The length of the line ed according to the description of the cube is; 8.5.
What is the length of ed in the given Cube?First, since the shape is a cube, it follows that the diagonal of the top face can be used to determine the length of the sides of the top face.
Therefore , we have; length of each side of the top face;
ag = ge = ef = fa = √288/2 = 6√2.
Also, the diagonal of a to d is; √432 = 12√3.
Hence, the length of ed in the group as evident from the length of sides of the cube's top face in which case,
Consequently, the length of line ed is;√432 × 8.5.
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The roots of the quadratic equation x 2 − 51x + k = 0 differ by 75, where k is a real number. Determine the sum of the squares of the roots
The sum of the squares of the root is 4113
In a quadratic equation ax² + bx + c , the sum of the roots is -b/a and the product of the roots is c/a
Let m, n be roots of the given equation.
So,
m - n = 75 -1)
m + n = 51 (as sum of roots of a quadratic equation is -b/a) -2)
adding both equations 1) and 2)
2m = 75 + 51
2m = 126
m = 63
substituting value of m in equation 1 we get
63 - n = 75
n = -12
So the sum of squares of the roots of the equation is = 63² + -12²
= 3969 + 144
= 4113
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If the maximum payment of $5,000 is made into a individual retirement account (ira) for 25 years at an annual interest rate of 3.2%, determine the amount in the account.round to the nearest cent. a. $187,159.62 b. $193,148.73 c. $129,082.99 d. $129,427.21
The amount in the ira's account s = $187,159.62.
How do you interest rate?
The interest rate is the amount a lender charges a borrower and is a percentage of the principal—the amount loaned. The interest rate on a loan is typically noted on an annual basis known as the annual percentage rate (APR).Future Value of an Ordinary Annuity
[tex]s = R(( 1 + i)^{n} - 1 ) / i[/tex]
where
S = the future value;
R = the periodic payment;
i = the interest rate per period;
n = the number of periods.
[tex]s = 5000 ( 1 + 0.032)^{25} - 1)/ 0.032[/tex]
[tex]s = 5000((1.032)^{25} - 1 )/0.032[/tex]
[tex]s = 5000( 2.19782157471 - 1)/0.032[/tex]
[tex]s = 5000(1.19782157471)/0.032[/tex]
[tex]s = 5000 * 37.4319242096[/tex]
s = $187,159.62
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Let f(x) = xe−x if x ≥ 0 and f(x) = 0 if x < 0
Is f a probability density function?
Yes. [tex]f(x)[/tex] is a PDF if
• [tex]f(x) \ge 0[/tex] for all [tex]x[/tex] in the support; this is true, since [tex]e^{-x}>0[/tex] for all [tex]x[/tex], and multiplying a positive number [tex]x[/tex] doesn't change this fact;
• the integral of [tex]f(x)[/tex] over its support is 1; this is also true, since
[tex]\displaystyle \int_{-\infty}^\infty f(x) \, dx = \int_0^\infty xe^{-x} \, dx = 1[/tex]
which can be computed by parts.
What is the classification of AABC with vertices A(0, 0), B(4, 3), and C(4, -3) by
its sides?
(A) equilateral
(B) isosceles
(C) scalene
(D) right
Check the picture below.
well, let's take a peek at the distances of each side.
[tex]~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad B(\stackrel{x_2}{4}~,~\stackrel{y_2}{3}) ~\hfill AB=\sqrt{[ 4- 0]^2 + [ 3- 0]^2} \\\\\\ ~\hfill AB=\sqrt{25}\implies \boxed{AB=5} \\\\\\ B(\stackrel{x_1}{4}~,~\stackrel{y_1}{3})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-3}) ~\hfill BC=\sqrt{[ 4- 4]^2 + [ -3- 3]^2} \\\\\\ ~\hfill BC=\sqrt{36}\implies \boxed{BC=6}[/tex]
[tex]C(\stackrel{x_1}{4}~,~\stackrel{y_1}{-3})\qquad A(\stackrel{x_2}{0}~,~\stackrel{y_2}{0}) ~\hfill CA=\sqrt{[ 0- 4]^2 + [ 0- (-3)]^2} \\\\\\ ~\hfill CA=\sqrt{25}\implies \boxed{CA=5} \\\\\\ \textit{so it's an \underline{isosceles triangle}}[/tex]
If the ice shop has only enough cocoa to make 4 gallons of chocolate ice cream, how many gallons of strawberry ice cream can the shop efficiently produce? 0 2 8 12
The complete questions is:
The ice cream shop needs 5 pounds of strawberries for every gallon of strawberry ice cream. the shop chooses to produce 4 gallons of chocolate ice cream. how many pounds of strawberries should the shop purchase?
