Quick algebra 1 question for 10 points!
Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!
Answers
Answer:
[tex]\textsf{A. } y=3x^2+10x-8[/tex]
Step-by-step explanation:
We are given the information that a function has zeros at x = ⅔ and x = -4. In order to find the function that has those zeros, we can substitute the value of the zeros into each function. If the value of a function equates to zero with both values, then that is the function we are looking for.
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Standard Form of a Quadratic: ax² + bx + c = 0.
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[tex]\large \text{$y = 3x^2+10x-8 \implies 0=3x^2+10x-8$}[/tex]
[tex]\boxed{\begin{minipage}{15 em}{\text{$x=\dfrac{2}{3}$}} \\ \\\implies 0=3\left(\dfrac{2}{3}\right)^2+10\left(\dfrac{2}{3}\right)-8\\\\\implies 0=3\left(\dfrac{4}{9}\right)+10\left(\dfrac{2}{3}\right)-8\\\\\implies 0=\not{3}\left(\dfrac{4}{\not{9}\ 3}\right)+\dfrac{20}{3}-8\\\\\implies 0=\dfrac{4}{3}+\dfrac{20}{3}-8\\\\\implies 0=\dfrac{24}{3}-8\\\\\implies 0=0\ \checkmark\end{minipage}}[/tex] [tex]\boxed{\begin{minipage}{15 em}{\text{$x=-4$}} \\ \\\implies 0=3(-4)^2+10(-4)-8\\\\\implies 0=3(16)-40-8\\\\\implies 0=48-48\\\\\implies 0=0\ \checkmark\end{minipage}}[/tex]
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[tex]\large \text{$y = 2x^2-5x-12 \implies 0=2x^2-5x-12$}[/tex]
[tex]\boxed{\begin{minipage}{15 em}{\text{$x=\dfrac{2}{3}$}} \\ \\\implies 0=2\left(\dfrac{2}{3}\right)^2-5\left(\dfrac{2}{3}\right)-12\\\\\implies 0=2\left(\dfrac{4}{9}\right)-\dfrac{10}{3}-12\\\\\implies 0=\dfrac{8}{9}-\dfrac{10}{3}-12\\\\\implies 0=\dfrac{8}{9}-\dfrac{10\times3}{3\times3}-\dfrac{12\times9}{9}\\\\\implies 0=\dfrac{8}{9}-\dfrac{30}{9}-\dfrac{108}{9}\\\\\implies0=-\dfrac{22}{9}-\dfrac{108}{9}\\\\\implies 0=-\dfrac{130}{9}\ \textsf{X}\end {minipage}}[/tex] [tex]\boxed{\begin{minipage}{15 em}{\text{$x=-4$}} \\ \\\implies 0=2(-4)^2-5(-4)-12\\\\\implies 0=2(16)+20-12\\\\\implies 0=32+20-12\\\\\implies 0=40\ \textsf{X}\end{minipage}}[/tex]
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[tex]\large \text{$y = 2x^2+5x-12 \implies 0=2x^2+5x-12$}[/tex]
[tex]\boxed{\begin{minipage}{15 em}{\text{$x=\dfrac{2}{3}$}} \\ \\\implies 0=2\left(\dfrac{2}{3}\right)^2+5\left(\dfrac{2}{3}\right)-12\\\\\implies 0=\dfrac{8}{9}\right)+\dfrac{10}{3}-12\\\\\implies 0=\dfrac{8}{9}\right)+\dfrac{10\times3}{3\times3}-\dfrac{12\times9}{9}\\\\\implies 0=\dfrac{8}{9}+\dfrac{30}{9}-\dfrac{108}{9}\\\\\implies0=\dfrac{38}{9}-\dfrac{108}{9}\\\\\implies 0=-\dfrac{70}{9}\ \textsf{X}\end{minipage}}[/tex] [tex]\boxed{\begin{minipage}{15 em}{\text{$x=-4$}} \\ \\\implies 0=2(-4)^2+5(-4)-12\\\\\implies 0=2(16)-20-12\\\\\implies 0=32-32\\\\\implies 0=0\ \checkmark\end{minipage}}[/tex]
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[tex]\large \text{$y = 3x^2-10x-8 \implies 0=3x^2-10x-8$}[/tex]
