Both particles could be at rest after the impact. You cannot have both things at rest.
What causes collisions and why?Distracted driving is the most frequent reason for a vehicle accident. Speeding, disobeying traffic signs, unsafe maneuvers, and operating a vehicle while inebriated or under the influence of drugs are additional risk factors for car accidents.
Which collision kinds are there?Elastic, inelastic, and entirely inelastic collisions are the three main types that can occur. To reiterate, momentum is preserved in each of the three categories of collisions. What happens to the kinetic energy is what characterizes the impacts.
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Do scientific models always have limitations?.
Yes, scientific models have limitations as it is simpler that the original objects.
Models cannot include all the info on the objects that they represent. as an instance, maps cannot consist of all of the details of the functions of the earth including mountains, valleys, and so forth. Hence they have limitations of their own respectively.
All models have barriers because they are now not representative of every feasible state of affairs. They use modern expertise and clinical statistics, but as the ones are subject to exchange, the models based totally on that know-how and statistics are a problem to alternate as properly. Scientific models always have some limitations they will never be completely accurate.
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which has the greater momentum, a concrete truck at rest or a concrete truck moving slowly up a steep hill?
Answer:
Since momentum is the product if mass and velocity therefore a concrete truck at rest has no velocity i.e mass × 0m/s = 0kg m/s
Whereas the momentum of a concrete truck slowly moving up a steep hill will defined by a given value greater than 0
determine the focal length of a lens in a camera if the film is 36.9 mm away from the lens and the object distance is 59.2 cm.
The focal length of the lens is 39.3 mm. The result is obtained by using the thin lens equation.
What is the Thin Lens Equation?The Thin Lens Equation is the equation used on a thin positive or negative lens.
[tex]\frac{1}{f} = \frac{1}{d_{1} } + \frac{1}{d_{2} }[/tex]
Where
f = focal lengthd₁ = object distanced₂ = image distanceWe have a camera with the film 36.9 mm away from the lens and the object distance is 59.2 cm. Determine the focal length!
Let's convert the object distance's unit!
59.2 cm = 592 mm
The distance of the film from the lens is the image distance. So, the focal length is
[tex]\frac{1}{f} = \frac{1}{d_{1} } + \frac{1}{d_{2} }[/tex]
[tex]\frac{1}{f} = \frac{1}{592 } + \frac{1}{36.9 }[/tex]
[tex]\frac{1}{f} = \frac{(592-36.9)}{21844.8 }[/tex]
[tex]\frac{1}{f} = \frac{555.1}{21844.8 }[/tex]
[tex]f = \frac{21844.8}{555.1}[/tex]
f = 39.3 mm
Hence, the focal length of a lens in the camera is 39.3 mm.
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what is the wavelength of an electromagnetic wave that travels at 3 x 10 m/s and has a frequency of 60 mhz? (1 mhz
An electromagnetic wave with a frequency of 60 MHz and a speed of 3 x 108 m/s has a wavelength of 5 m .
Explain about the wavelength of an electromagnetic?The wave number is given by the formula k = 2/, where is the wave's wavelength. The wave's frequency is given by the formula f = /2, where is the angular frequency.
The electromagnetic spectrum is a range of frequencies, wavelengths, and photon energies that includes frequencies between 1 hertz and over 1025 Hz and wavelengths between a few kilometers and a small portion of the size of an atomic nucleus in the spectrum of electromagnetic waves.
The radio waves Radio waves are those electromagnetic waves that have the lowest frequency and longest wavelengths.
The electromagnetic wave's wavelength can be determined using the following formula:
If =v/f, then
V is the speed.
The frequency is f.
given the aforementioned variables
f = 60 MHz = 60 000 000 Hz
v = 3 x 10 m/s
= 3 x 10 /6
=5
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What is 20 miles per hour in feet per second? round to the nearest tenth if necessary.
29.33 ft/sec is speed in feet per second.
20 miles= 105600 ft
1 hour= 3600 second
speed= distance/time
speed=105600/3600
speed=29.33 ft/sec
It is possible to express how much an object's location shifts over time or how much it shifts per unit of time using a scalar variable called speed. It is frequently abbreviated to "s." The distance traveled by an object divided by the duration of the period gives the average speed of the object over the period.
