 27 kilometers. each day since she walked 2/3 of what she walked the day before. what is the total distance cecelia has traveled be the end of the 5th day?
Answer: 70
Step-by-step explanation:
We are required to calculate the total distance Cecilia travelled in 5 days
The total distance Cecilia travelled for 5 days is 99 kilometers
Day 1 = 27 kilometers
Day 2 to day 5 = 2/3 of 27
= 2/3 × 27
= 2 × 9
= 18 kilometers each day
Total distance = day 1 + day 2 + day 3 + day 4 + day 5
= (27 + 18 + 18 + 18 + 18) kilometers
= 99 kilometers
Therefore, the total distance Cecilia travelled for 5 days = 99 kilometers
Read more:
https://brainly.com/question/17207658
Charlie dve 208 miles in 4 hours at a constant speed he continues at that speed give the equation that shows the relationship between driving hours
Answer:
52 miles per hour
Step-by-step explanation:
I think you're missing some info, so this is all I can help with right now
Please helpppp
Find l.
Answer:
Step-by-step explanation:
radius of base=8/2=4 ft
l²=4²+9²=16+81=97
l=√97 ft
Uma empresa do ramo de confecções produz e comercializa calças jeans. Se x representa a quantidade produzida e comercializada (em milhares de reais) e L(x) = -x² + 8x – 16 representa o lucro (em milhares de reais) da empresa para x unidades, então quando L(x) = 0 a empresa terá produzido e comercializadas quantas unidades dessas calças jeans? *
Answer:
I am in 5 classso i did not known answer