[tex]\boxed{\begin{minipage}{15 em}{\text{$x=\dfrac{2}{3}$}} \\ \\\implies 0=3\left(\dfrac{2}{3}\right)^2-10\left(\dfrac{2}{3}\right)-8\\\\\implies 0=3\left(\dfrac{4}{9}\right)-\dfrac{20}{3}-8\\\\\implies 0=\not{3}\left(\dfrac{4}{\not{9}\ 3}\right)-\dfrac{20}{3}-8\\\\\implies 0=\dfrac{4}{3}-\dfrac{20}{3}-\dfrac{8\times3}{3}\\\\\implies 0=-\dfrac{16}{3}-\dfrac{24}{3}\\\\\implies 0=-\dfrac{40}{3}\ \textsf{X}\end{minipage}}[/tex] [tex]\boxed{\begin{minipage}{15 em}{\text{$x=-4$}} \\ \\\implies 0=3(-4)^2-10(-4)-8\\\\\implies 0=3(16)+40-8\\\\\implies 0=48+40-8\\\\\implies 0=80\ \textsf{X}\end{minipage}}[/tex]
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Therefore, the function whose zeros are ⅔ and -4 is [tex]y=3x^2+10x-8[/tex].
Related Questions
How would you solve this? Please give an explanation.
Answers
The first three elements of the recursive series are 6, 10, 8. (Correct choice: B)
How to generate values from a recursive function
In this question we have a kind of recursive function known as Fibonacci's function, where a value of the series is generated from at least immediately previous elements. In this case, we need to find the first three elements from the fifth and fourth elements of the series:
[tex]a_{n-2} = a_{n-1} - a_{n} + 4[/tex]
a₄ = a₅ - a₆ + 4
a₄ = - 2 - 0 + 4
a₄ = 2
a₃ = a₄ - a₅ + 4
a₃ = 2 - (- 2) + 4
a₃ = 8
a₂ = a₃ - a₄ + 4
a₂ = 8 - 2 + 4
a₂ = 10
a₁ = a₂ - a₃ + 4
a₁ = 10 - 8 + 4
a₁ = 6
The first three elements of the recursive series are 6, 10, 8. (Correct choice: B)
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2. Five times a number is equal to the same number increased by 8.
Answers
Answer:
the number is 2
Step-by-step explanation:
5x = x + 8
5x - x = 8
4x = 8
x = 8/4
x = 2
Please helpp with my math hw I’ll give brainlest
Answers
Answer:
20 percent
40 percent
20 percent
20(.008) percent
Step-by-step explanation:
6) 54 - 45 = 9
45 / 9 = 5
100 / 5 = 20
20 percent
7) 60 - 36 = 24
60 / 24 = 2.5
100 / 2.5 = 40
40 percent
8) 30 - 24 = 6
30 / 6 = 5
100 / 5 = 20
20 percent
9) 24.99 - 19.99 = 5
24.99 / 5 = 4.998
100 / 4.998 approx. = 20.008
20.008 percent (or rounded 20 percent)
Solve the following systems of equations algebraically:
[tex]\left \{ {{y=\frac{1}{2}*2^x } \atop {y=5x+2}} \right.[/tex]
Answers
The value of x in the system of equation is 6
How to solve the system of equations?The system of equations is given as:
y = 1/2 * 2^x
y = 5x + 2
Substitute y = 1/2 * 2^x in y = 5x + 2
1/2 * 2^x = 5x + 2
Multiply through by 2
2^x = 10x + 4
Next, we use the trial by error.
Set x = 6
This gives
2^6 = 10 * 6 + 4
Evaluate the product and the exponent
64 = 60 + 4
Evaluate the sum
64 = 64
Hence, the value of x in the system of equation is 6
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Help, please 20 points!
Answers
Answer:
The second choice is correct.
Step-by-step explanation:
As we go right on the number line, we are getting to larger and larger values.
D is greater than C because it is to the right of C, so the first choice is not correct.