The speed-related metric is time divided by distance. While the meter per second (m/s) is the SI unit of speed, the kilometer per hour (kph) is the most widely used unit in daily life (kph).
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Answer:
figure itout 20
Explanation:
20 -0
a raft with a mass 50 kg and a volume of 0.250 m3 has a weight placed on top of it. how much mass does the weight have to have so that the raft is just barely submerged in pure water
The weight placed on top of the raft so that the raft is barely submerged in pure water is 200Kg.
Mass of raft (mₓ) = 50Kg
Volume of raft (V) = 0.250 m³
Density of pure water (d) = 1000 Kg/m³
Let, weight placed on top of the raft be = m
Using Archimedes Principle and Buoyant Force,
= mg + mₓ × g = V × d × g
= mg + 50 × g = 0.250 × 1000 × g
Taking g common on both sides
= g (m+50) = g(0.250 × 1000)
= m+50 = 250
= m = 200Kg
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What is the wavelength of a sound wave with a frequency of 500 Hz?.
The wavelength of sound wave is 0.662 m.
The wavelength of a wave, specifically the points of an electromagnetic wave, is the separation between successive crests. The relationship between wavelength and frequency is close. The wavelength gets shorter the higher the frequency.
We are given that,
Frequency = f = 500hz
Speed of sound = v = 331.2m/s
Thus to calculate the wavelength of sound by the formula,
λ = v/f
λ = (331.2 m/s) / (500 Hz)
λ = 0.662m
Therefore, the wavelength of sound wave would be 0.662 m.
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what is the volume flow rate through the nozzle in l/min ? assume that the water level in the tank is held constant. express your answer in liters per minute.
The volume flow rate through the nozzle in l/min is the amount ( in liter) of fluid travelling through a specific cross sectional area in a unit of time (in minute).
What is volume flow rate?Volume flow rate may sound dull to you when you first hear it, but it is what keeps you alive. In a moment, I'll explain how, but let's first establish volume flow rate. The amount of fluid travelling through a specific cross sectional area in a unit of time is known as the volume flow rate of a fluid. The region across which something is flowing is frequently described using the fancy term "cross sectional area."
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gram shows how entropy varies with temperature for a substance that is a gas at the highest temperature shown. a plot of entropy on the y axis versus the temperature in kelvin on the x axis. the entropy and the temperature are initially 0. as the temperature increases, the entropy increases linearly. at a point some distance from the initial point, the entropy increases as the temperature remains constant. this portion is labeled 1. the entropy then continues to increases linearly as the temperature increases. at a third point some distance from the second point, the entropy again increases as the temperature remains constant. this portion is labeled 2. the entropy then increases linearly again as the temperature increases. segment 2 is larger than segment 1. what process corresponds to the entropy increase along the vertical segment labeled 1? the melting of the solid substance to a liquid. the boiling of the liquid substance to a gas. the warming of the liquid substance to its boiling point. the warming of the gaseous substance to its final temperature. the warming of the solid substance to its melting point.
Studying the graph of entropy and temperature, we get,
1. The process corresponds to the entropy increase along the vertical segment labeled 1 is The melting point of the solid substance to a liquid.
2. The process corresponds to the entropy increase along the vertical segment labeled 2 is The boiling point of the liquid substance to a gas.
3. The entropy change for segment 2 is larger than that of segment 1 because the difference in entropy between the gas state and the liquid state is greater than the entropy differences between the solid and liquid states.
Entropy: It is a way to gauge how random something is.
Entropy is the measurement of the amount of thermal energy per unit of temperature in a system that cannot be used for productive work. Entropy is a measure of a system's molecular disorder or unpredictability since work is produced by organized molecular motion.
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A 4.0-kg mass is placed at (3.0, 4.0) m, and a 6.0-kg mass is placed at (3.0, -4.0) m. what is the moment of inertia of this system of masses about the z-axis?
The moment of inertia of this system of masses about the z-axis is 99 kg[tex]m^{2}[/tex].
