Homo erectus’s cranial capacity - ranges from 650 cc to 1,200 cc.
Homo erectus, an extinct species of Pleistocene archaic human, first appeared about 2 million years ago. The earliest known early human with dimensions similar to modern humans, including relatively long legs and small arms compared to the size of the torso, is Homo erectus. An extinct species of hominin that existed between 1.9 million and 135,000 years ago is known as homo Erectus.
The Homo erectus had certain ape-like characteristics, including huge teeth and a hefty jaw. They hunted and ate cooked meat, and they used fire. After closer inspection, it was discovered that the species' teeth showed signs of a diversified diet that included meat intake.
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1. Consider the potential energy diagram shown below. This graph shows the chemical potential energy in a reaction system over time. The y-axis is potential energy in kilojoules. The x-axis is the reaction progress or time.
Does this graph represent an endothermic or an exothermic reaction? Explain your answer.
What is the enthalpy change, ΔH, for this reaction? Show your work.
What is the activation energy, Ea, for this reaction? Show your work.
THE GRAPH IS BELOW
150 kJ of energy was given out over the course of the reaction and 200kJ is required for the reactants to be converted into products.
What is the potential energy graph?We know that the combination of the reactants is what leads to the formation of products. The interaction of the reactants and the products is what is shown on the potential energy curve. The hump at the highest point of the graph is the activation energy while the difference between the energy of the reactant and the products is the enthalpy of the reaction.
Now; the enthalpy change is given as;
ΔH = 200 kJ - 50 kJ = 150 kJ
Ea = 250 kJ - 50 kJ = 200kJ
We can see that 150 kJ of energy was given out over the course of the reaction and 200kJ is required for the reactants to be converted into products.
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differemces between liquid pressure and air pressure . give this answer is box
Answer:
The key difference between air pressure and liquid pressure is that air pressure allows the gaseous state of matter to be compressible, whereas liquid pressure makes a liquid incompressible.
Liquid pressure is the pressure that we can observe in a liquid. Air pressure is also known as atmospheric pressure, and it is the pressure as the force exerted by the collisions of particles in the air.
The aeroplane then continues at a CONSTANT VELOCITY for a further 800 m before leaving the runway. The length of the runway is 2 000 m. 8 m-s-1 1 .2 1.3 → Define the term vector. Convert 67 m-s¹ to km.h¹. 67 m-s¹ Calculate the: .3.1 3.2 1.3.3 3.4 30 s 800 m Acceleration of the aeroplane during the first 30 seconds Distance travelled by the aeroplane during the first 30 seconds Time taken by the aeroplane to travel the 800 m Length of the runway NOT USED when the aeroplane leaves the runway (2) (1 (4 (4 (3
800 = 0 + [tex]\frac{1}{2}[/tex]a(30)[tex]^{2}[/tex]
800 = 450a
a = 1.77m[tex]s^{-2}[/tex]
Distance = s = ut + [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]s = 0+ [tex]\frac{1}{2}[/tex]1.77[tex]t^{2}[/tex]
s = [tex]\frac{1}{2}[/tex]1.77(30)[tex]^{2}[/tex]
s = 796.5m
Time taken = distance / velocityt = 800/8
t = 100 sec
Length of the runway not used = total length of runway-total length covered before leaving runway2000 -800
length = 1200m
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A satellite is 1200 k above the earth (radius = 6400 k); it completes one revolution in 90min. what is the linear speed?
A satellite is 1200 k above the earth (radius = 6400 k); it completes one revolution in 90min. what is the linear speed?
530.58 (1200+6400)*pi*2/90
What is linear speed?The measurement of a moving object's actual distance traveled is called linear speed. Linear speed is the rate of motion of an object along a straight line. In plain English, it is the distance traveled along a linear path in the allotted amount of time.
A pseudovector used in physics to express how quickly the angular location or orientation of an item changes over time is called an angular velocity or rotational velocity The pseudovector's direction is normal to the instantaneous plane of rotation or angular displacement, and its magnitude corresponds to the object's angular speed, or the rate at which it rotates or revolves. The right-hand rule is a common way to specify the direction of angular velocity.