The third choice is showing absolute value. This is saying that the letters C and D are both the same distance from zero. They are not.
The last choice says that A is to the right of B and it is not.
The second choice that is B≥ C is correct.
The basics of this question requires us to read the number line perfectly
As we go right on the number line, we are getting to larger and larger values.
D is greater than C because it is to the right of C, so the first choice is not correct.
The third choice is showing absolute value. This is saying that the letters C and D are both the same distance from zero. They are not.
The last choice says that A is to the right of B and it is not.
Thus option 2) is correct
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What is the end behavior of the function f(x)=12x2?
Answers
dis i know functiin of fx is ♾
Answer:
4th option
Step-by-step explanation:
the end behaviour is what happens when x gets larger and positive (right- hand end )or larger and negative ( left- hand end )
f(x) = [tex]\frac{1}{2}[/tex] x² ← is of even degree (2) and has a positive leading coefficient , then
• even degree and positive leading coefficient
f(x) → +∞ as x → + ∞ and
f(x) → + ∞ as x → - ∞
Write the equivalent expression to
Answers
Answer:
Step-by-step explanation:
Begin by changing the radical form to exponential form:
[tex]((1024w^{-2}x^{-3}y^6z^{-1)^2)^{\frac{1}{5} }[/tex] There are a couple of ways to do this, but let's distribute the power of 2 into the parenthesis first by using the power to power rule of multiplication:
[tex](1024^2w^{-4}x^{-6}y^{12}z^{-2})^{\frac{1}{5}[/tex] Now we can use the same rule of power to power and distribute the power of 1/5 in:
[tex]1024^{\frac{2}{5}}w^{-\frac{4}{5}}x^{-\frac{6}{5}}y^{\frac{12}{5}}z^{-\frac{2}{5}[/tex]
The first term simplifies down to 16, and then in order to make the negative exponents positive, we move them to the denominator of a fraction, leaving the positive one where it is:
[tex]\frac{16y^{\frac{12}{5}} }{w^{\frac{4}{5}}x^{\frac{6}{5} }z^{\frac{2}{5} } }[/tex] which is the third choice down
Find the area of the semicircle.
Either enter an exact answer in terms of \piπpi or use 3.143.143, point, 14 for \piπpi and enter your answer as a decimal. 6
Answers
The area of the given semicircle is 56.574 sq. units. Half of the area of the circle is the area of the semicircle.
What is the area of the semicircle?The area of the semicircle is
A = [tex]\frac{1}{2}[/tex] πr² sq. units
Where r - radius
A semicircle is nothing but half part of the circle. So, its area is also half of the circle's area.
Calculation:It is given that,
The radius of the semicircle is
r = 6
So, its area in terms of π is
A = [tex]\frac{1}{2}[/tex] πr²
= [tex]\frac{1}{2}[/tex] × π × 6²
= 18π sq. units
On substituting π = 3.143, we get
A = 18 × 3.143 = 56.574 sq. units
Thus, the area of the given semicircle in terms of π is 18π or in terms of π =3.143 is 56.574 sq. units.
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What is the slope of the line represented by the equation y- 6 = 2(x+3)?
Answers
And m is slope and b is the y-intercept -
In this equation y-6=2(x+3)
m is 2 because if u multiply 2 to (x+3) it will become 2x+6
since m is 2 and b is 6
The slope is 2
And the y-int. is 6
So the slope is 2.
Answer: 2
Step-by-step explanation:
remember y=mx^2+c
where m = gradient = slope
∴ expand and simplify y-5=2(x+3)
y-5=2x+6
y=2x+11
m=2 ∴ slope: 2
A semi-circle window can be used above a doorway or as an accent window
in a room to allow more light in large rooms. The semi-circle window in your
home theater room lets too much light in so that the movie experience is not
optimal at any time of the day.
You research and find there are “room darkening” blinds and shades for
semi-circle windows. You can’t quite reach the semi-circle window to
measure but you are able to measure the window beneath. The height of the
rectangle window below is 85 in and the width of the window below the semi-circle is 50 in.