Given,
Mass of first object, [tex]m_{1}[/tex] = 4 kg at (3, 4) m
Mass of second object, [tex]m_{2}[/tex] = 6 kg at 3, -4) m
The moment of inertia (I) of a system of particles is given as,
I = [tex]m_{i}x_{i} ^{2}[/tex]
Here, I = [tex]m_{1}x_{1} ^{2}[/tex] + [tex]m_{2}x_{2} ^{2}[/tex]
Moment of inertia, I = (4×[tex]3^{2}[/tex] )+ (6×[tex]3^{2}[/tex])
= (5×9) + (6×9)
= 45 + 54
I = 99 kg[tex]m^{2}[/tex]
Hence, the moment of inertia will be 99 kg[tex]m^{2}[/tex].
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Constants Part A A string is wrapped several times around the rim of a small hoop with a radius of 0.0800 m and a mass of 0.190 kg. The free end of the string is held in place and the hoop is released from rest (see Figure 1)). Calculate the angular speed of the rotating hoop after it has descended 0.550 m Express your answer in radians per second to three significant figures. Figure < 1of1 4.104 rad/s Submit Previous Answers Request Answer X Incorrect: Try Again; 5 attempts remaining 0.0800 m
Previous question
After descending 0.550 m, the rotating hoop moves at a angular speed of 2.3 m/s for a Part A. A little hoop with a radius of 0.0800 m and a mass of 0.190 kg has its rim wrapped in a string multiple times.
As we can see, angular speed is the rate at which an object changes its angles over time, as measured in radians. For angular speed, there is simply a magnitude (a value). It's vital to remember that angular velocity and angular speed both employ the same formula.
In classical geometry, a circle's or sphere's radius (PL: radii) is any line segment that connects the object's Centre to its perimeter; in more contemporary usage, it is also the length of those line segments. Is called as radius.
MR^2 W^2 = Mgy1
W = (Gy1)^1/2/R
W =( (9.80)(0.550))^1/2/0.0800M =29.02 rad/sec
v = Rw = (0.0800*29.01) = 2.3m/s
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The range of cannon ball fired horizontally from laboratory table i equal to 8/3*the hight of the table what i the direction of the velocity of the projectile a it trike the ground?(from horizontal)
The direction of the velocity of the projectile a it trike the ground is 63.43°.
What is velocity?
A body's or an object's motion's direction. Speed is fundamentally a scalar quantity. Velocity is a vector quantity in its purest form. It refers to the rate at which distance varies. It is the rate of displacement change.
What is height?
Height is a measurement of vertical distance, or how high something or someone is (how tall they are) (how "high" a point is).
The range ( X) of cannon ball is equal to height (h) of the cliff, which is initial height of cannon ball.
∴ X= h
Therefore, the angle which final velocity vector of the cannon ball makes with and below horizontal is given by
θ= tan ⁻¹ (2h/x)
tan ⁻¹ (2h/h) (∴ X= h)
= tan ⁻¹ 2
≈ 63.43°
Therefore, the direction of the velocity of the projectile a it trike the ground is 63.43°.
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On the surface of planet x, a body with a mass of 10. Kilograms weighs 40. Newtons. The magnitude of the acceleration due to gravity on the surface of planet x is.
The acceleration due to gravity on the surface of planet X is 4 N/kg.
What is acceleration due to gravity?Acceleration due to gravity is the acceleration gained by an object due to gravitational force.
To calculate the magnitude of the acceleration due to gravity on the surce of planet X, we use the formula below.
Formula:
g = W/m............ Equation 1Where:
g = Acceleration due to gravity of the bodyW = Weight of the bodym = Mass of the body.From the question,
Given:
W = 40 Newtonsm = 10 kilogramsSubstitute these values into equation 1
g = 40/10g = 4 N/kgHence, the acceleration due to gravity is 4 N/kg.
