you are testing a new car using crash test dummies. consider two ways to slow the car from 90 km/h (56 mi/h) to a complete stop: (i) you let the car slam into a wall, bringing it to a sudden stop. (ii) you let the car plow into a giant tub of gelatin so that it comes to a gradual halt. in which case is there a greater impulse of the net force on the car?

Answers

Answer 1

In a car crash test, whether you let the car slam the wall or let the car plow into a tub of gelatin, the impulses are the same. However, you and your car will experienced greater force if the car slam the wall.

The impulse is defined as the change in momentum.

I = Δp = m . Δv

Where:

I = impulse

p = momentum

m = mass

v = velocity / speed.

From the Newton's second law of motion:

m = F/a

Where:

F = force

a = acceleration

Hence,

I = F / a . Δv

I = F . Δv/a = F . t

Where t = time period of the exerted force.

The initial and the final velocities of the car are the same for both cases. Hence, from the definition of impulse as the change of momentum, the impulses on both cases are the same. However, if the car experienced sudden stop, which means the force exerted on it in only a very short time, the exerted force on the car will be very large.

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Related Questions

an engineer is working on determining the speed limit for a curved stretch of road. she knows the coefficient of friction between the wheels and the road is 0.7 when the road is dry and 0.3 when the road is wet. she also knows that the mass of the vehicle does not matter, but completes her calculations for a 700kg car. in order to set a speed limit that is safe under any conditions, should she perform her calculations with the coefficient of friction for wet or dry pavement?

Answers

The speed limit for a curved stretch of road with the coefficient of friction between the wheels and the road is 0.7 when the road is dry and 0.3 when the road is wet is √ 2.94 r m / s

Fc = m ac

Ff = μ N

N = m g

Fc = Centripetal force

m = Mass

ac = Centripetal acceleration

Ff = Frictional force

μ = Co-efficient of friction

N = Normal force

μ = 0.3 ( Wet value to taken to provide zero skidding under any condition)

g = 9.8 m / s²

The only force that is providing the centripetal force is frictional force.

m ac = μ m g

ac = 0.3 * 9.8

ac = 2.94 m / s²

ac = v² / r

2.94 = v² / r

v = √ 2.94 r m / s

Therefore, the speed limit for the curved stretch of road is √ 2.94 r m / s. She should perform her calculations with the coefficient of friction for wet pavement.

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why the heliocentric theory of the solar system came to be regarded as preferable to the geocentric theory

Answers

Copernicus adopted the heliocentric view because it better explained the movements of the heavens mathematically.


Copernicus' heliocentrism could eliminate Ptolemy's epicycles because retrograde motion could be seen as the result of a combination of Earth and planetary motions and velocities.


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You are skiing and you push off from the top of the hill, giving yourself an initial velocity of 1 m/s. You accelerate down the hill at a rate of 2 m/s/s. What will your speed be after 10 seconds? How far will you have traveled after 10 seconds?

Answers

Using Equations of motion, speed after 10 seconds will be 21 m/s and the distance travelled after 10 seconds will be 110 m.

What are  Equations of motion?

Equations of motion are thought of as the relationships that assist us in relating the physical quantities, such as distance traveled, time spent traveling there, acceleration, and initial and final velocities.

First equation of motion

The velocity-time relation is the name given to the fundamental equation of motion, v = u + at.

Second equation of motion

The position-time relation can be defined as s = ut + 1 / 2at2 in the second equation of motion.

Third equation of motion

v2 = u2+ 2as, the position-velocity relation, is the third equation of motion.

Given,  initial velocity, u = 1 m/s

            acceleration, a = 2 m/s/s

            time = 10 s

Using First equation of motion, we find the speed after 10 seconds.

v = u + at

v = 1 + 2 x10

v = 1 + 20

v = 21 m/s

Using Second equation of motion, we find the distance travelled after 10 seconds,

s = ut + 1 / 2at2

s = 1 x 10 + ( 2 x 10 x 10)/2

s = 10 + 100

s = 110 m.