What is the area of the semi-circle window so that you can start your search for the correct size?
Be sure to show and explain your work.
Answers
A semicircle is a part of a circle, and it is referred to as half of a given circle. Thud the area of the semi-circle window is 982 [tex]in^{2}[/tex].
A circle is a shape that is bounded by a curved path which is referred to as the circumference. Some parts of a circle are radius, diameter, sector, arc, semi-circle, circumference, etc.
A semicircle is a part of a circle, and it is referred to as half of a given circle.
such that:
Area of a circle = [tex]\pi[/tex] [tex]r^{2}[/tex]
and
area of a semicircle = [tex]\frac{\pi r^{2} }{2}[/tex]
where: r is the radius of the circle, and [tex]\pi[/tex] is a constant with a value of [tex]\frac{22}{7}[/tex].
Thus from the given question, it can be inferred that;
r = [tex]\frac{50}{2}[/tex]
= 25
r = 25 in
Thus, the area of the semi-circle can be determined as;
area of the semi-circle = [tex]\frac{1}{2}[/tex] * [tex]\frac{22}{7}[/tex] * [tex]25^{2}[/tex]
= 982.1429
area of the semi-circle = 982.14 [tex]in^{2}[/tex]
The area of the semi-circle window is approximately 982 [tex]in^{2}[/tex].
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Solve the system of equations by substitution.
3 /8 x +1/3y =17/24
x + 7y = 8
Answers
By substitution, the value of x and y are 1 and 1 respectively.
How to solve system of equation?3 / 8 x + 1 /3 y = 17 / 24
x + 7y = 8
x = 8 - 7y
Let's substitute the value of x in equation(ii)
3 / 8(8 - 7y) + 1 / 3 y = 17 / 24
3 - 21 / 8 y + 1 / 3 y = 17 / 24
1 / 3 y - 21 / 8 y = 17 / 24 - 3
8y - 63y/24 = 17 - 72/ 24
-55y / 24 = -55 / 24
cross multiply
-1320y = -1320
divide both sides by -1320
y = -1320 / -1320
y = 1
Hence,
x + 7(1) = 8
x = 8 - 7
x = 1
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the senior class was going on a field trip to disneyland. A total of 350 student went on the trip. they filled seven busses . how many student were on each bus
Answers
Answer:
50 ^^
Step-by-step explanation:
So first an easy way to solve this problem is by removing the zeros then you'll have 35 and
7x1=7
7x2=14
7x3=21
7x4=28
7x5=35
So 7x5 dont forget to add your zeros to 35 and 5 and boom your answer is 50
need more explaining tell me ^^
The table can be used to determine the solution to the system of equations, 2y − x = 8, and y − 2x = −5.
A table with 6 columns and 2 rows. The first column, Original System has 2 y minus x equals 8 and y minus 2 x equals negative 5. The second column, Equivalent System, has 2 y minus x equals 8 and negative y plus 4 x equals 10. The third column, Sum of equations in Equivalent System, has 3 x equals 18. The fourth column, Solution to System, is blank. The fifth column, New System Using Sum, has2 y minus x equals 8 and 3 x equals 18. The sixth column, Solution to New System is blank.
Which solution can be used to fill in both blanks in the table?
Answers
The solution to the system and the solution that fills the blank space is (6, 1)
System of equationsThis are also known as a set of simultaneous equations, also known as a system of equations which is a finite set of equations for which common solutions
Given the following system of equations
2y − x = 8, and
y − 2x = −5.
From equation 2;
y = -5 + 2x ............. 3
Substitute equation 2 into equation 1 to have:
2(-5+2x) - x = 8
Expand to have:
-10 +4x -x = 8
-10 + 3x = 8
3x = 8 + 10
3x = 18
Divide both sides
by 3
3x/3 = 18/3
x = 6
Substitute x = 6 into equation 3
y = -5 + 2x
y = -5 + 2(3)
y = -5 + 6
y = 1
Hence the solution to the system and the solution that fills the blank space is (6, 1)
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Answer:
Its D (6,7)
Step-by-step explanation:
Three times my age in 5 years is 54. How old am i now.