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remarks notice the use of 2.01 m in the denominator of the last calculation, rather than 2.00 m. this is because, in effect, the strut was compressed back to the original length from the length to which it would have expanded. (the difference is negligible, however.) the answer exceeds the ultimate compressive strength of steel and underscores the importance of allowing for thermal expansion. of course, it's likely the strut would bend, relieving some of the stress (creating some shear stress in the process). finally, if the strut is attached at both ends by bolts, thermal expansion and contraction would exert sheer stresses on the bolts, possibly weakening or loosening them over time. question which of the following combinations of properties will result in the smallest expansion of a substance due to the absorption of a given amount q of thermal energy? small specific heat, large coefficient of expansion small specific heat, small coefficient of expansion large specific heat, small coefficient of expansion large specific heat, large coefficient of expansion practice it use the worked example above to help you solve this problem. a steel strut near a ship's furnace is 1.90 m long, with a mass of 1.67 kg and a cross-sectional area of 1.00 10-4 m2. during operation of the furnace, the strut absorbs thermal energy in a net amount of 2.50 105 j. (a) find the change in temperature of the strut.
To find the change in temperature of the strut, we need to use the equation for the heat capacity of a solid:
q = C * m * ΔT
Where q is the amount of thermal energy absorbed by the strut, C is the specific heat capacity of steel, m is the mass of the strut, and ΔT is the change in temperature of the strut. Substituting the given values into the equation, we get:
2.50 105 j = 0.47 J/g*C * 1.67 kg * ΔT
Solving for ΔT, we get:
ΔT = (2.50 105 j) / (0.47 J/gC * 1.67 kg) = 461.37 gC
The change in temperature of the strut is 461.37 g*C.
To find the expansion of the strut due to the absorption of thermal energy, we need to use the equation for thermal expansion:
ΔL = L * α * ΔT
Where ΔL is the change in length of the strut, L is the original length of the strut, α is the coefficient of thermal expansion of steel, and ΔT is the change in temperature of the strut. Substituting the given values into the equation, we get:
ΔL = 1.90 m * 1.2 10-5/C * 461.37 g*C = 0.0011 m
The expansion of the strut due to the absorption of thermal energy is 0.0011 m.
To find the compressive stress on the strut, we need to use the equation for stress:
σ = F / A
Where σ is the compressive stress on the strut, F is the compressive force on the strut, and A is the cross-sectional area of the strut. Since the strut is attached at both ends and is not allowed to move, the compressive force on the strut is equal to the force due to the thermal expansion of the strut:
F = k * ΔL
Where k is the spring constant of the strut, which is determined by the stiffness of the strut and its attachment points. Substituting this expression for F into the equation for stress, we get:
σ = (k * ΔL) / A
Substituting the given values into the equation, we get:
σ = (k * 0.0011 m) / (1.00 10-4 m2) = 11.00 kN/m2
The compressive stress on the strut is 11.00 kN/m2.
The smallest expansion of a substance due to the absorption of a given amount of thermal energy will occur when the substance has a small specific heat capacity and a small coefficient of thermal expansion.
This is because a small specific heat capacity means that the substance requires less thermal energy to raise its temperature by a given amount, and a small coefficient of thermal expansion means that the substance will experience less expansion per unit increase in temperature.
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in march 1958, fluorescent dye was injected into the northernmost of the blue sinks. it was detected 28 hr. later in sulphur springs on the hillsborough river to the south (see sketch map). use these data to calculate the approximate velocity of flow in this portion of the floridan aquifer system (show your work): 1. in feet/hour: 2. in miles/hour: 3. in meters/hour:
The Floridan aquifer system's approximate Velocity flow rate in this area
1. in feet/hour - 440 feet/hour
2. in miles/hour - 0.083 miles/hour
3. in meters/hour - 134.11 meters/hour
According to the computer display:
1 mile on the ground equals 1.2 cm on the map.
Distance between Blue sinks (as marked by you) and Sulphur springs = 2.8 cm
Then, 2.8 cm on the map = (1/1.2)*2.8 miles = 2.33 miles
Now,
The velocity of flow in Floridan Aquifer = distance/time = 2.33 miles/ 28 hours = 0.083 miles per hour
Velocity in feet per hour = 0.083*5280 feet/hour = 440 feet/hour
Velocity in meters per hour = 0.083 * 1609.344 meters/hour = 134.11 meters/hour.
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How many SCP sites are there?.
As of August 2021, there are approximately 6,600 articles about SCP objects. New articles are often written by contributors.
