The following formula models the number of automobiles, A,in thousands, that Washington residents purchased
x years after 1980.
A=2x2+24x+300

A) Write an equation that you can use to determine the first year in which residents purchased approximately 566 thousand cars.


B) Now solve your equation and specify the first year (for example, enter 2019 and not 39) in which residents purchased approximately 566 thousand cars.

The system of inequalities be

3x+2y ≤ 25, 4x+6y ≤ 37

1) Maximum number of sundaes possible exists 9.

2) Maximum number of milkshakes possible exists 6.

3) Combination that uses the most of both Ice-cream and Strawberries = 7 scoops of ice cream and 1 scoop of strawberries.

A system of inequalities exists the system where the set of more than one inequalities in more than or equivalent to one variable.

Given: A sundae needs 3 ice-cream scoops and 4 strawberries, and a milkshake requires 2 ice-cream scoops and 6 strawberries.

Ramses have to create sundaes and milkshakes with at most 25 ice-cream scoops and 37 strawberries.

Let x represent the number of sundaes he creates and y the number of milkshakes he creates.

We represent in tabular form,

                    Sundae(x)      Milkshake(y)     Total

Ice-cream          3                         2             3x+2y

Strawberries      4                        6             4x+6y

System of inequalities:

Sundaes and milkshakes with at most 25 ice-cream scoops exist

33x+2y ≤ 25.

Sundaes and milkshakes with at most 37 strawberries exist 4x+6y ≤ 37.

1) Maximum number of sundaes possible:

Maximum number of sundaes possible when y = 0

From the graph y = 0 at x = 9.25

Therefore, the maximum number of sundaes possible exists at 9.

2) Maximum number of milkshakes possible:

Maximum number of milkshakes possible when x = 0

From the graph x = 0 at y = 6.167

Therefore, the maximum number of milkshakes possible exists at 6.

3) Combination that utilizes the most of both Ice-cream and Strawberries:

A combination of both is possible there exists an intersection of both the equation.

From the graph, the intersection point exists x = 7.6 and y = 1.1.

Therefore, the Combination that utilizes the most of both Ice-cream and Strawberries = 7 scoops of ice cream and 1 scoop of strawberries.

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Once you detect that there is a delay or disability, then you should continue to be the reliable partner in child care to the family so this is True.

The observation and screening process can lead to a child care partner discovering a delay or disability.

When this happens, you should report to your supervisor to check if the child is eligible for federal and state programs related to their condition. Whatever the case, you should remain accessible to the family as their partner in child care.

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The lower-priced speaker docks and higher-priced speaker docks is 9 and 36 respectively.

Higher-priced speaker = 170 × x

= 170x

Lower-priced speaker = 80 × 4x

= 320x

Total sales = $4,410

170x + 320x = 4,410

490x = 4,410

divide both sides by 490

x = 4,410 / 490

x = 9

So,

Number of lower-priced speaker = 4x

= 4 × 9

= 36

Number of higher-priced speaker = x

= 9

Therefore, the lower-priced speaker docks and higher-priced speaker docks is 9 and 36 respectively.

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Answer:

93.39

Step-by-step explanation:

So the sum of exterior angles of the convex octagon is: 360 degrees

This means if we add all the equations that represent each angle, we can set it equal to 360 and solve for x

[tex](x+14) + (2x-3) + (3x+8) + (3x+16) + (2x-17) + (3x-4) + (3x-12) + (6x)[/tex]

Group like terms

[tex](x+2x+3x+3x+2x+3x+3x+6x) + (14-3+8+16-17-4-12)[/tex]

Add like terms

[tex]23x+2[/tex]

Now let's set the sum of exterior angles to 360

[tex]23x+2 = 360[/tex]

Subtract 2 from both sides

[tex]23x=358[/tex]

Divide both sides by 23

[tex]x\approx 15.565[/tex]

So by looking at all these, it appears that 6x is the highest value, given that x is positive. The way I estimated, is approximately 15.5, whenever I saw an equation like x+14, I estimated it's about 2x, since 14 is not exactly, but close to 15.5. I did this with each polynomial given. You could also manually check each one

Original equation

6x

Subsitute

6(15.565)

Simplify

[tex]93.39[/tex]

Answer: [tex]\Large\boxed{x=-\frac{4}{5} }[/tex]

Step-by-step explanation:

Given equation

[tex]-9+log_{4}(-5x)=-8[/tex]

Add 9 on both sides

[tex]-9+log_{4}(-5x)+9=-8+9[/tex]

[tex]log_{4}(-5x)=1[/tex]

Simplify the logarithm

[tex]-5x=4^1[/tex]

[tex]-5x=4[/tex]

Divide -5 on both sides

[tex]-5x\div-5=4\div-5[/tex]

[tex]\Large\boxed{x=-\frac{4}{5} }[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

2700 degrees

Step-by-step explanation:

The number of sides minus 2 times.

n = number of sides

(n-2)= 180

(17-2)(180)

(15)(180) = 2700

The given triangle has three angles with measurements: ∠A = 69°, ∠B = 52°, and ∠C = 59° respectively. Using the law of cosines, these angles are calculated from the given lengths of the triangle.

The law of cosines gives the relationship between the lengths of sides and the angles of the triangle ABC.

According to the law of cosines:

Cos A = (b² + c² - a²)/2bc

Cos B = (a² + c² - b²)/2ac

Cos C = (a² + b² - c²)/2ab

For the given triangle ABC,

a = 75, b = 63, and c = 69

So, using the law of cosines,

Cos A = (b² + c² - a²)/2bc

⇒ Cos A = (63² + 69² - 75²)/2×63×69

⇒ Cos A = 5/14

⇒ A = Cos⁻¹(5/14) = 69.07

∴ ∠A = 69°

Similarly,

Cos B = (a² + c² - b²)/2ac

⇒ Cos B = (75² + 69² - 63²)/2×75×69

⇒ Cos B = 31/50

⇒ B = Cos⁻¹(31/50) = 51.6 ≅ 52

∴ ∠B = 52°

Cos C = (a² + b² - c²)/2ab

⇒ Cos C = (75² + 63² - 69²)/2×75×63

⇒ Cos C = 179/350

⇒ C = Cos⁻¹(179/350) = 59.2

∴ C = 59°

Thus, the angles of the triangle ABC are 69°, 52°, and 59° respectively.

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The function position of the particle is s(t) = (1 / 12) · t⁴ + (7 / 6) · t³ + 3 · t² + (63 / 4) · t.

By mechanical physics we know that the function velocity is the integral of function acceleration and the function position is the integral of function velocity. Hence, we need to integrate twice to obtain the function position of the particle:

Velocity

v(t) = ∫ t² dt - 7 ∫ t dt + 6 ∫ dt

v(t) = (1 / 3) · t³ - (7 / 2) · t² + 6 · t + C₁

Position

s(t) = (1 / 3) ∫ t³ dt - (7 / 2) ∫ t² dt + 6 ∫ t dt  + C₁ ∫ dt

s(t) = (1 / 12) · t⁴ + (7 / 6) · t³ + 3 · t² + C₁ · t + C₂

Now we find the values of the integration constants by solving the following system of linear equations:

0 = C₂

63 / 4 = C₁ + C₂

The solution of the system is C₁ = 63 / 4 and C₂ = 0. The function position of the particle is s(t) = (1 / 12) · t⁴ + (7 / 6) · t³ + 3 · t² + (63 / 4) · t.

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The number paths between c and d of length 2.

Find the number of paths between c and d in the graph of length:

The number of paths between c and d is 0.

There is the number of paths between c and d of length 2.

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Answer:

Step-by-step explanation:

16 + 12 + 5 + 3 = 36

16 prefer email, 36 total students surveyed

16:36 / 4 = 4:9

4 out of 9 students prefer email

4:9 x 680 = 302.222

302 students can be expected to prefer email.

Answer:

ight first you add 4 to 6 and that gets you 10 so you left with p+5=10 then you subtract 5 from 10 so p is gonna be  5

Step-by-step explanation:

Answer:

shown below

Step-by-step explanation:

Look at the white squares, count them. 1, 2, 3. the next will be 4 and 5. draw 4 white squares, then house it in black squares like the others. to know if u did it right, count the black squares, there should be 8, then 9.

Answer:

43

Step-by-step explanation:

I would see a pattern like this

1 4 6 2 5 7 8 9 7 15 41 ?

------------------- ---------

start pattern key

then

15 = 8 × 2 - 1

a10 = a7 × a4 - a1

41 = 9 × 5 - 4

a11 = a8 × a5 - a2

? = 7 × 7 - 6 = 43

a12 = a9 × a6 - a3

If 2+3/4 hours is equal to 1+5/5 equal length shift then the single shift is 1.5 hours long.

