The borders, or cracks, between tectonic plates are called ________.
A
lithospheres

B
synclines

C
anticlines

D
faults

Answer:

7+z / 2

z = 10

replace the value of z

7 +10 /2

use order of operations ( division comes before addition)

7+5 = 12

Explanation: 12

Answer:

Initial velocity, u = 600km/h 

Final velocity, v = 1100km/h

Acceleration = 10km/h/s=600km/h2

From relation, 

a=t(v−u)

t=a(v−u)

t=600(1100−600)

=500/600=5/6 hr=50 sec

The ball's speed and direction are 3.1 m/s at its lowest point in its trajectory, and it swings to the other side at the same angle.

We are given that,

The weight of the ball = m = 500g

The height of the string = h = 41.0 cm

The pendulum is pulled at the angle of = θ = 25.0°

At the lowest point, we'll suppose that 100% of the motion will convert to kinetic energy. Now, the height difference will be,

Δh = (41.0cm– 41.0cos 2.5°) = 0.41cm

The change in potential difference is given as,

ΔP.E = mgΔh

ΔP.E = 9.8m/s² × 0.50kg × 0.0041 m

ΔP.E = 0.02009J

Then the kinetic energy of the pendulum is given by,

K.E = (1/2)mv²

Therefore , from the law of conservation the potential energy is equal to the kinetic energy of the pendulum and putting the values from the above i.e.

P.E = K.E

P.E = (1/2)(0.50kg)(v²)

v² = (0.02009J)/(0.5)(0.50kg)

v² = 0.08036m/s

v = 0.2834 m/s

Thus the speed of the pendulum would be 0.2834m/s.

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The kinetic energy of the object with a mass of 4 kilograms which was lifted at a rate of 10 m/sec was greater than the kinetic energy of the object that had a mass of 2 kilograms and was lifted at a speed of 2m/sec.

The kinetic energy of an object is the energy that an object has due to its motion.

The kinetic energy of a body is given mathematically as follows:

Kinetic energy = ¹/₂ * mass * velocity²

The kinetic energy of the objects is as follows:

Object 1; mass = 2 kilograms, speed = 2m/s

Kinetic energy =  ¹/₂ * 2 * 2²

Kinetic energy = 4 J

Object 2; mass = 4 kilograms, speed = 10 m/s

Kinetic energy = ¹/₂ * 4 * 10²

Kinetic energy = 200 N

Comparing the kinetic energy of the two objects, it can be seen that the kinetic energy of Object 2 was far greater than the kinetic energy of Object One.

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Answer:

1.2 m/s^2

Explanation:

F = m a

42000 = 35000 * a

a = 42000 / 35000 = 1.2 m/s^2

According to question, we know that

ux=ucosθax=0

uy=usinθay=−g

The projectile's maximum height h is equal to one-half of H, the triangle's altitude. = H - 12H, resulting in h = H/2, which is the desired result. If a projectile's maximum height is 15 m, its maximum range is 4 * max height, which equals 60 m.

The highest point of the structure or sign measured from the average natural ground level at the base of the supporting structure is referred to as the maximum height.

at max. height

Vy=0

0- usinФ = gt

t = usinФ/g

Now, we know that

H = ut + 1/2g[tex]t^{2}[/tex]

After putting all the values, we get

H(max) = [tex]u^{2} sin^{2}[/tex]Ф/2g

Hence proved

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To enter orbit, a spacecraft leaving the Earth's surface must travel at least 11 kilometers (7 miles) per second, or more than 40,000 kilometers per hour (25,000 miles per hour). One of the most difficult challenges in space travel is achieving escape velocity.

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The strength of the magnetic field is 4x10^-2 T

What is Magnetic Field?

A magnetic field is a vector field that describes the magnetic influence on moving charges, currents, and magnetic materials. A moving charge in a magnetic field is subjected to a force that is perpendicular to both its own velocity and the magnetic field.

Magnetic field at O due to wire 1,  B1 = UoI1/2pid;

where d = 5 cm

B1 = u0(10)/2pi(5)

Magnetic field at O due to wire 2,

B2 = uo I2/2pid

B2 = u0(5)/2pi(5)

The net magnetic field at O Bo = B2-B1

uo(10-5)/2pi(5)

B0 = (4pi x10^-7)(5)/2pi(5)

= 4x10^-2 T.
Therefore the answer is 4x10^-2 T

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Wave crest is the highest part of a progressive wave above average water level This statement is True.

The valley between wave crests that are lower than the average water level is known as the wave trough. Wave length is the distance horizontally between two troughs, whereas wave height is the vertical distance between a wave crest and the adjacent troughs.

The top of the waves is called as the crest. The lowest point is called the trough. The storm surge is the highest - end change in elevation between both the crest and the trough, whereas the wave length, often known as the wavelength, is the distance between two consecutive crests (or troughs).