Site-19 is an SCP Foundation facility and currently the largest operating site. It houses hundreds of Safe and Euclid class SCPs and is the most famous of the many locations under Foundation control. The foundation maintains and operates numerous facilities around the world, from small outposts with only a few employees to large complexes with thousands of employees.
Site-17 is known for containing a large team of medical and psychiatric professionals to deal with the complex nature of many SCPs. Site-17's exact location on Earth is unknown outside of Headcanon. There is a theory that SCP-096 was created as a result of SCP-1529. The theory is that 096 was once a climber trying to climb a mountain.
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Answer:
88
Explanation:
 Option analysis involves gathering significant amounts of information, synthesizing the data, and using the data in models applied in option analysis Consider the case of Smith and Thomas Co Smith and Thomas Co. is considering a project for a new cloud-based online storage system for companies and individuals to back up their data. The cost of the project is exist45 million, but the future cash flows depend on how this new cloud-based online storage will compete with existing companies that offer online data backup The company believes that this project has a strong selling feature but is uncertain that it would earn cash flows as projected. The team proposing this project has come up with the following data: The project team also noted that the company has an option to wait for one year in order to see its competitors' positions and observe how the market responds. This will help in getting more information about market demand and in figuring out which set of cash flows will occur Analysts used different approaches to evaluate the project, but the management team insists that the Black-Scholes option pricing model (OPM) will help them make a more informed decision. The model requires five inputs (1) the risk-free rate (2) the time until the option expires: (3) the strike price: (4) the current price of the stock, which in this case would be a proxy for the value of the underlying asset: and (5) the variance of the project's expected return You need to calculate both the value of the underlying asset in the project and its rate of return. For smith and The mass Co., the underlying asset is the project itself. The current value of the project will be the value of its expected cash flows resin Based on the data given, calculate the value of the project, its return, and the standard deviation of the returns (using the direct method) if the company decides to wait for a year. (Cash flow values in the table are in millions.) Analysts will use these values in the Black-Scholes model, which is represented by the following formula: Based on the data collected and results from the calculations, estimate the input values to be used in the Black-Scholes OPM:
1. Risk-free rate 5%
2. Time until the option expires 4 yrs.
3. Strike price: $ 45mn.
4. For calculating project value & standard deviation, we need to fill in the inputs in the below table. For calculating the PV of cash flows, use discounting rate of 13%. Standard deviation: stdev(5.85,4.55,2.6) = 1.64%
5. Sum of expected cash flows at t = 0: 37.61+18.28+4.18 = $ 60.07
The above-numbered figures are the inputs for the Black Scholes model.
The Black-Scholes model is used to determine the fair value of options contracts. This formula can estimate how the price of financial instruments such as futures and stocks change over time. Black-Scholes is used to determine the fair or theoretical value of a call or put option based on six variables including volatility option type underlying price time strike price and the risk-free rate pricing model.
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Radio wave from pace are gathered and reflected toward the focal point where the receiver receive them, and wave are tranmitted to the recording device
Radio waves from the pace are gathered and reflected toward the focal point where the receiver receives them, and waves are transmitted to the recording device the same radio source is being watched by two radio telescopes. On the ground, there is a known separation between the telescopes. As a result, the radio waves from the source will reach each telescope at a little different time. The waves appear slightly differently, with one arriving a little bit later than the other. The difference is a shift in the wave's phase over time.
Due to their phase shift, the two offset waves will not precisely overlap when combined, leading to interference fringes. The angles of their observations shift as the Earth rotates and the telescopes tilt to continue monitoring their source setting.
Similar to how shadows are longer when the Sun is lower, this tracking movement of the telescopes alters the distances that radio light travels from the source to each telescope. This results in various phase delays for the waves as they approach each telescope. The more variables we see, the longer we observe. We have more viewpoints on the object we're watching the more variants there are.
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why does nuclear fusion require high temperatures and high densities? (select all that apply.)
The nuclear fusion reaction occurs at temperatures approximately 107 degrees Celsius. It takes this high temperature for the nuclei to begin travelling at high speeds, increasing their kinetic energy.
