Quick algebra 1 question for 10 points!

Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!

The graph which represents Charlies distance from her car at different times is indicated as attached. The schedule of her movement is also attached.  This type of graph is called Distance Time Graph.

A distance-time graph can show the distance traveled while an item moves in a straight line.

The gradient of the line in a distance-time graph is equal to the object's speed. The item is travelling more quickly the steeper the line and the larger the gradient.

See the attached for Charlies Distance - Time movements visualized in a graph.

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Given :-

Solution :-

>> 2x + 5 < x + 1 / 4

>> 4 (2x + 5) < x + 1

>> 4 × (2x + 5) < x + 1

>> 8x + 20 < x + 1

>> 8x - x < 1 - 20

>> 7x < 1 - 20

>> 7x < -19

>> x = -19 / 7

[tex]\boldsymbol{\sf{2x+5 < \dfrac{x+1}{4} }}[/tex]

Multiply the two sides of the equation by 4. Since 4 is > 0, the direction of inequality remains the same.

          [tex]\boldsymbol{\sf{8x+20 < x+1 }}[/tex]

Resta x en los dos lados.

              [tex]\boldsymbol{\sf{8x+20-x < 1 }}[/tex]

Combine 8x and −x to get 7x.

                [tex]\boldsymbol{\sf{7x+20 < 1 }}[/tex]

Subtract 20 on both sides.

                 [tex]\boldsymbol{\sf{7x < 1-20 \ \ \longmapsto \ \ [To \ subtract] }}[/tex]

                  [tex]\boldsymbol{\sf{7x < -19 }}[/tex]

Divide the two sides by 7. Since 7 is >0, the direction of inequality remains the same.

                     [tex]\boldsymbol{\sf{x < -\dfrac{19}{7} } }[/tex]

As the end result, it is not simplified or divided, then

                               [tex]\blue{\boxed{\boldsymbol{\sf{Answer \ \ \longmapsto \ \ x < -\frac{19}{7} }}}}[/tex]

ヘ( ^o^)ノ＼(^_^ )If you want to learn more about mathematics, I share this link to complement your learning:

A graph can be defined as a type of chart that's commonly used to graphically represent data on both the horizontal and vertical lines of a Cartesian coordinate, which are the x-axis and y-axis.

By critically observing the graphs (see attachment) of the number of gas-fueled cars that were sold by Roger's car company for the first 8-months since the introduction of electric cars, we can logically deduce that it's much easier to determine the slope of graph A than that of graph B.

This ultimately implies that, it would be best for Roger to use graph A in emphasizing a decrease in the number of gas-fueled cars that were sold.

In conclusion, we can infer and logically deduce that Roger should use graph A for his presentation because the number of gas-fueled cars that were sold appears to decrease on this graph.

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Complete Question:

A car company wants to reduce the use of gas-fueled cars by introducing and promoting the use of electric cars. The graphs below show the number of gas-fueled cars sold, y, for the first eight months since the introduction of electric cars. Both graphs show the same information.

Complete the following sentences.

1. To emphasize the decrease in the number of gas-fueled cars sold, it would be best for Roger to use ______ for his presentation.

2. Roger should use this graph for his presentation because the number of gas-fueled cars sold ______ on this graph.

The value of r = 9.078.

pv = nrt. The factor “r” in the ideal gas law equation is known as the “gas constant”. r = [tex]\frac{pv}{nt}[/tex]. The pressure times the volume of a gas divided by the number of moles and temperature of the gas is always equal to a constant number.