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The magnitude of work input during this process is - 73.62 kJ

It is Given that

In a gas-tight, friction-free piston cylinder, 1.5 kg of air at 120 kPa and 24 °C is housed. This final pressure of 600 kPa is reached for the air. Heat is transferred from the air during the procedure, maintaining a consistent temperature inside the cylinder.

We have to Calculate the work input during this process.

Assuming air is an ideal gas at constant temperature, the ideal gas equation will be

P = mRT/V

Now mRT is constant at constant temperature, the equation for work will be V2

W = ∫ path P dv

= v1 ∫v1 to v2 mRT / Vdv

= ∫ v1 to v2 dV/V

= mRT (log V) v1 to v2

= mRT (log V2/V1)

We need to find V2/V1 for constant temperature

So V2/V1 mRT / P2/mRT/P1

V2/V1 mRT / P2/mRT/P1 = P1/ P2

Substituting P1/P2 in V2/V1 using gas constant for air = 0.2870,

So m = 1.5 kg

T = 24 degree Celsius = 285.15 K

So W = mRT log(P1/P2)

= 1.5 kg x 0.2870 kJ/kg K x 285.15 K log (120 kpa / 600 kpa)

= - 73.62 kJ

The negative sign implies that it is a work input of - 73.62 KJ

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1. When egg hits the ground with a force, the ground exerts the same force back on the egg. The faster the egg falls, greater is this force is. If extreme force is delivered to the egg shell, it will crack. When the egg is dropped, speed increases as it falls, and as speed goes up, it gains momentum from the impulse caused by gravity. When it hits the floor, it stops due to an impulse in the opposite direction.

2. Structure of lander:

3. Reasons that design would allow safe landing of egg:

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Force on the truck is 3402N .

An item having mass changes its velocity when it is pushed or pulled. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

We are given that,

Mass of the car = m = 800 kg

Mass of the truck = m = 2100kg

The car exerted the force on the ground = F = 4700N

The total mass of the car and truck = 800kg + 2100kg = 2900kg

According to Newton's second law of motion,

F = ma

Where, a is total acceleration of the system, m is total mass of the system and F is the total force on the system,

a = F/m

a = 4700N/ 2900kg

a = 1.62 m/s²

The product of this acceleration and the car's mass will determine the force on the truck acting alone. Since force on the truck can be calculated as,

F = ma

Where, F is force on the truck and m is the mass of truck and a is acceleration of the system. After putting the above value we can get,

Ft = 2100kg × 1.62m/s²

Ft = 3402 N

Thus, Force on the truck would be 3402N.

Force on the car the force from the truck will be equal to it but act in the other direction .

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Answer:

Volume of buoy = 1.09 m^3

Volume of seawater displaced = 1.09 m^3

Mass of seawater displaced = 1.09 m^3 * 1025 kg/m*3 = 1117 kg

Mass of buoy = 803 kg

Net mass = 1117 - 803 = 314 kg         Mass supported by cable

Net force on cable F = M a = 314 kg * 9.80 m / s^2 = 3077 N

Answer:  By multiplying mass by velocity

Explanation:  By multiplying mass by velocity

If a man walks south on the sidewalk at a speed of 0.8 m/s, then it would take him 14.3 seconds to travel 10 m relative to a stationary observer, therefore the correct answer is option A.

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.

As given in the problem A moving sidewalk has a velocity of 1.5 m/s north. If a man walks south on the sidewalk at a speed of 0.8 m/s,

The relative velocity the man  = 1.5 - 0.8

                                                  =0.7

The time is taken by him  to travel 10 m relative to a stationary observer,

Time = 10 / 0.7

        =14.3 seconds

Thus,it would take him 14.3 seconds to travel 10 m relative to a stationary observer, therefore the correct answer is option A.

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The soil we can carry with this wheelbarrow is 227.5 Netwon weight.

Mechanical advantage is a measure of the ratio of output pressure to enter pressure in a system, used to investigate the forces in simple machines like levers and pulleys. notwithstanding converting the forces which might be implemented the conservation of power continues to be authentic and the output energy remains identical to the enter strength.

The mechanical benefit is a measure of the pressure amplification carried out by using using a device, mechanical device, or system machine. The tool trades off enter forces in opposition to the motion to attain a desired amplification within the output force. The model for that is the law of the lever.

Mechanical advantage = load / effort

given mechanical advantage = 3.5

effort =-65 N

Load = mechanical advantage effort

           = 3.5 65

           = 227.5 Netwon

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The mass of the object if the acceleration of a mass is 15 m/s^2 to the left is 1.27 kg

F = F1 + F2 + F3

F1 = - 8 N

F2 = 7 N

F3 = - 18 N

F = - 8 + 7 - 18

F = - 19 N

Negative symbol indicates that the force is acting towards the left.