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A small fan in a closed insulated room releases heat at the rate of 42 watts and pushes the air at the rate of 9 m/s with a mass flow rates of 1.2 kg/s. The room has a heater that produces heat at the rate of 0.30 kJ/s as well as a computer that produces 65 watts. Light bulbs in the room produce up to 125 watts. The room loses 0.32 kJ/s. Calculate the amount of heat maintained in the room.
The refrigerator is removing 300 watts of heat every hour.
Energy can only be changed in form; it cannot be created or destroyed, according to the basic law of thermodynamics. For any system, energy transfer examples include mass crossing the control boundary, external work, or heat transfer across the barrier. These have an impact on the energy reserves of the control volume.
The rate of heat removal from within the refrigerator may be calculated using the formula below thanks to the First Law of Thermodynamics and the definition of a refrigeration cycle.
Rate of heat transfer to the space, measured in watts.
Q=800 W W=500
The refrigerator removes heat at a rate of (800-500) 300 watts per hour.
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The first time that astronomers observed both gravitational waves and electromagnetic waves from the same event, what they were observing was:_____
Higher frequencies are present in more dramatic events and have thus been the first to be noticed, but the frequencies of ordinary gravitational waves are relatively low and considerably more difficult to detect.
A gamma-ray burst (GRB), which was discovered by the orbiting Fermi gamma-ray burst monitor on 2017 August 17 at 12:41:06 UTC, triggered an automatic notice throughout the world in addition to a merger of black holes. Six minutes later, a gravitational-wave observatory in Hanford, Washington, detected a gravitational-wave candidate that occurred 2 seconds before the gamma-ray explosion.
This collection of data supports the merger of two neutron stars, as shown by a multi-messenger transient event that was detected by gravitational waves as well as electromagnetic (gamma-ray burst, optical, and infrared) spectrum observations.
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Aluminium has a work function of 4. 08 ev. (a) find the cutoff wavelength and cutoff frequency for the photoelectric effect?
Aluminium has a work function of 4. 08 eV. The cutoff wavelength and cutoff frequency for the photoelectric effect is 303.9nm and 911.7× 10¹⁷ s⁻¹ respectively.
Work Function is the minimum energy required to eject an electron from a photoelectric material.
Cutoff Wavelength is the maximum wavelength below which electron will be ejected
Cutoff Frequency is the minimum frequency required to eject electron.
Let the work function of Aluminium be Φ
Given, work function Φ = 4.08eV
We know that hc/λ = Φ
where, h is Planck constant
c is speed of light
λ is wavelength of light used
Hence, on subsitution
1240 / λ = 4.08 eV (hc = 1240)
⇒ λ = 303.9 nm
Hence, cutoff wavelength used is 303.9 nm
We know that ν = c/λ
ν = 3 × 10⁸ / 303.9
⇒ ν = 911.7 × 10¹⁷ s⁻¹
Hence, cutoff frequency used is 911.7 × 10¹⁷ s⁻¹
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Wavelength and frequency are: ________.
a. directly proportional to each other
b. inversely proportional to each other
c. inversely proportional to the square of their distance
d. unrelated to each other
Answer: b. inversely proportional to each other
Explanation:
The wave with the greatest frequency has the shortest wavelength. Twice the frequency means one-half the wavelength.
A blue train of mass 50 kg moves at 4 m/s toward a green train of 30 kg
initially at rest. The trains collide. After the collision the green train moves with a speed of 3 m/s. What is the final momentum of the blue train?
A. 90 kgm/s
B. 200 kgm/s
C. 110 kgm/s
D. 20 kgm/s
Answer:
C
Explanation:
Use conservation of momentum
Momentum before collision = mv = 50 (4) = 200 kg-m/s
AFTER collision
30 * 3 + Blue momentum = 200
blue momentum = 110 kg-m/s
An fm radio station broadcasts at 98. 6 mhz. What is the wavelength of the radiowaves?.