a.10
b.11
c.12
d.13
e.14
Answers
Answer:
D. 13
Step-by-step explanation:
54 ÷ 3 = 18 (your age in 5 years)
18 - 5 = 13 (your age now)
54/3=18
18-5=13
This is correct
The equation 2x2 − 12x 1 = 0 is being rewritten in vertex form. fill in the missing step. given 2x2 − 12x 1 = 0 step 1 2(x2 − 6x ___) 1 ___ = 0 step 2 2(x2 − 6x 9) 1 − 18 = 0 step 3 ✔ 2(x − 3)2 17 = 0 2(x − 3)2 − 17 = 0 2(x 3)2 − 17 = 0 2(x − 6)2 − 17 = 0
Answers
Given: [tex]2x^2 - 12x + 1 = 0[/tex]
Step 1: [tex]2(x^2- 6x + 3^2) + 1 - 2(3^2) = 0[/tex]
Step 2: [tex]2(x^2 - 6x + 9) + 1 - 18 = 0[/tex]
Second answer: [tex]2(x - 3)^2 - 17 = 0[/tex]
Explanation in detail:
The quadratic equation a[tex]x^{2} + bx + c = 0[/tex]'s vertex form is
where a[tex](x - h)^{2} + k[/tex] equals zero
A is the [tex]x^{2}[/tex] coefficient, and h is the vertex's x-coordinate on the equation's graph.
The vertex of the equation's graph, k, has the y-coordinate.
The completing square can be used to determine the vertex form.
[tex]2x^{2} - 12x + 1 = 0[/tex] is the equation.
Put[tex]2x^{2} -12x[/tex] in a bracket and subtract 2 from them as a common component to utilize the completing square.
∵ [tex]2(x^{2} - 6x) + 1 = 0[/tex]
To determine the product of the first and second terms in the binomial, divide the second term by two.
∵ [tex]6x / 2 = 3x[/tex]
∵[tex]3x = 3 * x[/tex]
∴ The binomial's first and second terms are x and 3, respectively.
The phrase in the bracket's middle is (-)
∴ Middle of the binomial's sign is (-)
∴ The binary value is [tex](x - 3)^2[/tex]
Square 3 is nine.
To keep the equation from altering, you must deduct the same number from the bracket after adding 9 there.
∴ [tex]2(x^2 - 6x + 9 - 9) + 1 = 0[/tex]
- Remove the brace and multiply -9 by 2.
∵ [tex]2 *-9 = -18[/tex]
∴ [tex]2(x^2- 6x + 9) + 1 - 18 = 0[/tex]
- Construct a square binomial from [tex](x^{2} - 6x + 9)[/tex]
∵ [tex]x^2 - 6x + 9 = (x - 3)^2[/tex]
∴ [tex]2(x - 3)^2 + 1 - 18 = 0[/tex]
Include related terms.
∴[tex]2(x - 3)^2 - 17 = 0[/tex]
∴ The equation's vertex form is[tex]2(x - 3)^2 - 17 = 0.[/tex]
Given that: [tex]2x^2 - 12x + 1 = 0[/tex]
Step 1: [tex]2(x^2- 6x + 3^2) + 1 - 2(3^2) = 0[/tex]
Step 2: [tex]2(x^2 - 6x + 9) + 1 - 18 = 0[/tex]
Step 3: [tex]2(x - 3)^2 - 17 = 0[/tex]
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The graphs below are both quadratic functions. The equation of the red graph
is fx) = ». Which of these is the equation of the blue graph, g(x)?
Answers
Answer:
A. y = 1/3x^2
Step-by-step explanation:
The red graph is stretched horizontally by a factor 1/3 to give the blue graph
what is the next word in the pattern below?
Fall, Winter, Spring, Summer, Fall, __, ...
A. Winter
B. Summer
C. Spring
D. Fall
Answers
Winter comes after fall in the pattern as we see already. Because this is true, winter is next.
The answer is A. Winter.
As the pattern is : F, W, Sp, Su, F... (letters used for convenience), then the next word in the pattern will be Winter, because that was shown in the previous sequence.