Hence, after 10 seconds speed will be 21 m/s and distance will be 110 m.

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What is the correct order of the planets in the solar system, starting closest to the sun?.

Answers

Answer:

Mercury

Venus

Earth

Mars

Jupiter

Saturn

Uranus

Neptune

and then drawf planets

consider a cube with a mass of 500 kg and sides of 50 cm. calculate the pressure on the floor from such a cube.

Answers

The pressure applied by the cube of mass 500 kg and side 50 cm on the floor is 200000 Pascal

The mass of the cube is 500 kg and the side of the cube is 50 cm.

Converting the side of the cube from cm to m.

The side of the cube is 0.5 m.

The pressure applied by any body is given by the force applied by the body divided by the area on which the force is applied.

Pressure = force/area

The force applied by the cube will be equal to the weight of the cube,

The weight of the cube is 5000 Newton.

The area of only one side of the cube is in contact with the floor so the area is,

Area = 0.025 m

Putting values,

P = 5000/0.025

P = 200000 Pascal.

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Gabe is designing a flashlight that uses a parabolic reflecting mirror and a light source. the shape of the mirror can be modeled by a parabola that opens upward with a diameter of 4 in. and a depth of 1 in. the vertex of the parabola is at the origin. where should gabe place the bulb to ensure a perfect beam of light? (0, 1) (0, 4) (1, 0) (4, 0)

Answers

Gabe should place the bulb to ensure a perfect beam of light at (C) (1,0).

A reflective surface used to gather or project energy like light, sound, or radio waves is known as a parabolic, paraboloid, or paraboloidal reflector, dish, or mirror. Its form is a component of a circular paraboloid or the surface produced by a parabola rotating around its axis.

Suppose the equation of parabolic mirror is Y2 = 4ax

The given data in the problem is x = 1 and y = 2

So the subject value is y2 = 4ax

4 = 4 a (1)

4 = 4a

a = 1

So  x = 1

thus focus is at  (x, y) = (1,0)

Thus option C is the correct answer.

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other than 120 and 240 volts, what is another common voltage used inside a building? i. 208 ii. 277 iii. 480

Answers

Other than 120 and 240 volts, what is another common voltage used inside a building is 208,277and 480volts.

What is the standard input voltage?

When the same signal is applied to the IN(+) and IN(-) terminals of an op-amp, it must operate satisfactorily within a range of input voltages known as the common-mode input voltage (CMVIN), which is described in the datasheet of the device. You may think of it as never applying common-mode signals to an op-amp.

The voltage shared by an electrical device's two input terminals is known as a common-mode signal. The common-mode signal on a transmission line in telecommunications is also referred to as longitudinal voltage. The signal is typically transmitted between two conductors using a differential voltage in electrical circuits.

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ultraviolet radiation falls in the wavelength region of 1.00 * 10^-8 to 1.00*10^-7 meters. what is the wavelength of ultraviolet radiation that has an energy of 1.99*10^-20 kj/photon? wavelength

Answers

The wavelength of ultraviolet radiation that has an energy of 1.99*10^-20 kj/photon  is 3.00 x 1016 sec-1.

How to find the wavelength of ultraviolet radiation?

Frequency = speed of light divided by wavelength

wavelength times the speed of light to calculate frequency.

F = c/ = (1.00 x 10^-8 m) / (3.00 x 108 m/s) = 3.00 x 1016 sec-1

When calculating light energy, we require the following two equations:

E = hv, where h = Planck's constant (see below), v = frequency in Hz, and E = energy of a photon of light.

c =, where = wavelength in m, = frequency in Hz, and c = speed of light (3x108 m/sec).