Why are high temperatures required for nuclear fusion?Nuclear fusion is a nuclear reaction that occurs when two light nuclei collide to form a single, heavier nucleus. Because the mass of the new nucleus is smaller than the sum of the original masses, fusion releases energy. According to the concept of mass-energy equivalence, this mass difference indicates that some of the "lost" mass has been turned into energy. Fusion necessitates both extremely high temperatures in order to provide enough energy to hydrogen atoms to overcome proton repulsion. Microwaves or lasers must be employed to heat hydrogen atoms to the required temperatures.
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we actually made an approximation in this lab that the tension (force pulling the cart) is equal to the weight of the washers. make a fbd and write an equation for the washers as they accelerate. based on that equation, explain why is it a reasonable approximation.
The tension (force pulling the cart) is equal to the weight (W) of the washers.
According to the Newton's second law of motion force exerted on a object is directly proportional to the rate of change of momentum and can be written as:
F = [tex]\frac{dp}{dt}[/tex]
Or, F = ma
Where mass multiplied with acceleration due to gravity (a=g) can also be represented as Weight (W) of the object.
So, F = Weight of the object (W)
Hence, the tension (force pulling the cart) is equal to the weight of the washers.
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suppose a popular fm radio station broadcasts radio waves with a frequency of 104 mhz . calculate the wavelength of these radio waves.
The wavelength of these radio waves are 2.88 m
What are radio waves ?In the electromagnetic spectrum, radio waves have the longest wavelengths. These waves, which fall under the category of electromagnetic radiation, range in frequency from 300 GHz to 3 kHz, though they are sometimes classified as microwaves above 3 GHz.
The given frequency is 104 mhz
Any radiation in the electromagnetic spectrum, including radio waves, travels at a speed of 3.00 x 10^8 m/s in vacuum.
Consequently, the following equation can be used to determine the wavelength:
c = wavelength × frequency
frequency is given in mHz thus we convert it into Hz
and get 104 × 10 ^6
this implies
wavelength = [tex]\frac{3 X 10^8}{104 X 10^6}[/tex]
wavelength = 0.0288× [tex]10^{2}[/tex] m
= 2.88 m
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Simple Way to Measure Magnetic Fields The induced emf in the loop is measured to be V. What is the magnitude B of the magnetic field that the loop was in? Express your answer in terms of some or all of the variables A, C, and V. A loop of wire is at the edge of a region of space containing a uniform magnetic field B. The plane of the loop is perpendicular to the magnetic field. Now the loop is pulled out of this region in such a way that the area A of the coil inside the magnetic field region is dA decreasing at the constant rate c. That is, -C, with c > 0. For the case of a square loop of side length L being pulled out of the magnetic field with constant speed v (see the figure), what is the rate of change of area dA с
The Value of the Magnetic Field (B) is V/c
a)Induced Emf in the loop is given
[tex]V = -\frac{d\phi }{dt}[/tex]
since [tex]\phi =BA[/tex]
[tex]V=-\frac{d}{dt}(BA)=-B\frac{dA}{dt}[/tex]
given dA/dt = -c
V=-B(-c)=Bc
=>[tex]B=\frac{V}{c}[/tex]
b) since induced emf V=BLv
B=(BLv)/c
c=Lv
The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is moving through a magnetic field. Nearly a magnetic dipole, the Earth's magnetic field (and surface magnetic field) has two poles, one at the planet's geographic north pole (see Magnetic North Pole) and the other near its geographic south pole (see Magnetic South Pole).
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Sam, whose mass is 75 kg, straps on his skis and starts down a 50-m-high, 20 ^\circ frictionless slope. A strong headwind exerts a horizontal force of 200 N on him as he skies.
a)Find Sam's speed at the bottom using work and energy.
b)Find Sam's speed at the bottom using Newton's laws.
Thanks!
Sam's speed at the bottom is computed using the Work-Energy Theorem is 15.73m/s.
Sam is moving at a speed of 15.73 m/s near the base of the inclination plane.
Sam's weight is 75 kg, and his height is 50 metres. The slope's inclination is 200 degrees, and its horizontal force is 200 N.
The following formula is used to compute Sam's gravitational potential;
P.E = mgh
P.E = 75 x 9.8 x 50
P.E = 36,750
Friction's work is estimated as follows;
W=F x d
The following formula is used to determine Sam's horizontal distance:
d = 50/tan20,
d = 137.35 metres.