Given that Paolo helped in the community garden for 2 +3/4 hours this week which is 1+5/6 times length shift.

We are required to find the length of a single shift.

First we have to find the proper fraction of the given mixed fractions.

Fraction is combination of numerator and denominator.The number that is present above the division sign is known as numerator and the number that is present below the division sign is known as denominator.

2+3/4=(8+3)/4=11/4

1+5/6=(6+5)/6=11/6

let the length of a shift is x hours.So,

11/4=11*x/6

11/4=11/6 x

66/44=x

x=3/2

x=1.5 hours.

Hence if 2+3/4 hours is equal to 1+5/5 equal length shift then the single shift is 1.5 hours long.

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Using it's concept, the probability that the first coin is a nickel and the second coin is a quarter is:

2/39.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

Hence the probability will be given as follows:

p = 4/13 x 2/12 = 4/13 x 1/6 = 2/13 x 1/3 = 2/39.

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The two ordered pairs that the mid point is (4,-10) are (4,-20),(4,0) & (4,0),(4,-20).

Given the coordinates of mid point be (4,-10).

We are required to find the ordered pairs that the mid point is (4,-20).

Coordinates show positions of points or something else on a surface.

There are various combinations whose mid point is (4,-10).

First are (4,-20),(4,0).

Mid point =[(4+4)/2,(-20+0)/2]

=(4,-10)

Second are (4,0) , (4,-20)

Mid point=[(4+4)/2,(0-20)/2]

=(4,-10)

Third are (8,-20),(0,0)

Mid point=[(8+0)/2,(-20+0)/2]

=(4,-10)

Fourth are (0,-20),(8,0)

Mid point =[(0+8)/2,(-10+0)/2]

=(4,-10)

Hence the ordered pairs that the mid point is (4,-10) are (4,-20),(4,0) & (4,0),(4,-20)& (8,-20),(0,0)&(0,-20),(8,0)&(0,0),(8,-20).etc.

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If there are 23 students study Economics,6 students study both government and economics and 48 students study either government or economics or both then there are 31 students study government, 17 students study economics only and 25 students are there who study government only.

Given that in a secondary school class, 23 students study Economics, 6 students study both government and economics. 48 students study either government or Economics or both.

We are required to find :

Suppose E represents economics students and G students government students. In this way:

E=23

G∩E=6  (And represents intersection between sets)

G∪E=48 (Or represents union of sets)

G∪E=G+E-G∩E

48=G+23-6

G=48-17

G=31

Economics only=E-G∩E

=23-6

=17

Governments only=G-G∩E

=31-6

=25

Hence if there are 23 students study Economics,6 students study both government and economics and 48 students study either government or economics or both then there are 31 students study government, 17 students study economics only and 25 students are there who study government only.

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The standard deviation for the number of people with the genetic mutation is 3.77

The given parameters are:

Sample size, n = 300

Proportion that has the particular genetic mutation, p = 5%

The standard deviation for the number of people with the genetic mutation is calculated as:

Standard deviation = √np(1 - p)

Substitute the known values in the above equation

Standard deviation = √300 * 5% * (1 - 5%)

Evaluate the product

Standard deviation = √14.25

Evaluate the exponent

Standard deviation = 3.77

Hence, the standard deviation for the number of people with the genetic mutation is 3.77

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The quartiles of the data are: 60.5,64,66

Option(b) is correct.

The quartile divides the distribution into four groups and calculates the range of values above and below the mean.

A quartile separates the dataset into four categories by dividing the data into three points: the lowest, median, and upper quartiles.

Similar to how the median divides the data in half, with 50% of the measurements falling below it and 50% falling above it, the quartile divides the data into fourths, with 25% of the measurements falling below the lower quartile, 50% falling below the median, and 75% falling below the upper quartile.

The interquartile range, a measurement of variation around the median, is calculated using quartiles.

For the given data set: 58,60,60,61,62,64,64,64,66,70,72

Median = 64

Lower quartile = Median of the lower half = 60.5

Upper quartile = Median of the upper half = 66

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Answer: If they worked together, it would take 31.5 minutes

Step-by-step explanation:

There's a certain formula for equations like this:

[tex]\frac{1}{t1} +\frac{1}{t2}=\frac{1}{tb}[/tex]

t1= the time it took for the first person to complete the task.

t2= the time it took for the second person to complete the task.

tb= the time it took for both of them to complete the task.