Pounds of strawberry ice cream needed to be bought by the shop exists 20 pounds.
How many gallons of strawberry ice cream can the shop efficiently produce?The ice cream shop requires 5 pounds of strawberries for every gallon of strawberry ice cream and the shop chooses to make 4 gallons of ice cream,
Quantity of chocolate ice cream created in the shop = 4 gallons
Quantity of strawberries needed for each gallon of ice cream = 5 pounds
Pounds of strawberries needed to be bought by the shop = Quantity of chocolate ice cream created by the shop [tex]*[/tex] Quantity of strawberries needed for each gallon of ice cream
[tex]$= 4 * 5[/tex]
= 20 pounds.
Pounds of strawberries needed to be bought by the shop exists 20 pounds.
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Answer:
12
Step-by-step explanation:
A teapot is 1/3 full of tea. When all of the tea is poured into an empty container, the container 2/3 full. What fraction of the tea from a full teapot is needed to fill 1 entire container?
Answer:1/2 of the teapot
Step-by-step explanation: Since 1/3 of the teapot is equal to 2/3 of the container, 1/3 of the container is equal to half of 1/3 of the teapot. We know that 1/3 divided by 2 equals 1/6, so 1/6 of the teapot is equal to 1/3 of the container. There are 3-thirds in a whole so we have to multiply 1/6 by 3. This equals 3/6 or 1/2.
Consider the steps to solve the equation. 2 5 ( 1 2 y + 20 ) − 4 5 = 9 20 (2y − 1)
Distribute: 1 5 y + 8 − 4 5 = 9 10 y − 9 20
What is the next step after using the distributive property?
*Use the multiplication property of equality to isolate the variable term on one side of the equation.
*Use the multiplication property of equality to isolate the constant on one side of the equation.
*Combine the like terms on the right side of the equation.
*Combine the like terms on the left side of the equation.
Answer:
D
Step-by-step explanation:
I did the assignment
hope this helps :)
In circle D, which is a secant?
EF
DC
Line segment A B
Line G H
The secant of circle D is the 'line GH'. Where the line segment EF is the diameter of the circle, line segment DC is the radius, and the ray AB is the tangent of the given circle.
What is the secant of the circle?The line that passes through the circle and touches the circle at two points is said to be a secant line of the circle.
Which is the secant line in the given circle D?The given circle D has a center at D.
The radius of the circle is given by the line segment CD
The diameter (or) the longest chord of the circle is given by the line segment EF
The ray AB passes touches the circle at point B, which is called the tangent of the circle.
Where the line GH passes through the circle and touches at two points. So, this line GH is said to be the secant of the circle.
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Disclaimer: The given question is incomplete(needs a diagram). Here is the required diagram attached.
Question: In circle D, which is a secant?
a) EF
b) DC
c) Line segment AB
d) Line GH
Answer:
ray ab
Step-by-step explanation:
#14
quick answer pls :)
Answer:
35.56
Step-by-step explanation:
Small numbers that are added to avoid unfair scoring of low-probability outcomes are called ___.
Small numbers that are added to avoid unfair scoring of low-probability outcomes are called pseudocodes
How to complete the blank?From the statement, we have the following highlights:
The numbers are small numbers Adding the numbers is used to avoid unfair scoring of low-probability outcomesThe term for the statements in the above highlight is pseudocodes
This is because pseudocodes are false codes or small numbers
Hence, the small numbers that are added to avoid unfair scoring of low-probability outcomes are called pseudocodes
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Can you solve and explain how to solve problems like these.
Step-by-step explanation:
there are some formulas to know about this.
I am sure you discussed this in class.
when 2 lines (originating from the same point) cut through the same circle creating some circle segments (such lines are also called Secants), then there is a relationship in the lengths of the different parts of the lines among themselves.
the outer portion of such a line multiplied with the length of the whole line to the second point it intersects the circle is the same for every secant from the same point through the same circle.
that means in our case :
7(x - 6) = 6(x - 3)
7x - 42 = 6x - 18
x = 24
and so,
EG = (x - 3) + 6 = (24 - 3) + 6 = 21 + 6 = 27
Evaluate the expression under the given conditions. tan(2); cos() = 5 13 , in quadrant i
The solution to given expression tan(2θ) is 22.615°
For given question,
We have been given an expression tan(2θ)
Given that cos(θ) = 5/13, and θ is in quadrant 1.