The wavelength of radiowaves is 3.042 m.
What is radiowaves?The electromagnetic spectrum's longest wavelengths, which are found in radio waves, are normally found at frequencies of 300 gigahertz and below.
Frequency given, f = 98.6 MHz = 98.6 x [tex]10^{6}[/tex] cycles/second
Electromagnetic waves including radiowaves also travel at the speed of light.
Therefore, c = 3.0 x [tex]10^{8}[/tex] m/sec
Wavelength = speed/frequency
wavelength of 98.6 MHz = 3.0 x [tex]10^{8}[/tex]/98.6 x [tex]10^{6}[/tex] meters
=3.042 meters
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1. Magnetic force acting on a unit positive charge moving perpendicular to the magnetic field with a unit velocity is called
a. magnetic flux
b. magnetic field intensity
c. magnetic induction
d. self-inductance
Magnetic Flux is the magnetic force acting on a unit positive charge moving perpendicular to the magnetic field with a unit velocity
What does magnetic flux depend on ?The magnetic flux or field lines linking a coil depends on;
The magnetic field strengthThe number of turns of the coilThe area of each turnAccording to the question, the Magnetic force acting on a unit positive charge moving perpendicular to the magnetic field with a unit velocity is called magnetic flux
To obtain a large induced electromotive force, we cause a coil of many turns to move at a high speed across a strong magnetic field.
According to Faraday's law, which state that whenever there is a change in the magnetic lines of force, an electromotive force is induced, the strength of which is proportional to the rate of change of the flux linked with the circuit.
Therefore, Magnetic Flux is the magnetic force acting on a unit positive charge moving perpendicular to the magnetic field with a unit velocity
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Assuming the diode is ideal but with a forward voltage drop of. 65 volts, what is the current in ma if v1=0v, and r1=490ω?
The current in the ideal diode with forward biased voltage drop of 65V is 132.6 mA.
To find the answer, we have to know more about the ideal diode.
What is an ideal diode?A type of electronic component known as an ideal diode has two terminals, only permits the flow of current in one direction, and has less zero resistance in one direction and infinite resistance in another. A semiconductor diode is the kind of diode that is used the most commonly. It is a PN junction-containing crystalline semiconductor component that is wired to two electrical terminals.How to find the current in ideal diode?Here we have given with the values,[tex]V_2=65V\\V_1=0V\\R_1=490Ohm.[/tex]
We have the expression for current in mA of the ideal diode with forward biased voltage drop as,[tex]I=\frac{V_2-V_1}{R_1} =\frac{65}{490} =132.6mA[/tex]
Thus, we can conclude that, the current in mA of the ideal diode with forward biased voltage drop of 65 V is 132.6.
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What was the major problem with the hubble space telescope when it was first launched into orbit?
Answer:
Apparently, a measuring rod had been used incorrectly and the telescope was not focusing properly - changes were later made to the telescope to correct this problem.
Please help, I don't understand lol
The resulting velocity of marble B after the collision is 2.4 m/s.
The object with the faster velocity, and thus larger momentum, will impart more energy to the slower object during the collision than vice versa. Following the collision, the object with the lower beginning velocity will travel away from the other object with a higher speed and momentum.
Marble A's mass, marble B's mass, marble B's initial velocity, marble A's final velocity, marble B's final velocity, and marbles A and B's combined mass and initial velocity
Applying the mass-conservation principle
Momentum is conserved.
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(0.08 kg)(0.5 m/s) + (0.05 kg)(0 m/s) = (0.08 kg)(-0.1 m/s) + (0.05 kg) v
0.04 kg m/s = -0.08 kg m/s + (0.05 kg) v
0.12 kg m/s = (0.05 kg) v
v = 2.4 m/s
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3. [-/2 Points]
A race car traveling northward on a straight, level track at a constant speed travels 0.760 km in 21.0 s. The return trip over the
same track is made in 26.0 s.