Friction's work is estimated as follows;
W = 200 x 137.36
W = 27,472 J
Sam's speed at the bottom is computed using the Work-Energy Theorem as follows;
W = K.E
36750 - 27472 = 1/2 x 75 x (v)2 - (0)2
v= 15.73m/s
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Water emerges straight down from a faucet with a 1.80-cm diameter at a speed of 0.500 m/s. (Because of the construction of the faucet, there is no variation in speed across the stream.) (a) What is the flow rate in cm3 /s ? (b) What is the diameter of the stream 0.200 m below the faucet? Neglect any effects due to surface tension.
The flow rate of the faucet is 127.23 cm²/s and diameter below the faucet is 1.88 cm.
For calculating the flow rate, we will use the formula -
Q = Ar
A = πr², were Q is flow rate, A is area and r is radius.
Also, radius = diameter/2
Radius = 1.8/2
Radius = 0.9 cm
Speed = 50 cm/s
Q = πr²v
Q = 3.14×0.9²×50
Q = 127.23 cm²/s
The diameter of stream will be calculated by the formula -
[tex] v_{f}[/tex]² - [tex] v_{i}[/tex]² = 2gy, where [tex] v_{f}[/tex] is final velocity, [tex] v_{f}[/tex] is initial velocity, g is acceleration due to gravity and y is diameter of stream.
[tex] v_{f}[/tex] = ✓50² - 2×9.8×20
[tex] v_{f}[/tex] = ✓2500 - 392
[tex] v_{f}[/tex] = ✓2108
[tex] v_{f}[/tex] = 45.9 cm/s
r = ✓Q/πv
r = ✓127.23/3.14 × 45.9
r = ✓127.23/144.2
r = ✓0.88
r = 0.93 cm
d = 2r
d = 2×0.93
d = 1.88 cm
Thus, flow rate is 127.23 cm²/s and diameter is 1.88 cm.
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a potter's wheel is spinning with an initial angular velocity of 14 rad/s . it rotates through an angle of 80.0 rad in the process of coming to rest.
The factors remain unrealistic and constant Centre of mass and gravity.
Given - The initial angular velocity is 14rad/s with an angle of rotation is 80rad.
To find out the distance formula.
[tex]Wo-w=\frac{x}{rotation}---[1]\\ \\Q=\frac{1}{4\pi \alpha \beta } -------[2][/tex]
The Rotational effect of wheel has a displacement with angle factor.
The velocity breaking and reducing the speed.
[tex]Q= \lim_{w \to \infty} W_o-w[/tex]
[tex]w=\pi \alpha +Q\\\\w-Q=\alpha \\\\w-Q=\left \{ {{y=x} \atop {y\neq x}} \right.[/tex]
The effect reduced to the decrement in displacement .
This is results in constant angle shift and uniform motion.
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If you are lying down and stand up quickly, you can get dizzy or feel faint. This is because the blood vessels don't have time to expand to compensate for the blood pressure drop. If your brain is 0.4 m higher than your heart when you are standing, how much lower is your blood pressure at your brain than it is at your heart? The density of blood plasma is about 1025 kg/m3 and suppose your maximum (systolic) pressure of the blood at the heart is 116.4 mm of Hg (Note that 120 mm of Hg = 16 kP = 1.6 x 104 N/m2). Since most doctors still use mm of Hg, give your result in those units.
91.655 mm of Hg pressure is lower when our blood pressure at brain than it is at your heart.
pressure at brain= 121.8-30.135
pressure=91.655 mm Hg
Pressure is defined as force/area. To demonstrate the pressure from snow on a roof, divide the weight of the snow by the surface area of the roof. Gases are a typical pressure source in physics. A "vacuum" is used to describe the lack of pressure. Humans have long held the belief that vacuums are both improbably rare and unnatural since "nature abhors a vacuum." Actually, this is not the case.
The number of pressure units is ridiculous. It's common to use the torr or mmHg unit. This discussion is solely focused on the height of a mercury column. The atmosphere contains 760 torr, or mmHg. You could also look at mmH2O, which makes use of a comparable idea.