so the student weights out .0422 grams of the magnesium metal so from here we can calculate that more's, the magnesium that he used, that is the mass of the magnesium over the more mass, which is .024422 over 24 point. That's equal to about .001758. More so also, it says the magnesium metal is react with excessive hydrochloric acid and produce hydrogen gas. A sample of the hydrogen gas is collected over water in a meter at 22 cecr, the volume of clictic gas is 43.9 and mastic pressure. Is that so using the experimental and collected data calculated are in the percent error? So we know the magnesium react with hydrochloride. The reaction ratio is 1 to 2 and we produce 1. More is the hydrogen and 1. More is magnesium chloride. So from this equatium we know that more of the hydrogen that would be produced in this case is equal to the mass of the magnesium here, that's his .001758 more and set way. There's among hydrogen. The temperature is 32 (degree celcius) which we need to convert the unit into kelvin, so it's actually about field 5.15 kelvin and tells you. The volume of the gas is 43.9 in ml, which is .0439 liter and tells you the pressure of the gas is about 832 millimeter. Mercury, which is a 2 times 13332 plus ca, that's equal to about 110922.24 par. So in this case we know p v = n r t.

r = [tex]\frac{pv}{nt}[/tex]

So p = 110922.24. V = 0.0439 , n = 0.001758 t =  305.15. So let's just do the calculations here.

In this case you will find r=?

Here it's about 9.078.

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The correct function that has been represented on the graph is,

f(x) = { 2 if -1 < x ≤ 2 as the values of f(x) for the other two parts, -6 ≤ x ≤ -1 and 2 ∠ x ≤ 6 are (2x+17)/5 and (16-7x)/2 respectively.

This can be broken into three parts :

   y-3/x+1 = 2/5

  5y -15 = 2x +2

  2x - 5y = -17

 y-1/x-2 = -7/2

 2y -2 = -7x + 14

2y + 7x = 16

Thus function becomes

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We have enough data to reject our null hypothesis if the value of our test statistics falls below critical values of z at a 1.25% level of significance (critical values are -1.645 and 1.645). This is because the test statistic value will not fall within this region.

Given that the population mean is 650, we do a two-tail hypothesis test with a level of significance of 0.025.

Let, μ = population mean

Thus, Null hypothesis, [tex]H_{0}[/tex]:μ= 650.

Alternate Hypothesis, [tex]H_{A}[/tex]:μ≠650

In this case, the population mean is equal to 650, according to the null hypothesis.

The alternative hypothesis, on the other hand, contends that the population mean is not 650.

First things first: the level of significance to be accepted for the two-tailed test is ([tex]\frac{\alpha }{2}[/tex]= [tex]\frac{0.025}{2}[/tex]) = 0.0125 or 1.25%.

Therefore, the following is the decision rule for rejecting a null hypothesis:

We have enough data to reject our null hypothesis if the value of our test statistics falls in the rejection region and is less than the critical values of z at a 1.25% level of significance (critical values are -1.645 and 1.645). This is because the test statistic value will not fall within this region.

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The magnitude of the larger earthquake is about 1.3 greater than the magnitude of the smaller earthquake.

In physics, significance is defined actually as “distance or quantity.” It depicts the absolute or relative course or size wherein an object moves within the sense of motion. it's miles used to express the scale or scope of something. In physics, importance normally refers to distance or quantity.

Magnitude is described as big in size or very vital. An example of value is the depth of the Grand Canyon. An instance of importance is the dimensions of the trouble of world hunger. (geology) A measure of the amount of energy launched by using an earthquake, as indicated on the Richter scale.

The magnitude is more than a few that characterizes the relative size of an earthquake. value is primarily based on the measurement of the maximum movement recorded with the aid of a seismograph.