We know that the trigonometric identity
sin²θ + cos²θ = 1
⇒ cos²θ = (5/13)²
⇒ sin²θ = 1 - 25/169
⇒ sin²θ = 169 - (25/169)
⇒ sin²θ = 144/169
⇒ sin(θ) = 12/13
We know that the identity cos(2x) = cos²x - sin²x
⇒ cos(2θ) = cos²θ - sin²θ
⇒ cos(2θ) = 25/169 - 144/169
⇒ cos(2θ) = -119/169
And sin(2x) = 2sin(x)cos(x)
⇒ sin(2θ) = 2sin(θ)cos(θ)
⇒ sin(2θ) = 2 × 12/13 × 5/13
⇒ sin(2θ) = 120/169
We know that, tan(x) = sin(x)/cos(x)
⇒ tan(2θ) = sin(2θ)/cos(2θ)
⇒ tan(2θ) = (120/169) / (-119/169)
⇒ tan(2θ) = 120 / (-119)
⇒ tan(2θ) = -1.008
Since θ is in quadrant 1, tan(2θ) = 1.008
⇒ 2θ = arctan(1.008)
⇒ 2θ = 45.23
⇒ θ = 22.615°
Therefore, the solution to given expression tan(2θ) is 22.615°
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Help me ASAP mark you BRAINLIEST!!!!!!!!!!!
Answer:
11÷7=[tex]\frac{11}{7}[/tex]
v= 11/7
For each of the number lines, write an absolute value equation that has the following solution set. 26 and m
On a number line, an absolute value equation that has the given solution set is |m - 4| = 2.
How to write the absolute value equation?By critically observing the given question, we can infer and logically deduce that the solution sets for this absolute value equation is given by:
m = {2, 6}
Next, we would calculate the mean of the solution sets as follows:
m₁ = (2 + 6)/2
m₁ = 8/2
m₁ = 4.
Also, we would calculate the difference in the solution sets as follows:
m₂ = (6 - 2)/2
m₂ = 4/2
m₂ = 2.
Mathematically, the absolute value equation is given by:
|m - m₁| - m₂ = 0
|m - 4| - 2 = 0
|m - 4| = 2.
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what is the general form of the equation for the given circle?
The general equation for a circle is [tex](x-h)^2+(y-k)^2=r^2[/tex], where [tex](h,k)[/tex] is the centre of the circle and [tex]r[/tex] is the radius.
Solving the QuestionFirst, we can determine the centre of the circle.
( _ , _ )
The point directly on top is (4,7). Because it lies on the same vertical line as the centre, they have the same x-coordinate.
(4, _ )
The point directly to the right of it is (7,4). Because it lies on the same horizontal line as the centre, they have the same y-coordinate.
(4,4)
Therefore, the centre of the circle is (4,4). Plug this into the general equation:
[tex](x-h)^2+(y-k)^2=r^2\\(x-4)^2+(y-4)^2=r^2[/tex]
Now, we can determine the radius of the circle.
To do this, we can calculate the distance between the centre of the circle and one of the given points that lie on the circumference.
The centre is (4,4), and one of the points is (4,7). Because they only have a difference of 3 units in the y-direction (and none in the x-direction), this means that the radius is 3 units. Plug this into the general equation:
[tex](x-4)^2+(y-4)^2=r^2\\(x-4)^2+(y-4)^2=3^2\\(x-4)^2+(y-4)^2=9[/tex]
Answer[tex](x-4)^2+(y-4)^2=9[/tex]
What is the probability that a class of 50 has an average midterm mark that is less than 75?
The probability that a class of 50 has an average midterm mark that is less than 75 is value=0
Average is the mathematics mean, and is calculated by means of adding a group of numbers and then dividing with the aid of the count of these numbers. for instance, the average of 2, three, three, five, 7, and 10 is 30 divided with the aid of 6, that is five.
The common is described as the implied value that is identical to the ratio of the sum of the number of a given set of values to the whole wide variety of values gift within the set.
There are three primary sorts of common: imply, median, and mode. each of those techniques works slightly differently and frequency effects in barely specific regular values. The suggestion is the maximum normally used average. To get the suggested fee, you add up all of the values and divide this total by using the number of values.
The probability that a class of 50 has an average midterm mark that is less than 75
n = 50
P(<75)=P(Z<75)
P(Z<75−786√50)
P(Z<−3.5355)
We will look for the value in the StandardNormal able. We will get the value=0
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Rhett is solving the quadratic equation 0= x2 – 2x – 3 using the quadratic formula. which shows the correct substitution of the values a, b, and c into the quadratic formula? quadratic formula: x = startfraction negative b plus or minus startroot b squared minus 4 a c endroot over 2 a endfraction
Answer:
Step-by-step explanation:
0= x2 – 2x – 3
a = 1, b = -2 and c = -3.