F = m a

F = Force

m = Mass

a = Acceleration

a = - 15 m / s²

m = F / a

m = - 19 / - 15

m = 1.27 kg

Therefore, the mass of the object is 1.27 kg

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The velocity in the x direction is 26 m/s minimum horizontal speed.

Were asked to find the speed in the x (horizontal) direction which can be acquired from

x = vxt or vx = x/t.

We know x (15.4 m) but we need to find t.

We can find how long it takes for gravity to force the ball down from the initial height (tennis racket) to the final height (top of net) from y = yo + vot + 1/2 at2.

We'll choose y to be positive up.

The initial height yo = 2.6 m, final height y = 0.90 m, the initial velocity in the y direction is zero

vo = 0, and

a = -g (since y is positive up, gravity is downward and negative,

-g = -9.8 m/s2).

We have:0.90m = 2.6 m - 4.9 m/s2 * t2 4.9 m/s2 * t2

= 1.7 mt = ± [ 1.7 m / 4.9 m/s2 ]1/2t

= ± 0.6 s (choose + s)

Therefore, The velocity in the x direction: vx = 15.4 m / 0.6 s = 26 m/s minimum horizontal speed.

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The velocity of the two wagons after the collision can be calculated using the principle of momentum conservation.

Only one of the wagons is moving in this scenario prior to the accident. We also assume that following the impact, the wagons lock together.

According to the rule of conservation of momentum, absent an external force, the combined momentum of a number of bodies operating upon one another in an isolated system remains constant. As a result, momentum cannot be gained or lost.

The conservation of momentum is a general law of physics which states that the total momentum of the system remains constant and that the quantity called momentum which characterizes motion never varies in an isolated collection of objects.

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The frictional force due to sliding.

What is frictional force?

Frictional force is the force produced when two surfaces slide against and touch each other. The surface texture and amount of force needing them together have the biggest an impact on these forces. The amount of frictional force is influenced by the object's position and angle.

Two forces are applied to the block as it moves up a ramp; the first is the weight component, and the second is the frictional force from sliding.

The weight and frictional forces that are pulling the block up are parallel to one another. These forces are directed downward toward the plane, which results in a stronger force and acceleration.

The components of weight and frictional force are moving in the opposite directions as the block down the ramp. The upward direction is where the frictional force operates.

Since the force's magnitude is small as a result of the opposite directions, the acceleration will also be smaller. As a result, the acceleration on the descent is lower than on the rise.

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The maximum angle theta to which the box of sand with embedded projectile swings is 20.7 degrees, and the energy lost after impact is 99.8%.

Given quantities:
QM(1)= 2oz = (2/16)lb
QM(2)= 50 lb

U= 2000 ft/sec
r= 6ft

Conservation of linear momentum:
G(1)=G(2)
m1v+m2(o)= (m1+m2)U^1
U^1 is the velocity of box and bullet immediately after impact
U^1= -m1v/(m1+m2)

After impact, conservation of total energy:
in U(1-2)=0, Tension does not work

= -1/2 (m1+m2)(U^1)^2 + (M1+M2)Qh= 0

- 1/2 (4.99 ft/sec)^2 + 32.2 ft/sec^2 6ft (1-cos theta)=0

{Theta= 20.7}

Energy lost in impact:
Final energy: (m1+m2)Qr (1-cos theta)= 19.248ft -lb

Initial energy: 1/2 mv^2= 7763.98 ft-lb
Energy loss: 7763.90- 19.248/7763.98 x 100%

= 99.8%

Therefore, the total percentage of energy lost after impact is 99.8% and the value of theta is 20.7 degrees.

Given complete question:

The ballistic pendulum is a simple device to measure prohectile velocity v by observing the maximum angle theta to which the box of sand with embedded projectile swings. Calculate the angle theta if the 2-oz projectile is fired horizontally into the suspended 50lb box of sand with a velocity v = 2000ft/sec. Also find the percentage of energy lost during impact.

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Answer:

F = 64655.86 N

Explanation:

Im not sure about the initial velocity but its somewhere near 0.23 m/s

The distance travelled by the car and the velocity of the car, both will increase weather the mass increases or not.

Let us say that there is a horizontal surface inclined at an angle A, the acceleration is g(acceleration due to gravity) and the car is going down the inclined.

Let us say that the mass M of the car is increasing constantly.

Now, we know, because the inclined is at an angle, so the component of g that will be in the direction of the motions is gsinA.

This component of acceleration not going to change, so the acceleration is now constant.

As there is some acceleration, that too in the direction of the motion, so the velocity of the car will increase constantly regardless of the mass until it reaches the final maximum value.

Because the velocity of the car is increasing so obviously the distance will also increase.