We have the values for both t1 and t2, but not for tb.

t1= 45

t2= 105

tb= x

[tex]\frac{1}{45} +\frac{1}{105} = \frac{1}{x}[/tex]

Now it's simple algebra, and all we need to do is solve for x

The LCM for both fractions is 315, so now we multiply BOTH sides of the equation by 315.

[tex]\frac{315}{45} + \frac{315}{105} = \frac{315}{x}[/tex]

This will simplify nicely, so now we just need to get x on the other side.[tex]7 + 3 = \frac{315}{x} \\\\\ 10*x = \frac{315}{x} * x[/tex]

[tex]10x = 315 \\\\x = 31.5[/tex]

Answer: 120

Step-by-step explanation:

There are 5 digits that are odd, 1 3 5 7 9

There are 5 possibilities for the first digit, 4 for the second, 3 for the third, and 2 for the last, so there are 5 x 4 x 3 x 2 = 120

The expression which can be used to determine the algebraic sum of the given polynomials as in the task content is; -11x² +4x +14.

It follows from the task content that the polynomials whose sum are to be determined are; (9 - 3x2) + (-8x2 + 4x + 5).

Hence, the sum can be evaluated as follows;

= 9 - 3x² + -8x² + 4x + 5

= -11x² +4x +14.

Consequently, the required expression is; -11x² +4x +14.

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Answer:

Step-by-step explanation:

is 100 for the points

Answer:

[tex]x^{\frac{1}{2} } + 48[/tex]

Step-by-step explanation:

This is hard to explain, but basically you use exponent rules to switch it to an exponent

[tex](\sqrt[4]{x^{2} +4} )^{3}[/tex]

It's easiest if you calculate [tex]4^{3}[/tex] first

4³ = 4 x 4 x 4 = 48

Then convert the root to a fraction exponent

[tex]\sqrt[4]{x^{2}} = x^{\frac{2}{4}} = x^{\frac{1}{2} }[/tex]

Combine them using addition, since addition was in the problem

[tex]x^{\frac{1}{2} } + 48[/tex]

I hope this helps!

Answer:

Perimeter o the rectangle = 16x - 2

Step-by-step explanation:

Perimeter of a rectangle = 2(long+ wide)

Then:

Perimeter = 2((6x-4)+(2x+3))

Perimeter = 2(6x+ 2x + 3 - 4)

Perimeter = 2(8x - 1)

Perimeter = 2*8x + 2*-1

Perimeter = 16x - 2

[tex]l = sec {}^{2} x - 1 \\ l = \frac{1}{cos {}^{2} x} - \frac{cos {}^{2} x}{cos {}^{2} x} \\ l = \frac{1 - cos {}^{2} x}{cos {}^{2}x } \\ l = \frac{sin {}^{2} x}{cos {}^{2} x} = ( \frac{sinx}{cosx} ) {}^{2} = tan {}^{2} x[/tex]

The required value is 8

How can we find value?

We will find the value by putting the value of w in the given function to get the required value.

We can find the value of given function foe w=2 as shown below:

Given, function is 2w+w^3-1/2w^2

Let A=2w+w^3-1/2w^2

for w=2

A=2(2)+(2)^3-1/2(2)^2

= 2+8-1/2(4)

=2+8-2

=8

Hence, the required value is 8.

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Step-by-step explanation:

volume = area of circle × hight of cylinder ....

V = πr² × h

so V = πr²h

Answer:

  10831 mm³

Step-by-step explanation:

The volume of any solid figure with a uniform cross section parallel to the base can be found using the volume formula ...

  V = Bh

where B is the area of the base, and h is the height perpendicular to the base.

The base of this cylindrical stack of pennies is a circle of diameter 19.05 mm. The area formula for a circle in terms of diameter is ...

  A = (π/4)d²

The stack of pennies has a base area of ...

  A = (π/4)(19.05 mm)² ≈ 285.023 mm²

The volume formula tells us the stack of pennies has a volume of ...

  V = Bh

  V = (285.023 mm²)(38 mm) ≈ 10830.9 mm³

The volume of the stack of pennies is approximately 10831 mm³.