DETAILS SHIPPS13 2.E.010. MY NOTES
ASK YOUR TEACHER
(a) What is the average velocity of the car in m/s for the first leg of the run?
m/s
(b) What is the average velocity (in m/s) for the total trip?
m/s
PRACTICE ANOTHER
(a) The average velocity of the car in m/s for the first leg of the run is 36.2 m/s.
(b) The average velocity (in m/s) for the total trip is 0.
Average velocity
The average velocity of the car in m/s for the first leg of the run is calculated as follows;
Average velocity = total displacement/total time
Average velocity = (760) / (21) = 36.2 M/S
Average velocity for total tripThe average velocity (in m/s) for the total trip is calculated as follows;
v = total displacement/total time
v = 0/(26 + 21)
v = 0
Thus, the average velocity of the car in m/s for the first leg of the run is 36.2 m/s.
The average velocity (in m/s) for the total trip is 0.
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Mercury at 25°c flows over a 3-m-long and 2-m-wide flat plate maintained at 75°c with a velocity of 0. 01 m/s. Determine the rate of heat transfer from the entire plate?
The rate of heat transfer from the entire plate is 710.8 kW
The properties of mercury at the film temperature of (75+25)/2= 50°C
k = 8.83632 W/m °C
v = 1.056 × [tex]10^-^7[/tex] m²/s
Pr = 0.0223
The local Nusselt number relation for liquid metals is given by
[tex]N_u =\frac{h_sx}{k} = 0.565 9Re_x Pr)^\frac{1}{2}[/tex]
The average heat transfer coefficient for the entire surface can be determined from
[tex]h = \frac{1}{L} \int\limits^1_0 {h_x} \, dx[/tex]
Substituting the local Nusselt number relation into the above equation and performing the integration we obtain
[tex]N_u = 1.13 (Re_s Pr)^\frac{1}{2}[/tex]
The Reynolds number is
[tex]Re_L = \frac{VL}{v} = \frac{(0.01)(3m)}{1.056 * 10^-^7 m^2/s} = 0.028 * 10^7[/tex]
Using the relation for the Nusselt number, the average heat transfer coefficient and the heat transfer rate are determined to be
Q = 710.8 kW
Therefore, the rate of heat transfer from the entire plate is 710.8 kW
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A crowbar of 2m is used to lift an object of 800N if the efforts arm is 160cm clalculate the efforts applied
The applied effort represents the time devoted to the analysis of theory, attendance at theory classes, and the authentic performance of all practical skills.
How to calculate efforts applied?The applied effort represents the time devoted to the analysis of theory, attendance at theory classes, and the authentic performance of all practical skills.
The effort, application, endeavor, and exertion imply activities directed or force expended toward a definite end. Effort exists as an expenditure of energy to perform some objective: He created an effort to control himself. The application exists continuous struggle plus careful attention: constant application to duties.
Length of crow bar = 2m
length of load arm = 0.1M
length effort arm = length of crow bar -length of load arm
=2−0.1=1.9m
so, velocity ratio = length of effort arm/length of load arm = 1.9/0.1 = 19
use formula, velocity ratio = load/effort
19 = 100kgf/effort
effort = 100/19= 5.26 kgf
hence,5.26 effort is required.
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What is the total mass of the earth's atmosphere? (the radius of the earth is 6.4 ´ 106 m, and atmospheric pressure at the surface is 105 n/m2.)
The total mass of the earth's atmosphere is 5×[tex]10^{8}[/tex] kg.
How do you calculate the total mass of the earth's atmosphere ?To calculate the total mass of the earth's atmosphere we use the expression
[tex]P=\frac{F}{A}[/tex]
or, [tex]F=P\times A[/tex]
or,[tex]M\times g=P\times A[/tex]
or,[tex]M=\frac{P\times 4\times \pi\times r^{2} }{g}[/tex]
Here, P= Atmospheric pressure at the surface = [tex]10^{5}[/tex] N/m2
F= Force at the earth surface.