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Answer:

Cellular respiration involves the complete breakdown of glucose in presence of oxygen gas to yield carbon dioxide ,water , and energy in the form of atp

According to the given statement The induced voltage opposing this is 3.60 V.

Electrons transport electrical energy through conducting materials (like power lines). The voltage of the transmission line gauges the amount of potential energy that each electron is transporting along the power line. Voltage, in other terms, is the force that forces current through the electrical supply network.

Magnitude of change in current, dI = 4.00 A as current reduces to zero

Inductance of the inductor, L = 7.50 mh = 7.50 *10⁻³

Time elapsed dt = 8.33 ms = 8.33 * 10⁻³

The induced emf is given by replacing the specified values with:

[tex]\epsilon=L \frac{d I}{d t}[/tex]

=7.50 *10⁻³H * (4.00 A / 8.33 * 10⁻³)

= 3.60 V

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We have:

vi = initial speed = 4 m/s

vf = final speed = 25 m/s

t= time = 5 s

a = acceleration = ?

Apply:

Replace with the values given:

Answer: 4.2 m/s^2

The Acceleration of the car is 4.2 m/s.

We will use the formula of acceleration.

a = vu - vi / t

Given:

vi = initial speed = 4 m/s

vu = final speed = 25 m/s

t= time = 5 s

a = acceleration = ?

Now, we will put the given values in the formula,

a = vu - vi / t

a = 25 - 4 / 5

a = 21 / 5

a = 4.2 m/s

Therefore, the Acceleration of the car is 4.2 m/s.

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A ball of mass 0.3 kg, initially at rest, is kicked directly toward a fence from a point 16m away. The velocity of the ball as it leaves the kicker's foot is 16 m/s at an angle of 48 degrees above the horizontal. The top of the fence is 3 m high. The ball hits nothing while in flight and air resistance is negligible. The acceleration due to gravity is 9.8 meters per second square.

a) The time it takes for the ball to reach the plane of the fence is (t)= 1.49 s

b) The ball pass above the top of the fence will be (h)=3.81m

c) The vertical component of the velocity when the ball reaches the plane of the fence is [v(y)]= -2.71 m/s

The term velocity means that the object's covered distance within the given time. Example: A car goes 3m in 1 second the velocity of the car is 3m/s.

a) To calculate the time we are using the formula,

x=vcosθt

Or, t = x/ vcosθ

Here we are given,

v= the initial velocity of the ball =16 m/s

θ =  the initial angle = 48°

x= The distance of the fence = 16m

W have to calculate the time =t

Now we put the values in the above equation we get,

t = x/ vcosθ

Or, t= 16/16*cos48°

Or, t = 1.49 S

Now we know that, the time it takes for the ball to reach the plane of the fence is (t)=1.49 s

b) Now we have to calculate the height of the ball when it cross the fence. we are using the formula,

y= vsinθt-(1/2)gt²

t =  the time we got earlier = 1.49 s

g= The acceleration due to gravity = 9.8 m/s².

Now we put the values in the above equation we get,

y= vsinθt-(1/2)gt²

Or, y = 16*sin48*1.49-(1/2)*9.8*(1.49)²

Or, y= 6.81 m

The  ball pass above the top of the fence will be (h)=(y-y₁)=(6.81-3)=3.81m

c) To calculate the vertical component of the velocity when the ball reaches the plane of the fence, we are using the formula,

v(y)=vsinθ-gt

Or, v(y)=16*sin48-9.8*1.49

Or, v(y)= -2.71 m/s

From the calculation we assure, The vertical component of the velocity when the ball reaches the plane of the fence is [v(y)]= -2.71 m/s.

[Note: The component is negative cause the velocity is decreasing]

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A ball of mass 0.3 kg, initially at rest, is kicked directly toward a fence from a point 16m away. The velocity of the ball as it leaves the kicker's foot is 16 m/s at an angle of 48 degrees above the horizontal. The top of the fence is 3 m high. The ball hits nothing while in flight and air resistance is negligible. The acceleration due to gravity is 9.8 meters per second squared.

a) Determine the time it takes for the ball to reach the plane of the fence.

b) How far above the top of the fence will the ball pass? Consider the diameter of the ball to be negligible.

c) What is the vertical component of the velocity when the ball reaches the plane of the fence?

The acceleration of this jet is equal to: C. 6.26 m/s².

In Physics, the acceleration of a physical object (jet) or body can be calculated by using this formula:

a = (V - U)/t

Where:  

Substituting the given parameters into the formula, we have;

Acceleration, a = (432.8 m/s - 138.5 m/s)/47 seconds

Acceleration, a = 294.3/47

Acceleration, a = 6.26 m/s².

In conclusion, we can logically deduce that this jet has an acceleration of 6.26 meters per seconds square (m/s²).

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