A rectangle has dimension 23cm by 41cm and is made with a piece of wire How long will each length be for an equilateral triangle?
Answers
Each side of equilateral triangle will have the length equals to 42.7 cm.
Quadrilaterals
There are different types of quadrilaterals, for example, square, rectangle, rhombus, trapezoid, and parallelogram. Each type is defined accordingly to its length of sides and angles. For example, in a rectangle, the opposite sides are equal and parallel and their interior angles are equal to 90°.
The perimeter of a geometric figure is the sum of its sides. Thus, for a rectangle, the perimeter is 2L+2W.
You should find the perimeter of the rectangle.
2P=23+23+41+41= 128 cm
The equilateral triangle will have the same perimeter of the rectangle. An equilateral triangle presents the equal three sides, thus,
128= 3L
L=128/3=42.7 cm
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A parabola with a vertex at (0,0) has a focus along the negative part of the x-axis. which could be the equation of the parabola?
Answers
Answer:
y^2 = -8x for example.
Step-by-step explanation:
General form is y^2 = -4ax
The focus of this parabola will be at (-a , 0) on the x axis.
So the parabola might be:
y^2 = -4x
y^2 = -12x
y^2 = -0.9x and so on......
Enter the correct answer in the box.
This graph represents a transformation of the parent square root function.
-10-8 -6
A
-2
10-
8
6-
2-
-2-
-4-
-6-
-8-
-10-
O
2
6 8 10
➜X
Replace the values of h and k to create the equation of the transformed function.
Answers
Answer:
Step-by-step explanation:
The most basic quadratic function is f(x) = x2, whose graph appears below. ... us to graph an entire family of quadratic functions using transformations.
A hydrogen atom has one positively charged proton and one negatively charged electron.
Write an addition equation to represent how their charges combine to make the overall charge of the atom.
Answers
The addition equation to represent how their charges combine to make the overall charge of the atom is + 1 + - 1 = 0
How to write equation to represent charges of atom?A hydrogen atom has one positively charged proton and one negatively charged electron.
An atom of every elements has an electron(negatively charged) and positively charge(proton) part.
An atom as a whole is electrically neutral if the number of proton and electron are equal. They will cancel each other to make the atom neutral.
Therefore, the addition equation to represent how their charges combine to make the overall charge of the atom is as follows;
+ 1 + - 1 = 0
1 positively charged proton plus single negatively charged electron = zero(neutral)
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what do I check off
Answers
Answer:
E. >
Because 65 is greater than 56.
Identify sinJ as a fraction and as a decimal rounded to the nearest hundredth.
The figure shows right triangle J K L with right angle L. The length of leg L J is equal to 7 point 2 units. The length of leg K L is equal to 3 units. The length of hypotenuse J K is equal to 7 point 8 units.
Answers
In the given right triangle, the trigonometric ratio, sin J has a fractional value of 5/13 and a decimal value of 0.39.
In trigonometry, for a right triangle, the sine (sin) of any angle θ is given as the ratio of its opposite side to the hypotenuse of the triangle, that is, sin θ = (opposite side)/(hypotenuse).
In the question, we are asked to find the trigonometric ratio, sin J, for the given right triangle JKL.
The side opposite to angle J is KL, which has a value of 3 units.
The hypotenuse of the given right triangle is JK, which has a value of 7.8 units.
Thus, sin J can be calculated as:
sin J = KL/JK = 3/7.8 = 5/13 = 0.39.
Thus, in the given right triangle, the trigonometric ratio, sin J has a fractional value of 5/13 and a decimal value of 0.39.
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LK=
Help please asap thx so much
Answers
Answer:
LK = 4[tex]\sqrt{2}[/tex]
Step-by-step explanation:
given point J (4, 4 )
then LJ = 4 and JK = 4
using Pythagoras' identity in right triangle LJK
LK² = LJ² + JK² = 4² + 4² = 16 + 16 = 32 ( take square root of both sides )
LK = [tex]\sqrt{32}[/tex] = [tex]\sqrt{16(2)}[/tex] = [tex]\sqrt{16}[/tex] × [tex]\sqrt{2}[/tex] = 4[tex]\sqrt{2}[/tex]
I need help with this
Answers
Answer:
s = -24
Step-by-step explanation:
This is a 2-step linear equation, so can be solved the way all 2-step equations are solved.