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Answer: [tex]\Large\boxed{y-1=\frac{4}{5} (x+2)}[/tex]

Step-by-step explanation:

Given the requirement for function

Point-slope form : y - y₁ = m (x - x₁)

Given information

m = 4/5

Point = (x₁, y₁) = (-2, 1)

Substitute values into the function form

y - y₁ = m (x - x₁)

y - (1) = (4/5) (x - (-2))

Simplify the function

[tex]\Large\boxed{y-1=\frac{4}{5} (x+2)}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

(3, -3 8/9)

Step-by-step explanation:

Use a slope calculation or a graph to find the slope of the line.

m = (y-y)/(x-x)

m = (-3- -5)/(7- -2)

m = 2/9

Then write the equation of the line. I used point-slope form. (You could use y=mx+b, slope-intercept form, but you'd have to first calculate b as well)

Point-slope form:

y -Y = m(x-X)

y - -3 = 2/9(x- 7)

y + 3 = 2/9(x - 7)

We know the x-coordinate of the point we're looking for is 3. Fill that in as well and calculate the y that goes with it.

y + 3 = 2/9(3-7)

y+3=2/9(-4)

y = -8/9 - 3

y = -3 8/9

In decimal form this is -3.8888repeating

see image.

The point at x=3 on the line between M(7,-3) and N(-2,-5) is (3, -3 8/9).

Answer:

See below

Step-by-step explanation:

Using triangle side rule :  The sum of any two sides must be greater than the third side

.5<x<16.5

The range of possible sizes for side x for given triangle is 0.5<x<16.5.

In the given triangle, one side measures 8.5 units, other side is 8.0 units and third side is x units.

The length of one side of a triangle must be greater than the difference and less than the sum of the lengths of the other two sides.

Here, the range of x is 8.5-8.0<x<8.5+8.0

0.5<x<16.5

Therefore, the range of possible sizes for side x for given triangle is 0.5<x<16.5.

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Answer:

==============================

Inequality:

1. Distribute:

2. Multiply:

3. Collect like terms:

4. Addition:

5. Divide both sides by 6:

Interval notation for this solution is:

Answer:

[tex]x < -3[/tex]

Interval notation:  (-∞, 3)

Step-by-step explanation:

Given inequality:

[tex]-4 \left(\dfrac{5}{2}+\dfrac{3}{2}x\right) > 8[/tex]

Divide both sides by -4 (remembering to change the direction of the inequality sign, since we are dividing by a negative):

[tex]\implies \dfrac{ -4 \left(\dfrac{5}{2}+\dfrac{3}{2}x\right)}{-4} > \dfrac{8}{-4}[/tex]

[tex]\implies \dfrac{5}{2}+\dfrac{3}{2}x < -2[/tex]

Subtract ⁵/₂ from both sides:

[tex]\implies \dfrac{5}{2}+\dfrac{3}{2}x-\dfrac{5}{2} < -2-\dfrac{5}{2}[/tex]

[tex]\implies \dfrac{3}{2}x < -\dfrac{9}{2}[/tex]

Multiply both sides by 2:

[tex]\implies \dfrac{2 \cdot 3}{2}x < -\dfrac{2 \cdot 9}{2}[/tex]

[tex]\implies \dfrac{\diagup\!\!\!\!2 \cdot 3}{\diagup\!\!\!\!2}x < -\dfrac{\diagup\!\!\!\!2 \cdot 9}{\diagup\!\!\!\!2}[/tex]

[tex]\implies 3x < -9[/tex]

Divide both sides by 3:

[tex]\implies \dfrac{3x}{3} < \dfrac{-9}{3}[/tex]

[tex]\implies x < -3[/tex]

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The answer is x < 1.

Bring the constant to the other side.

Divide by 4 on both sides.

[tex]\Large\texttt{Answer}[/tex]

[tex]\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\quad\space\space\qquad\qquad\qquad}}[/tex]

[tex]\Large\texttt{Process}[/tex]

[tex]\rm{4x-6 < -2}[/tex]

Do you remember that we need to get x by itself to find its value?