Answer:
A on edge
Step-by-step explanation:
Give me the brainiest please
I need to find the Value of x
Answer:
x = 4
Step-by-step explanation:
These triangles are similar by the AA Similarity Postulate.
12 + 4 = 16
(5x - 2)/12 = 6x/16 (3x/8)
Cross multiply: 8(5x - 2) = 12(3x)
40x - 16 = 36x
4x - 16 = 0
4x = 16
x = 4
can someone help me please?
Answer:
the answer to the question is answer C
Answer:
Step-by-step explanation:
B is your answer
Consider the function f(x) = 1/3(6)*. What is the value of the growth factor of the function?
1/3
2
6
18.
Answer:
6
Step-by-step explanation:
The growth factor is the same as the base of the exponential factor.
The value of the function [tex]$f(x)=(1/3)(6)^x[/tex] growth factor exists 6.
How to estimate the value of the growth factor of thefunction [tex]$f(x)=(1/3)(6)^x[/tex]?
Given: [tex]$f(x)=(1/3)(6)^x[/tex]
For any equation [tex]$ f(x)=ab^x[/tex]
Let, 'a' exists the initial value
b exists the growth or decay factor.
When the value of b exists greater than 1 then its growth factor
when the value of b exists between 0 and 1 then it exists a decay factor
Let x exists the number of years
Given function, [tex]$ f(x)=(1/3)(6)^x[/tex]
The value of b exists 6.
So the growth factor exists 6.
Therefore, the correct answer is option c. 6.
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How many fruits did Anna get?
Answer: Anna got 30
Step-by-step explanation: 2x+3y=25
15+10=25
How old is David
please help me
Answer: 25 ?
Step-by-step explanation:
anyone think they can help me??
The kind of transformation that is illustrated based on the information given is reflection.
What is transformation?It should be noted that transformation simply means the change in the position of an object while maintaining the length and other properties.
In this case, the kind of transformation that is illustrated based on the information given is reflection.
This is the flipping of the pre image and then producing the mirror image.
Here, there'll be no change in the shape of the size. This depicts congruency.
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Write two different integers x, y, and z, and meet the following conditions. they do not all have the same sign and x-y-z=0
Two different integers are the same numbers, which have different signs.
What is integers?An integer is a number that includes negative and positive numbers, including zero. It does not include any decimal or fractional part. A few examples of integers are: -5, 0, 1, 5, 8, 97.
Given that,
x, y, and z are three integers. They follow the one condition: x-y-z = 0.
Any number in the number system that has only two signs, either + or -, So we consider that the third integer is 0 because 0 is a whole number that has neither a positive nor a negative sign.
The remaining two integers are the same numbers, but they have different signs to follow the given condition.
x-y-z = 0
x = y+z
Let y,z are the same numbers, They have different signs and x = 0.
Note: The value of x is always negative and y's value is always positive.
Example:
x = 0, y = +6, z = -6
x-y-z = 0
x = y+z
0 = +6-6
0 = 0
Hence, two different integers are the same numbers, which have different signs.
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ratio and proportion
1. there are 24 green cars and 48 white cars in a parking lot.
i) find the ratio of green cars to white cars.
ii) what can you say about them?
Based on the given tast content; the ratio of green cars to white cars is 1 : 2 and it can be said that there are twice as many white cars as green cars.
Ratio and proportionNumber of green cars = 24Number of white cars = 48Ratio of green cars to white cars = 24 : 48
= 24 / 48
= 1 / 2
Ratio of green cars to white cars = 1 : 2
Therefore, the ratio of green cars to white cars is 1 : 2 and it can be said that there are twice as many white cars as green cars
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VERY URGENT: Alexis surveys a random sample of 80 students at his school and finds that 22 of them usually walk to school. There are 1,760 students at the school. Predict the number of students who usually walk to school.
Answer:
484 Students
Step-by-step explanation:
This is simple probability. Assuming 22/80 students walk to school within a small population, and there are 1760 students at the school, there should be (22/80)*1760 students that walk to school in total. (This is just theoretical). This is 484 students.
Solve the given differential equation by separation of variables. dy dx = e4x 5y
The solution to the given differential equation [tex]\frac{dy}{dx} = e^{4x+5y}[/tex] is , [tex]\frac{e^{-5y}}{-5}=\frac{e^{4x}}{4} +c[/tex], where c is constant of integration.