When these two equations are rearranged, we obtain

We will apply the equation E = hc/ to resolve the current issue.

h = 6.626 x 10 – 34 Jsec

c = 3 x 10 ^8 m/s

λ = 1.00 * 10^^7 m

E = (1.00x10-8 m)/(6.626x10-34 Jsec)(3x108 m/sec)

E = 1.99x10-20 kJ/photon x 1 kJ/103 J, or 1.99x10-20 J/photon per photon.

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If a car, with an initial velocity of 15 m/s, accelerates at a rate of 5 m/s^2 for 4 seconds, what will its final velocity be? ​

Answers

Answer:

35 m/s

Explanation:

vf = vo + at

vf = 15  +  5(4) = 35 m/s

a 10 kg ball is tied to a 7 meter long string. the ball is spun in a circle with a constant speed. the maximum tension allowed in the string before it breaks is 100 n. (a)if spun in a horizontal circle, what is the maximum speed the mass can attain?

Answers

The highest rate of speed a person can reach is called maximum speed.When athletes alter the magnitude or direction of their motion, or both.

What is the maximum speed the mass can attain?

The maximum speed the stone can attain is 8.366 m/s

Data;

   Mass = 10kg

   radius of tangential path = 7m

   Tension = 100N

Centripetal Force

The centripetal force of the stone can be calculated as

Fe =mv/r

v² = Tr/m

v=√Tr/m

v=√100*7/10

v=8.366 m/s

The tension acting on the string is given as

The maximum speed the stone can attain is 8.366m/s

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world-class sprinters can accelerate out of the starting blocks with an acceleration that is nearly horizontal and has magnitude 15 m/s^2. how much horizontal force f must a sprinter of mass 60 kg exert on the starting blocks to produce this acceleration?

Answers

The force exerted by the sprinter who is having a mass of 60 kg and accelerating at 15 m/s² is 900 N

The acceleration of the sprinter is 15 m/s²

The mass of the sprinter is 60 kg

The force exerted by the printer can be found using the formula,

                 F = ma

where F is the force exerted by the sprinter

          m is the mass of the sprinter

          a is the acceleration of the sprinter

Let us substitute the known values in the above equation, we get        

                          F = 60 x 15

                             = 900 N

Therefore, the force exerted is 900 N

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the product of a force and the perpendicular distance from the force's line of action to the axis of rotation is known as

Answers

The product of a force and the perpendicular distance from the force's line of action to the axis of rotation is known as Torque.

Torque or moment of the force is the term used to describe a force's ability to turn.

The moment arm is the length that separates the line of action perpendicular to the axis of rotation. Torque is a mathematical combination of force F and moment arm L. Torque is equal to F times L. The moment arm affects torque. The torque will create more of an increase the longer the moment arm.

The line of action of a force is the path it travels when exerting its power.

The moment arm of the force is the length that separates the force's path of action from its axis of rotation perpendicularly.

The newton meter is the torque SI unit (Nm). A force of 1 N operating perpendicular to the moment arm's length of 1 m produces a torque of 1 N m.

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a uniform meter stick is suspended from the ceiling by a string attached to the 60. cm mark. a 0.050 kg mass placed at 90. cm mark causes the meter stick to balance in the horizontal position. find the mass of the meter stick.

Answers

The mass of the meter stick is 0.15 kg.

The parameter

Meter Stick length = 100 cmA string attached to the 60 cmMass = m = 0.05 kgA mass placed at 90 cmAcceleration due to gravity = 10 m/s²

Calculate the weight of the mass.

w = mg

w = [tex]0.05 \times 10[/tex]

w = 0,5 N

Look at the picture. The weight of the stick is in the middle of its length at 50 cm. The meter stick is balanced in the horizontal position. At point A

Distance between mass and string = 90-60 = 30 cmDistance between weight of the stick and string = 60-50 = 10 cm