We should do this:

⇨ Add 6 to both sides

[tex]\rm{4x-6+6 < -2+6}[/tex]

On the left hand side (lhs), the 6s add up to zero; on the right hand side (rhs), the -2 and 6 result in 4. Hence

[tex]\rm{4x < 4}[/tex]

Now divide both sides by 4

[tex]\rm{\cfrac{4x}{4} < \cfrac{4}{4}}[/tex]

Simplifying fractions gives us

[tex]\rm{x < 1}[/tex]

* what this means is: numbers less than 1 will make the statement true

[tex]\Large\texttt{Verification}[/tex]

Substitute 1 into the original inequality [tex]\boxed{4x-6 < -2}[/tex]

[tex]\rm{4(1)-6 < -2}[/tex]

[tex]\rm{4-6 < -2}[/tex]

Do the arithmetic

[tex]\rm{-2 < -2}[/tex]

Hope that helped

Length of the line

= [tex]\sqrt{((-2)-(-8))^{2}+(10-2)^{2} }[/tex]

= [tex]\sqrt{36+64}[/tex]

=[tex]\sqrt{100}[/tex]

= 10

Answer:

{(5, 3)}

Step-by-step explanation:

Consider the system :

x + 2y = 11

x - 2y = -1

We notice that :

5 + 2×3 = 11

5 - 2×3 = -1

We conclude that :

(5, 3) is the solution to the system.

Answer:

QP = | a - d |

Step-by-step explanation:

since the y- coordinates of P and Q are equal , both b

then PQ is the absolute value of the difference of the x- coordinates, that is

QP = | a - d | = | d - a |

Answer:

10, 8

Step-by-step explanation:

l + w = 18

l*w = 80

8 and 10 works

The value of function f(x) at x = 7 is f(7) = 28

For given question,

we have been given the value of function f(x) at x = 5.

f(5) = 12

We have been given that f'(x) is continuous on 5 and 7

Also, [tex]\int\limits^7_5 {f(x)} \, dx =16[/tex]

We need to find the value of f(7)

Since ∀x, f'(x) = f'(x), f is a primitive function of f' .

And f ' is continuous

[tex]\Rightarrow \int\limits^7_5 {f(x)} \, dx =16\\\\\Rightarrow [f(x)]_5^7=16[/tex]

⇒  [f(7) - f(5)] = 16

⇒ f(7) - 12 = 16

⇒ f(7) = 16 + 12

⇒ f(7) = 28

Therefore, the value of function f(x) at x = 7 is f(7) = 28

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**Disclaimer** Hi there! I assumed the unit [ mph ] represents miles per hour and [ m/s ] represents meters per second. The following answer will be according to this understanding. If I am wrong, please let me know and I will modify my answer.

Answer: [tex]\Large\boxed{23~m/s}[/tex]

Step-by-step explanation:

Given information

Speed = 52 mph

Given conversion factors

1 mile ≈ 1609 meters

1 hour = 3600 seconds

Convert the unit from mph to m/s using conversion factors

The basic idea is that you utilize the factors and cancel out unnecessary units

[tex]\dfrac{52~miles}{1~hour} \times\dfrac{1~hour}{3600~seconds} \times\dfrac{1609~meters}{1~miles}[/tex]

Simplify by multiplication

[tex]=\dfrac{52~miles}{3600~Seconds} \times\dfrac{1609~meters}{1~miles}[/tex]

[tex]=\dfrac{52\times 1609~meters}{3600~Seconds}[/tex]

Simplify the fraction

[tex]=\dfrac{83668~meters}{3600~Seconds}[/tex]

[tex]\Large\boxed{\approx23~m/s}[/tex]

Hope this helps!! :)

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∆BOC is equilateral, since both OC and OB are radii of the circle with length 4 cm. Then the angle subtended by the minor arc BC has measure 60°. (Note that OA is also a radius.) AB is a diameter of the circle, so the arc AB subtends an angle measuring 180°. This means the minor arc AC measures 120°.

Since ∆BOC is equilateral, its area is √3/4 (4 cm)² = 4√3 cm². The area of the sector containing ∆BOC is 60/360 = 1/6 the total area of the circle, or π/6 (4 cm)² = 8π/3 cm². Then the area of the shaded segment adjacent to ∆BOC is (8π/3 - 4√3) cm².