A= Area of the earth.
r= Radius of the earth=6.4 × [tex]10^{6}[/tex] m
g= Acceleration due to gravity. = 9.8 m/s2 ≈ 10 m/s2
Let, M be the total mass of the earth's atmosphere.
Now, [tex]M=\frac{10^{5}\times4\times\pi\times(6.4\times10^{6} )^{2} }{10}[/tex]
M= 5×[tex]10^{8}[/tex] kg.
Thus from the above calculation we can show that, the total mass of the earth's atmosphere is 5×[tex]10^{8}[/tex] kg.
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A proton moves a distance 10 cm in a uniform electric field of 3.5 kN C, in the direction of the field.
Calculate the change in potential energy of the proton.
The change in potential energy of the proton is 5.6 x [tex]10^{-17}[/tex] Joule
What is a Uniform Electric Field ?A uniform electric field is where the electric field strength is the same at all points in the field. In the uniform field, the force experienced by a charge is the same no matter where it is placed in the field.
Given that a proton moves a distance 10 cm in a uniform electric field of 3.5 kN C, in the direction of the field.
The distance d = 10 cm = 0.1 mElectric field E = 3.5 KN/CProton charge q = 1.6 x [tex]10^{-19}[/tex] CThe Work done = Fd
but F = Eq
Recall that Electric field E = F/q = V/d
Where V = potential difference.
Let us first calculate the V
E = V/d
V = Ed
Substitute all the parameters into the formula above
V = 3.5 × 10³ × 0.1
V = 350 v
from F/q = V/d
make F the subject of formula and substitute it in work formula
F = Vq/d
W.D = Vq/d x d
W.D = Vq
Substitute all the parameters into the formula above
W.D = 350 x 1.6 x [tex]10^{-19}[/tex]
W.D = 5.6 x [tex]10^{-17}[/tex] J
Work done = Energy = Potential Energy
Therefore, the change in potential energy of the proton is 5.6 x [tex]10^{-17}[/tex] Joule
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Approximating the eye as a single thin lens 2. 70 cm from the retina, find the focal length of the eye when it is focused on an object at a distance of 265 cm?
The focal Length of the eye is 0.37cm.
The retina, which is always 2.70 cm away from the lens, serves as the image's primary imaging medium. Image distance is 2.70 cm as a result.
The object is located 265 cm away from the eye's lens.
Based on lens formula:
[tex]\frac{1}{f} = \frac{1}{u} + \frac{1}{v}[/tex]
where the object distance is u, the image distance is v, and the focal length is f.
Consequently, u is 265.00 cm and v is 2.70 cm.
[tex]\frac{1}{f} = \frac{1}{265} + \frac{27}{10}[/tex]
[tex]\frac{1}{f} = \frac{7165}{2650}[/tex]
[tex]f = \frac{2650}{7165}[/tex]
f = 0.37
Thus, the focal length of the eye is 0.37cm.
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how is that velocity got like this? pls explain
Answer:
if a car is increasing it's acceleration uniformly in a unit time, the graph will be moving away from it's origin. that's how you get this kind of graph.
As a gaseous element condenses, the atoms become ________ and they have ________ attraction for one another.
Answer:
blank 1: close together
blank 2: more
What angle (in degrees) is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value?
The 60 degrees is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value.
It is given that axis of a polarizing filter to cut its intensity to one-fifth of its initial value.
It is required to find the angle between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value.
What is the angle between the direction of polarized light and the axis of a polarizing filter?Suppose the angle between the polarizer and the axis of filter is θ.
The intensity of light that is passing after the filter is 0.2 l₀.
From the law of Malus, we have
I = I₀ [tex]cos^{2}[/tex]θ
0.2I₀= I₀ [tex]cos^{2}[/tex]θ
0.2 = [tex]cos^{2}[/tex]θ
[tex]cos\\[/tex]θ = 0.447
θ = 60°
Thus the angle between the direction of polarized light and the axis of a polarizing filter is 60 degree.
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A fisherman's scale stretches 3. 2 cm when a 2. 6 kg fish hangs from it. part a what is the spring stiffness constant?