Σ τ = 0

(ws × 10) - (w × 30) = 0

ws × 10 = w × 30

ws × 10 = 0.5 × 30

ws × 10 = 15

[tex]w_s = \frac{15}{10}[/tex]

ws = 1.5 N

ms × 10 = 1.5

[tex]m_s = \frac{1.5}{10}[/tex]

ms = 0.15 kg

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In each of three trials of an investigation, a single force is applied to a mobile. Each time, the mobile acquires a different acceleration. The table
shows the relationship between the acceleration and the acting force.
Acceleration (m/s²)
Force (N)
1.2
0.7
1.6
4.8
2.8
6.4
Which phrase best describes a graph that would represent the relationship shown in the table? (1 point)
an upward-sloping line drawn on a graph with acceleration shown on the x-axis and force shown on the y-axis
a downward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the x-axis
a downward-sloping line drawn on a graph with acceleration shown on the x-axis and force shown on the y-axis
an upward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the x-axis

Answers

Answer: an upward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the X-axis


just took the test

an upward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the X-axis best describes a graph that would represent the relationship shown in the table

What are the features of graph ?

A graph is represented as pictorial form  the of data or numeric values in an organized manner which enables user to represent large amount of data in visual form.

There are 2 types of questions and the features of graphs are interpretation of given graphs or selecting a graph based on a verbal description.

The bar graphs are the most common type of graph, other graphs are dot plots, histograms, line graphs and scatterplots.

A Bar Graph is represented as the graphical display of data using rectangular bars of different parameters like heights, The structure can be represented  in the y axis contains values, and the x axis contains categories or time periods.  

A dot plot is a simple graphical representation  which shows the frequency with which items appears in a data set and present data on the x axis.

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a bus travels with an average velocity of 60km how long does it take to cover a distance of 500km​

Answers

Solution: given that; velocity (v)=60km/hr, distance (d)=500km, time (t)=? From velocity=distance/time....... :. 60=500/t, cross-multiply..... 60t=500, divide both sides by 60...... 60t/60=500/60, t=500/60, t=8.33~. Therefore the bus took 8hours, 33 minutes to cover the distance of 500km.

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a certain automobile of mass 1470 kg travels on a german autobahn at 150 km/h. what is the wavelength of the automobile? answer in units of m

Answers

9.8m is the wavelength  of the automobile. The distance between identical points (adjacent crests) in adjacent waveform signal cycles carried in space or along a wire is defined as the wavelength.

What  is wavelength?

The distance between identical points (adjacent crests) in adjacent cycles of a waveform signal carried in space or along a wire is defined as the wavelength. This length is typically defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).

A spectrum is the range of wavelengths or frequencies for wave phenomena. The term started with the visible light spectrum, but it is now used to refer to the full electromagnetic spectrum, as well as a sound or vibration spectrum.

wavelength=1470/150

                 =9.8m

In a series of waves, the distance between one peak and the next, or between one dip and the next. It is also one of the "yardsticks" used in radiation measurement.

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1. on december 26, 2004, a great earthquake occurred off the coast of sumatra and triggered immense waves (tsunami) that killed some 200,000 people. satellites observing these waves from space measured 800 km from one wave crest to the next and a period between waves of 1 hour. what was the speed of these waves in m/s and in km/h? does your answer help you understand why the waves caused such devastation?

Answers

222.22 m/s is how fast these waves are moving. Relationship between wave speed, wavelength, frequency, and period.

How can I determine the wave speed?

The equation wave speed = frequency x wavelength describes the relationship between wave speed, wavelength, frequency, and period.

Reason: A. Given that we are aware that the formula for calculating a wave's speed is:

v = f, where v is the wave's speed.

f = the wave's frequency

A wavelength is

Here, stands for the separation between adjacent wave crests.

f = 1/Time Period = (1/1 hr)(1 hr/3600 s) f = 2.77 x 104 s1 = 800 km = 8 x 105 m

Therefore,

v = (2.77 x 10⁻⁴ s⁻¹)(8 x 10⁵ m)

v = 222.22 m/s.    