∆AOC is isosceles, with vertex angle measuring 120°, so the other two angles measure (180° - 120°)/2 = 30°. Using trigonometry, we find

[tex]\sin(30^\circ) = \dfrac{h}{4\,\rm cm} \implies h= 2\,\rm cm[/tex]

where [tex]h[/tex] is the length of the altitude originating from vertex O, and so

[tex]\left(\dfrac b2\right)^2 + h^2 = (4\,\mathrm{cm})^2 \implies b = 4\sqrt3 \,\rm cm[/tex]

where [tex]b[/tex] is the length of the base AC. Hence the area of ∆AOC is 1/2 (2 cm) (4√3 cm) = 4√3 cm². The area of the sector containing ∆AOC is 120/360 = 1/3 of the total area of the circle, or π/3 (4 cm)² = 16π/3 cm². Then the area of the other shaded segment is (16π/3 - 4√3) cm².

So, the total area of the shaded region is

(8π/3 - 4√3) + (16π/3 - 4√3) = (8π - 8√3) cm²

The age of Tommy is currently 40-years old

According to the statement

we have given that the tommy is five times as old as bianca and in eight years, tommy will only be three times as old as bianca.

And we have to find the present age of the tommy.

So, This is a question involving the ratio of ages.

Let the ages of Tommy and Bianca in the present be T and B respectively.

STEP 1: Let:

T = 5B

T + 8 = 3 (B+8)

Then

STEP 2: We can substitute T with 5B since the two variables are equal, to create:

5B + 8 = 3 (B + 8)

Then

STEP 3: Finally, we can expand and solve:

5B + 8 = 3B + 24

2B = 16

B = 8

T = 5B = 5 x 8 = 40

T = 40

Therefore, The age of Tommy is currently 40-years old

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Answer:

D) 4 8/12

Step-by-step explanation:

To first start this, let's make 2 5/6 an in-proper fraction by adding 12 and removing the whole 2. =17/6. Then let's get a common denominator by multiplying both the denominators by each other...6x4 and 4x6, but we also multiply the numerators by the same thing that the denominators are getting multiplied by... 17x4 and 7x6. We will then get 68/24 and 42/24. And then we can add both numerators with eachother and keep the denominator to get, 110/24... and making this into a propor fraction would equal 4 16/24... and dividing by 2 would equal 4 8/12

The reverse number of the three-digit number is 732

Let the three-digit number be xyz.

So, the reverse is zyx

This means that

Number = 100x + 10y + z

Reverse = 100z + 10y + x

From the question, we have the following parameters:

y = x + 1

z = 1 + 2y

The sum is represented as:

100x + 10y + z + 100z + 10y + x = 10^3 - 31

100x + 10y + z + 100z + 10y + x = 969

Evaluate the like terms

101x + 101z + 20y = 969

Substitute y = x + 1

101x + 101z + 20(x + 1) = 969

101x + 101z + 20x + 20 = 969

Evaluate the like terms

101x + 101z + 20x = 949

121x + 101z = 949

Substitute y = x + 1 in z = 1 + 2y

z = 1 + 2(x + 1)

This gives

z = 2x + 3

So, we have:

121x + 101z = 949

121x + 101* (2x + 3) = 949

This gives

121x + 202x + 303 = 949

Evaluate the sum

323x = 646

Divide by 323

x = 2

Substitute x = 2 in z = 2x + 3 and y = x + 1

z = 2*2 + 3 = 7

y = 2 + 1 = 3

So, we have

x = 2

y = 3

z = 7

Recall that

Reverse = 100z + 10y + x

This gives

Reverse = 100*7 + 10*3 + 2

Evaluate

Reverse = 732

Hence, the reverse number of the three-digit number is 732

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The equation of the parabola given in the graph is:

(x - 5)² = -8(y + 4).