The spring stiffness constant is 796.25 N/m.
A spring's "spring constant" is a property that quantifies the relationship between the force acting on the spring and the displacement it produces.
The slope of the plot of the straight line W vs x represents the spring constant, K. Weight (W) is defined as mass times the gravitational acceleration (g), where g is equal to approximately 980 cm/sec².
Mass of the fish = 2.6 kg
Length of the fisherman's scale, x = 3.2 cm
= 3.2/100 m
= 0.032 m
We have to find the value of k;
We know that,
F = - kx
Where k is the spring constant,
F is the force applied over x
x is the displacement by the spring expressed in N/m.
mg = - kx
g = 9.8 m/s²
[tex]K = \frac{mg}{x}[/tex]
[tex]= \frac{2.6*9.8}{0.032}[/tex]
[tex]= 796.25 N/m[/tex]
Therefore, the spring's constant is 796.25 N/m.
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Which method of measurement would be accurate but lack precision?
A. Measuring a volume of water by estimating the size of the
container
B. Measuring a volume of water using a graduated cylinder that can
be read to nearest mL
C. Measuring air temperature with a thermometer that has just been
taken out of hot water
D. Measuring air temperature with a thermometer that can be read to
the nearest degree and is calibrated to the correct temperature
Answer:
B
Explanation:
reading the volume of water in a graduated cylinder which can be read to the nearest mL is accurate, it lacks precision due to the bottom meniscus formed.
the bottom meniscus may cause a wrong reading due to refraction of light
Two point charges of 20. 0 μc and -8. 00 μc are separated by a distance of 20. 0 cm. what is the intensity of electric field e midway between these two charges? group of answer choices
The intensity of electric field E midway between these two charges is 2.52*10^7N/C.
To find the answer, we have to know more about the electric field.
How to find the electric field?We have the expression for net electric field as,[tex]E=\frac{kQ}{r^2}[/tex]
where, k is the constant equal to 8.99*10^9.
Thus, we can write the electric field created by 20micro coulomb charge at the midway between two charges is,[tex]E_1=\frac{8.99*10^9*20*10^{-6}}{10*10^{-2}} =1.79*10^7N/C[/tex]
We can write the electric field created by -8micro coulomb charge at the midway between two charges is,[tex]E_2=\frac{8.99*10^9*8*10^{-6}}{(10*10^{-2})^2} =7.19*10^6N/C[/tex]
Thus, the net field at the midway due to two charges will be,[tex]E=1.79*10^7+7.19*10^6=2.52*10^7N/C[/tex]
Thus, we can conclude that, the intensity of electric field e midway between these two charges is 2.52*10^7N/C.
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When starting a foot race, a 89 kilogram sprinter exerts an average force of 518 newtons backward on the ground for 0.75 seconds. what is his final speed in meters/second at the end of this action?
The final speed of the sprinter is 4.8 m/s.
What is newtons second law of motion?According to the second law, the mass of the item or the net force acting on it both affect how quickly an object accelerates.
An object's acceleration is directly proportional to the net force applied on it and inversely proportional to its mass.
An object's acceleration increases as the amount of force exerted on it does.
A decreasing acceleration is caused by a rise in an object's mass.
Calculation of final velocity;
The sprinter exerts an average force of 518 newtons backward on the ground.
The taken by sprinter is 0.75 sec.
The wight of the sprinter is 89Kg.
According to Newton's second law
Force = mass×acceleration
F = m×a
a = F/m
a = 518/89
a = 6.4 m/sec²
Now, apply the equation of motion of straight line;
final velocity = initial velocity + acceleration×time
As, the sprinter starts from rest; initial velocity = 0.
Substitute all the values;
final velocity = 0 + 6.4×0.75
= 4.8 m/sec
Therefore, the final velocity of sprinter comes out to be 4.8 m/sec.
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A wooden block contains some nails so that its density is exactly equal to that of water. if it is placed in a tank of water and released from rest when it is completely submerged, it will?