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What is the density of a liquid if a volume of 0.025 L has a mass of 0.034 Kg? Express the result in g/cm3?

Answers

Answer: density = 1.36g/cm3

Explanation: 0.025L = 25cm3 and 0.034kg = 34 grams

  Density= mass/volume

           = 34/25

           = 1.36g/cm3

                   

Answer:

Explanation:

Given:

V = 0.025 l;   or V = 25 cm³

m = 0.034 kg = 34 g

______________

ρ - ?

ρ = m / V

ρ = 34 / 25 = 1.36 g/cm³

my solar system has two types of planets: terrestrials and jovians. the solar nebula hypothesis offers what explanation for the different compositions of these two types of planets?

Answers

According to the nebular hypothesis, small terrestrial planets are formed through the process of accretion, in which dense solid particles condensed and collided with one another as a result of their mutual gravitational pull.

As opposed to this, all heavier elements condensed near the sun and formed terrestrial planets, while lighter elements moved away from the sun and formed jovian planets due to the high temperature near the sun, which only allowed heavier particles to condense there.

The solar nebular hypothesis is the explanation put forth and accepted by most scientists as to how the earth came to be. It claims that a nebular, or huge clump of dust, is where the solar system originated. The heavier materials that could resist higher temperatures formed closer to the sun as the condensation of the nebular continued. Because these minerals weren't abundant, the planets they generated weren't very big.

The Jovian planets, on the other hand, formed above the frost line and could support icy compounds. These planets' larger sizes can be attributed to the abundance of ices that formed them. The lighter hydrogen and helium elements were stripped away by solar winds, which caused their accumulation far from the sun.

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suppose i perform a double-slit experiment on 1,000 electrons. is it possible to predict the pattern they will make when they land?

Answers

We cannot. The precise location of the electron cannot be predicted. The likelihood of where an electron will land can be predicted.

Can you forecast the location of an electron?

Only the likelihood of an electron being present at different sites can be predicted. The probability distribution can even tell you the average location of several electrons, but quantum theory cannot tell you the precise location of the electron. It can only give you a rough sense of where the one electron will end up.

The wave effectively splits into two new waves as it travels through both holes, each of which spreads out from a different slit. Then, there is interference between these two waves. A peak and a trough may occasionally cross paths where they cancel one another out.

The double-slit experiment, which was conducted to study the characteristics of light in the eighteenth century, has subsequently been found to illustrate the duality of photons as well as the ideas of superposition and quantum interference.

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two workers are sliding 260 kg crate across the floor. one worker pushes forward on the crate with a force of 450 n while the other pulls in the same direction with a force of 370 n using a rope connected to the crate. both forces are horizontal, and the crate slides with a constant speed. what is the crate's coefficient of kinetic friction on the floor?

Answers

To find out the kinetic friction, using the coefficient friction formula.

What is kinetic friction?

A force that acts between moving surfaces is called "kinetic friction." A force acting in opposition to the direction of a moving body on the surface is felt. The two materials' kinetic friction coefficients will determine how much force is applied.

What is coefficient friction?

A measure of the degree of friction between two surfaces is the coefficient of friction. A coefficient of friction is determined by calculating the resistance to motion at the intersection of two surfaces made of the same or different materials.

UK

U-coefficient of friction

K-Kinetic friction

Using UK

450+370-f=m*o

f=820=UK*260*9.8

UK=2.548

820/2.548

UK= 321.8210361

Therefore the coefficient of kinetic friction is 321.8210361

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a bowling ball of mass 4.5 kg moves in a straight line at 3.98 m/s. how fast must a ping-pong ball of mass 1.322 g move in a straight line so that the two balls have the same momentum? answer in units of m/s.

Answers

It should travel at a speed of [tex]13.55[/tex] × [tex]10^{-3}[/tex] [tex]\frac{m}{s}[/tex] so that the two balls have the same momentum.