The equation of a quadratic function, of vertex (h,k), is given by:

a(y - k) = (x - h)²

In which a = 4p is the leading coefficient.

In this problem, the vertex is at point (5,-4), hence h = 5, k = -4, and the equation is:

a(y + 4) = (x - 5)²

The focus is at y = -6, which means that p = -6 - (-4) = -2, hence the leading coefficient is:

a = 4p = 4(-2) = -8

Hence the equation is:

(x - 5)² = -8(y + 4).

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-5x - 5 = 3x + 19

---Move the x's to one side

-5x - 3x - 5 = 3x - 3x + 19

-8x - 5 = 19

---Isolate the -8x by removing the -5 from the left side

-8x - 5 + 5 = 19 + 5

-8x = 24

---Divide both sides by -8 to get x by itself

x = -3

Hope this helps!

-5x-5= 3x+19

= > -5x-3x= 19+5

= > -8x= 24

= >-x=24/8

= >x= -3

The amount paid to the man in the first year given the total he received in four years is $3,700.

= (x + 1000)

= (x + 1500)

Total payment = first year + second year + third year + fourth year

x + (x + 500) + (x + 1000) + (x + 1500) = 17,800

x + x + 500 + x + 1000 + x + 1500 = 17800

4x + 3000 = 17,800

4x = 17,800 - 3000

4x = 14,800

x = 14,800/4

x = $3,700

Therefore, $3,700 was paid to the man in the first year.

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Answer:

no

Step-by-step explanation:

A simultaneous equation refers to two or more equations that are solved at the same time.

A simultaneous equation refers to two or more equations that are solved at the same time. Now we shall solve each of the equations;

a. 2x + y = 3 ------(1)

   x - y = 4 ------ (2)

x = 4 + y  ----- (3)

Substituting (3) into (1)

2(4 + y) + y = 3

8 + 2y + y = 3

8 + 3y = 3

3y = 3 - 8

3y = -5

y = -5/3

Hence;

 x - y = 4

x - (-5/3) = 4

x = 4 + 5/3

x = 17/3

b. 2x + 6y =9 -----(1)

x + 3y = 2 ------ (2)

x = 2 - 3y ------ (3)

Substitute (3) into (1)

2( 2 - 3y)  + 6y =9

4 - 6y + 6y = 9 (From this stage we can see that it is not possible to solve the quadratic)

c. 6x - 3y = 12 -----(1)

4x + 2y = 10 ---- (2)

12x - 6y = 24 ---- (3)

12x + 6y = 30 --- (4)

Add (3) to (4)

24x = 54

x= 54/24 = 9/4

Hence;

4(9/4) + 2y = 10

9 + 2y = 10

2y = 10 - 9

y = 1/2

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Answer: 5 cm

Step-by-step explanation:

B = [tex]\sqrt{13^{2} -12^{2} } = 5[/tex]

Answer:

OPTION C, 5

Step-by-step explanation:

Using the formula, substitute the hypotenuse and the other leg of the right triangle.

13²=12²+b²

Rearrange appropriately.

13²-12²=c²

Convert.

13²=169

12²=144

Apply and work out.

169-144= 25

c²=25

c=√25

c=5

OPTION C is therefore the answer.

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The data which is most likely to be normally distributed is total points scored by a basketball team the whole season.

Given five statements:

1)Daily temperature highs for winter in 25 US cities.

2)Daily stock reports from the stock market.

3) Height of flowers.

4) Total points scored by a basketball team the whole season.

We are required to choose a statement whose data is most likely to be normally distributed.

A normal distribution is an arrangement of data set in which most values cluster in the middle of the range and the rest off symmetrically towards either extreme.It is basically a probability distribution that is most likely symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean. Its graph is a bell curve.

So,the statement which is likely to be normally distributed is total points scored by a basketball team the whole season.

Hence the data which is most likely to be normally distributed is total points scored by a basketball team the whole season.

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