A wooden block contains some nails so that its density is exactly equal to that of water. if it is placed in a tank of water and released from rest when it is completely submerged, it will remain where it is released.
The concept of density seeks to measure the weight of an object in relation to its size. It is the measure of how packed together the particles of that object are. An object placed in a liquid displaces a certain volume of the liquid, based on the relative density of the object and the liquid.
If an object is less dense than a liquid in which it is placed, it displaces a smaller volume of the liquid than its volume, hence only some part of the object will be seen to be under the liquid, the other part will float.
If an object is denser than the liquid in which it is placed, it displaces a larger volume of the liquid than its own volume, making the object to sink and is submerged, sometimes to the bottom of the liquid, but mostly below the point at which it was released.
Finally, if the density of an object and the liquid into which it is submerged is the same. the object's mass per unit volume is the same as the liquid's mass per unit volume, hence the weight and force created due to density will balance and cancel each other out hence making the object to remain where it was submerged.
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An electron is traveling at 0. 85c. what is its mass? (the rest mass is 9. 11 × 10-31 kg. )
The mass of the electron is [tex]1.72\times 10^{-30}[/tex] Kg.
How can we calculate the mass of the electron?To calculate the mass of the electron we are using the formula,
[tex]m=\frac{m_{0} }{\sqrt{1-\frac{v^{2} }{c^{2} } } }[/tex]
Here we are given,
[tex]m_0[/tex]=The rest mass of an electron = [tex]9. 11 \times 10^{-31}[/tex] kg.
v= The velocity of electron = 0. 85c.
c= The velocity of light = c. (c=[tex]3\times 10^8[/tex] m/s)
We have to found the mass of an electron = m Kg.
Now we substitute the known values, we found that,
[tex]m=\frac{9. 11 \times 10^{-31} }{\sqrt{1-\frac{(0.85c)^{2} }{c^{2} } } }[/tex]
Or,[tex]m=\frac{9. 11 \times 10^{-31} }{\sqrt{1-(\frac{0.85c}{c})^2 } }[/tex]
Or,[tex]m=\frac{9. 11 \times 10^{-31} }{\sqrt{1-({0.85})^2 } }[/tex]
Or, [tex]m=1.72\times 10^{-30}[/tex] Kg.
From the above calculation we can conclude that, The mass of the electron is [tex]1.72\times 10^{-30}[/tex] Kg.
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(Repost) I need help with this physics question. Thanks in advance! Answer ASAP.
(a) The gravitational force received by each 1 kg mass is 8.66 N.
(b) The magnitude of gravitational acceleration is 8.66 m/s².
(c) The orbital speed of the ISS is 7,663.6 m/s.
(d) The time take for the ISS to orbit round the Earth is 5,558.75 seconds which is equal to 1.54 hours.
Gravitational force received by each 1 kg massThe gravitational force received by each 1 kg mass is calculated as follows;
F = Gm₁m₂/r²
where;
m₁ is mass of Earthm₂ is mass of ISSr is the distance between the ISS and center of EarthF = (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ x 1) / (6780,000)²
F = 8.66 N
Magnitude of gravitational accelerationmg = GMm/r²
g = GM/r²
where;
M is mass of Earthg = (6.67 x 10⁻¹¹ x 5.97 x 10²⁴ ) / (6780,000)²
g = 8.66 m/s²
Orbital Speed of the ISSv = √GM/r
v = √(6.67 x 10⁻¹¹ x 5.97 x 10²⁴ / 6780,000)
v = 7,663.6 m/s
Time of motion of the ISS round the EarthT = 2πr/v
T = (2π x 6780,000) / (7663.6)
T = 5,558.75 seconds
1 hour = 3600 seconds
= 5,558.75/3600
= 1.54 hours
Thus, the gravitational force received by each 1 kg mass is 8.66 N.
The magnitude of gravitational acceleration is 8.66 m/s².
The orbital speed of the ISS is 7,663.6 m/s.
The time take for the ISS to orbit round the Earth is 5,558.75 s = 1.54 hours.
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