M = mass of the bowling ball = [tex]4.5 kg[/tex]

V = speed of bowling ball = [tex]3.98 \frac{m}{s}[/tex]

P = magnitude of momentum of bowling ball = ?

magnitude of momentum of bowling ball is given as

[tex]P = MV[/tex]

inserting the values

P = [tex]4.5 * 3.98[/tex]

P = [tex]17.91[/tex] [tex]\frac{kgm}{s}[/tex]

m = mass of ping-pong ball = [tex]1.322[/tex] [tex]g[/tex]= [tex]1.322[/tex] x [tex]10^{-3}[/tex] [tex]Kg[/tex]

v = speed of the ping-pong ball = ?

p = magnitude of momentum of ping-pong ball

Given that :

Magnitude of momentum of ping-pong ball  =  magnitude of momentum of bowling ball

[tex]p = P[/tex]

[tex]m v = 17.91[/tex]

([tex]1.322[/tex] x [tex]10^{-3}[/tex]) [tex]v[/tex] = [tex]17.91[/tex]

v = [tex]13.55[/tex] x [tex]10^{-3}[/tex] [tex]\frac{m}{s}[/tex]

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two parallel plates are maintained with constant voltage by a battery as they are pulled apart. what happens to the strength of the electric field during this process?

Answers

During this process, the electric field gets stronger.

Between parallel plates, why does the electric field remain constant?

Because of the assumption that the distance between the plates is small in comparison to the area of the plates, the electric field in parallel plates is uniform and roughly constant. Due to the interaction of the fields produced by the two plates, the field is roughly zero outside of the plates.

The capacitor's two oppositely charged plates are separated by an electric field that is constant throughout, with the exception of the plate edges. The electric field does not change because the space between the plates is smaller than their combined surface area.

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The xylem tube which transports sap to the top of a tree can be considered as uniform cylinders if the transport of sap is entirely due to capillarity determine the diameter of the tube which will move the sap up a tree which is 25m tall.take the surface tension of sap to be 5*10^-2 s.g is 1 g is 9.8 an

Answers

The wide wood pores that link to the tree's roots allow sap to be drawn up into the maple tree when it starts to freeze. The tree is really replenishing itself with fluids at this time from its roots.

As long as the temperature is below freezing and the sap is increasing, the process continues.

How does the xylem sap of tall trees go from the roots to the top?

Water is drawn up from the roots to the top of the plant according to the cohesion-tension hypothesis of sap ascent. Water and minerals travel upward from the roots through the xylem due to a negative water potential gradient created by the evaporation of mesophyll cells in the leaves.

The water potential gets increasingly negative as you climb the tree, and these variations provide a pull or tension that causes the water to ascend the tree. The loss of water from the leaves through a process called transpiration is a crucial element in the draw of water up the tree.

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you throw a rock straight down with an initial speed of 5 m/s. It took 4.5 seconds to hit the ground below. How high was the cliff?

Answers

The height of the cliff is 121.75 m.

What are the equation of motion?

An equation of motion, describes the behavior of a physical system in terms of motion as a function of time. More specifically, the equations of motion describe the behavior of a physical system as a set of mathematical functions related to dynamic variables. The equations of motion are:

v = u + atut + 1/2 at²v² = u² + 2as

For the given case we will use the following equation:

s = ut + 1 / 2 gt²

s = Height of the cliff

u = Initial velocity of rock (5 m/s)

a = Gravitational acceleration (9.8 m/s²)

t = Time (4.5 sec.)

s = (5 × 4.5) + ( 1 / 2 × 9.8 × 4.5² )

s = 22.5 + 99.25

s = 121.75 m

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if an input force of 220 n is applied to the handles of the wheelbarrow in the sample problem, how large is the output force that just lifts the load