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assume that light is incident normal to the surface of a film of thickness d . how much farther does the light reflected from the back surface travel than the light reflected from the front surface? express your answer in terms of d .
Therefore the difference in the optical path between the reflected ray on the surface and the end film is Λ = 2 t.
Light or seen mild is electromagnetic radiation that may be perceived by means of the human eye. seen mild is typically defined as having wavelengths inside the range of 400 seven hundred nanometres, corresponding to frequencies of 750420 terahertz, among the infrared and the ultraviolet.
As an adjective, mild is something that is not heavy, burdensome, or somber. A knapsack may be mild, as should a topic of verbal exchange, or a chunk of tune. as an instance, The manner is long, however, the burden is light.
Inside the Bible, mild has continually been an image of holiness, goodness, expertise, information, grace, hope, and God's revelation. via evaluation, darkness has been associated with evil, sin, and despair.
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A 1500 kg elevator, suspended by a single cable with tension 16.0 kN, is measured to be moving upward at 1.2 m/s. Air resistance is negligible.1. We want to find the elevator’s speed after traveling upward 10.0 m. This could be solved with Newton's laws and kinematics, but we will use the energy principle. How much work does tension do on the elevator as it rises 10.0 m?2. How much work does gravity do on the elevator as it rises 10.0 m?3. What is the elevator's kinetic energy after rising 10.0 m?4. What is the elevator's speed after rising 10.0 m?
Tension in the Cable is 0.87 m/s6^2, Elevator's speed after it has moved 10m is 1.6*10^5 N, Work done by gravity is 1.47 * 10^3 N, Elevator Kinetic Energy is 13897.5J and Elevator Speed after rising to 10m is 4.312 m/s.
Tension is a pulling force that operates in one dimension along the cables' axes in the opposite direction from the direction of the applied force. The combined weight of the elevator box and the passenger riding inside it, in the case of an elevator, provides the pulling force in the cables is called Tension.
A moving object or particle's kinetic energy, which depends on both mass and speed, is one of its characteristics. The type of motion can be vibration, translation, rotation around an axis, or any combination of these. Kinetic energy is a type of energy that an item or particle possesses as a result of motion.
We know that,
Tension in the Cable
T = m(g+a) = g+a = T/m = 16 * 103 / 1500 = 10.67 m/s2
a = 10.67 - 9.8 = 0.87 m/s6^2
Elevator's speed after it has moved 10m.
U^2 = u^2 +2as
= 1.22 +2*0.87*10
=1.6*10^5 N
Work done by gravity = mg * 10 = 14700 * 10 = 1.47 * 10^3 N
Elevator Kinetic Energy = 1/2 mv^2 = 1/2*1500*18.53 = 13897.5J
Elevator Speed after rising to 10m ,
U^2 = u^2 +2as = 1.2 +2*0.87*10 = 18.6
U =(18.6)^1/2=4.312 m/s
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Stephen drove from manchester to oxford. He drove at an average speed of 60 miles per hour, for two and a half hours. How far did he drive?.
He drives to a distance of 30 miles
1 h = 60 min
60 mph/ 60 min = 1 mph per minute
1h/2 = 30 min (only half an hour)
30 x 1 (mph) = 30
What is average speed ?Velocity is the direction speed of an object in motion as a measure of the rate at which its position is changing as seen from a specific point of view and as measured by a specific unit of time.
The total distance travelled by the object in a specific amount of time is its average speed. A scalar quantity, average speed, exists. The magnitude serves as its representation, and it lacks direction.
Speed is a scalar quantity that describes how quickly an object travels over space. The ratio of distance to time, which is a scalar quantity, is the average speed.
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Will an empty plate heat up in the microwave?.
No, empty plate doesn't get heated up in the microwave.
This is because the microwave oven heats the food by heating the water molecules that compose it.
This is achieved by increasing the vibration amplitude of the water molecules and their kinetic energy, therefore, increasing their temperature.
So, if the element that gets into the microwave oven does not contain water (as is the case of an empty paper plate), it will not heat up.
Therefore, this is all about the transfer of energy. This the principle on which microwave works. The transfer of heat energy from one object to the other increases the kinetic energy of the particle of the other object. But no object mean no heat energy transfer and the plate isn't heated.
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