For given question,
We have been given a differential equation [tex]\frac{dy}{dx} = e^{4x+5y}[/tex]
We know that for any real number a, m, n,
[tex]a^{m + n} = a^m \times a^n[/tex]
⇒ dy/dx = [tex]e^{4x}[/tex] × [tex]e^{5y}[/tex]
Separating the variables (x and its differential in one side and y and its differential in another side )
⇒ [tex]\frac{1}{e^{5y}}[/tex] dy = [tex]e^{4x}[/tex] dx
⇒ [tex]e^{-5y}[/tex] dy = [tex]e^{4x}[/tex] dx
Integrating on both the sides,
⇒ [tex]\int e^{-5y}[/tex] dy = [tex]\int e^{4x}[/tex] dx
We know that, [tex]\int e^{ax}\, dx=\frac{e^{ax}}{a} +C[/tex]
⇒ [tex]\int e^{4x}\, dx=\frac{e^{4x}}{4} +C[/tex]
and [tex]\int e^{-5y}\, dy=\frac{e^{-5y}}{-5} +C[/tex]
So the solution is, [tex]\frac{e^{-5y}}{-5}=\frac{e^{4x}}{4} +c[/tex], where c is constant of integration.
Therefore, the solution to the given differential equation [tex]\frac{dy}{dx} = e^{4x+5y}[/tex] is , [tex]\frac{e^{-5y}}{-5}=\frac{e^{4x}}{4} +c[/tex], where c is constant of integration.
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The height of water shooting from a fountain is modeled by the function f(x)= -4x^2 +24x -29 where access to distance from the spot in feet. complete the square to determine the maximum height of the path of the water.
By the use of the completing the square method, the maximum height of the path of the water 3 ±√29/4 + 9 m.
What is called distance?
Distance is a numerical measurement of how far apart objects or points are. The distance between two points is the length of the path connecting them.In everyday usage, distance may refer to a physical length or an estimation based on other criteria (e.g. "two counties over"). The distance from a point A to a point B is sometimes denoted as. .h = -4x² +24x -29
Now we have;
0 = -4x² +24x -29
-4x² +24x -29= 0
x² - 6x = -29/4
(x - 3)² = -29/4 + 3²
(x - 3)² = -29/4 + 9
x = 3 ±√29/4 + 9 m
Therefore, the maximum height of the path of the water x = 3 ±√29/4 + 9 m
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I need help, pls and thx
The solutions for the quadratic equation are given as follows:
x = -1, x = 7/5
What is a quadratic function?A quadratic function is given according to the following rule:
y = ax^2 + bx + c
The solutions are:
[tex]x_1 = \frac{-b + \sqrt{\Delta}}{2a}[/tex][tex]x_2 = \frac{-b - \sqrt{\Delta}}{2a}[/tex]In which:
[tex]\Delta = b^2 - 4ac[/tex]
For this problem, the equation is:
5x² - 2x - 7 = 0.
Hence the coefficients are a = 5, b = -2 and c = -7, and then the solutions are found as follows:
[tex]\Delta = (-2)^2 - 4(5)(7) = 144[/tex][tex]x_1 = \frac{2 + \sqrt{144}}{10} = \frac{7}{5}[/tex][tex]x_2 = \frac{2 - \sqrt{144}}{10} = -1[/tex]The solutions are:
x = -1, x = 7/5
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amplificar la siguientes fracciones con tal que de un numero igual al final las fracciones son:
a. 1/2, 3/4, 5/10, 9/20
b. 3/8, 1/15, 3/20, 9/10
c. 7/9, 1/3, 5/6, 3/4
d.3/12, 1/5 7/15 1/20
The arrangement of the fractions given from the lowest to the highest is illustrated
How to illustrate the information?a. 1/2, 3/4, 5/10, 9/20.
We can change this to percentages.
1/2 = 1/2 × 100 = 50%
3/4 = 3/4 × 100 = 75%
5/10 = 5/10 × 100 = 50%
9/20 = 9/20 × 100 = 45%
Therefore, the arrangement will be 9/20, 5/10, 1/2, and 3/4.
b. 3/8, 1/15, 3/20, 9/10
3/8 = 37.5%
1/15 = 6.67%
3/20 = 15%
9/10 = 90%
The arrangement will be 1/15, 3/20, 3/8, and 9/10.
c. 7/9, 1/3, 5/6, 3/4
7/9 = 77.7%
1/3 = 33.3%
5/6 = 82%
3/4 = 75%
The arrangement will be 1/3, 3/4, 7/9, and 5/6.
d.3/12, 1/5 7/15 1/20
3/12 = 25%
1/5 = 20%
7/15 = 48%
1/20 = 5%
The arrangement will be 1/20, 1/5, 3/12, and 7/15.
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