Answers

The output force that only lifts the load is 484 N

What is force?In mechanics, force is defined as any action that tends to maintain or alter the motion of a body or to distort it. The concept of force is commonly explained in terms of Isaac Newton's three laws of motion, which are laid out in his Principia Mathematica (1687). Newton's first principle states that a body at rest or moving uniformly in a straight line will remain in that state until some force is applied to it.The second law states that when an external force acts on a body, it causes the body to accelerate (change in velocity) in the direction of the force. The acceleration is proportional to the magnitude of the external force and inversely proportional to the amount of matter in the body. According to Newton's third law, when one body exerts a force on another, the second body exerts an equal force on the first. This action-reaction principle explains why a force tends to deform (i.e., change the shape of) a body whether it causes the body to move. When studying the motion of a body, it is common to overlook.

Calculation

For this case, the relationship between the two forces is given by

[tex]F_{1} =nF_{2}[/tex]

Where,

F1: output strength

F2: input force

n: mechanical advantage

Then, replacing the values ​​we have:

[tex]F_{1} = 2.2*220[/tex] = 484 N

Hence, the output force that only lifts the load is 484 N

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how far from the lens should you hold the print to see a final virtual image 30 cm from the lens (at the eye's near point)?

Answers

m= near point/ s.

s=4.28 cm ( the distance of the contract from the magnifying glasses)

Near point = 30cm

so m= 30/4.28= 7

Thus, far from the lens should you hold the print to see a final virtual image 30 cm from the lens (at the eye's near point) is 7

Gabriel kicks a soccer ball so that it has an initial velocity 22 meters per second, at an angle of 16 above the ground. How much time does it take for the soccer ball to reach its maximum height?

0.62s
2.24s
0.77s
2.16s

WHICH ONE???

Answers

The time taken to reach the maximum height, given that the ball has an initial velocity of 22 m/s is 0.62 s

How do I determine the time taken to reach the maximum height?

The time taken to reach the maximum height can be obtained by using the following formula:

t = uSineθ / g

Where

t is the time taken to reach the maximumu is the initial velocityθ is the angle of projectiong is the acceleration due to gravity

Now, we shall determine the time taken to reach the maximum as follow:

Initial velocity (u) = 22 m/sAngle of projection (θ) = 16 °Acceleration due to gravity (g) = 9.8 m/s²Time taken to reach the maximum height (t) = ?

t = uSineθ / g

t = (22 × Sine 16) / 9.8

t = 0.62 s

Thus, the time taken is 0.62 s

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In the period 6 inner transition element series, the 4f orbitals begin to be filled after the element _____.

Answers

In the period 6 inner transition element series, the 4f orbitals begin to be filled after the element Lanthanum(La) and Cerium(Ce).

The d and f Block elements in the groups of 3 to 11 are also called transition elements and inner transition elements respectively. 4f and 5f orbitals of f-block elements are steadily in the latter of two long periods.

Inner transition element:

Inner transition elements are those elements in which the last electron enters the f-orbital. The elements in which the 4f and the 5f orbitals are progressively filled are called f-block elements. These includes lanthanoids( Z = 58 - 71) and actinoids (Z = 90 - 103).

Therefore period 6 inner transition elements begin with Lanthanum and Cerium.

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A hair dryer uses the energy from the plug in order to power a small fan that blows air. When a hair dryer is being used, which is one of the energy transformations that takes place?.

Answers

Energy transformation takes place when using a hair dryer, electrical energy into kinetic energy and thermal energy.

Energy can be converted according to the law of conservation of energy. Every object transforms the original form of energy into another form called a converter. Every electrical device works to convert electrical energy into other forms.

A microwave converts electrical energy into thermal energy.A lightbulb converts electric energy into light energy.A mixer converts electric energy into kinetic energy.

When we use a hairdryer

The temperature of small wires inside it will be raised because the electrical energy transforms into thermal energy.The motion of a small fan happens because the electrical energy transforms into kinetic energy.The small fan gonna blows the air between hot wires and creates hot air that comes out from it.

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