SolutionStep 1
Identify the constant term on the side of the equation with the variable term, and add its opposite to both sides.
[tex]7 = \dfrac{1}{6}s+11\qquad\text{given}\\\\7-11=\dfrac{1}{6}s+11-11\qquad\text{add $-11$ to both sides}\\\\-4=\dfrac{1}{6}s\qquad\text{simplify}[/tex]
Step 2
Multiply both sides by the inverse of the coefficient of the variable.
[tex](6)(-4)=(6)\left(\dfrac{1}{6}s\right)\qquad\text{multiply both sides by 6}\\\\\boxed{-24=s}\qquad\text{simplify}[/tex]
Alternate solutionOften, when equations contain fractions, you are advised to "eliminate fractions" as a first step. That generally means you multiply both sides of the equation by a suitable common denominator.
Here, the only denominator is 6, so the fraction can be eliminated by multiplying both sides of the equation by 6.
[tex]7=\dfrac{1}{6}s+11\qquad\text{given}\\\\6(7)=6\left(\dfrac{1}{6}s+11\right)\qquad\text{multiply both sides by 6}\\\\42=s+66\qquad\text{simplify}\\\\42-66=s+66-66\qquad\text{add the opposite of 66 to both sides}\\\\\boxed{-24=s}\qquad\text{simplify}[/tex]
You will note this requires the same number of steps, but you don't have to mess with fractions after the first step.
CheckThe value we found for the variable can be checked in the original equation.
[tex]7=\dfrac{1}{6}(-24)+11\\\\7=-4+11\qquad\text{true}[/tex]
The first quartile of the dataset {1, 2, 3, 4, 5, 6} is _______. (give your answer as a whole number.
Answers
The first quartile of the dataset {1, 2, 3, 4, 5, 6} is 2.
Given data set: {1,2,3,4,5,6}
Median of the given data set =3.5
The data set can be split into 2 parts as, {1,2,3} and {4,5,6}. The first quartile is calculated by simply finding the median of the first part of the data set.
Thus, the first quartile is 2.
The quarter divides the distribution into four groups and calculates the range of values above and below the mean.
A quartile separates the dataset into four categories by dividing the data into three points: the lowest, median, and upper quartiles.
The interquartile range, a measurement of variation around the median, is calculated using quartiles.
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Geometry: complete this proof, ASAP!!!!!!!
Answers
The complete proof from the figure is:
AC ≅ DF; AB ≅ DE; ∠1 ≅ ∠6 -- Given∠1 ≅ ∠2; ∠5 ≅ ∠6 -- vertical angles∠2 ≅ ∠5 --- corresponding anglesΔABC ≅ ΔDEF --- SAS postulate∠3 ≅ ∠4 --- corresponding anglesBC || EF ---- provedHow to complete the proof?The given parameter is:
AC ≅ DF; AB ≅ DE; ∠1 ≅ ∠6
Angles 1 and 2, & Angles 5 and 6 are vertical angles
So, we have: ∠1 ≅ ∠2; ∠5 ≅ ∠6 by the definition of vertical angles.
From the figure, triangles ABC and DEF are congruent by the SAS postulate.
So, we have: ΔABC ≅ ΔDEF by the definition of SAS postulate
Angles 3 and 4 are corresponding angles
So, we have: ∠1 ≅ ∠2; ∠5 ≅ ∠6 by the definition of corresponding angles.
Hence, the lines BC and EF are parallel lines
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A car travels the first 50 km of its journey at an average speed of 25 m/s and the next 120 km at an average speed of 80 km/h. The car completes the last part of its journey at an average speed of 90 km/h in 35 minutes. Find the average speed for its entire journey, giving your answer in km/h.
Answers
Answer:81.85 km/hr is the average speed
Step-by-step explanation:
Answer: ≈ 84,3 km/h.
Step-by-step explanation:
[tex]\displaystyle\\V{average}=\frac{\Delta S}{\Delta t}=\frac{S_1+S_2+S_3}{t_1+t_1+t_3} .\\1.\ S_1=50\ km\\ t_1=\frac{S_1}{V_1}\\ V_1=25*\frac{3600}{1000} \\V_1=90\ \frac{km}{h} .\\t_1=\frac{50}{90}\\ t_1=\frac{5}{9} \ h.\\2.\ S_2=120\ km\ \ \ \ V_2=80\ \frac{km}{h} \\t_2=\frac{S_2}{V_2} \\t_2=\frac{120}{80} \\t_2=\frac{3}{2}\ h.\\[/tex]
[tex]3.\ V_3=90\ \frac{km}{h} \\t_3=35\ minutes\\t_3=\frac{35}{60} \\t_3=\frac{7}{12}\ h.\\ S_3=V_3*t_3\\S_3=90*\frac{7}{12} \\S_3=52,5\ km.\\Hence,\\V{average}=\frac{50+120+52,5}{\frac{5}{9}+\frac{3}{2} +\frac{7}{12} } \\V{average}=\frac{222,5}{\frac{95}{36} } \\Vaverege\approx84,3\ \frac{km}{h} .[/tex]
Quick algebra 1 question for 10 points!
Only answer if you know the answer, quick shout-out to tariqareesha2 and MrBrainly, tysm for the help!
Answers
Answer:
109x
Step-by-step explanation:
We know that there are 109 students in the fourth grade, who each have x cupcakes. In order to find the total amount of cupcakes, we could add all of the cupcakes together to get:
x + x + x + x + .... x
109 times because there are 109 students.
This can be simplified to become 109x.
Austin is a human resources executive for a technology company. He is deciding between two types of plans for vacation allowance for the employees of the company: Unlimited and Traditional, Austin wants to deterrine, for workers in the tech Industry, if the yearly mean number of vacation days taken by workers with an Unlimited plan is greater than the yearly mean number of vacation days taken by workers with a Traditional plan Austin surveys a random sample of 17 workers who have the Unlimited plan and a random sample of 15 workers who have the Traditional plan. (These samples are chosen independently.) For each worker, he records the number of vacation days taken last year. For the workers with an Unlimited plan, the sample mean is 18.9 with a sample variance of 30.8. For the workers with a Traditional plan, the sample mean is 17.4 with a sample variance of 6.1 Assume that the two populations of vacation days taken are approximately normally distributed. Can Austin conclude, at the 0.10 level of significance, that the population mean of the yearly number of vacation days taken by workers with an Unlimited plan is greater than the population mean of the yearly number of vacation days taken by workers with a Traditional plan? Perform a one-talled test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, (If necessary, consult a list of formulas.) (*) State the null hypothesis and the alternate hypothesis (a) Determine the type of test statistic to use (a) state the null hypothesis H, and the alternate hypothesis (b) Determine the type of test statistic to use. (c) Find the value of the test statistic (Round to three or more decimal places.) (d) Find the critical value. (Round to three or more decimal places) (e) At the 0.10 level of significance, can Austin conclude that the yearly mean number of vacation days taken by workers with an Unlimited plan is greater than the yearly mean number of vacation days taken by workers with a Traditional plan?
Answers
The question requires that we have to state the hypothesis:
null hypothesis;H0: u1 < u2, the alternate hypothesis;H1: u1 > u2. The one tail test is what is to be used.
A. How to state the hypothesisH0: u1 < u2
H1: u1 > u2
The one tail test statistic is what is to be used here
B. standard error[tex]\sqrt{\frac{30.8}{17} +\frac{6.1}{15} }[/tex]
= 1.49
The df = 17 + 15 - 2
= 30
test statistic = 18.9 - 17.4 / 1.49
= 1.007
We have the critical value on excel as T.INV(0.9,30)
= 1.310
E. At 0.1, we can conclude that t-value (1.007) does not lies in the rejection area. We fail to reject the null hypothesis. Hence we conclude that the mean vacation with the unlimited plan is greater.
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